This is my table in my database. It should only contain one row.
I have this code, that checks if there is no data , if there is not.. The data is inserted, else it's updated. The problem is, that if i update only Brevet, the value of Baccalaureabt will disappear from my database. Any help?
Code:
if(isset($_POST['submit']))
{ $brevet = $_POST['Brevet'];
$baccalaureatbt = $_POST['Baccalaureatbt'];
$sql1="SELECT Brevet,Baccalaureatbt FROM university";
if ($result=mysqli_query($con,$sql1))
{
$rowcount=mysqli_num_rows($result);
}
if($rowcount==0)
{
$sql="INSERT INTO university(Brevet,Baccalaureatbt) VALUES('$brevet','$baccalaureatbt')";
$result = mysql_query($sql);
}
else
{
$sql2 = "UPDATE university SET Brevet = '$brevet' , Baccalaureatbt = '$baccalaureatbt'";
$result2 = mysql_query($sql2);
}
The issue is that you are setting both values, if however either $baccalaureatbt or $brevet is empty, it will be updated with a empty value, i.e the original value will be deleted.
There are multiple ways to avoid this, but one way to do it is like so:
$sql2 = "UPDATE university SET ";
if(!empty($brevet)){
$sql2 .= "Brevet = '$brevet'";
$first = 1;
}
if(!empty($baccalaureatbt)){
$sql2 .= isset($first) ? ", Baccalaureatbt = '$baccalaureatbt'" : "Baccalaureatbt = '$baccalaureatbt' " ;
}
$result2 = mysql_query($sql2);
To update the values dynamically, use the following code. Just add the values you want in the values array.
if(isset($_POST['submit']))
{
$brevet = $_POST['Brevet'];
$baccalaureatbt = $_POST['Baccalaureatbt'];
$sql1="SELECT Brevet,Baccalaureatbt FROM university";
$result=mysqli_query($con,$sql1);
if ($result)
{
$rowcount=mysqli_num_rows($result);
}
if($rowcount==0)
{
$sql="INSERT INTO university(Brevet,Baccalaureatbt) VALUES('$brevet','$baccalaureatbt')";
$result = mysql_query($sql);
}
else
{
$values = array("brevet","baccalaureatbt");
$sql2 = "UPDATE university ";
$n = 0;
foreach($_POST as $key => $val) {
if(in_array($key, $values)) {
$sql2 += ($n !== 0 ? ", " : 0);
$sql2 += "SET".$key." = ".$val;
$n++;
}
if($n > 0) {
$result2 = mysql_query($sql2);
}
}
}
}
Related
When Inserting data into SQL it inserts two into rows, and I don't know why.
most probably of the if statement I added after the results you can find it as my comment:
// id_no update
And I used the select query two times to fetch the id and make it an auto-increment thing.
my table:
<?PHP
$query = "SELECT id_no FROM db_name ORDER BY id_no DESC";
$result = mysqli_query($con,$query);
$row = mysqli_fetch_array($result);
$lastid = $row['id_no'];
if(empty($lastid))
{
$number = "SX000001";
}
else
{
$idd = str_replace("SX", "", $lastid);
$id = str_pad($idd + 1, 6, 0, STR_PAD_LEFT);
$number = 'SX'.$id;
}
?>
<?PHP
if(isset($_POST['add_id']))
{
$id_no = mysqli_real_escape_string($con,$_POST['id_no']);
$sql="INSERT INTO `db_name`(`id_no`) VALUES ('$id_no')";
$result=mysqli_query($con,$sql);
// id_no update
if(mysqli_query($con,$sql))
{
$query = "SELECT id_no FROM db_name ORDER BY id_no DESC";
$result = mysqli_query($con,$query);
$row = mysqli_fetch_array($result);
$lastid = $row['id_no'];
if(empty($lastid))
{
$number = "SX000001";
}
else
{
$idd = str_replace("SX", "", $lastid);
$id = str_pad($idd + 1, 6, 0, STR_PAD_LEFT);
$number = 'SX'.$id;
}
}
else
{
echo "Record Faileddd";
}
if($result)
{
$success="Post has been added successfully";
} else
{
$error="Something went wrong!";
}
$id_no = '';
}
?>
You should check if $result is truthy to see if the insertion succeded (without running another query):
$id_no = mysqli_real_escape_string($con,$_POST['id_no']);
$sql="INSERT INTO `db_name`(`id_no`) VALUES ('$id_no')";
$result=mysqli_query($con,$sql);
// id_no update
if($result)
{
...
