I am trying to link through to the single row record information in my mysql database from my search using php/ajax_pagination and the code that I am trying to get to work is:
<div id="posts_content">
<?php
//Include pagination class file
include('Pagination.php');
//Include database configuration file
include('dbConfig.php');
$limit = 3;
//get number of rows
$queryNum = $db->query("SELECT COUNT(*) as postNum FROM posts");
$resultNum = $queryNum->fetch_assoc();
$rowCount = $resultNum['postNum'];
//initialize pagination class
$pagConfig = array(
'totalRows' => $rowCount,
'perPage' => $limit,
'link_func' => 'searchFilter'
);
$pagination = new Pagination($pagConfig);
//get rows
$query = $db->query("SELECT * FROM posts ORDER BY id DESC LIMIT $limit");
if($query->num_rows > 0){ ?>
<div class="posts_list">
<?php
while($row = $query->fetch_assoc()){
$postID = $row['id'];
?>
<div class="list_item"><h2><?php echo $row["title"]; ?></h2></div>
<?php } ?>
</div>
<?php echo $pagination->createLinks(); ?>
<?php } ?>
</div>
There is obviously something wrong with my href link:
<h2><?php echo $row["title"]; ?></h2>
OR my file.php page:
<?php
// GET ID FROM THE URL
$id = $_GET['id'];
?>
<!DOCTYPE HTML>
<html lang="en">
<head>
<title>Ajax Pagination with Search and Filter in PHP</title>
<link href='style.css' rel='stylesheet' type='text/css'>
<script src="jquery.min.js"></script>
<script type="text/javascript"></script>
</head>
<body>
<?php
$sql =mysql_query("select * from posts where id='".$id."'");
while($row = mysql_fetch_array($sql)){
?>
<tr>
<th>title:</th>
<th>created:</th>
<th>modified:</th>
<th>statusr:</th>
</tr>
<tr>
<td><?=$row['title']?></td>
<td><?=$row['created']?></td>
<td><?=$row['modified']?></td>
<td><?=$row['status']?></td>
</tr>
<?php
}
?>
But I cannot understand why as everything else seems to be working fine, maybe I have been looking at this to long and missed something blatently obvious... but any help would be greatly appreciated.
Use Below Code:
<div class="list_item"><h2><?php echo $row["title"]; ?></h2></div>
The following query returns all rows from the campaign table that have the user_id of 1:
SELECT * FROM campaign WHERE user_id=1
In the case of testing this is two results. How would I be able to echo a set column from each of the rows. For example, I want to echo the campaign_name from each of the results. I have tried various methods however, I have had no success.
My end goal would be something like this:
<?php foreach($queryRow as $row) { ?>
<li>
<a>
<div>
<p><?php echo($row['campaign_name']); ?></p>
<p>
Description Text
</p>
</div>
</a>
</li>
<?php } ?>
I'm quite at lost with this so I apologise if my intended result is completely off...
Try this:
$qry = "SELECT * FROM campaign WHERE user_id=1";
$res = mysqli_query($conn, $qry);
if(mysqli_num_rows($res) > 0) // checking if there is any row in the resultset
{
while($row = mysqli_fetch_assoc($res)) // Iterate for each rows
{
?>
<li>
<a>
<div>
<p><?php echo($row['campaign_name']); ?></p>
<p>
Description Text
</p>
</div>
</a>
</li>
<?php
}
}
It will iterate for each row in the resultset.
