ajax jquery returns the whole page - php

this question has been asked before but the answers seem not to work on me. My Ajax returns the whole page when i perform a autocomplete search
ajax to search from database
$(function(){ $(".search_keyword").keyup(function() {
var search_keyword_value = $(this).val();
var dataString = 'search_keyword='+ search_keyword_value;
if(search_keyword_value!='')
{
$.ajax({
type: "POST",
url: "/ajax/search.php",
data: dataString,
cache: false,
success: function(html)
{
$("#result").html(html).show();
}
});
} else{
document.getElementById('result').innerHTML ='';
}
return false; });
html page
<form method="get" action="/?page=results" class="navbar-form" autocomplete="off">
<input type="text" name="query" class="search_keyword"/>
<button type="submit" nam>Search</button>
</form>
<div id="result"></div>
would really appreciate the help Guys

check whether the page you are calling correct path or not...
due to 404 error only, it will returns whole page. may be the ajax url not found

The url used in ajax should be used to return(echo) the required data only, nothing else.
I've usually resolve this problem passing a 'action' POST to to php page wich contains what i would like to request from it and it gets selected with a switch.
The php code usually looks like this:
if(isset($_POST["action"]))
{
switch(action){
case "func_1":
func_1();
break;
case "func_2":
func_2();
break;
case "func_2":
func_3();
break;
case "func_2":
func_4();
break;
}
} else {
echo "error";
}
function func_1{
//do something
}
function func_2{
//do something
}
function func_3{
//do something
}
function func_4{
//do something
}
Inside the function I write the desired code, like getting autocompletion data, then echo it wia json, or something.
Also, the ajax 'data' tag capable to do html post/get paramteres via prebuilding a string:
$.ajax({
type: "POST",
url: "/ajax/search.php",
data:
{
search_keyword : search_keyword_value
}
cache: false,
success: function(html)
{
$("#result").html(html).show();
}
});

Related

The best way passing value from jQuery to PHP

I wonder how I can pass value from Jquery to PHP. I found similar codes but not even one of them work.
Everytime alert shows value of variable but when I open site there is not any. Var_dump shows that $_POST is null. I am ran out of ideas do you have any?
jQuery code:
$("#password-button").click(function(){
var password="";
var numbers =[0,0,0,0,0,0];
for(var i=0;i<=5;i++){
numbers[i] = Math.floor((Math.random() * 25) + 65);
password += String.fromCharCode(numbers[i]);
}
$(".LoginError").text("Nowe haslo: " + password);
$.ajax({
type: 'post',
url: 'dzialaj.php',
data: {'password': password},
cache:false,
success: function(data)
{
alert(data);
console.log(result)
console.log(result.status);
}
});
});
PHP:
if(isset($_POST['password'])){
$temp = $_POST['password'];
echo $temp;
}
Since it looks like you are new on ajax, let's try something more simple ok? Check this js:
<script>
var string = "my string"; // What i want to pass to php
$.ajax({
type: 'post', // the method (could be GET btw)
url: 'output.php', // The file where my php code is
data: {
'test': string // all variables i want to pass. In this case, only one.
},
success: function(data) { // in case of success get the output, i named data
alert(data); // do something with the output, like an alert
}
});
</script>
Now my output.php
<?php
if(isset($_POST['test'])) { //if i have this post
echo $_POST['test']; // print it
}
So basically i have a js variable and used in my php code. If i need a response i could get it from php and return it to js like the variable data does.
Everything working so far? Great. Now replace the js mentioned above with your current code. Before run the ajax just do an console.log or alert to check if you variable password is what you expect. If it's not, you need to check what's wrong with your js or html code.
Here is a example what i think you are trying to achieve (not sure if i understand correctly)
EDIT
<script>
var hash = "my hash";
$.ajax({
type: 'post',
url: 'output.php',
data: {
'hash': hash },
success: function(data) {
if (data == 'ok') {
alert('All good. Everything saved!');
} else {
alert('something went wrong...');
}
}
});
</script>
Now my output.php
<?php
if(isset($_POST['hash'])) {
//run sql query saving what you need in your db and check if the insert/update was successful;
// im naming my verification $result (a boolean)
if ($result) echo 'ok';
else echo 'error';
}
Since the page won't redirect to the php, you need a response in you ajax to know what was the result of you php code (if was successful or not).
Here is the others answers i mentioned in the coments:
How to redirect through 'POST' method using Javascript?
Send POST data on redirect with Javascript/jQuery?
jQuery - Redirect with post data
Javascript - redirect to a page with POST data

