how to pass AJAX response value to PHP variables? - php

Question

I want to use the result value and pass it to php variable,
here is my code...
billingCoffee.php
$("#linkAddSize").click(function(e){
e.preventDefault();
var txtCoffeeName = document.getElementById("txtCoffeeName").value;
var cmbSizes = document.getElementById("cmbSizes").value;
var txtPrice = document.getElementById("txtPrice").value;
$.ajax({
url: "addSizeandPrice.php",
type: "POST",
data: {coffeename: txtCoffeeName, sizes: cmbSizes, price: txtPrice},
datatype: "json",
success: function (result){
//set it php variable
}
});
});
addSizeandPrice.php
if($tableresult){
$query = "INSERT INTO tbl$CoffeeName (CoffeeSize, Price) VALUES ('$Size', '$Price');";
$insertresult = mysqli_query($con, $query);
if($insertresult){
SESSION_START();
$_SESSION['nameCoffee'] = $CoffeeName;
echo $_SESSION['nameCoffee'];
}
else{
echo "Something went wrong!";
}
}
I want to use the variable without refreshing the page... and I got this idea to use AJAX but don't know how to set it in php variable.

Answer 1

You are using POST as the method to send variables to your PHP script. So in PHP, they will be in the superglobal named $_POST
For example,
$coffeename = $_POST['coffeename'];
Further reading: http://php.net/manual/en/reserved.variables.post.php
Please also do some research about preventing SQL injection.