I looked into the documentation as Oldskool kindly suggested and realised I was using the wrong method to create an array. I instead use the fetch_all feature of the mysqli_results class to create a multidimensional array with my results. Then I was able to use the following code to echo out the results:
<!DOCTYPE html>
<html>
<body>
<?php
include('inc/database_initiation.php');
//print_r($userCampaigns);
foreach ($userCampaigns as $row) {
//echo $row[2];
//echo $row[4];
echo $row['campaign_name'];
echo '<br>';
echo $row['promotion_coins'];
echo '<br>';
}
?>
</body>
</html>
The include 'inc/database_initiation is as follows'
<?php
session_start();
include_once 'userManagement/dbconnect.php';
if(!isset($_SESSION['userSession']))
{
header("Location: login.php");
}
$query = $MySQLi_CON->query("SELECT * FROM users WHERE user_id=".$_SESSION['userSession']);
$userRow=$query->fetch_array();
$campaignQuery = $MySQLi_CON->query("SELECT * FROM campaign WHERE user_id=1");
$userCampaigns = $campaignQuery->fetch_all(MYSQLI_ASSOC);
//$MySQLi_CON->close();
?>
I am working on a search page where I am getting the input from the user and then using PHP, I am connecting to a database, executing a query and trying to display the results on the page. I need to display the result in a div tag where I need various search results to be displayed.
<?php
ob_start();
$host="localhost"; // Host name
$username="root"; // Mysql username
$password=""; // Mysql password
$db_name="test1"; // Database name
$tbl_name="postjob"; // Table name
// Create connection
$conn = new mysqli($host, $username, $password);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
$dbconn = mysqli_select_db($conn, $db_name) or die(mysql_error());
echo $dbconn;
echo "Connected to Database<br />";
$output = '';
$keywords=$_POST['keywords'];
$location=$_POST['location'];
$keywords = mysqli_real_escape_string($conn, $keywords);
$location = mysqli_real_escape_string($conn, $location);
$sql="SELECT * FROM $tbl_name WHERE job_title LIKE '%$keywords%' OR job_type
LIKE '%$keywords%' OR job_category LIKE '%$keywords%' OR job_tags LIKE
'%$keywords%' OR description LIKE '%$keywords%' OR company_name LIKE
'%$keywords%' OR location LIKE'%$location%'";
$result=mysqli_query($conn, $sql);
$count=mysqli_num_rows($result);
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Sign Up</title>
</head>
<body>
<section class="content_area">
<div class="banner">
<div class ="result">
<table>
<tr>
<?php
while($jobsearch=mysqli_fetch_assoc($result)) {
echo "<tr>";
echo "<td>"."<h3>".$jobsearch['job_title']."</h3>"."
<br>".$jobsearch['company_name']."<br>".$jobsearch['description']."</td>";
echo "</tr>";
}
?>
</tr>
</table>
</div>
</div>
</section>
</body>
</html>
I am calling the above PHP file using post action from HTML form page which has Keywords and location textbox. I am fetching job_title, company_name and description from Database and displaying it. Here I am using a table to display. But I wanted use a div where I need to do some styling. I tried to use below code replacing table with div, but it is not displaying any result.
<?php
while($jobsearch=mysqli_fetch_assoc($result)) {
echo "<div>"."<h3>".$jobsearch['job_title']."</h3>"."
<br>".$jobsearch['company_name']."<br>".$jobsearch['description'].
</div>";
}
?>
I am expecting result like below inside a div
job_title
company_name
description
<button>Apply</button>
I tried the below code, but it is not displaying any result.
<?php
while($jobsearch=mysqli_fetch_assoc($result)) {
echo "<div><h3>".$jobsearch['job_title']."</h3></div>
<div>".$jobsearch['company_name']."</div>
<div>".$jobsearch['description']. "</div>";
}
?>
I need to customize this div to do some styling. Could someone help me how to achieve this?
Hope it will work.
<ul>
<?php
while($jobsearch=mysqli_fetch_assoc($result)) {
echo "<li>"."<h3>".$jobsearch['job_title']."</h3>"."</li>"
echo "<li>"."<h3>".$jobsearch['company_name']."</h3>"."</li>"
echo "<li>"."<h3>".$jobsearch['description']."</h3>"."</li>"
echo "<button>Apply</button>";
}
?>
</ul>
your code should throw an error as " is missing in your echo statement
try this
echo "<div><h3>".$jobsearch['job_title']."</h3></div>
<div>".$jobsearch['company_name']."</div>
<div>".$jobsearch['description']. "</div>";
attached is the output, this output is by replacing your variables with some defined values
Try this.
