Hello I am using the following SELECT
"SELECT
P.id
,P.price
,P.contract
,P.property_type
,CT.id
,CT.english_text
,PT.id
,PT.english
,C.cityname
,S.sectorname
,S.id
FROM properties P
JOIN contract CT
ON CT.id = P.contract
JOIN property_type PT
ON PT.id = P.property_type
JOIN city C
ON C.id = P.city
JOIN sector S
ON S.id = P.sector WHERE 1"
It occur that in the final result I always have id=2, which I think is the id from S.id since it is the last one.
How I can get in foreach loop of this query to display P.id inside $row['id'] ?
Right now is always $row['2'] on each result.
You have multiple columns with the same name, which confuses php. Use aliases to give them different names:
SELECT P.id as p_id, P.price, P.contract, P.property_type,
CT.id as c_id, CT.english_text,
PT.id as pt_id, PT.english
C.cityname,
S.sectorname, S.id as s_id
. . .
This removes all ids from the result set. What you want is called s_id.
Related
I have two sql queries that I need to combine into one query for better efficiency, just not sure how to do it. Basically I need to query my Supplier, then for each supplier check to see if the Listing table has more than one record that matches based upon "supplier id", if it does then I need to return the supplier name and id. Here are my two queries:
Query 1:
SELECT s.name, s.id
FROM Supplier s
Query 2:
SELECT l.asin,
l.id,
COUNT(*) c
FROM Listing l
LEFT JOIN Product p
ON p.id = l.product_id
LEFT JOIN Supplier s
ON p.supplier_id = s.id
WHERE (l.matchValidated IS NULL OR l.matchValidated = 0)
AND s.id = SUPPLIER_ID_GOES_HERE
GROUP BY l.asin HAVING c > 1);
You already have supplier joined in the second query so you just need to add the supplier name and id to your SELECT and GROUP BY.
SELECT l.asin,
l.id,
s.name AS supplier_name,
s.id AS supplier_id,
COUNT(*) c
FROM Listing l
LEFT JOIN Product p
ON p.id = l.product_id
LEFT JOIN Supplier s
ON p.supplier_id = s.id
WHERE (l.matchValidated IS NULL OR l.matchValidated = 0)
GROUP BY l.asin, l.id, s.name, s.id
HAVING c > 1;
I am using php and I have to get the data from multiple tables with common id, but the problem is that in few tables that common id contains multiple records,using inner join gives me separate rows of data e.g.
{"dish_id":"52","quantity":"1","STATUS":"pending","franchise_id":"5","order_type":"PickUp","extraId":"2"}
{"dish_id":"52","quantity":"1","STATUS":"pending","franchise_id":"5","order_type":"PickUp","extraId":"3"}
extraId is the multiple record for the dish_id:52.
I need result like this.
{"dish_id":"52","quantity":"1","STATUS":"pending","franchise_id":"5","order_type":"PickUp","extraId"[{"id":"2"},{"id":"3"]}}
My query is:
$orders = "Select DISTINCT order_detail.dish_id,order_detail.quantity,order_detail.STATUS,
order_main.franchise_id,order_main.order_type,
order_extras.extra_id,order_extras.extra_title,
order_addons.addon_id,order_addons.addon_size
from order_main
INNER JOIN order_detail ON order_main.id=order_detail.order_id
INNER JOIN order_extras ON order_main.id=order_extras.order_id
INNER JOIN order_addons ON order_main.id=order_addons.order_id
WHERE order_main.franchise_id='$storeId'
and
order_detail.STATUS!='$order_status'";
please help.
Use group by and group_concat. Something like this:
Select d.dish_id, d.quantity, d.STATUS, m.franchise_id, m.order_type,
group_concat(e.extra_id) as extraids
from order_main m INNER JOIN
order_detail d
ON m.id = d.order_id INNER JOIN
order_extras e
ON m.id = e.order_id INNER JOIN
order_addons a
ON m.id = a.order_id
where m.franchise_id = '$storeId' and d.STATUS <> '$order_status'
group by d.dish_id, d.quantity, d.STATUS, m.franchise_id, m.order_type;
Your desired results do not include these columns:
e.extra_title
a.addon_id
a.addon_size
I would also suggest that you remove the join to order_addons.
