I have a datetime field in my database that contains the following information:
2015-08-04 18:59:01
I want to check the difference between that datetime field and now using Cakephp framework ?
See DateTime::diff
$date = '2015-08-04 18:59:01';
$dateTime = new DateTime($date);
$now = new DateTime();
$interval = $now->diff($dateTime);
echo $interval->format('%R%a days');
See DateInterval::format for other formatting options.
You can also get diff in seconds:
$date = '2015-08-04 18:59:01';
$dateTime = new DateTime($date);
$diff = time() - $dateTime->getTimestamp();
Calculate the difference between two dates:
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
Output:
+272 days
The date_diff() function returns the difference between two DateTime objects.
Related
Trying to get the difference between last date vs today.
In a json file, i have unix date:
"lastUpdate": 1568937600,
And i've tried this but with no success.
<?php
$day = $item['lastUpdate'];;
$datetime1 = date_create('$day');
$datetime2 = date_create('now');
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%R%a');
?>
Try this:
$datetime1 = new DateTime(date('Y-m-d', $item['lastUpdate'])); //assuming that you have timestamp in the var $item
$datetime2 = new DateTime(date("Y-m-d", strtotime(date("now"))));
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a');
Hope it Helps.
Your date_create call on $day is wrong. You need to use double quote to render the variable inside. Also you need an # sign prefix to indicate it to be a timestamp:
<?php
$day = (int) $item['lastUpdate'];
$datetime1 = date_create("#{$day}");
$datetime2 = date_create('now');
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%R%a');
?>
Demo: http://sandbox.onlinephpfunctions.com/code/504afecb72bab656bcaf3be8d95bf7f06f5be845
date_create() receives the date/time string in with one of the specific Date and Time Formats. In your case, you're trying to convert a Unix Timestamp to a DateTime object. You can do that properly by replacing the following line:
$datetime1 = date_create('$day');
with:
$datetime1 = date_create('#'.$day);
I have an issue.I need to calculate the time difference but here the date_create function is not showing any output in php.I am explaining my code below.
while($row=mysqli_fetch_assoc($orderqry)){
$exit_date=$row['delivered_datetime'];
if($exit_date!=='0000-00-00 00:00:00'){
$deldate=date_create($exit_date);
$today=date_create(date('Y-m-d H:i:s'));
echo $today;exit;
$interval = date_diff($deldate, $today);
$hours = $interval->format('%h');
}
}
Here i am trying to echo $today but its not giving any result.Here i need to calculate the time difference in hour.In my DB i have existing time in the format of date('Y-m-d H:i:s').Please help me.
$today is DateTime instance. To echo it you need to call its format() method.
echo $today->format('Y-m-d H:i:s');
date_create is an alias of: DateTime::__construct(). see below example, I have assigned 6 Hour ago date in $exit_date. so ideally difference from current date should be 6 Hour.
$exit_date = date('Y-m-d H:i:s', strtotime('-6 Hours'));
$deldate=date_create($exit_date); //returns datetime class object
$today=date_create(date('Y-m-d H:i:s'));
$interval = date_diff($deldate, $today);
echo $hours = $interval->format('%h'); // output 6 hours
If you want to print date from $today variable then use:
echo $today->format('Y-m-d H:i:s'); //output: today's date in Y-m-d H:i:s format
for more detail have a look at http://php.net/manual/en/book.datetime.php
I have a datetime field in my database that contains the following information:
2012-05-03 17:34:01
I want to check the difference between the datetime field and now:
$now = date("Y-m-d H:i:s");
I am attempting to work out how many days have passed between now and the time written to the database field.
How can I achieve this?
Here is the answer :)
$now = new DateTime();
$date = new DateTime("2012-05-03 17:34:01");
echo $date->diff($now)->format("%d days, %h hours and %i minutes");
$diff = abs(strtotime($date2) - strtotime($date1));
date_diff:
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime("now");
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
I need to substract 2 datetimes, I tried a lot of things but nothing seems to work:
$startime = $historial->getStarttime(); //Datetime
$endtime = $historial->getEndtime(); //Datetime
$mytime = $endtime - $startime;
I also tried with strtotime(), date()...