}
$a_forms = array("a_GG", "a_FF");
$sql = "SELECT name, field FROM categories WHERE enabled = '1' ";
$result = mysqli_query($con,$sql);
$Others = array();
while($row = mysqli_fetch_array($result)) {
$Other_names[] = $row['name'];
$Other_fields[] = $row['db_field'];
}
for ($i=0;$i<count($a_forms);$i++) {
if ($a_forms[$i] == "a_FF") {
$dforms_sql = "SELECT *
FROM a_FF
where id=".$id;
$dforms_result = mysqli_query($con,$dforms_sql);
while ($forms_row = mysqli_fetch_array($dforms_result)) {
for ($i=0; $i<count($Other_fields); $i++) {
echo "<tr><td colspan='3'>".$Other_names[$i]."</td></tr>";
}
}
} elseif ($a_forms[$i] == "a_GG") {
$dforms_sql = "SELECT *
FROM a_GG where id=".$id;
$dforms_result = mysqli_query($con,$dforms_sql);
while($forms_row = mysqli_fetch_array($dforms_result)) {
echo 'Other cool stuff';
}
}
} //END (first) For Loop
So, for some reason, if that second for loop, $Other_field is there it will only show the IF statement for a_FF. But if the array = a_FF and a_GG and the for loop for $other_field is NOT there it displays them both. So it's obviously that for loop that is breaking something, I have no idea what though. Anyone have any thoughts?
I'm inserting into my database id and hours, which is working successfully. However when i insert a new value for an id that has a previous value, the old val isn't replaced by the new, instead they're kept both. I'm trying to update the function with an if/else statement (commented part). But still the same result. The if/else statement must check first if hours (a column in the table) value is empty, if so then perform sql insert, else perform sql update. Any help please?
if (isset($_POST['submit'])) {
$hours = $_POST['Hours'];
$selectid = $_POST['SelectID'];
$sql1 = "INSERT INTO `editedworkhours` (`id`,`H`) VALUES('$selectid','$hours')";
$getResult = mysql_query($sql1);
if (mysql_affected_rows() > 0) {
} else {
}
$tempname = $row['Field'];
$sql2 = "UPDATE editedworkhours SET H ='" . $_GET["hours"] . "' WHERE IDNumber='" . $_GET["selectid"] . "'";
$result2 = mysqli_query($con, $sql2);
if ($con->query($sql2) === TRUE) {
} else {
}
}
echo $menu;
Try this
<?php
if(isset($_POST['submit']))
{
$addedhours = $_POST['AddedHours'];
$selectaf = $_POST['SelectAF'];
$sql1="SELECT * FROM editedworkhours WHERE AFNumber='$selectaf' and AddedWH ='$addedhours'";
$getResult = mysql_query($sql1);
$count = count($getResult);
if(!empty($count) || $count==1)
{
$tempname = $row['Field'];
$sql2 = "UPDATE editedworkhours SET AddedWH ='$addedhours' WHERE AFNumber='$selectaf'";
$result2 = mysql_query($sql2);
if (isset($result2))
{
//Data inserted
}
else
{
//Insert Failed
echo '<script>swal("Error", "Something went wrong error");</script>';
}
echo '<script>swal("Success", "Changes have been saved", "success");</script>';
}
else
{
$sql3 = "INSERT INTO editedworkhours (AFNumber,AddedWH) VALUES('$selectaf','$addedhours')";
$Result = mysql_query($sql3);
if(isset($Result))
{
echo 'Success';
}
else
{
echo 'Failed';
}
}
}
echo $menu;
Hello I'm checking duplicated data from tables. I have a problem that from where data selected. My code is:
$sub_cat = array();
$select = array("core_network","daisy_chain", "rf_bts", "rf_power", "rf_transmission");
$d='0';
for ($i=0;$i<=4;$i++){
$SQL = "SELECT sub_cat FROM (".$select[$i].") WHERE location=('".$id."')";
$result = mysql_query($SQL);
$cs=$d;
if ($result) {
while ($db_field = mysql_fetch_array($result)) {
if(!in_array($db_field['sub_cat'],$sub_cat)) {
$sub_cat[]= $db_field['sub_cat'];
$cs++;
$d=$cs;
$d--;
}
}
}
I need to know that sub_cat selected from which $select[i]. How to find it?