<div class ="result">
<table>
<?php
while($jobsearch=mysqli_fetch_assoc($result)) {
echo "<tr>";
echo "<td>"."<h3>".$jobsearch['job_title']."</h3></td>";
echo "</tr>";
echo "<tr>";
echo "<td>"."<h3>".$jobsearch['company_name']."</h3></td>";
echo "</tr>";
echo "<tr>";
echo "<td>"."<h3>".$jobsearch['description']."</h3></td>";
echo "</tr>";
echo "<br />";
}
?>
</table>
</div>
I have a site that will have pages for various countries and regions. On a main page I'm looking to populate an HTML table that is 4 columns by 12 rows (48 results) from an array. I current have a loop working that is placing each country into it's own paragraph but I'm lost on how to place them into the table and have them setup in the 4x12 way I described above.
Here is the query:
$country_sql = "SELECT * FROM country";
$country_query = mysql_query($country_sql) or die(mysql_error());
$rsCountry = mysql_fetch_assoc($country_query);
Then within the page I have this working right now that inserts each country into a new paragraph:
<?php do {?>
<p><?php echo $rsCountry['countryname'];?></p>
<?php } while ($rsCountry = mysql_fetch_assoc($country_query)) ?>
First I need to have this place data into seperate td's instead of new paragraphs. Once I have this data in a table I then need the country names link to each countries respective page which is setup as mydomain.com/country/countryabbreviation (countryabbreviation is within the same table as countryname). Any help on this would be greatly appreciated as I'm very new to php. Thanks!
----Full Code---
<?php
///CONNECTION INFORMATION REMOVED FOR PRIVACY//////////
$country_sql = "SELECT * FROM country";
$country_query = mysql_query($country_sql) or die(mysql_error());
$rsCountry = mysql_fetch_assoc($country_query);
?>
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8" content="text/html">
<title>TEST PAGE </title>
</head>
<body>
<h1>List of Countries</h1>
<?php do {?>
<p><?php echo $rsCountry['countryname'];?></a></p>
<?php } while ($rsCountry = mysql_fetch_assoc($country_query)) ?>
</body>
</html>
Outputs this:
http://postimg.org/image/f2muo627d/
This should do the trick:
<?php
// Rewrote the query to only get 48 items.
$country_sql = "SELECT * FROM country LIMIT 48";
$country_query = mysql_query($country_sql) or die(mysql_error());
// Initialize an empty array.
$rsCountry = array();
// Put all our countries in there.
while ($row = mysql_fetch_assoc($country_query)) {
$item = array();
$item['href'] = '/country/' . $row['countryabbreviation'];
$item['title'] = $row['countryname'];
$rsCountry[] = $item;
}
// Chop up our massive array in rows of 4, should give us 12 rows.
$rsCountry = array_chunk($rsCountry, 4);
?>
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8" content="text/html">
<title>TEST PAGE</title>
</head>
<body>
<table>
<thead>
<tr>
<td colspan="4">
<h1>List of Countries</h1>
</td>
</tr>
</thead>
<tbody><?php
foreach ($rsCountry as $row => $countries): ?>
<tr><?php
foreach ($countries as $country): ?>
<td><?= echo $country['title'] ?></td><?php
endforeach; ?>
</tr><?php
endforeach; ?>
</tbody>
</table>
</body>
</html>
is this what you want? I didn't test if it compiles
$country_sql = "SELECT * FROM country";
$country_query = mysql_query($country_sql) or die(mysql_error());
$rsCountry = mysql_fetch_array($country_query)
echo "<table><th>";
$firstrow ="";
foreach( $rsCountry as $name => $cell ){
echo "<td>$name</td>";
$firstrow = $firstrow + "<td>$cell</td>";
}
echo "</th>";
echo "<tr>$firsrow</tr>";
while( $rsCountry = mysql_fetch_array($country_query) ){
echo "<tr>";
foreach( $rsCountry as $cell ){
echo "<td>$cell</td>";
}
echo "</tr>";
}
echo "</table>";
I wish to set the title of my webpage to Ultan.me - Whatever the post title. I want it to display the post title. The posts are submitted to a MySQL database and the title row is called "title". Any help is appreciated with this small question.
