multiple array in function not show in result using php mysql - php

I need to print/show list of comments for articles using this PHP function:
function _is_comments_($id,$type){
$db = mysqli_access::F("SELECT message FROM " . COMMENTS . " WHERE pid = ? AND type = ? AND approved = 1 ", $id, $type);
foreach($db as $row){
$commentdata['message'] = $row['message'];
}
return $commentdata;
}
In action :
$comments_list = _is_comments_('125','article');
print_r($comments_list);
In result :
Array ( [message] => this is a One comment )
But in MySQL database I have 18 comments for article id 125 and my result is false and show only One result!
how do fix This ?!

Your issue is the assignment in the loop here:
foreach($db as $row){
$commentdata['message'] = $row['message'];
}
Even if you got multiple result $rows, each iteration would overwrite the same $commentdata['message'] key. Which is why you only get to see one entry when returned from the function.
Instead you want to collect multiple entries. I would just drop the ['message'] key, and use an additive indexed array:
foreach($db as $row){
$commentdata[] = $row['message'];
}
This way your result array might contain:
Array (
[0] => this is a One comment
[1] => this is a second comment
[2] => third one
)

You need to make the message index an array.
$commentdata['message'][] = $row['message'];

Related

Delete an array not working with PDO SQL?

it's been 3 hours that i'm trying to delete a row in mysql based on a id ...
Seems simple right ?
Taking into consideration that the array might contains several value:
$result = Array ( [3] => 4_Couture )
Array ( [3] => 4_Couture )
$sql_delete = "DELETE FROM users_resumes WHERE id_training_key = ? ";
$stmt_delete= $pdo->prepare($sql_delete);
foreach($result as $r) {
$stmt_delete->execute($r);
}
This seems to be right no ?
error : PDOStatement::execute() expects parameter 1 to be array, string given
Any, any, any clue is very welcome ! thanks a lot from France !
Assuming $result is a one-dimensional array like
$result = [ 3 => '4_Couture' ];
That means you're trying to call $stmt->execute() with a single string value where it requires an array.
I suggest you use bindParam instead
$stmt_delete = $pdo->prepare("DELETE FROM users_resumes WHERE id_training_key = ?");
$stmt_delete->bindParam(1, $r);
foreach ($result as $r) {
$stmt_delete->execute();
}

Make Associative array with three element in array

I want three element in associative array, so far am successful in getting two in the array.
$sql = "SELECT * FROM `notification_table` ";
$resultsd1 = mysqli_query($conn, $sql);
$row = mysqli_fetch_assoc($resultsd1);
$associativeArray = array();
while ($row = mysqli_fetch_assoc($resultsd1))
{
$associativeArray[$row['name']] = $row['price'] ;
}
foreach($associativeArray as $k => $id){
echo $k."=>".$id .' ';
}
And am getting the response like this
name1=>24.725 name2=>24.265
Now i want to add another column in array as well and the name is column is notification_check .
Am not able to get how to add three columns in a single array. Any help will be appreciated.
I want the output like name1=>24.725=>yes_notification name2=>25.43=>no_notification
And when i print_r($row) is show this output Array ( [sno] => 1 [name] => name1 [price] => 23 [notification_check] => yes_notification)
You could shorten this and use mysqli_fetch_all to create an array of all of the data and then manipulate the array using array_column to create the index...
$result = mysqli_fetch_all($resultsd1, MYSQLI_ASSOC);
$associativeArray = array_column($result, null, 'name');

