I couldn't understand what is wrong here. I cannot take the first row on database. I also cannot the data which are single according to $ara parameter. Here are the codes:
$ara =$_POST['ara'];
$query=$db->prepare("SELECT * FROM uyeler WHERE
name like '%".$ara."%' or
surname like '%".$ara."%' or
email like '%".$ara."%'
");
$query->execute(array());
if ($num_row = $query->fetchAll(PDO::FETCH_BOTH)){
echo "<li><a href='profil.php?id=".$num_row['user_id']."'>" .$num_row['name']. " " .$num_row['surname']."</a></li>";
}else{
echo "Hiç birşey bulunamadı!";
}
You need to correct your array call:
from
$num_row['user_id']
To
$num_row[0]['user_id']
Your code is tested and works, nice job.
what you need to correct is the following line:
echo "<li><a href='profil.php?id=" . $num_row[0]['user_id'] . "'>" . $num_row[0]['name'] . " " . $num_row[0]['surname'] . "</a></li>";
If you face such problem in the future, it is a good practice to var_dump the results like:
var_dump($num_row);
This will give you a total raw picture of the content.
Related
I split this string ($messageText) using a formula like this:
list($msgat, $message) = explode("!", "$messageText", 2);
selecting a row from my database:
with this:
$sql = "SELECT verse FROM ".$datatable." WHERE book LIKE '%".$message."'";
I need to come up with a way to make this: (which works, on a page echoing)
echo " " . $row["book"]. " " . $row["verse"]. "<br>";
something back into a single string: something like this I've been trying.
$answer = " . $row["verse"]. "
thus, I would be able to use the original but changed, variable elsewhere.
I have tried various methods, trying to concoct a solution...
$answer = $row["verse"] ;
etc etc... I am stumped... it is probably right before me I just can't find it.
$answer = " " . $row["book"]. " " . $row["verse"]; //this will store value into single variable answer
echo $answer; // use this if you want to display the result on the page.
this will definitely work if not show us the error so that we can resolve it.
I would like to do something quite simple but I dont know the right code in php.
I have a variable $go which content is GO:xxxxx
I would like to query that if the content of a variable has the pattern "GO:" and something else, echo something, but if not, echo another thing
I want to declare an if statement like:
if (preg_match('/GO/', $go) {
echo "something";
}
else {
echo "another thing";
But I cannot make it work...
I want to embed this statement between this portion of my script:
$result = mysqli_query($enlace,"select count(distinct name2) as total from " . $table . " where go_id like '%" . $go . "%'");
$items = mysqli_fetch_assoc($result);
echo "<br/>";
echo "<b> The total number of genes according to GO code is:</b> " . $items['total'];
mysqli_free_result($result);
$result2 = mysqli_query($enlace,"select count(distinct name2) as total from " . $table . " where db_object_name like '%" . $go . "%'");
$items2 = mysqli_fetch_assoc($result2);
echo "<br/>";
echo "<b>The total number of genes according to GO association is:</b> " . $items2['total'];
mysqli_free_result($result2);
As it is right now, the variable $go can have a value like GO:xxxx or a random sentence, and, with this code, I get two strings, one with value 0 and another with value according to the total apperances matching $go content.
What I want is to declare an if statement so that it just prints one string, the one that has the number of matches according to $go content, but not both.
Any help?
Use strpos():
if (strpos($go, 'GO:') !== false) {
echo 'true';
}
Try this
echo (!strpos($go, 'GO:')) ? "another thing" : "something";
Will surely work
I'm looking to create a formatted product list from an SQL database. My aim is to have a store on my website with a series of small boxes containing some shorthand information about each product, that when clicked will open a pop-up containing detailed information. (I have a working Javascript/JQuery code to create the pop-ups.)
Here is the PHP code so far, simply to get the information from the database and display it on a webpage...
