I have this table for insert comments data:(comments)
|id|message|timestamp|approved|parent_id|name|email|
and this table for insert reviews for comments:(reviews)
|id|cid|review_field1|review_field2|review_field3|...
php function :
function _comments_($id,$type){
$DB = mySqli::f("SELECT id,name,email,message,timestamp,review_field_1,review_field_2,review_field_3 FROM " . NEWS_COMMENTS . " LEFT JOIN " . NEWS_REVIEWS . " ON " . NEWS_COMMENTS . ".id = " . NEWS_REVIEWS . ".cid WHERE
pid = ? AND type = ? AND approved = 1 ORDER BY timestamp DESC LIMIT 12", $id, $type);
foreach($DB as $row){
$commentdata[] = $row;
}
return $commentdata;
}
for result:
<?PHP
$comments_list = _comments_('125','news');
foreach($comments_list as $row):
?>
/// HTML tags
<?PHP
$endforeach;
?>
This worked for me and show list of comments and reviews for each comments.
Now i need to show threaded comments(parent) for each comment.
how do can i show threaded comments ?!
NOTE: for parent comment i dont send reviews.
Related
I have two MySQL table for insert comment data and reviews data like this :
comments:
|id|post_id|text|name|timestamp|approved|parent_id|type|ip|
reviews:
|id|postID|comments_id|reviewfield1|reviewfield2|reviewfield3
in action I insert for each comments One reviews. Now, I need to show/print comment list with comment name and text + reviewfield1 reviewfield2 reviewfield3 for each comments where comments is approved like this :
commenter 1
text
reviewfield1
reviewfield2
reviewfield3
TRY:
"SELECT name,text,timestamp FROM " . COMMENTS . " LEFT JOIN " . REVIEWS . " WHERE " . COMMENTS . ".id = " . REVIEWS . ".comments_id AND
post_id = ? AND type = ? AND approved = 1 ", $id, $type"
But this not work for me. how do generate this with PHP JOIN method?
You are making mistake in the query. It must be like this:
"SELECT name,text,timestamp,reviewfield1 FROM " . COMMENTS . " LEFT JOIN " . REVIEWS . " ON " . COMMENTS . ".id = " . REVIEWS . ".comments_id WHERE
post_id = ? AND type = ? AND approved = 1 ", $id, $type"
And you can select rows from the second(joined) table, same as the first one.
I am querying the database in Wordpress to retrieve comment_content in the wp_comments table as well as the meta_value of 2 meta_keys in the wp_commentmeta table. My aim is to take every comment in the database and output it within a list, with each list item displaying the comment, as well as my 2 commentmeta items (name and country).
I am using an alias for each meta_key as so:
$querystr = " SELECT * FROM $wpdb->comments, $wpdb->commentmeta AS commentmeta1, $wpdb->commentmeta AS commentmeta2
WHERE $wpdb->comments.comment_ID = commentmeta1.comment_id
AND $wpdb->comments.comment_ID = commentmeta2.comment_id
AND commentmeta1.meta_key = 'comment_name'
AND commentmeta2.meta_key = 'comment_country' ORDER BY $wpdb->comments.comment_date DESC";
$comment_info = $wpdb->get_results($querystr, OBJECT);
I then run run my loop to display my results:
echo '<ul>';
// display the results
foreach($comment_info as $info) {
echo '<li class="commentBox"><p>' . $info->comment_content . '</p>
<h6>' . $info->meta_value['commentmeta1'] . ', ' . $info->meta_value['commentmeta2'] . '</h6></li>';
}
echo '</ul>';
What I need to do is pass the alias I defined for each meta_key into my loop so I can display it's respective meta_value. I tried using $info->comment_content and $info->meta_value['commentmeta2'] but it doesn't work. Using $info->meta_value only displays commentmeta2. Can anybody help?
Thanks to MatBailie's suggestion, the final working code is as follows:
$querystr = " SELECT comment_content, commentmeta1.meta_value AS comment_name, commentmeta2.meta_value AS comment_country
FROM $wpdb->comments, $wpdb->commentmeta AS commentmeta1, $wpdb->commentmeta AS commentmeta2
WHERE $wpdb->comments.comment_ID = commentmeta1.comment_id
AND $wpdb->comments.comment_ID = commentmeta2.comment_id
AND commentmeta1.meta_key = 'comment_name'
AND commentmeta2.meta_key = 'comment_country' ORDER BY $wpdb->comments.comment_date DESC";
$comment_info = $wpdb->get_results($querystr, OBJECT);
echo '<ul>';
// display the results
foreach($comment_info as $info) {
echo '<li class="commentBox"><p>' . $info->comment_content . '</p>
<h6>' . $info->comment_name . ', ' . $info->comment_country . '</h6></li>';
}
echo '</ul>';
I have latest MySQL version (5.5) and this is the screenshot of groupid field
I didn't touch anything yet, but some cells are not ordered correctly like this
But if I click groupid name in the top, it will ordered correctly like this:
Below PHP code output is like first screenshot above, that are not ordered correctly. Please help how to make the output ordered correctly, like it is displayed in the second screenshot above,
Maybe add code like this : order by id asc, but which is the right place to add it below?