Update:
Here is the page itself now but it doesn't display the title. Should I open the php document and connect to my database somewhere different to it's current locations?
The Code (The only necessary piece is the beginning):
<html>
<head>
<meta name="keywords" content="Mac user Ultan Casey TheCompuGeeks UltanKC">
<title>Ultan.me - <?echo $title;?></title>
<link rel="stylesheet" href="css/styles.css" type="text/css" />
<script type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js"></script>
<script type="text/javascript"
src="js/jquery.labelify.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$(":text").labelify();
});
</script>
<style>
a {text-decoration:none}
</style>
</head>
<body>
<div id="main">
<!-- Menu Start -->
<div id="menu">
<ul>
<li>home</li>
<li>about me</li>
<li>archives</li>
<li>contact</li>
<li>gallery</li>
</ul>
</div>
<!-- Menu End -->
<img src="images/banner.png" />
<div id="content">
<div id="posts">
<?php
mysql_connect ('localhost', 'root', 'root') ;
mysql_select_db ('ultankc');
if (!isset($_GET['id']) || !is_numeric($_GET['id'])) {
die("Invalid ID specified.");
}
$id = (int)$_GET['id'];
$sql = "SELECT * FROM php_blog WHERE id='$id' LIMIT 1";
$result = mysql_query($sql) or print ("Can't select entry from table php_blog.<br />" . $sql . "<br />" . mysql_error());
while($row = mysql_fetch_array($result)) {
$date = date("l F d Y", $row['timestamp']);
$title = stripslashes($row['title']);
$entry = stripslashes($row['entry']);
$get_categories = mysql_query("SELECT * FROM php_blog_categories WHERE `category_id` = $row[category]");
$category = mysql_fetch_array($get_categories);
?>
<p><?php echo "<p id='post-title'><strong>" . $title . "</strong></p>"; ?><br /><br />
<div id="entry"><?php echo $entry; ?>
</div><br /><br />
<p id="date">Posted in <?php echo $category['category_name']; ?> on <?php echo $date; ?></p>
</p>
<h2 id="share-title">Share This Post</h2>
<div id="social-share">
<li id="link-right"><a href="http://twitter.com/home?status=
I just read <?php echo $title; ?> at http://ultan.me/post.php?id=<?php echo $id; ?>"><center>Twitter</center></a></li>
<li id="link-left"><center>Digg</center></li>
<br>
<li id="link-right"><center>Facebook</center></li>
<li id="link-left"><a href="http://www.google.com/buzz/post?url=http://ultan.me/post.php?id=<?php echo $id; ?>
"><center>Google Buzz</center></a></li>
<div class="clr"></div>
</div>
<h2 id="comments-title">Comments</h2>
<div id="comment-list">
<?php
}
$commenttimestamp = strtotime("now");
$sql = "SELECT * FROM php_blog_comments WHERE entry='$id' ORDER BY timestamp";
$result = mysql_query ($sql) or print ("Can't select comments from table php_blog_comments.<br />" . $sql . "<br />" . mysql_error());
while($row = mysql_fetch_array($result)) {
$timestamp = date("l F d Y", $row['timestamp']);
printf("<div class='comment-ind'><p id='comments'><a id='username' href=\"%s\">%s</a> %s</p>", stripslashes($row['url']), stripslashes($row['name']), $timestamp);
print("<p class='comments'>" . stripslashes($row['comment']) . "</p><div class='clr'><br></div></div>");
}
?>
<div class="clr"></div>
<form id="commentform" method="post" action="process.php">
<p><input type="hidden" name="entry" id="entry" value="<?php echo $id; ?>" />
<input type="hidden" name="timestamp" id="timestamp" value="<?php echo $commenttimestamp; ?>">
<input type="text" name="name" id="name" title="Name (required)" /><br />
<input type="text" name="email" id="email" title="Mail (will not be published) (required)" /><br />
