Order Multiple Arrays (Including Each Other) - php

Question

Let's say we have arrays like below.
$arr00 = [0,1,2,...,9]; // It includes 9 arrays. So the score should be 9.
$arr01 = [0,1,...,8]; // score = 8
...
$arr09 = [0]; // score = 0
ArrScore (definition): If an array include an array with all elements it
gets one point. So in this case $arr00's total score is 9. Because it
includes all other 9 arrays. And $arr09's score will be 0.
Actual Conditions
Our array elements could be random numbers. (not sequent orders ascending +1)
There could be thousands of arrays.
Our arrays are always flat. (no duplicated element in an array)
We are using php (any theoretical approach is also ok)
Think that you have a standard PC and you will order these arrays everyday once. (No need for the result of "which arr eats which ones". Just ArrScores.)
Goal is to order arrays by ArrScore. And we need ArrScores. What should be the approach? (Theoretical or practical)

Answer 1

If I understood right, this might help:
function compare($a,$b) {
if(count(array_intersect($a, $b)) == count($a)) return -1;
else return 1;
}
$arr0 = [0,2,4,7];
$arr1 = [7,0,2,9,4];
$arr2 = [4,2];
$arr = [$arr0,$arr1,$arr2];
usort($arr,"compare");
foreach($arr as $a) {
print_r($a);
}
prints:
Array ( [0] => 4 [1] => 2 ) Array ( [0] => 0 [1] => 2 [2] => 4 [3] => 7 ) Array ( [0] => 7 [1] => 0 [2] => 2 [3] => 9 [4] => 4 )
EDIT:
Compute the ArrayScore for each array:
$arr0 = [0,2,4,7];
$arr1 = [7,0,2,9,4];
$arr2 = [4,2];
$arr = [$arr0,$arr1,$arr2];
$arrayScores = [];
//initialize the Scores with 0
foreach($arr as $a){
$arrayScores[] = 0;
}
//run through all arrays
for($i=0;$i<count($arr);$i++){
//with $j=$i+1, every combination is only checked once
for($j=$i+1; $j<count($arr);$j++){
if(count(array_intersect($arr[$j], $arr[$i])) == count($arr[$j])) {
$arrayScores[$i]++;
}
if(count(array_intersect($arr[$i], $arr[$j])) == count($arr[$i])){
$arrayScores[$j]++;
}
}
}