I have to Tables: Users hasmany Memberhip. I would like to build a query to get ALL Users but EACH User should only contain the FIRST Membership (after ordering).
$users = $this->Users->find()->contain([
'Membership' => function ($q) {
return $q->order([
'year' => 'ASC'
])->limit(1);
},
'Countries',
'Board',
]);
Seems good so far. The problem is, that this query only gets a single Membership alltogether. So in the end of all Users that are beeing fetched, only one User has one Membership.
How do I get CakePHP to fetch ONE Membership for EACH User?
Thanks!
Sort key for hasOne option doesn't exist (see : CakePhp3 issue 5007)
Anyway I had the same problem and thanks to ndm : here his solution
I ended up using this:
$this->hasOne('FirstPhoto', [
'className' => 'Photos',
'foreignKey' => false,
'conditions' => function (\Cake\Database\Expression\QueryExpression $exp, \Cake\ORM\Query $query) {
$subquery = $query
->connection()
->newQuery()
->select(['Photos.id'])
->from(['Photos' => 'photos'])
->where(['Photos.report_id = Reports.id'])
->order(['Photos.id' => 'DESC'])
->limit(1);
return $exp->add(['FirstPhoto.id' => $subquery]);
}
]);
Reference: How to limit contained associations per record/group?
You can do this is by creating another association (Make sure you don't include a limit you don't need one as the hasOne association creates the limit):
$this->hasOne('FirstMembership', [
'className' => 'Memberships',
'foreignKey' => 'membership_id',
'strategy' => 'select',
'sort' => ['FirstMembership.created' => 'DESC'],
'conditions' => function ($e, $query) {
return [];
}]);
This works for limiting to 1 but if you want to limit to 10 there still seems to be no good solution.
Related
I'm using Cake's $table->find('list') finder method to retrieve an array of associated users [id => name]. Have used it in the past and its worked well. In this find I'm containing a belongsToMany table and retrieving [id => name].
In \App\Model\Table\SitesTable::initialize the ClientUsersWithAuthorities belongsToMany relationship is defined
$this->belongsToMany('ClientUsersWithAuthorities', [
'className' => 'AppUsers',
'joinTable' => 'sites_client_users',
'foreignKey' => 'site_id',
'targetForeignKey' => 'user_id',
'propertyName' => 'client_users_with_authorities']);
In \App\Controller\ClientGroupsController::getClientgroupUsers
$siteClientUsers = $this->Sites->find('list', [
'keyField' => 'client_users_with_authorities.id',
'valueField' => 'client_users_with_authorities.full_name'])
->where(['id' => $siteId])
->contain(['ClientUsersWithAuthorities'])
->toArray();
$siteClientUsers returns [0 => null] instead of [1234 => 'Client 1 name', 5678 => 'Client 2 name'] as expected. Both users exist in the join table.
Three other methods (below) return the array I'm looking for and which I'm expecting $this->Sites->find('list') to produce.
The cookbook describes associated data can be listed.
https://book.cakephp.org/3.0/en/orm/retrieving-data-and-resultsets.html#finding-key-value-pairs
So why isn't $this->Sites->find('list') producing the expected array?
mapReduce
$mapper = function ($data, $key, $mapReduce) {
if (!empty($data['client_users_with_authorities'])) {
foreach ($data['client_users_with_authorities'] as $user) {
$mapReduce->emit($user);
}}};
$siteClientUsers = $this->Sites->find('list', [
'keyField' => 'id',
'valueField' => 'full_name'])
->where(['id' => $siteId])
->contain(['ClientUsersWithAuthorities'])
->mapReduce($mapper)
->toArray();
Hash::combine
$siteClientUsers = $this->Sites->find('all')
->where(['id' => $siteId])
->contain(['ClientUsersWithAuthorities'])
->toArray();
$siteClientUsers = Hash::combine($siteClientUsers,'{n}.client_users_with_authorities.{n}.id', '{n}.client_users_with_authorities.{n}.full_name');
Temp belongsTo relationship on the join table
$table = $this->getTableLocator()->get('SitesClientUsers');
$table->belongsTo('Users', [
'className' => 'AppUsers',
'foreign_key' => 'user_id']);
$siteClientUsers = $table->find('list', [
'keyField' => 'Users.id',
'valueField' => 'Users.full_name'
])
->select(['Users.id', 'Users.full_name'])
->where(['SitesClientUsers.site_id' => $siteId])
->contain(['Users'])
->toArray();
The Cookbook says:
You can also create list data from associations that can be reached with joins
The important part being "that can be reached with joins", which isn't the case for belongsToMany associations. Given that list transformation happens on PHP level, the description should maybe focus on that instead, but it's still kinda valid as it stands.
