I have the three Models Post, Page and Category.
Each Page is assigned to one Category and each Post is assigned to one Page.
I have already defined the relationships in the models. What I want to do now is to use Eloquent ORM to get all Post-objects that are from a Page with a certain Category. So basically, in SQL I would need to do it like this
select p.* from posts p INNER JOIN pages pa ON pa.id = p.page_id where p.created_time > '2015-08-18 00:00:00' and pa.categories_id = 1 and p.isVisible = 1 order by p.total_count desc limit 100
I'm now somehow trying to do the same with Eloquent, but I'm stuck. My current code looks like this
// Getting all the top posts from facebook for today.
/** #var Builder $topPosts */
$topPosts = Post::where('created_time', '>', Carbon::today()->toDateTimeString());
if ($type !== null) {
$topPosts = $topPosts->where('type', $type);
}
return $topPosts->orderBy('total_count', 'desc')
->visible()
->take($limit)
->get();
Now, I wanted to add the category, but I don't know how to do it. I tried these steps here:
$topPosts = $topPosts->with(['page' => function($query) use($categoryId){
$query->where('page_categories_id', $categoryId);
}]);
and this one
$topPosts = $topPosts->with('page')->where('page_categories_id', $categoryId);
but none of them worked. How would I achieve that? I always get the error message
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'categories_id' in 'where clause' (SQL: select * from posts where created_time > 2015-08-18 00:00:00 and categories_id = 1 and isVisible = 1 order by total_count desc limit 100)
It looks like you need to use whereHas() in place your with() statement there (http://laravel.com/docs/4.2/eloquent#querying-relations)
This should work, and is basically just querying Posts with associated Pages with the particular category_id. I haven't included your ordering and things..
$posts = Post::where('created_time', '>', Carbon::today()) // Eloquent shouldn't actually need the toDateTimeString()
->with('page') // leave this in to eager load the page
->whereHas('page', function($query) use ($categoryId) {
$query->where('page_categories_id', $categoryId);
})
->get();
Related
I have a table (A) that has a One to Many relation with another table (B).
I want to query Table A and eager load Table B with the Table A results - but I also want to sort Table A by a value in Table B.
I have tried using OrderBy in the query and also trying SortBy on the resultant collection but cannot get the Table A data to be sorted by the value found in Table B.
Example of what I have tried:
$query = ModelA::with("ModelB"])->get()->sortByDesc('ModelB.sortValue');
Keep in mind, I am only interested in the LATEST record from Table B. So I need to query Table A and sort by a value in the LATEST records of Table B.
How can I achieve this?
EDIT:
The below (as suggested by #ljubadr) works pretty close, but the issue is that there are many record in Table B which means that it doesn't reliably sort as it doesn't seem to sortby the latest records in Table B. Can I have the join return ONLY the latest record for each ID?
$query = ModelA::select('TableA.*')
->join('TableB', 'TableA.id', '=', 'TableB.col_id')
->groupBy('TableA.id')->orderBy('TableB.sortCol', 'desc')
->with(['x'])
->get();
EDIT 2:
#Neku80 answer has gotten me closest but it seems to not sort the column with the greatest accuracy.. I'm sorting a Decimal column and for the most part it is in order but in some places the items are out of order..
$latestTableB = ModelB::select(['TableA_id', 'sortByColumnName'], DB::raw('MAX(created_at) as created_at'))
->groupBy('TableA_id');
$query = ModelA::select('TableA.*')
->joinSub($latestTableB, 'latest_TableB', function ($join) {
$join->on('TableA.id', '=', 'latest_TableB.TableA_id');
})
->orderBy('latest_TableB.sortByColumnName')
->get();
For example, the ordering is like:
0.0437
0.0389
0.0247 <-- -1
0.025 <-- +1
0.0127
When I delete all rows except for the 'latest' rows, then it orders correctly, so it still must be ordering with old data...
I have found a solution:
ModelA::select('TableA.*', 'TableB.sortByCol as sortByCol')
->leftJoin('TableB', function ($query) {
$query->on('TableB.TableA_id', '=', 'TableA.id')
->whereRaw('TableB.id IN (select MAX(a2.id) from TableB as a2 join TableA as u2 on u2.id = a2.TableA_id group by u2.id)');
})
->orderBy('TableB.sortByCol')
->get();
Another alternative to order is like this:
$users = User::orderBy(
Company::select('name')
->whereColumn('companies.user_id', 'users.id'),
'asc'
)->get();
Here we are ordering in asc order by company name field.
In this article it is explained in detail.