$group_ids = explode(" ", $options['groupchoice_ids']);
$groupsql = "SELECT id, title FROM " . TABLE_PREFIX . "thegroup WHERE";
$first = true;
foreach($group_ids as $value)
{
if (!$first)
{
$groupsql = $groupsql . " OR ";
}
else
{
$first = false;
}
$groupsql = $groupsql . " id = '" . $value . "' ";
}
$kh_optionsgroup = '<select name = "accounttype">';
$checksec = $db->query_read($groupsql);
if ($db->num_rows($checksec))
{
while ($lboard = $db->fetch_array($checksec))
{
$kh_optionsgroup = $kh_optionsgroup . "<option value
='" . $lboard['id'] . "'>" . $lboard['title'] . "</option>";
}
}
$verifystring = '$human_verify';
$kh_optionsgroup = $kh_optionsgroup . "</select>";
At the end of your query, you need to set an order, like so:
$groupsql="SELECT id, title FROM " . TABLE_PREFIX . "thegroup WHERE";
$first=true;
foreach($group_ids as $value){
if(!$first){
$groupsql = $groupsql." OR ";
}else{
$first = false;
}
$groupsql = $groupsql." id = '".$value."' ORDER BY groupid ASC";
}
ORDER BY id ASC
This will make the query return its results in ascending order from the groupid column. Simply change ASC to DESC if you want it to go descendinng (high->low).
I have two tables that I am creating a list that shows all the expenses under each expense type. I have been able to get it to work except when I add the
AND WHERE expenses.pid = " . $pid
it cases a Syntax error and I can't figure out way.
The biggest thing is I need to limet the Expense Type to only show the ones that have some data to go below them
EXPENSETYPE
typeid
pid
exptype
EXPENSES
expid
pid
expdate
checktype
payee
typeid
details
amount
<?php
$pid = 6;
$sql = "SELECT expensetype.typeid, expensetype.exptype
FROM `expensetype` WHERE expensetype.pid = $pid
ORDER BY expensetype.typeid DESC";
$expensetype = $db->query($sql);
foreach($expensetype as $type) {
echo '<li>' . $type['exptype'] . '<ul>';
$sql2 = "SELECT expenses.expid, expenses.expdate, expenses.checktype, expenses.payee, expenses.details, expenses.amount
FROM `expenses` WHERE `expenses`.typeid = " . $type['typeid'] . "AND WHERE expenses.pid = " . $pid ;
$expenses = $db->query($sql2);
foreach($expenses as $exp) {
echo '<li>' . $exp['expdate'] . ' ' . $exp['checktype'] . ' ' . $exp['expdate'] . ' ' . $exp['payee'] . ' ' . $exp['details'] .' ' . $exp['amount'] .'</li>';
}
echo '</ul></li>';
}
?>
Try this SQL statement instead of making two of them :
SELECT `expensetype`.`typeid`, `expensetype.exptype`, `expenses`.`expid`,
`expenses`.`expdate`, `expenses`.`checktype`, `expenses`.`payee`,
`expenses`.`details`, `expenses`.`amount`
FROM `expensetype` INNER JOIN `expenses` ON
`expensetype`.`typeid` = `expense`.`typeid`
WHERE (...)
Also, you cannot use two WHERE in a SQL statement, only use AND.
So I have to add a WHERE query to this plugin I'm using for a reporting feature on a WordPress site. I have no time to do anything but add in another column and filter by the values in that column as there is not that much data to manage each update. The default value for the column I added is zero but I'll add new entries to represent years new people are added. However, when I filter based on the column value the whole query breaks and doesn't show up. I have no idea why. Here is the section involving its set up query displaying results.
<?php
$sql = "SELECT COUNT(*) FROM " . $wpdb->prefix . "presidentsreport_breakdown WHERE list_id = " . $atts['list_id'];
$total_breakdowns = $wpdb->get_var($sql);
$sql = "SELECT p.person_id, p.name, p.notes, p.school_year, b.breakdown_id, b.name as breakdown, b.description as breakdown_description FROM " . $wpdb->prefix . "presidentsreport_person p INNER JOIN " . $wpdb->prefix . "presidentsreport_breakdown b ON b.breakdown_id = p.breakdown_id INNER JOIN " . $wpdb->prefix . "presidentsreport_list l ON l.list_id = b.list_id";
$clean_where = " WHERE l.list_id = " . $atts['list_id'];
$where = "";
if($search != ''){
$where = " AND (p.name LIKE %s)";
$arg = '%' . $search . '%';
$args = array($arg);
}
$where = $wpdb->prepare($where, $args);
$order = " ORDER BY b.sort_order, b.breakdown_id, p.sort_name, p.name, p.person_id";
$results = $wpdb->get_results($sql . $clean_where . $where . $order);
?>
If I add anything in the variable $where it breaks the whole query. So if I add
<?php
$where = " WHERE p.school_year <= 2011";
?>
or
<?php
$where = " WHERE p.school_year = 0";
?>
Nothing will show up, For the last example if the default value is 0 everything should show up regardless. Thanks in advance for reading through!
Don't add WHERE to your variable. It is already assigned in $clean_where
$clean_where = " WHERE l.list_id = " . $atts['list_id'];
Here ------------^
You need to concatenate your addition parameters to the $where variable:
$where .= " AND p.school_year <= 2011";
There's no need of WHERE in where!