Any help or clue?
Look at diff() method of DateTime object: http://www.php.net/manual/en/datetime.diff.php
<?php
$interval = $startTime->diff($endTime);
It returns a DateInterval method that you can format as you want: http://www.php.net/manual/en/dateinterval.format.php
<?php
echo $interval->format('%d days');
The substraction operator doesn't work like that, you'll need DateTime::diff():
$diff = $starttime->diff($endtime);
This shall return a DateInterval instance, that you can output in whatever format you want.
$datetime1 = new \DateTime('2009-10-11');
$datetime2 = new \DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
$datetime1->sub($interval);
echo $datetime1->format("Y-m-d"); // 2009-10-09
In certain situations I want to add 1 day to the value of my DATETIME formatted variable:
$start_date = date('Y-m-d H:i:s', strtotime("{$_GET['start_hours']}:{$_GET['start_minutes']} {$_GET['start_ampm']}"));
What is the best way to do this?
There's more then one way to do this with DateTime which was introduced in PHP 5.2. Unlike using strtotime() this will account for daylight savings time and leap year.
$datetime = new DateTime('2013-01-29');
$datetime->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');
// Available in PHP 5.3
$datetime = new DateTime('2013-01-29');
$datetime->add(new DateInterval('P1D'));
echo $datetime->format('Y-m-d H:i:s');
// Available in PHP 5.4
echo (new DateTime('2013-01-29'))->add(new DateInterval('P1D'))->format('Y-m-d H:i:s');
// Available in PHP 5.5
$start = new DateTimeImmutable('2013-01-29');
$datetime = $start->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');
If you want to do this in PHP:
// replace time() with the time stamp you want to add one day to
$startDate = time();
date('Y-m-d H:i:s', strtotime('+1 day', $startDate));
If you want to add the date in MySQL:
-- replace CURRENT_DATE with the date you want to add one day to
SELECT DATE_ADD(CURRENT_DATE, INTERVAL 1 DAY);
The DateTime constructor takes a parameter string time. $time can be different things, it has to respect the datetime format.
There are some valid values as examples :
'now' (the default value)
2017-10-19
2017-10-19 11:59:59
2017-10-19 +1day
So, in your case you can use the following.
$dt = new \DateTime('now +1 day'); //Tomorrow
$dt = new \DateTime('2016-01-01 +1 day'); //2016-01-02
Use strtotime to convert the string to a time stamp
Add a day to it (eg: by adding 86400 seconds (24 * 60 * 60))
eg:
$time = strtotime($myInput);
$newTime = $time + 86400;
If it's only adding 1 day, then using strtotime again is probably overkill.
You can use
$now = new DateTime();
$date = $now->modify('+1 day')->format('Y-m-d H:i:s');
You can use as following.
$start_date = date('Y-m-d H:i:s');
$end_date = date("Y-m-d 23:59:59", strtotime('+3 days', strtotime($start_date)));
You can also set days as constant and use like below.
if (!defined('ADD_DAYS')) define('ADD_DAYS','+3 days');
$end_date = date("Y-m-d 23:59:59", strtotime(ADD_DAYS, strtotime($start_date)));
I suggest start using Zend_Date classes from Zend Framework. I know, its a bit offtopic, but I'll like this way :-)
$date = new Zend_Date();
$date->add('24:00:00', Zend_Date::TIMES);
print $date->get();
Using server request time to Add days. Working as expected.
25/08/19 => 27/09/19
$timestamp = $_SERVER['REQUEST_TIME'];
$dateNow = date('d/m/y', $timestamp);
$newDate = date('d/m/y', strtotime('+2 day', $timestamp));
Here '+2 days' to add any number of days.
One liner !
echo (new \DateTime('2016-01-01 +1 day'))->format('Y-m-d H:i:s');