add values into multidimensional array

I have a foreach loop that goes through a list of items. For each of these items, I have a while loop that grabs data out of a database.
$output = array();
//$reference is a multidimensional array has been passed to this page
where the element `color` contains the color I want.
foreach ($reference as $c) {
$color = $c['color'];
$query = "SELECT DISTINCT name FROM $table where colorPreference = $color";
$exquery = mysqli_query($con, $customerQuery);
while ($row = mysqli_fetch_array($exquery)) {
$person = $row['person'];
array_push($output[$color], $person);
}
}
So this loops through, the first time searching 'red', and finding 5 people in the fake table who like red. Next, 'blue', where it finds 1 person, and then 'green' where it finds 3.
If I look at the individual results, my first array has "red, blue, green" and my second array has these lists of names.... I just don't know how to add them into an array together.
I'm trying to build an array like this:
Array
(
[Red] => Array
(
[0] => John
[1] => Sally
[2] => Bob
...
)
[Blue] => Array
(
[0] => Luke
)
[Green] => Array
(
..etc...
)
I'm not using array_push correctly though - I'm getting an Warning: Illegal offset type error. What am I doing wrong?
It's been a while since I've worked with PHP, but I think you need to initialize each "color" array that you're going to push into. So...
$output = array();
//$reference is a multidimentional array has been passed to this page
where the element `color` contains the color I want.
foreach ($reference as $c) {
$color = $c['color'];
$query = "SELECT DISTINCT name FROM $table where colorPreference = $color";
$exquery = mysqli_query($con, $customerQuery);
while ($row = mysqli_fetch_array($exquery)) {
$person = $row['person'];
if (!array_key_exists($color, $output)) {
$output[$color] = array();
}
array_push($output[$color], $person);
}
}
Try changing:
array_push($output[$color], $person);
Into:
$output[$color][] = $person;
From the manual on array_push:
Note: If you use array_push() to add one element to the array it's better to use $array[] = because in that way there is no overhead of calling a function.
Note: array_push() will raise a warning if the first argument is not an array. This differs from the $var[] behaviour where a new array is created.

PHP MYSQL multidimensional array

I'm having major headaches trying to create a multidimensional array from two separate MySQL selects.... I've been searching here and Google all day and have to finally admit defeat and ask for some help (I'm a newbie as well which doesn't help!!!).
I have two tables, one which contains a single row result per id and another which can contain several rows for an id. What I'm trying to do is combine the two into a multidimensional array.
My code (poor as it may be) looks like this:
require 'php/phpConnection.php';
$sqlString1 = mysql_query("SELECT id FROM supportstaff_section1_a");
$firstArray = array();
$secondArray = array();
while ($r = mysql_fetch_assoc($sqlString1)) {
$applicantID = $r['id'];
$sqlString2 = mysql_query("SELECT educationalname FROM supportstaff_section5 WHERE id = '$applicantID'");
while ($x = mysql_fetch_assoc($sqlString2)) {
$secondArray[] = $x;
}
$firstArray[] = $r + $secondArray;
$secondArray = array();
}
print json_encode($firstArray);
mysql_close($con);
The result is this:
[{"id":"8m8wwy","0":{"educationalname":"GCSE - English"},"1":{"educationalname":"GCSE - Maths"}},{"id":"wiL7Bn"},{"id":"zAw6M1"}]
But I think it needs to look something like this:
[{"id":"8m8wwy","Array2":"[{"educationalname":"GCSE - English"},{"educationalname":"GCSE - Maths"}]"},{"id":"wiL7Bn"},{"id":"zAw6M1"}]
Anyway, how can I insert my second SQL Select into my first SQL Select for each ID.
Thanks for any advice/help.
EDIT
Taken from W3Schools.com:
Array
(
[Griffin] => Array
(
[0] => Peter
[1] => Lois
[2] => Megan
)
[Quagmire] => Array
(
[0] => Glenn
)
[Brown] => Array
(
[0] => Cleveland
[1] => Loretta
[2] => Junior
)
)
I'm trying to make it work like the above.
You need to get a little creative here. Something like the following would work as a join AND with multi-dimensional data:
<?php
require 'php/phpConnection.php';
// ======================================================================
// Create a join query (way faster than several separate ones!)
$sqlquery =
"SELECT SSSA.id, SSS5.educationalname" .
" FROM supportstaff_section1_a SSSA" .
" LEFT OUTER JOIN supportstaff_section5 SSS5 ON SSS5.id = SSSA.ID";
// ======================================================================
// Run the query and get our results
$resultarray = array();
if ($resource = mysql_query($sqlquery)) {
while ($curarray = mysql_fetch_assoc($resource)) {
// Create an array, if it doesn't exist
if (!isset($resultarray[$curarray["id"]]))
$resultarray[$curarray["id"]] = array();
// Add to the array, if not null
$curstring = (string) $curarray["educationalname"];
if ($curstring != "")
$resultarray[$curarray["id"]][] = $curstring;
}
mysql_free_result($resource);
}
// ======================================================================
// Convert from a keyed array to a standard indexed array (0, 1, 2, etc.)
$finalarray = array();
foreach ($resultarray as $id => & $data) {
// Start with just ID
$newarray = array(
"id" => $id
);
// Get the data, if we have any
if (count($data))
$newarray["educationalnames"] = & $data;
// Add to our final array and clear the newarray
$finalarray[] = & $newarray;
unset($newarray);
}
// ======================================================================
// Get the JSON of our result
$jsonresult = json_encode($finalarray);
// ======================================================================
// Echo it to test
echo $jsonresult;
// ======================================================================
// Close the database
mysql_close($con);
?>
And the resulting $jsondata would look like this (but not so unravelled of course):
[
{
"id": "8m8wwy",
"educationalnames": ["GCSE - English", "GCSE - Maths"]
},
{
"id": "wiL7Bn"
},
{
"id": "zAw6M1"
}
]
If you have an ID from the first Array, you can check for keys / values with this ID in the second Array.
If you want to get the key you should use
array_key_exists($string)
And if you want to get the value you should use
in_array($string)
You can use a foreach loop to execute this functions!