Notice that table aliases make the query easier to write and to read.
You can use group bywith dish_id
$orders = "Select DISTINCT order_detail.dish_id,order_detail.quantity,order_detail.STATUS,
order_main.franchise_id,order_main.order_type,
order_extras.extra_id,order_extras.extra_title,
order_addons.addon_id,order_addons.addon_size
from order_main
INNER JOIN order_detail ON order_main.id=order_detail.order_id
INNER JOIN order_extras ON order_main.id=order_extras.order_id
INNER JOIN order_addons ON order_main.id=order_addons.order_id
WHERE order_main.franchise_id='$storeId'
and
order_detail.STATUS!='$order_status' group by order_detail.dish_id";
I wish to join multiple tables like- Categories, menus, restaurants, reviews, etc.
to return the restaurants that provide the inserted food with their prices.
Everything works except numberOfReviews in reviews table.
If a restaurant has no reviews then output should be 0 for numOfReviews column but other column values should be retrieved i.e. price, name, etc.
With following query I get all fields as null and count(numReviews) as 0:
select r.id
,r.`Name`
,r.`Address`
,r.city
,r.`Rating`
,r.`Latitude`
,a.`AreaName`
,m.`Price`
,count(rv.id)
from `categories` c, `menus` m, `restaurants` r, areas a, reviews rv
where m.`ItemName`="tiramisu"
and c.`restaurant_id`=r.`id`
and m.`category_id`=c.id
and r.`AreaId`=a.`AreaId`
and if I can't match rv.restaurant_id=r.id in where clause(obviously).
Where am I getting wrong? How do I solve this?
edited
select r.id,
r.`Name`,
r.`Address`,
r.city,
r.`Rating`,
r.`Latitude`,
a.`AreaName`,
m.`Price`,
r.`Longitude`,
r.Veg_NonVeg,
count(rv.id)
from restaurants r LEFT JOIN `reviews` rv on rv.`restaurant_id`=r.`id`
inner join `categories` c on c.`restaurant_id` = r.id
inner join `menus` m on m.`category_id` = c.id
inner join `areas` a on a.`AreaId` = r.`AreaId`
where m.`ItemName`="tiramisu"
First of all, don't use this old school syntax for the jointures.
Here is a query that may solve your problem:
SELECT R.id
,R.Name
,R.Address
,R.city
,R.Rating
,R.Latitude
,R.Longitude
,A.AreaName
,M.Price
,R.Veg_NonVeg
,COUNT(RV.id) AS numOfReviews
FROM restaurants R
INNER JOIN categories C ON C.restaurant_id = R.id
INNER JOIN menus M ON M.category_id = C.id
INNER JOIN areas A ON A.AreaId = R.AreaId
LEFT JOIN reviews RV ON RV.restaurant_id = R.id
WHERE M.ItemName = 'tiramisu'
GROUP BY R.id, R.Name, R.Address, R.city, R.Rating, R.Latitude, R.Longitude, A.AreaName, M.Price, R.Veg_NonVeg
I used explicit INNER JOIN syntax instead of your old school syntax and I modified the jointure with table reviews in order to get the expected result. The GROUP BY clause is required to use the aggregate function COUNT, every rows will be grouped by the enumerated columns (every column except the one used by the function).
Here is another solution that simplify the GROUP BY clause and allow the modification of SELECT statement without having to worry about the fact that every columns need to be part of the GROUP BY clause:
SELECT R.id
,R.Name
,R.Address
,R.city
,R.Rating
,R.Latitude
,R.Longitude
,A.AreaName
,M.Price
,R.Veg_NonVeg
,NR.numOfReviews
FROM restaurants R
INNER JOIN (SELECT R2.id
,COUNT(RV.id) AS numOfReviews
FROM restaurants R2
LEFT OUTER JOIN reviews RV ON RV.restaurant_id = R2.id
GROUP BY R2.id) NR ON NR.id = R.id
INNER JOIN categories C ON C.restaurant_id = R.id
INNER JOIN menus M ON M.category_id = C.id
INNER JOIN areas A ON A.AreaId = R.AreaId
WHERE M.ItemName = 'tiramisu'
As you can see here I added a new jointure on a simple subquery that does the aggregation job in order to provide me the expected number of reviews for each restaurant.
