I did connection to the DB with PHP code, everything ok. BUT i can't do any manipulations in DB with PHP code, f.e. add/edit tables.
here is piece of code:
<?php
$mysqli = new mysqli("localhost", "root", "mypass", "mybase");
if ($mysqli->connect_error) {
die('Connect Error (' . $mysqli->connect_errno . ') ' . $mysqli->connect_error);
}
$mysqli->query("SET NAMES 'utf8'");
// editing existing table
$success = $mysqli->query ("INSERT INTO `myBase`.`users` (`login`, `password`, `reg_date`) VALUES ('aaa', '".md5("123")."', '".time()."')");
echo $success; // this echo does not work
$mysqli->close();
?>
No new user after this edit.
Try debugging with
echo $mysqli->error;
Generally, errors that prevent you from inserting into your table are syntax or user database permissions.
Related
I have been trying to connect my hosted sql database with mitinventor2 in a registeration form and I am getting an error that says something about
URL. error 1109
This is my php code :
<?php
DEFINE ('DBUSER', '******');
DEFINE ('DBPW', '*****');
DEFINE ('DBHOST', 's******');
DEFINE ('DBNAME', '*******');
$dbc = mysqli_connect(DBHOST,DBUSER,DBPW);
if (!$dbc) {
die("Database connection failed: " . mysqli_error($dbc));
exit();
}
$dbs = mysqli_select_db($dbc, DBNAME);
if (!$dbs) {
die("Database selection failed: " . mysqli_error($dbc));
exit();
}
$clientusername = mysqli_real_escape_string($dbc, $_GET['clientusername']);
$clientemail = mysqli_real_escape_string($dbc,$_GET['clientemail']);
$clientpno = mysqli_real_escape_string($dbc,$_GET['clientpno']);
$clientpass = mysqli_real_escape_string($dbc,$_GET['clientpass']);
$query = "INSERT INTO ssudb(clientusername, clientemail, clientpno, clientpass) VALUES ('$clientusername', '$clientemail', '$clientpno', '$clientpass')";
$result = mysqli_query($dbc, $query) or trigger_error("Query MySQL Error: " . mysqli_error($dbc));
mysqli_close($dbc);
?>
I am sure about the database info yet I hide them for security reasons. My database is well structured with phpmyadmin.
The link to the php file is right with no errors, and here is my mit inventor block:
I hope I didn't validate any rule.
Thanks in advance!
note:
when open phpmyadmin somtimes i see the table is having new attributes with no values in it but the increment ID.
$clientlocation is missing in the VALUES
Newish to php. I have been trying to query a database, and I keep getting the exception thrown that the query could not be completed. I checked to make sure I was connecting to the database, and everything looked fine, until I dug deeper. It appears that the my code tells me that I am connecting to the database regardless of what I put in for a password, username, or even if I do not have this data defined. I don't get it. Originally I had the following code in a function, but I put it no its own page to debug:
<?php
echo'this is working so far <br>';
/*$db = 'fake';
$host = 'localhost';
$password = 'wrong';
$user = 'root';
*/
$result = new mysqli($host, $user, $password, $db);
if(!$result){
echo 'did not connect to database';
throw new Exception('Could not connect to database');
}
else{
echo'connected to database';
return $result;
}
It always tells me I am connected to the database..
Because you are mixing Object oriented style with Procedural style To check database connection
Procedural style
<?php
$link = mysqli_connect('localhost', 'my_user', 'my_password', 'my_db');
if (!$link) {
die('Connect Error (' . mysqli_connect_errno() . ') '
. mysqli_connect_error());
}
echo 'Success... ' . mysqli_get_host_info($link) . "\n";
mysqli_close($link);
?>
Object oriented style
<?php
$mysqli = new mysqli('localhost', 'my_user', 'my_password', 'my_db');
if ($mysqli->connect_error) {
die('Connect Error (' . $mysqli->connect_errno . ') '
. $mysqli->connect_error);
}
?>
Read http://php.net/manual/en/mysqli.construct.php
Note:
OO syntax only: If a connection fails an object is still returned. To check if the connection failed then use either the mysqli_connect_error() function or the mysqli->connect_error property as in the preceding examples.
Source
That means if($result) check is always true no matter what. So no, you don't have that database connection but you are verifying it incorrectly leading you to believe you do.
Your check should be
if($result->connect_error)
// no luck
else
// game on
You should check connect_errno property which stores the error code from last connect call.