<input type="text" name="url" id="url" title="Website" value="http://" /><br />
<br />
<textarea title="Your Comment Goes Here" name="comment" id="comment"></textarea></p>
<p><input type="submit" name="submit_comment" id="submit_comment" value="Add Comment" /></p>
</form>
</div>
<div id="pages">
<?php
$total_results = mysql_fetch_array(mysql_query("SELECT COUNT(*) AS num FROM php_blog"));
$total_pages = ceil($total_results['num'] / $blog_postnumber);
if ($page > 1) {
$prev = ($page - 1);
echo "<< Newer ";
}
for($i = 1; $i <= $total_pages; $i++) {
if ($page == $i) {
echo "$i ";
}
else {
echo "$i ";
}
}
if ($page < $total_pages) {
$next = ($page + 1);
echo "Older >>";
}
?>
</div>
</div>
</div>
<!-- Sidebar Start -->
<div class="sidebar">
<!-- Item 1 -->
<div id="side-item">
<h2>
<a href="http://www.dailybooth.com/UltanCasey">
<img src="images/db-icon.jpg">Dailybooth
</a></h2>
<div id="side-item-content">
<center>
<img src="http://dailybooth.com/UltanCasey/latest/medium.jpg" />
</center>
</div>
</div>
<!-- Item 2 -->
<div id="side-item">
<h2><img src="images/connect.jpg" />Connect</h2>
</div>
<div id="side-item-content">
<div class="tweet-title"><p>Latest Tweet:</p></div>
<div id="tweet">
<?php
function getTwitterStatus($userid){
$url = "http://twitter.com/statuses/user_timeline/$userid.xml?count=1";
function auto_link_twitter ($text)
{
// properly formatted URLs
$urls = "/(((http[s]?:\/\/)|(www\.))?(([a-z][-a-z0-9]+\.)?[a-z][-a-z0-9]+\.[a-z]+(\.[a-z]{2,2})?)\/?[a-z0-9._\/~#&=;%+?-]+[a-z0-9\/#=?]{1,1})/is";
$text = preg_replace($urls, " <a href='$1'>$1</a>", $text);
// URLs without protocols
$text = preg_replace("/href=\"www/", "href=\"http://www", $text);
// Twitter usernames
$twitter = "/#([A-Za-z0-9_]+)/is";
$text = preg_replace ($twitter, " <a href='http://twitter.com/$1'>#$1</a>", $text);
// Twitter hashtags
$hashtag = "/#([A-Aa-z0-9_-]+)/is";
$text = preg_replace ($hashtag, " <a href='http://hashtags.org/$1'>#$1</a>", $text);
return $text;
}
$xml = simplexml_load_file($url) or die("could not connect");
foreach($xml->status as $status){
$text = $status->text;
}
echo auto_link_twitter ($text);
}
getTwitterStatus("UltanKC");
?>
</div>
<br>
<ul>
<li id="social">YouTube</li>
<li id="social">Twitter</li>
<li id="social">LastFM</li>
<li id="social">Email</li>
</ul>
</div>
<!-- Item 2 End-->
<div id="side-item">
<h2><img src="images/archive.jpg" />Archives</h2>
</div>
<div id="archive-side">
<?php
mysql_connect ('localhost', 'root', 'root') ;
mysql_select_db ('ultankc');
$result = mysql_query("SELECT FROM_UNIXTIME(timestamp, '%Y') AS get_year, COUNT(*) AS entries FROM php_blog GROUP BY get_year");
while ($row = mysql_fetch_array($result)) {
$get_year = $row['get_year'];
$entries = $row['entries'];
echo "<li id='tag'>Entries from " . $get_year . " (" . $entries . ")<br /></li>";
}
$result1 = mysql_query("SELECT * FROM php_blog_categories ORDER BY category_name ASC");
while($row = mysql_fetch_array($result1)) {
$result2 = mysql_query("SELECT COUNT(`id`) AS entries FROM php_blog WHERE category = $row[category_id]");
$num_entries = mysql_fetch_array($result2);
echo '<li id="tag">' . $row['category_name'] . ' (' . $num_entries['entries'] . ')</li>';
}
?>
</div>
</div>
<div class="clr" />
</div>
<!-- Sidebar End -->
<div id="footer">
<p> © Ultan Casey 2010</p>
<p style="margin-top: -18px; float:right">Home | About Me | Email Me</p>
</div>
</div>
</div>
</body>
</html>
?>
Here's the method I use (for similar things, not just title):
<?