client_users_with_authorities will be an array, ie possibly multiple records, so you cannot use it to populate a parent record - one Sites record represents one list entry. If you want to find a list of ClientUsersWithAuthorities that belongs to a specific site, then you can either use one of your other solutions (or something similar to that), or you could for example query from the other side of the association and use a matcher on Sites:
$query = $this->Sites->ClientUsersWithAuthorities
->find('list', [
'keyField' => 'id',
'valueField' => 'full_name'
])
->matching('Sites', function (\Cake\ORM\Query $query) use ($siteId) {
return $query->where([
'Sites.id' => $siteId
]);
})
->group('ClientUsersWithAuthorities.id');
This would create joins based on Sites.id, so that you'd only retrieve the ClientUsersWithAuthorities that are associated with Sites where Sites.id matches $siteId.
See also
Cookbook > Database Access & ORM > Query Builder > Filtering by Associated Data
I am trying to make a list of grouped things in CakePHP 3, to create a grouped list of things in a select list in a form. I'm not sure if I am missing something or if I'm expecting too much of Cake and should be doing more myself.
I have a controller called Issues and a self-referencing column called RelatedIssues. Each Issue belongs to a System, and it's the systems I want the issues grouped by.
In my IssuesTable.php:
$this->belongsTo('RelatedIssues', [
'className' => 'Issues',
'foreignKey' => 'issue_id'
]);
$this->belongsTo('Systems', [
'foreignKey' => 'system_id',
'joinType' => 'INNER'
]);
...and in my IssuesController's edit method:
$relatedIssues = $this->Issues->RelatedIssues->find('list', [
'groupField' => 'system_id'
]);
When I get to the drop-down list, items are grouped by system_id as specified, but I cannot figure out how to get them grouped by the System's title field. Is this even possible, or do I have to write a nice nested foreach structure to do this myself?
should be (can'try it now):
$relatedIssues = $this->Issues->RelatedIssues->find('list', [
'groupField' => 'system.title'
])->contain('Systems');
Consider the following, is more clear:
$relatedIssues = $this->Issues->RelatedIssues->find('list', [
'contain' => ['Systems'],
'order' => [ 'Systems.title' => 'ASC', 'RelatedIssues.title' => 'ASC'],
'groupField' => function($entity) {
return $entity->system->title;
}
]);
I'm asking myself something... Here is the question :
I have a model Request. This model has a status. (let's say it is an integer)
As the status will change through the time AND as I want to keep a record of each changes this was pretty clear in my mind that the status will not be a field of the Request table/model.
I thought I will add a table/model RequestStatus and say to CakePHP
Request hasMany RequestStatus
Then I thought that it will be simple to retrieve all the Request that has a valid status only.
But I was wrong.
Using containable is not good as it retrieve the Request even if they have a wrong status (or even if they don't have a status).
So, I tested 2 solutions :
Binding on the fly the RequestStatus model as a hasOne relation but
it not works as expected
Use a joins key/array when making my find call.
There is clearly something that I missed because, this is not working.
Am I missing something ? Or the best way to do it is by having a status field in the Request table ?
EDIT : What I forgot to mention is that I need to use this query with the pagination of CakePHP
I will assume a couple of things you didn't mention. First of all, I suppose you also created a RequestStatus belongsTo Request relationship. And I imagine your RequestStatus table have four columns: id, status, request_id and created. The request_id column is the foreign key and created is the magic field that CakePHP populates when a new row is created. I also assume you are using Containable behaviour.
With that, you can go three different ways:
1) You can retrieve last valid Statuses along with their Requests.