$mysqli = new mysqli($host, $user, $password, $db);
/* check connection */
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
I have got a problem with a script that I am developing.I'm testing it on windows XAMPP and I have got a database and a table which I am trying to insert a row.I am using the mysqli extension and using prepared statements to prevent sql injection.But when I execute the query I gets Error 2006:MySQL server gone away,but the server is working well.The server is my own computer.So I don't know what happens.
This is the code I am using:
<?php
header('Content-type: text/html; charset=utf-8');
if(isset($_GET['user']) && isset($_GET['pass'])){
$db = new mysqli("localhost", "root", "", "admin");
if ($db->connect_errno) {
echo "Falló la conexión a MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
}
if (!($db = $db->prepare("INSERT INTO logins(user,pass,ip,url) VALUES (?,?,?,?)"))) {
echo "Falló la preparación: (" . $mysqli->errno . ") " . $mysqli->error;
}
if (!$db->bind_param('ssss', $_GET['user'], $_GET['pass'],$_SERVER['REMOTE_ADDR'],$_SERVER["HTTP_REFERER"])){
echo "Falló la vinculación de parámetros: (" . $db->errno . ") " . $db->error;
}
if (!$db->execute()) {
echo "Falló la ejecución: (" . $db->errno . ") " . $db->error;
}
$db->close();
}
?>
Thanks
EDIT:I forgot to put that I have tried to use the ini_set trick,but didn't worked
I think the problem is $db = $db->prepare, reassigning $db variable probably causes disconnect. Try to write it this way:
$db = new mysqli("localhost", "root", "", "admin");
$stmt = $db->prepare("INSERT INTO logins(user,pass,ip,url) VALUES (?,?,?,?)");
$stmt->bind_param('ssss', $_GET['user'], $_GET['pass'],$_SERVER['REMOTE_ADDR'],$_SERVER["HTTP_REFERER"]);
$stmt->execute();
$db->close();
Your connection string is wrong it should be like this: (unless you have a database called admin and no password)
$db = new mysqli('localhost', 'my_user', 'my_password', 'my_db');
Hey i am using Mamp on imac and my problem is that when i hit the submit button (on a post form) to enter the data then nothing shows up and the database remains empty.
Here is my code :
<?php
define('DB_NAME', 'demob');
define('DB_USER','brom');
define('DB_PASSWORD','****');
Define('DB_HOST','localhost');
$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if (!$link){
die('Could not connect : ' . mysql_error());
}
$db_selected = mysql_select_db(DB_NAME, $link);
if (!$db_selected){
die('cant use' . DB.NAME . ' : ' .mysql_error());
}
$value = $_POST['input1'];
$sql = "INSER INTO memberss ('input1') VALUES ('$value')";
mysql_close();
?>
You are not executing a query.
$sql = "INSER INTO memberss ('input1') VALUES ('$value')";
mysql_query($sql);
You should know that, the method you are using to connect to mysql is deprecated now. please read up about PDO or mysqli
I just referenced this answer and what I preferred was very first solution, now the issue is he has given an information for mysql_() but am using mysqli_(), so using 4th parameter as true, I select the database when user logs in, the moment he logs in he gets redirected to respective page but it is showing that connection was actively refused. any Idea how I can use 2 database, 1 is my default engine database which I need to keep it on for running my framework and second database to run respective scripts according to the user logged in...
What am trying is this
<?php
$database_connect = mysqli_connect('localhost', 'root', '', 'engine');
if(!$database_connect) {
die ('Connect Error (' . mysqli_connect_errno() . ') '. mysqli_connect_error());
}
if(isset($_SESSION['system_id'])) {
$system_database = mysqli_connect('localhost', 'root', '', $_SESSION['system_name'], true);
if(!$system_database) {
die ('Connect Error (' . mysqli_connect_errno() . ') '. mysqli_connect_error());
}
}
?>
P.S I want a procedural way
You don't need any extra parameters, simply do it like this
<?php
$database_connect = mysqli_connect('localhost', 'root', '', 'engine');
if(!$database_connect) {
die ('Connect Error (' . mysqli_connect_errno() . ') '. mysqli_connect_error());
}
if(isset($_SESSION['system_id'])) {
$system_database = mysqli_connect('localhost', 'root', '', $_SESSION['system_name']);
if(!$system_database) {
die ('Connect Error (' . mysqli_connect_errno() . ') '. mysqli_connect_error());
}
}
//Now whatever query you write, just do it like this
$access = mysqli_query($database_connection_var, "/*Query Goes Here*/"); //Will get database name from $database_connection_var
$access2 = mysqli_query($database_connection_var2, "/*Query Goes Here*/"); //Will get database name from $database_connection_var2
?>