HTML : Enable Multiple Submission without refreshing

I want to enhance my tool's page where as soon use click a button. Request goes to server and depending upon return type (fail/pass) i change color of button. No Refresh/page reload
Page has multiple buttons : some what like below.
Name 9-11 - 11-2 2-5
Resource1 - Button - Button - Button
Resource2 - Button - Button - Button
Resource1 - Button - Button - Button
I am a c++ programmer so you might feel i asked a simple question
Here's a sample of jQuery Ajax posting a Form. Personally, I'm unfamiliar with PHP but Ajax is the same no matter what. You just need to post to something that can return Success = true or false. This POST happens asynchronously so you don't get a page refresh unless you do something specific in the success: section.
$("document").ready(function () {
$('form').submit(function () {
if ($(this).valid()) {
$.ajax({
url: yourUrlHere,
dataType: "json",
cache: false,
type: 'POST',
data: $(this).serialize(),
success: function (result) {
if(result.Success) {
// do nothing
}
}
});
}
return false;
});
});
Of course you don't have to be doing a POST either, it could be a GET
type: 'GET',
And if you don't need to pass any data just leave data: section out. But if you want to specify the data you can with data: { paramName: yourValue },
The cache: false, line can be left out if you want to cache the page. Seeing as how you aren't going to show any changes you can remove that line. jQuery appends a unique value to the Url so as to keep it from caching. Specifying type: "json", or whatever your specific type is, is always a good idea but not necessary.
Try using the $.post or $.get functions in jquery
$.post("url",$("#myform").serialize());
Adding a callback function as Fabrício Matté suggested
$.post("url",$("#myform").serialize(),function(data){alert(data);$("#myform").hide()//?Do something with the returned data here});
Here you go. You will find an example of a form, a button a the necessary ajax processing php page. Try it out and let us know how it goes:
<form action="" method="post" name="my_form" id="my_form">
<input type="submit" name="my_button" id="my_button" value="Submit">
</form>
<script type="text/javascript">
$("document").ready(function () {
$('#my_form').submit(function () {
$.ajax({
url: "ajaxpage.php",
dataType: "json",
type: "POST",
data: $(this).serialize(),
success: function (result)
{
//THere was an error
if(result.error)
{
//So apply 'red' color to button
$("#my_button").addClass('red');
}
else
{
//there was no error. So apply 'green' color
$("#my_button").addClass('green');
}
}
});
return false;
});
});
</script>
<?php
//ajaxpage.php
//Do your processing here
if ( $processed )
{
$error = false;
}
else
{
$error = true;
}
print json_encode(array('error' => $error));
die();
?>