In your RequestModel:
public function getValidRequests() {
$db = $this->RequestStatus->getDataSource();
$subquery = $db->buildStatement(array(
'fields' => array('request_id', 'max(created) as lastcreated'),
'table' => $db->fullTableName($this->RequestStatus),
'alias' => 'temp',
'group' => array('request_id')
), $this->RequestStatus);
return $this->RequestStatus->find('all', array(
'contain' => array('Request'),
'joins' => array(
array(
'table' => '(' . $subquery . ')',
'alias' => 'rs2',
'type' => 'right',
'conditions' => array(
'RequestStatus.request_id = rs2.request_id',
'RequestStatus.created = rs2.lastcreated'
)
)
),
'conditions' => array('RequestStatus.status' => 1),
'order' => array('RequestStatus.request_id' => 'desc')
));
}
2) You can retrieve all Requests with their Status, then return only those with last valid status.
In your RequestModel:
public function getValidRequests() {
$requests = $this->find('all', array(
'contain' => array(
'RequestStatus' => array(
'order' => array('RequestStatus.created' => 'desc')
)
)
));
$result = array();
foreach ($requests as $request) {
if ($request['RequestStatus'][0]['status'] == 1)
$result[] = $request;
}
return $result;
}
3) Denormalization.
Add a last_status column in your Request table. So every time you update a request's status, insert that new status into your RequestStatus table and save that new status to Request.last_status. Now you can simply do:
public function getValidRequests() {
return $this->find('all', array(
'conditions' => array('Request.last_status' => 1)
));
}
I wrote 2 days ago to ask about andConditions and it appeared that I didn't understand the idea but the fact is that for two days now I am stuck with the next step using CakeDC:
How do I implement complex HABTM conditions in "query" methods for CakeDC search plugin?
I have Offer HABTM Feature (tables: offers, features, features_offers) and the below works just fine when used in controller:
debug($this->Offer->find('all', array('contain' => array(
'Feature' => array(
'conditions' => array(
'Feature.id in (8, 10)',
)
)
)
)
)
);
The problem comes when I want to use the same conditions in the search:
public $filterArgs = array(
array('name' => 'feature_id', 'type' => 'query', 'method' => 'findByFeatures'),
);
........
public function findByFeatures($data = array()) {
$conditions = '';
$featureID = $data['feature_id'];
if (isset($data['feature_id'])) {
$conditions = array('contain' => array(
'Feature' => array(
'conditions' => array(
'Feature.id' => $data['feature_id'],
)
)
)
);
}
return $conditions;
}
I get an error:
Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column
'contain' in 'where clause'
which makes me think that I cannot perform this search and/or use containable behavior in searches at all.
Can someone with more experience in the field please let me know if I am missing something or point me to where exactly to find a solution for that - perhaps a section in the cookbook?
EDIT: Also tried the joins. This works perfectly fine in the controller, returning all the data I need:
$options['joins'] = array(
array('table' => 'features_offers',
'alias' => 'FeaturesOffers',
'type' => 'inner',
'conditions' => array(
'Offer.id = FeaturesOffers.offer_id'
),
array('table' => 'features',
'alias' => 'F',
'type' => 'inner',
'conditions' => array(
'F.id = FeaturesOffers.feature_id'
),
)
),
);
$options['conditions'] = array(
'feature_id in (13)' //. $data['feature_id']
);
debug($this->Offer->find('all', $options));
... and when I try to put in the search method I get the returned conditions only in the where clause of the SQL
WHERE ((joins = (Array)) AND (conditions = ('feature_id in Array')))
...resulting in error:
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'joins' in 'where clause'
EDIT: Maybe I am stupid and sorry to say that but the documentation of the plugin sucks a ton.
I double, triple and quadruple checked (btw, have lost already 30 hours at least on 1 filed of the search form facepalm) and the stupid findByTags from the documentation still doesn't make any sense to me.
public function findByTags($data = array()) {
$this->Tagged->Behaviors->attach('Containable', array('autoFields' => false));
$this->Tagged->Behaviors->attach('Search.Searchable');
$query = $this->Tagged->getQuery('all', array(
'conditions' => array('Tag.name' => $data['tags']),
'fields' => array('foreign_key'),
'contain' => array('Tag')
));
return $query;
}
As I understand it
$this->Tagged
is supposed to be the name of the model of the HABTM association.
