Filling an array with missing values afterwards - php

Question

I'm getting values for my flot chart via ajax.
At the backend script my test array looks like this:
Array
(
[0] => Array
(
[0] => 6
[1] => 1
)
[1] => Array
(
[0] => 7
[1] => 7
)
[2] => Array
(
[0] => 8
[1] => 37
)
[3] => Array
(
[0] => 9
[1] => 44
)
)
The value with the offset [0] represents the hour.
Now I need 24 array objects for every hour. How to maintain this without touching the given elements?
e.g.
Array
(
[0] => Array
(
[0] => 0
[1] => 0
)
[6] => Array
(
[0] => 6
[1] => 1
)
[...]
[7] => Array
(
[0] => 7
[1] => 7
)
[8] => Array
(
[0] => 8
[1] => 37
)
[9] => Array
(
[0] => 9
[1] => 44
)
Thanks in advance.

Answer 1

You want to "re-key" this result set according to the first subarray value, and then merge it into an array of 24 hour elements.
Try this:
$data = [
[6, 1],
[7, 7],
[8, 37],
[9, 44]
];
$hours = array_fill(0, 25, [0, 0]);
$data = array_combine(array_column($data, 0), $data);
$hours = array_replace($hours, $data);
print_r($hours);
This:
Creates a 24 element array $hours containing sub-arrays containing default values [0, 0]
Re-keys your $data, pulling out and using the first value of each sub-array to do so. This assumes you are using PHP 5.5.
Finally, replace the modified $data into $hours
This yields:
Array
(
[0] => Array
(
[0] => 0
[1] => 0
)
[1] => Array
(
[0] => 0
[1] => 0
)
[2] => Array
(
[0] => 0
[1] => 0
)
[3] => Array
(
[0] => 0
[1] => 0
)
[4] => Array
(
[0] => 0
[1] => 0
)
[5] => Array
(
[0] => 0
[1] => 0
)
[6] => Array
(
[0] => 6
[1] => 1
)
[7] => Array
(
[0] => 7
[1] => 7
)
[8] => Array
(
[0] => 8
[1] => 37
)
[9] => Array
(
[0] => 9
[1] => 44
)
[10] => Array
(
[0] => 0
[1] => 0
)
[11] => Array
(
[0] => 0
[1] => 0
)
[12] => Array
(
[0] => 0
[1] => 0
)
[13] => Array
(
[0] => 0
[1] => 0
)
[14] => Array
(
[0] => 0
[1] => 0
)
[15] => Array
(
[0] => 0
[1] => 0
)
[16] => Array
(
[0] => 0
[1] => 0
)
[17] => Array
(
[0] => 0
[1] => 0
)
[18] => Array
(
[0] => 0
[1] => 0
)
[19] => Array
(
[0] => 0
[1] => 0
)
[20] => Array
(
[0] => 0
[1] => 0
)
[21] => Array
(
[0] => 0
[1] => 0
)
[22] => Array
(
[0] => 0
[1] => 0
)
[23] => Array
(
[0] => 0
[1] => 0
)
)
Hope this helps :)

Answer 2

You can try also this:
// yours test array
$times = array(
array(6,1),
array(7,7),
array(8,37),
array(9,44)
);
// array with all hours
$fullTimes = array_fill(0, 24, array(0,0));
foreach ($times as $time) {
$fullTimes[$time[0]] = $time;
}

Answer 3

Solution for me:
while ($stmt->fetch()) {
$x = $hour;
$y = $zugriffe;
$data1[$x] = array ($x, $y);
}
for ($i=0;$i<=24;$i++){
if (!isset($data1[$i])){
$data1[$i] = array ($i,0);
}
}
sort($data1);

Answer 4

Assume the array's name is $a, you can do like this:
for($i = 0; $i < 24; $i++) {
if(isset($a[$i])) continue;
else {
$a[$i] = array($i,"something you like here");
}
}