(I've been using XAMPP to provide an environment for me to test the code in)
<?php
mysql_connect("localhost", "root", "") or die (mysql_error ());
mysql_select_db("Database1") or die(mysql_error());
$strSQL = "SELECT * FROM Products";
$rs = mysql_query($strSQL);
while($row = mysql_fetch_array($rs)) {
echo $row['Brand'] . " " . $row['ProductName'] . " " . $row['Image'] . "<br />";
}
mysql_close();
?>
I want the echoed line to be displayed in a divider, with a divider generated for each record in the SQL database (say I have 10 products available, there would be ten dividers, and 10 different boxes on the webpage). The divider's class is "ProductBox".
echo "<div class=\"ProductBox\">"; $row['Brand'] . " " . $row['ProductName'] . " " . $row['Image'] . "</div>";
This was the closest I have come to a solution, which was simply managing to write a code with no syntax errors - alas, nothing actually displays on the webpage.
If I'm going about this entirely the wrong way please tell me - I'm fairly sure I need to use a SQL database to dynamically update stock on a live website, but if I need to implement a different programming language or whatever then just tell me what you think would work and help me with a solution.
You have an extra semicolon in your code
echo "<div class=\"ProductBox\">"; $row['Brand'] . " " . $row['ProductName'] . " " . $row['Image'] . "</div>";
Replace with
echo "<div class=\"ProductBox\">". $row['Brand'] . " " . $row['ProductName'] . " " . $row['Image'] . "</div>";
mysql_fetch_array needs to be used like this (see PHP Doc):
while($row = mysql_fetch_array($rs, MYSQL_ASSOC)) {
}
or you could just use "mysql_fetch_assoc" instead.
HOWEVER, if you're new to PHP, I HIGHLY RECOMMEND that you get started on the right foot. mysql_query functions are soon to be deprecated. DON'T USE THEM. Most recommend using "PDO" for querying your database. Here's a great tutorial to teach you: http://wiki.hashphp.org/PDO_Tutorial_for_MySQL_Developers
Also, as mentioned, you have an extra semi-colon.
Dont forget these basics markups :
`<HTML>
<HEAD>
</HEAD>
<BODY> put in here your divs
</BODY>
</HTML>`
I have deleted the table and started over with new data over and over and tried to figure out why my loop is adding an extra empty result at the beginning. The code that I am using for the loop is below.
$sql = "SELECT * FROM `addresses` WHERE `company_name` = '$pro_company'";
$query = $mysqli->query("$sql");
while($array[] = $query->fetch_object());
array_pop($array);
foreach($array as $listing) :
echo $listing->Taddress . " ";
echo $listing->Tcity. " ";
echo $listing->Tstate . " ";
echo $listing->Tzip . " ";
echo " <a href='edit.php?pid=". $listing->PID . "'>edit</a> |";
echo " <a href='delete.php?pid=". $listing->PID . "'>delete</a>";
echo "</a><br />";
endforeach;
The results I am getting from this loop are below.
edit | delete
14220 Parrott Ext. TestCity AL 84106 edit | delete
I am trying to learn mysqli statements so I am sure there is something I am missing.
Thanks for your help in advance.
Throw a
print_r($array);die;
Before the foreach and look at the output. This should give you an idea of where exactly the problem is located.
Most likely your database has a row with no values. Check that first. happens more often than you realise (to me anyway)
As a possible solution, you can add an extra condition before echo'ing to ensure a value exists
foreach($array as $listing) :
if($listing->Taddress){
echo $listing->Taddress . " ";
Personally, I'd find the cause first. print_r will help
for some friends and family (different sites), I created a script that allows them to input data into the database. With
echo ("<a href=\"./pagina.php?ID=" . $row['ID'] . "\">" . $row['ID'] . "<br>");
, I 'send' the ID of the requested table to the URL.
In pagina.php, I have this code:
ID: <?php echo $_GET["ID"]; ?>
That works, of course, but now I want to use that ID to also display the data from the database, so not from the URL. These values are " . $row['onderwerp'] . " and " . $row['tekst'] . "
(There may be more values to come, but I'm just a beginner, trying to get something to work).
I know this is possible, but I just can't get anything to work, as I have just started learning PHP.
I hope you can help me.
If you don't care whether data came from a $_COOKIE, $_GET, or $_POST, you can use $_REQUEST.
$id = (int)$_GET['id'];
$sql = "SELECT onderwerp, tekst FROM yourtable WHERE id=$id";
$result = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_assoc($result)) {
echo "{$row['onderwerp']} - {$row['tekst']}<br />";
}