This is quite far from the standards of cakePHP though: http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html#hasandbelongstomany-habtm
The way it is described here, says that you don't need another model but rather you associate Recipe with Ingredient as shown below:
class Recipe extends AppModel {
public $hasAndBelongsToMany = array(
'Ingredient' =>
array(
'className' => 'Ingredient',
'joinTable' => 'ingredients_recipes',
'foreignKey' => 'recipe_id',
'associationForeignKey' => 'ingredient_id',
'unique' => true,
'conditions' => '',
'fields' => '',
'order' => '',
'limit' => '',
'offset' => '',
'finderQuery' => '',
'deleteQuery' => '',
'insertQuery' => ''
)
);
}
meaning that you can access the HABTM assoc table data from Recipe without needing to define model "IngredientRecipe".
And according to cakeDC documentation the model you need is IngredientRecipe and that is not indicated as something obligatory in the cakePHP documentation. Even if this model is created the HABTM assoc doesn't work properly with it - I tried this as well.
And now I need to re-write the search functionality in my way, using only cakePHP even though I spent already 30 hours on it... so unhappy. :(
Every time I come to do this in a project I always spend hours figuring out how to do it using CakeDC search behavior so I wrote this to try and remind myself with simple language what I need to do. I've also noticed that although Using the CakeDC search plugin with associated models this is generally correct there is no explanation which makes it more difficult to modify it to one's own project.
When you have a "has and belongs to many" relationship and you are wanting to search the joining table i.e. the table that has the two fields in it that joins the tables on either side of it together in a many-to-many relationship you want to create a subquery with a list of IDs from one of the tables in the relationship. The IDs from the table on the other side of the relationship are going to be checked to see if they are in that record and if they are then the record in the main table is going to be selected.
In this following example
SELECT Handover.id, Handover.title, Handover.description
FROM handovers AS Handover
WHERE Handover.id in
(SELECT ArosHandover.handover_id
FROM aros_handovers AS ArosHandover
WHERE ArosHandover.aro_id IN (3) AND ArosHandover.deleted != '1')
LIMIT 20
all the records from ArosHandover will be selected if they have an aro_id of 3 then the Handover.id is used to decide which Handover records to select.
On to how to do this with the CakeDC search behaviour.
Firstly, place the field into the search form:
echo $this->Form->create('Handover', array('class' => 'form-horizontal'));?>
echo $this->Form->input('aro_id', array('options' => $roles, 'multiple' => true, 'label' => __('For', true), 'div' => false, true));
etc...
notice that I have not placed the form element in the ArosHandover data space; another way of saying this is that when the form request is sent the field aro_id will be placed under the array called Handover.
In the model under the variable $filterArgs:
'aro_id' => array('name' => 'aro_id', 'type' => 'subquery', 'method' => 'findByAros', 'field' => 'Handover.id')
notice that the type is 'subquery' as I mentioned above you need to create a subquery in order to be able to find the appropriate records and by setting the type to subquery you are telling CakeDC to create a subquery snippet of SQL. The method is the function name that are going to write the code under. The field element is the name of the field which is going to appear in this part of the example query above
WHERE Handover.id in
Then you write the function that will return the subquery:
function findByAros($data = array())
{
$ids = ''; //you need to make a comma separated list of the aro_ids that are going to be checked
foreach($data['aro_id'] as $k => $v)
{
$ids .= $v . ', ';
}
if($ids != '')
{
$ids = rtrim($ids, ', ');
}
//you only need to have these two lines in if you have not already attached the behaviours in the ArosHandover model file
$this->ArosHandover->Behaviors->attach('Containable', array('autoFields' => false));
$this->ArosHandover->Behaviors->attach('Search.Searchable');
$query = $this->ArosHandover->getQuery('all',
array(
'conditions' => array('ArosHandover.aro_id IN (' . $ids . ')'),
'fields' => array('handover_id'), //the other field that you need to check against, it's the other side of the many-to-many relationship
'contain' => false //place this in if you just want to have the ArosHandover table data included
)
);
return $query;
}
In the Handovers controller:
public $components = array('Search.Prg', 'Paginator'); //you can also place this into AppController
public $presetVars = true; //using $filterArgs in the model configuration
public $paginate = array(); //declare this so that you can change it
// this is the snippet of the search form processing
public function admin_find()
{
$this->set('title_for_layout','Find handovers');
$this->Prg->commonProcess();
if(isset($this->passedArgs) && !empty($this->passedArgs))
{//the following line passes the conditions into the Paginator component
$this->Paginator->settings = array('conditions' => $this->Handover->parseCriteria($this->passedArgs));
$handovers = $this->Paginator->paginate(); // this gets the data
$this->set('handovers', $handovers); // this passes it to the template
If you want any further explanation as to why I have done something, ask and if I get an email to tell me that you have asked I will give an answer if I am able to.