array to string conversion error, need to explode and then implode

I want to explode an array, read each value and print them back in an array...
I dont understand where i am getting wrong. Please help me..this is my code..
I am getting an array to string conversion error
$query="SELECT categories FROM shops";
$result = mysql_query($query);
while($column = mysql_fetch_assoc($result)){
$categories=explode(",",$column['categories']);
foreach($categories as $value){
$new_query="SELECT name from categories where id='$value'";
$name = mysql_query($new_query);
$name_column= mysql_fetch_assoc($name);
array_push($shops_list,$name_column);
}
}
echo implode(",",$shops_list);
$shop_list is not defined, before using it in this line array_push($shops_list,$name_column);. And, this line
array_push($shops_list,$name_column);
needs to be, as you need to mention the key name,
array_push($shops_list,$name_column['name']); //or better
$shop_list[] = $name_column['name'];
Several issues:
$name_column = mysql_fetch_assoc($name);
$name_column = $name_column['name'];
name_column is an array.
shops_list is never initialized.
You should use [] instead of array_push.
The other guys hit it on the nose, but when you did your array push on $name_column, since $name_column is an array, you end up with:
Array
(
[0] => Array
(
[name] => boo
)
)
Obviously doing an implode on that is going to not work.
That being said, what you really need to do here is not keep your category mappings as a comma delimited string in the database. Standard DB architecture dictates you use a mapping table.
Table shops
Table categories
Table shop_category_map that has shop_id and category_id
use group_concat to retrieve values. and after getting the result, use them directly for searching. like
$result_array = explode(",",$row['category']);
foreach($result_array as $ra)
{
//sql command. fetch here.
$new_query="SELECT name from categories where id='$value'";
$name = mysql_query($new_query);
$name_column= mysql_fetch_assoc($name);
$shops_list[] = $name_column;
}
try else go for better solution
// explode an array and then implode until a particular index of an array
$a = '192.168.3.250';
$b = explode('.',$a);
$ar = array();
for($i=0;$i<=2;$i++)
{
array_push($ar,$b[$i]);
}
$C = implode($ar,'.');
print_r($C);

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