Hope this will help you.
I have table name students having fields student_id, house_id etc..
and subjects, houses, students_subjects
I am using this query
SELECT students_subjects.student_id,students.house_id,students_subjects.subject_id,subjects.subject_name,students.rollno,students.first_name, students.last_name FROM
students_subjects LEFT JOIN students on students_subjects.student_id=students.id
LEFT JOIN subjects on students_subjects.subject_id=subjects.id WHERE students_subjects.class_years_section_id=1
This is working fine for me ..
Now i want to get house name too from houses table
I tried this query
SELECT students_subjects.student_id,students.house_id,houses.house_name, students_subjects.subject_id,subjects.subject_name,students.rollno,students.first_name, students.last_name FROM
students_subjects LEFT JOIN students on students_subjects.student_id=students.id
LEFT JOIN subjects on students_subjects.subject_id=subjects.id
LEFT JOIN houses on students.house_id=houses.id
WHERE students_subjects.class_years_section_id=1
AND students_subjects.school_session_id=1 AND students.is_active=1
and it gives me house_name = NULL
Can anybody tell me how to get house name too . using join query
Thanks
The error in your query is caused by the LEFT JOIN keyword that is after WHERE clause,
SELECT students_subjects.student_id,
students.house_id,
students_subjects.subject_id,
subjects.subject_name,
students.rollno,
students.first_name,
students.last_name
FROM students_subjects
LEFT JOIN students
on students_subjects.student_id=students.id
LEFT JOIN subjects
on students_subjects.subject_id=subjects.id
LEFT JOIN houses
on students.house_id=houses.id
WHERE students_subjects.class_years_section_id = 1 AND
students_subjects.school_session_id = 1 AND
students.is_active = 1
Remember that JOINs are part of the FROM Clause.
UPDATE 1
SELECT b.student_id,
a.house_id,
b.subject_id,
c.subject_name,
a.rollno,
a.first_name,
a.last_name,
d.house_name
FROM students a
INNER JOIN students_subjects b
ON b.student_id = a.id
INNER JOIN subjects c
ON b.subject_id = c.id
INNER JOIN houses d
ON a.house_id = d.id
WHERE b.class_years_section_id = 1 AND
b.school_session_id = 1 AND
a.is_active = 1
You've miss placed the WHERE clause, try this:
SELECT students_subjects.student_id,students.house_id,students_subjects.subject_id,subjects.subject_name,students.rollno,students.first_name, students.last_name
FROM students_subjects
LEFT JOIN students ON students_subjects.student_id=students.id
LEFT JOIN subjects ON students_subjects.subject_id=subjects.id
LEFT JOIN houses ON students.house_id=houses.id
WHERE students_subjects.class_years_section_id=1
AND students_subjects.school_session_id=1 AND students.is_active=1
I'm a little confused in here and need some help...
the situation is I've made three tables(fr_Leagues, fr_nations and fr_confeds), all i want to do is add a league which shows the name of the categories not the i.d with pagination. Here is the code:
NOW FIXED!
"SELECT
a.id as confed_id,
a.fr_short_name as confed_name,
b.id as nation_id,
b.fr_name as nation_name,
c.id as league_id,
c.fr_name as league_name"
." FROM fr_confeds as a
INNER JOIN fr_nations as b ON a.id = b.confed_id
INNER JOIN fr_leagues as c ON b.id = c.nation_id"
." LIMIT $paginate->start, $paginate->limit"
You are missing on how to link the different tables together. On each INNER JOIN, you need to have it:
INNER JOIN fr_nations ON a.<someColumn> = b.<anotherColumn> INNER JOIN fr_leagues ON a.<someColumn> = b.<anotherColumn>
USE THIS QUERY
SELECT * FROM fr_confeds as A
INNER JOIN fr_nations as B ON A.id = B.confed_id
INNER JOIN fr_leagues as C ON B.confed_id = C.league_id
LIMIT $paginate->start, $paginate->limit