This is not an issue of the plugin but how you build the associations. You need to properly join them for a search across these three tables. Check how CakePHP is fetching the data from HABTM assocs by default.
http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html#joining-tables
Suppose a Book hasAndBelongsToMany Tag association. This relation uses
a books_tags table as join table, so you need to join the books table
to the books_tags table, and this with the tags table:
$options['joins'] = array(
array('table' => 'books_tags',
'alias' => 'BooksTag',
'type' => 'inner',
'conditions' => array(
'Books.id = BooksTag.books_id'
)
),
array('table' => 'tags',
'alias' => 'Tag',
'type' => 'inner',
'conditions' => array(
'BooksTag.tag_id = Tag.id'
)
)
);
$options['conditions'] = array(
'Tag.tag' => 'Novel'
);
$books = $Book->find('all', $options); Using joins allows you to have
a maximum flexibility in how CakePHP handles associations and fetch
the data, however in most cases you can use other tools to achieve the
same results such as correctly defining associations, binding models
on the fly and using the Containable behavior. This feature should be
used with care because it could lead, in a few cases, into bad formed
SQL queries if combined with any of the former techniques described
for associating models.
Also your code is wrong somewhere.
Column not found: 1054 Unknown column 'contain' in 'where clause'
This means that $Model->contain() is somehow called. I don't see such a call in your code pasted here so it must be somewhere else. If a model method can not be found this error usually happens with the field name as column.
I want to share with everyone that the solution to working with HABTM searches with the plugin lies here: Using the CakeDC search plugin with associated models
#burzum, the documentation is far from ok man. Do you notice the use of 'type' => 'checkbox' and that it is not mentioned anywhere that it is a type?
Not to mention the total lack of grammar and the lots of typos and missing prepositions. I lost 2 days only to get a grasp of what the author had in mind and bind the words in there. No comment on that.
I am glad that after 5 days on the uphill work I made it. Thanks anyway for being helpful.
I am stuck on pagination in CakePHP 1.3. I am trying to paginate feePayment records based on certain criteria.
feePayments belongs to Students which in turn belongs YearGroups.
I want to paginate 'unpaid' feePayments for each year group. The problem I am having is that the SQL query seems to only take into account the conditions I specified for the FeePayment model and ignores the YearGroup criteria so only overdue unpaid records are returned regardless of the year group specified.
Here is my code:
function unpaidClass($id) {
$this->paginate = array(
'FeePayment' => array ('recursive' => 1, 'conditions' => array('FeePayment.status' => 'Unpaid', 'FeePayment.due_date <= ' => date("Y-m-d"))),
'YearGroup' => array ('recursive' => 1, 'conditions' => array('YearGroup.school_year' => $id))
);
$this->set('feePayments', $this->paginate());
}
Hope this makes sense, appreciate any help.
Thanks,
Sid.
You should consider using the Containable behavior. This behavior allows you to group the necessary data you want without relaying on the "recursiveness" of your query. You can place conditions on your contained data similar to the way you would in your queries and is a more permanent way to structure data across your application instead of specifying conditions over and over again in each query.
Paginate should automatically pick up these associations when you Paginate your main model. Here's an example of what I mean here: http://cakephp.1045679.n5.nabble.com/Paginate-with-Containable-td1300971.html#a1300971
These should make your task easier.
After a lot of searching the net and reading CakePHP's documentation, here is the solution I came up with:
function unpaidClass($id) {
$this->FeePayment->unbindModel(array(
'belongsTo' => array('Student')
), $reset = 0);
$this->FeePayment->bindModel(array(
'belongsTo' => array(
'Student' => array(
'foreignKey' => false,
'conditions' => array('Student.id = FeePayment.student_id')
),
'YearGroup' => array(
'foreignKey' => false,
'conditions' => array('YearGroup.id = Student.year_group_id')
)
)
), $reset = 0);
$this->paginate = array(
'contain' => array('Student','YearGroup'),
'conditions' => array('YearGroup.school_year' => $id,
'FeePayment.status' => 'Unpaid',
'FeePayment.due_date <= ' => date("Y-m-d")));
$this->set('feePayments', $this->paginate());
}