return php variable to jquery ajax

I have an ajax function in jquery calling a php file to perform some operation on my database, but the result may vary. I want to output a different message whether it succeeded or not
i have this :
echo '<button id="remove_dir" onclick="removed('.$dir_id.')">remove directory</button>';
<script type="text/javascript">
function removed(did){
$.ajax({
type: "POST",
url: "rmdir.php",
data: {dir_id: did},
success: function(rmd){
if(rmd==0)
alert("deleted");
else
alert("not empty");
window.location.reload(true);
}
});
}
</script>
and this
<?php
require('bdd_connect.php');
require('functions/file_operation.php');
if(isset($_POST['dir_id'])){
$rmd=remove_dir($_POST['dir_id'],$bdd);
}
?>
my question is, how to return $rmd so in the $.ajax, i can alert the correct message ?
thank you for your answers
PHP
<?php
require('bdd_connect.php');
require('functions/file_operation.php');
if (isset($_POST['dir_id'])){
$rmd=remove_dir($dir_id,$bdd);
echo $rmd;
}
?>
JS
function removed(did){
$.ajax({
type: "POST",
url: "rmdir.php",
data: {dir_id: did}
}).done(function(rmd) {
if (rmd===0) {
alert("deleted");
}else{
alert("not empty");
window.location.reload(true);
}
});
}
i advice to use json or :
if(isset($_POST['dir_id'])){
$rmd=remove_dir($dir_id,$bdd);
echo $rmd;
}
You need your php file to send something back, then you need the ajax call on the original page to behave based on the response.
php:
if(isset($_POST['dir_id'])){
$rmd=remove_dir($dir_id,$bdd);
echo "{'rmd':$rmd}";
}
which will output one of two things: {"rmd": 0} or {"rmd": 1}
We can simulate this return on jsBin
Then use jquery to get the value and do something based on the response in our callback:
$.ajax({
type: "POST",
dataType: 'json',
url: "http://jsbin.com/iwokag/3",
success: function(data){
alert('rmd = ' + data.rmd)
}
});
View the code, then watch it run.
Only I didn't send any data here, my example page always returns the same response.
Just try echoing $rmd in your ajax file, and then watching the console (try console.log(rmd) in your ajax response block)
$.ajax({
type: "POST",
url: "rmdir.php",
data: {dir_id: did},
success: function(rmd){
console.log(rmd);
}
});
You can then act accordingly based on the response
Try echo the $rmd out in the php code, as an return to the ajax.
if(isset($_POST['dir_id'])){
$rmd=remove_dir($dir_id,$bdd);
//if $rmd = 1 alert('directory not empty');
//if $rmd = 0 alert('directory deleted');
echo $rmd;
}
Your "rmd" in success: function(rmd) should receive the callabck.

Calling PHP function using ajax not working

I am calling a php function using ajax call but its not working. I have a table with some rows when I click on any column of a row it becomes editable with its value but when I edit the value and click on another column or enter the changed value is not displayed again. Actually I am doing an ajax call where I change the data of the column in my table but its not calling that php function.
My script is as follows
<script type="text/javascript" >
$(document).ready(function()
{
$(".edit_tr").click(function()
{
var ID=$(this).attr('id');
$("#span_"+ID).hide();
$("#input_"+ID).show();
}).change(function()
{
var ID=$(this).attr('id');
var input=$("#input_"+ID).val();
var dataString = 'id='+ ID +'&data='+input;
$("#span_"+ID).html('<img src="load.gif" />'); // Loading image
if(input.length>0)
{
$.ajax({
type: "POST",
url: "worker_app::edit_ajax()",
data: dataString,
cache: false,
success: function(html)
{
$("#span_"+ID).html(span);
}
});
}
else
{
alert('Enter something.');
}
});
// Edit input box click action
$(".editbox").mouseup(function()
{
return false
});
// Outside click action
$(document).mouseup(function()
{
$(".editbox").hide();
$(".text").show();
});
});
The HTML table looks like this
<tbody>
<tr id="{IDWORKERS}" class="edit_tr">
<td class="edit_td">
<span id="span_{IDWORKERS}" class="text">{FIRM}</span>
<input type="text" value="{FIRM}" class="editbox" id="input_{IDWORKERS}" />
</td>
</tr>
</tbody>
And the php function is inside apps folder in a file called wroker_app.php
public function edit_ajax(){
///echo "<pre>";
///print_r($_POST);
//echo "</pre>";
// sql to update the database goes here
echo 'I am here';
}
Any ideas?
Thanks in advance
You can not call specific functions using the request alone. You need to tell your script that edit_ajax is supposed to be executed.
So change your url to worker_app.php, listen for the request using a (e.g) get variable like ?[function].
if (isset($_GET['edit_ajax']) && function_exists($_GET['edit_ajax']))
edit_ajax();
You cant call a php function like this. You can only call a php file where you can decide which function should be executed.
A simple example:
$.ajax({
type: "POST",
url: "/apps/worker_app.php",
data: dataString,
cache: false,
success: function(html) {
$("#span_"+ID).html(span);
}
});
And in your apps/worker_app.php:
<?php
function edit_ajax(){
echo 'I am here';
}
// You can put some logic before this line to decide which function to call based on the request
edit_ajax();
url: "worker_app::edit_ajax.php"
Where is this url referrs to.
check this reference
jquery .ajax
If you want to call function use try to post any specific post field to that file.
After use below in that file
if($_POST['field']!="") {
requredfunction () {
// your code run here
}
}