To get the values, do this:
$sub_cat = array();
$select = array("core_network","daisy_chain", "rf_bts", "rf_power", "rf_transmission");
$d='0';
for ($i=0;$i<=4;$i++){
$SQL = "SELECT sub_cat FROM (" . $select[$i] . ") WHERE location=('".$id."')";
$result = mysql_query($SQL); // deprecated - use PDO
$cs = $d;
if ($result) {
while ($db_field = mysql_fetch_array($result)) {
if(!in_array($db_field['sub_cat'], $sub_cat)) {
$table = $select[$i];
$sub_cat[$table][] = $db_field['sub_cat'];
// I have no clue what's going on here in your example:
$cs++;
$d=$cs;
$d--;
}
}
}
}
Then, to retrieve it:
foreach ($sub_cat as $table_name => $values) {
foreach ($values as $row) {
// output values here
}
}
I'm using PHP/MySql and I'm trying to team users into pairs based on a skill that they have. I have an existing table for users, and an existing table for the teams.
For example, I executed a query which returned 6 members which needs to be paired up into a team.
SELECT * FROM users WHERE skill = 'Office'
users
id/name/skill
1/Bob/Office
2/Ted/Office
3/Tim/Office
4/Bill/Office
5/Shawn/Office
6/Gab/Office
These results must be then paired up, and the expected output should be:
teams
name/member
Office1/Bob
Office1/Ted
Office2/Tim
Office2/Bill
Office3/Shawn
Office3/Gab
Once 2 members are placed in a team, the team name should increment by one.
Any help will be greatly appreciated Thanks.
Edit: I tried this:
$results = mysql_query("SELECT * FROM users WHERE skill = 'Office'");
$numrows = mysql_num_rows($results); $name ="";
if($numrows!=0) {
while($row = mysql_fetch_assoc($results)) {
$name = $row['userName'];
}
}
//For incrementing the team name
$namectr=0;
for($ctr=0;$ctr<$results_num;$ctr++) {
if($ctr%2==0) {
$query = mysql_query("INSERT INTO teams VALUES ('Office$namectr','$name')");
$ctr++; if($ctr%2==1) {
$query = mysql_query("INSERT INTO teams VALUES (Office$namectr','$name')");
$namectr++;
}
}
}
why not try:
$result = mysql_query("SELECT * FROM users WHERE users.skill = 'office'");
$count = 0;
$sqlcount = 0;
$offcount = 1;
while ($source = mysql_fetch_array($result)) {
if ($count < 1) {
$office = $source['skill'] . $offcount;
$name = $source['name'];
$result[$sqlcount] = mysql_query("INSERT INTO teams ('name', 'member') VALUES ('$office', '$name')");
$sqlcount++;
} else if ($count >= 1) {
$offcount++;
$count = 0;
$office = $source['skill'] . $offcount;
$name = $source['name'];
$result[$sqlcount] = mysql_query("INSERT INTO teams ('name', 'member') VALUES ('$office', '$name')");
$sqlcount++;
} else {
echo "ERROR" . mysql_error();
}
}//end while
$sqlcount = 0;
while ($result[$sqlcount] != "") {
if ($source = $result) {
} else {
echo "ERROR! " . mysql_error();
}
}//end while
Couldn't you do your database query, then do something like the below:
$count=0;
$team=1;
$teams = array();
foreach($result as $output){
if($count % 2 == 0){
// if even number, reset count and increment position
$count=0;
$team++;
}
$teams[] = $output['skill']." ".$team." - ".$output['member'];
$count++;
}
Something like the above, but it is untested, but should work in theory.