ob_start (); // Buffer output
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<title><!--TITLE--></title>
</head>
<body>
<?
$pageTitle = 'Title of Page'; // Call this in your pages' files to define the page title
?>
</body>
</html>
<?
$pageContents = ob_get_contents (); // Get all the page's HTML into a string
ob_end_clean (); // Wipe the buffer
// Replace <!--TITLE--> with $pageTitle variable contents, and print the HTML
echo str_replace ('<!--TITLE-->', $pageTitle, $pageContents);
?>
PHP usually works be executing any bits of code and printing all output directly to the browser. If you say "echo 'Some text here.';", that string will get sent the browser and is emptied from memory.
What output buffering does is say "Print all output to a buffer. Hold onto it. Don't send ANYTHING to the browser until I tell you to."
So what this does is it buffers all your pages' HTML into the buffer, then at the very end, after the tag, it uses ob_get_contents () to get the contents of the buffer (which is usually all your page's HTML source code which would have been sent the browser already) and puts that into a string.
ob_end_clean () empties the buffer and frees some memory. We don't need the source code anymore because we just stored it in $pageContents.
Then, lastly, I do a simple find & replace on your page's source code ($pageContents) for any instances of '' and replace them to whatever the $pageTitle variable was set to. Of course, it will then replace <title><!--TITLE--></title> with Your Page's Title. After that, I echo the $pageContents, just like the browser would have.
It effectively holds onto output so you can manipulate it before sending it to the browser.
Hopefully my comments are clear enough.
Look up ob_start () in the php manual ( http://php.net/ob_start ) if you want to know exactly how that works (and you should) :)
You parse the field from the database as usual.
Then let's say you put it in a variable called $title, you just
<html>
<head>
<title>Ultan.me - <?php echo htmlspecialchars($title);?></title>
</head>
EDIT:
I see your problem. You have to set $title BEFORE using it. That is, you should query the database before <title>...
header.php has the title tag set to <title>%TITLE%</title>; the "%" are important since hardly anyone types %TITLE% so u can use that for str_replace() later. then, you use output buffer like so
<?php
ob_start();
include("header.php");
$buffer=ob_get_contents();
ob_end_clean();
$buffer=str_replace("%TITLE%","NEW TITLE",$buffer);
echo $buffer;
?>
For more reference, click PHP - how to change title of the page AFTER including header.php?
What about using something like:
<?php
$page_title = "Your page tile";
include("navigation.php"); // if required
echo("<title>$page_title</title>");
?>
Move the data retrieval at the top of the script, and after that use:
<title>Ultan.me - <?php echo htmlspecialchars($title, ENT_QUOTES, 'UTF-8'); ?></title>
You need to set the value of $title before echoing it.