Submitting form with jQuery

Apologies if this has been answered before (I couldn't find the answer when I searched the archives)
I've got a page protected by a password:
<?php
if($_POST['pw'] == 'pw')
{
//Page content
} else
{
//Display password form
}
?>
Within the page content, I've got another form, which I want to submit using jQuery, and have the following code:
<script type='text/javascript'>
var dataString = $('input#input1').val();
$(function() {
$('#submit').click(function()
{
$.ajax({
type: 'POST',
url: 'p2.php',
data: dataString,
dataType: html,
success: function(data2) {
$('#testResult').html(data2);
}
});
return false;
});
});
</script>
<form name='form1' id='form1' action=''>
<fieldset>
<label for='input1' id='input1_label'>Input 1</label>
<input type='text' name='input1' id='input1' size='30' />
<input type='submit' value='Update / reset' id='submit' class='buttons' />
</fieldset>
</form>
<div id='#testResult'></div>;
However, clicking submit then sends the form to p1.php?input1=test (i.e., the data string is being sent to p1.php, not p2.php). If I edit the code and remove dataType:html and the 2 references of data2, then this doesn't happen (infact, nothing happens, so I assume that jQuery is submitting the data to the form). I've also changed the type to 'GET', incase the 2 POST requests on the same page were causing problems, but this didn't change the result.
What am I missing to get the information from p2.php (i.e. data2) and displaying it?!
EDIT
Thanks to a comment pointing out a typo, I've changed dataType: html to dataType: 'html' - this now doesn't cause the page to redirect to p1.php?input1=test, but once again, it doesn't do anything (when it should still be returning the value of data2)
EDIT 2
I've updated the code so dataString is now:
var dataString = $('input#input1').val();
dataString = 'var1='+dataString;
but this hasn't made any difference
For clarification, my p2.php just contains the following:
<?php
echo "<p>HELLO!</p>";
?>
EDIT 3
I made the changes to my code has suggested by Damien below; I get the alert of "works!" but still nothing seems to be returned from p2.php, and nothing is inserted into the #testResult div.
var dataString = $('input#input1').val();
$(function() {
$('#submit').click(function(evt)
{
evt.preventDefault();
$.ajax({
type: 'POST',
url: 'p2.php',
data: "someval="+dataString,
dataType: 'html',
success: function(data2) {
$('#testResult').html(data2);
}
});
return false;
});
});
$(function() {
$('#submit').click(function()
{
var dataString = $('#form1').serialize();
$.ajax({
type: 'POST',
url: 'p2.php',
data: dataString,
success: function(data2) {
alert('works!'); // ADDED AFTER UPDATE
$('#testResult').html(data2);
},
/* ADDED AFTER UPDATE */
error:function(obj,status,error)
{
alert(error);
}
});
return false;
});
});
Edit:
In p2.php:
<?php
var_dump($_POST['pw']);
?>
In p2.php you then need to output ( using echo, for example) what you want to be returned as 'data2' in your ajax success call.
UPDATE:
Since you're Ajax request fires succesfully, that means either your post is not passed correctly, or you're not outputting anything. I've re-looked at your code and I saw this:
<input type='text' name='input1' id='input1' size='30' />
that means you're fetching the wrong $_POST variable!
Do this:
Since you're sending a name="input1", in your p2.php try with:
<?php
if(isset($_POST['input1'])
{
echo $_POST['input1'];
}
else
{
echo 'No post variable!';
}
And in your jquery success:
success: function(data2) {
alert(data2);
$('#testResult').html(data2);
},
That oughta work, if you follow it literally. In the remote possibility it won't work, forget AJAX, remove the javascript and do a normal post submitting with p2.php as an action of your form :)
I think you have to prevent the default action of the form.
Try this:
$('#submit').click(function(e)
{
e.preventDefault();
$.ajax({
type: 'POST',
url: 'p2.php',
data: dataString,
dataType: html,
success: function(data2) {
$('#testResult').html(data2);
}
});
return false;
});
});
The data should be formatted like this:
variable1=value1&variable2=varlue2
I also think you can remove the dataType property.

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