You can simply execute a left join query:
ModelA::query()->leftJoin('model_b_table', 'model_a_table.primary_key', '=', 'model_b_table.foreign_key')->orderBy('model_a_table.target_column')->get();
This should work if you only need TableB's ID and created_at columns:
$latestTableB = ModelB::select('TableA_id', DB::raw('MAX(created_at) as created_at'))
->groupBy('TableA_id');
$query = ModelA::select('TableA.*')
->joinSub($latestTableB, 'latest_TableB', function ($join) {
$join->on('TableA.id', '=', 'latest_TableB.TableA_id');
})
->orderBy('latest_TableB.created_at')
->get();
In laravel 8, I am filtering blog articles by category. However when I select multiple categories in my select menu. I do get the proper request . for example: articles/category/?category_ids=3,4
But it will only output one selected filter. If I select 2 filters it just selects that next filter as if I only selected that one. (I also use Axios but the request is done proper, so its in my Controller)
Here is my code I tried:
$data['articles'] = Article::whereHas('categories', function ($query) use($category_ids){
$query->whereHas('category_id', '=', $category_ids)->where('premium',0);
;})->get();
I also tried:
$data['articles'] = Article::whereHas('categories', function ($query) use($category_ids){
$query->whereIn('category_id', [$category_ids])->where('premium',0);
;})->get();
So how do I get to query both or more category id's ?
I am using a pivot table:
Articles can have many Categories
Categories can have many Articles
I use article_category as a pivot table
When checking for relationship existence in many-to-many relations, the check is still to be done against the id in the categories table.
Try this
$category_ids = collect(explode(',', $request->category_ids))
->map(fn($i) => trim($i))
->all();
$data['articles'] => Article::whereHas('category', fn($query) =>
$query->whereIn('categories.id', $category_ids)
->where('categories.premium', 0)
)->get();
You can explode the categories and then make the query like this.
$categories = explode(',',$request->categories);
$data['articles'] = Article::whereHas('categories', function ($query) use($categories){
$query->whereIn('category_id', $categories)->where('premium',0);
})->get();
I have two models: Users, Posts. User has many posts.
public function getPosts()
{
return $this->hasMany(Posts::className(), ['user_id' => 'id']);
}
I need to get only those users who have posts (posts>0).
How do I write query?
Users:find()->where(['>', 'posts', 0])->all()
The code above doesn't work.
Try This query :
Users:find()
->where('id IN (select user_id FROM posts GROUP BY user_id)')
->all();
To get users with at least one post you need to use INNER JOIN:
Users::find()
->innerJoinWith('posts', false)
->groupBy('users.id')
->all();
It should be more efficient that subquery.
If you want to filter by number of posts, you should add HAVING clause with count condition:
Users::find()
->innerJoinWith('posts', false)
->groupBy('users.id')
->having(new \yii\db\Expression('COUNT(*) > :posts_nr', ['posts_nr' => 2]))
->all();
But such queries may be really heavy on large databases - you should consider adding additional column with posts count to users table.
$orders = Users::find()->with('posts')->all();
Inner join should remove users where posts are null
I use laravel 5.3
My sql query is like this :
SELECT *
FROM (
SELECT *
FROM products
WHERE `status` = 1 AND `stock` > 0 AND category_id = 5
ORDER BY updated_at DESC
LIMIT 4
) AS product
GROUP BY store_id
I want to change it to be laravel eloquent
But I'm still confused
How can I do it?
In cases when your query is to complex you can laravel RAW query syntax like:
$data = DB::select(DB::raw('your query here'));
It will fire your raw query on the specified table and returns the result set, if any.
Reference
If you have Product model, you can run
$products = Product::where('status', 1)
->where('stock', '>', 0)
->where('category_id', '=', 5)
->groupBy('store_id')
->orderBy('updated_at', 'desc')
->take(4)
->get();
I think this should give you the same result since you pull everything from your derived table.
I am attempting to do the equivalent of this:
select p.id, p.title, b.brand,
(select big from images where images.product_id = p.id order by id asc limit 1) as image
from products p
inner join brands b on b.id = p.brand_id
Here is where I am at now, but it of course doesn't work:
public function getProducts($brand)
{
// the fields we want back
$fields = array('p.id', 'p.title', 'p.msrp', 'b.brand', 'p.image');
// if logged in add more fields
if(Auth::check())
{
array_push($fields, 'p.price_dealer');
}
$products = DB::table('products as p')
->join('brands as b', 'b.id', '=', 'p.brand_id')
->select(DB::raw('(select big from images i order by id asc limit 1) AS image'), 'i.id', '=', 'p.id')
->where('b.active', '=', 1)
->where('p.display', '=', 1)
->where('b.brand', '=', $brand)
->select($fields)
->get();
return Response::json(array('products' => $products));
}
I don't really see anything in the docs on how to do this, and I can't seem to piece it together from other posts.
In "regular" SQL, the subquery is treated AS a column, but I am not sure how to string that together here. Thanks for any help on this.
I strongly recommend you to use Eloquent, instead of pure SQL. It's one of the most beautful things in Laravel. Two models and relations and it's done! If you need to use pure SQL like that, put it all in DB::raw. It's easier, simpler and (ironically) less messy!
With the models, you could use relations between the two tables (represented by the models itself) and say (so far I understood) that Brands belongs to Products, and Images belongs to Product. Take a look at Eloquent's documentation on Laravel. Probably will be more clearly.
Once the relations are done, you can only say that you wanna get
$product = Product::where(function ($query) use ($brand){
$brand_id = Brand::where('brand', '=', $brand)->first()->id;
$query->where('brand_id', '=', $brand_id);
})
->image()
->get();
That and a better look at Eloquent's documentation should help you to do the job.
P.S.: I didn't test the code before send it and wrote it by head, but i think it works.