Also, you should really sanitize any data before using it in queries as this is a security risk
create a new page php and add this code:
<?php
function ch_title($title){
$output = ob_get_contents();
if ( ob_get_length() > 0) { ob_end_clean(); }
$patterns = array("/<title>(.*?)<\/title>/");
$replacements = array("<title>$title</title>");
$output = preg_replace($patterns, $replacements,$output);
echo $output;
}
?>
in <head> add code: <?php require 'page.php' ?> and on each page you call the function ch_title('my title');
The problem is that $title is being referenced on line 5 before it's being assigned on line 58. Rearranging your code isn't easy, because the data is both retrieved and output at the same time. Just to test, how does something like this work?
Because you're only retrieving one row, you don't need to use a while loop, but I left it with hopes that it'll make it easier for you to relate to your current code. All I've done is removed the actual output from your data retrieval, and added variables for category and category name which are then referred to as usual later on. Also, I haven't tested this. :)
It'll be tricky to rearrange your code to make this work, but I'll try :)
So, put this at the top of your code:
<?php require_once('mysql.php'); ?>
The top of the file should look like:
<?php require_once('mysql.php'); ?>
<html>
<head>
<meta name="keywords" content="Mac user Ultan Casey TheCompuGeeks UltanKC">
<title>Ultan.me - <?php echo htmlspecialchars($title); ?> </title>
Then, create a file called mysql.php in the same directory that the file which contains the code you quoted is in.
Put this is mysql.php:
<?php
mysql_connect ('localhost', 'root', 'root');
mysql_select_db ('ultankc');
if (!isset($_GET['id']) || !is_numeric($_GET['id'])) {
die("Invalid ID specified.");
}
$id = (int)$_GET['id'];
$sql = "SELECT * FROM php_blog WHERE id='$id' LIMIT 1";
$result = mysql_query($sql) or print ("Can't select entry from table php_blog.<br />" . $sql . "<br />" . mysql_error());
$res = mysql_fetch_assoc($result);
$date = date("l F d Y", $res['timestamp']);
$title = $res['title'];
$entry = $res['entry'];
$get_categories = mysql_query("SELECT * FROM php_blog_categories WHERE `category_id` = $res['category']");
$category = mysql_fetch_array($get_categories);
?>
Well, hope that helped :)
I know this is an old post but having read this I think this solution is much simpler (though technically it solves the problem with Javascript not PHP).
<html>
<head>
<title>Ultan.me - Unset</title>
<script type="text/javascript">
function setTitle( text ) {
document.title = text;
}
</script>
<!-- other head info -->
</head>
<?php
// Make the call to the DB to get the title text. See OP post for example
$title_text = "Ultan.me - DB Title";
// Use body onload to set the title of the page
print "<body onload=\"setTitle( '$title_text' )\" >";
// Rest of your code here
print "<p>Either use php to print stuff</p>";
?>
<p>or just drop in and out of php</p>
<?php
// close the html page
print "</body></html>";
?>
Simply add $title variable before require function
<?php
$title = "Your title goes here";
require("header.php");
?>
header.php
<title><?php echo $title; ?></title>
<?php echo APP_TITLE?> - <?php echo $page_title;?>
this should work fine for you
if you want to current script filename as your title tag
include the function in your project
function setTitle($requestUri)
{
$explodeRequestUri = explode("/", $requestUri);
$currentFileName = end($explodeRequestUri);
$withoutExt = preg_replace('/\\.[^.\\s]{3,4}$/', '', $currentFileName);
$explodeCurrentFileName = explode("-", $withoutExt);
foreach ($explodeCurrentFileName as $curFileValue)
{
$fileArrayName[] = ucfirst($curFileValue);
}
echo implode(" ", $fileArrayName);
}
and in your html include the function script
and replace your title tag with this
<title>Your Project Name -
<?php setTitle($_SERVER['REQUEST_URI']); ?>
</title>
it works on php7 and above but i dont have any idea about php 5.*
Hope it helps