I want to get all the records from the while loop. I'm unable to get all the rows from the query. It shows only the first row.
Is there anything I was going wrong in my code.
function Connect($DB_HOST = 'localhost', $DB_USER = 'root', $DB_PASS = '', $DB_NAME = 'bodhilms')
{
$mysqli = new mysqli($DB_HOST, $DB_USER, $DB_PASS, $DB_NAME);
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
return $mysqli;
}
function GetCoeficient($coeficient = false, $con)
{
if(!$con)
return 0;
$result = array();
$sql[] = "SELECT * FROM users ";
if($coeficient != false)
$sql[] = "WHERE username = '".$coeficient."' ORDER BY u.id";
//print_r($coeficient);
$query = $con->query(implode(" ",$sql));
//print_r($query);
while($row = $query->fetch_assoc())
{
$result[] = $row;
}
return (!empty($result))? $result : 0;
}
$con = Connect();
$result = GetCoeficient($coeficient,$con);
$username = $result[0]['username'];
$firstname = $result[0]['firstname'];
$lastname = $result[0]['lastname'];
$email = $result[0]['email'];
First of all,to make sure the infomation of mysql is right,like port.
and I wonder the code of you $result = Getcourse($coeficient,$con);, how the var coeficient come from.Then
You can try the code below:
$mysqli=new mysqli("localhost","root","root","123");
$query="select * from test";
$result=$mysqli->query($query);
if ($result) {
if($result->num_rows>0){
while($row =$result->fetch_array() ){
echo ($row[0])."<br>";
echo ($row[1])."<br>";
echo ($row[2])."<br>";
echo ($row[3])."<br>";
echo "<hr>";
}
}
}else {
echo 'failure';
}
$result->free();
$mysqli->close();
Related
I can't run my codes.
It says:
syntax error, unexpected '$query' (T_VARIABLE).
Code
<?php
$hostname="localhost";
$username="";
$password="";
$dbname="thesis";
$usertable="product";
$yourfield="product_id";
msql_connect($hostname,$username,$password) or die ("<html><script>
language='Javascript'>alert('Unable to connect to database!.'),history.go(-1)</script></html>")
$query = "SELECT * FROM $usertable";
$result = mysql_query($query);
if($result)
{
while ($row = mysql_fetch_array($result))
{
$name = $row["$yourfield"];
echo "Name: ".$name."</br>";
}
}
?>
msql_connect($hostname,$username,$password) or die ("<html><script>
language='Javascript'>alert('Unable to connect to database!.'),history.go(-1)</script></html>")
should have a semicolon.
Replace it with this:
msql_connect($hostname,$username,$password) or die ("<html><script>
language='Javascript'>alert('Unable to connect to database!.'),history.go(-1)</script></html>");
<?php
$hostname = "localhost";
$username = "";
$password = "";
$dbname = "thesis";
$usertable = "product";
$yourfield = "product_id";
$mysqli = new mysqli($hostname, $username, $password, $dbname);
/* check connection */
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
/* Select queries return a resultset */
if ($result = $mysqli->query("SELECT * FROM $usertable")) {
while ($row = mysql_fetch_array($result))
{
$name = $row["$yourfield"];
echo "Name: ".$name."</br>";
}
/* free result set */
$result->close();
}
$mysqli->close();
http://php.net/manual/en/mysqli.query.php
This my PHP URL for fetching the data from MySQL. I need to make mysqli_fetch_array code saying if filled uid in the app-data table is the same with uid in users table fetch the data from all row in app-data to the uid like every user show his items from app-data table.
$host = "";
$user = "";
$pwd = "";
$db = "";
$con = mysqli_connect($host, $user, $pwd, $db);
if(mysqli_connect_errno($con)) {
die("Failed to connect to MySQL: " . mysqli_connect_error());
}
$sql = "SELECT * FROM app_data ORDER By id";
$result = mysqli_query($con, $sql);
$rows = array();
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
$rows[] = $row;
}
mysqli_close($con);
echo json_encode($rows);
I think this is the correct answer:
<?php
$host = "";
$user = "";
$pwd = "";
$db = "";
$con = mysqli_connect($host, $user, $pwd, $db);
if(mysqli_connect_errno($con)) {
die("Failed to connect to MySQL: " . mysqli_connect_error());
}
$sql = "SELECT * FROM app_data WHERE u_id=".$_POST['posted_uid']." ORDER By id";
$result = mysqli_query($con, $sql);
$rows = array();
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
$rows[] = $row;
}
mysqli_close($con);
echo json_encode($rows);
Little tip for the future:
Don't search exactly what you want, only search in parts.
I got little problem with my code... because I try to SELECT sth from database and then INSERT some value to another table, but in normal code from w3school
and I got error
Tryingo to get property of non-object
Here is my code:
<?php
session_start();
function connectionDB(){
$host = "localhost";
$username = "root";
$password = "";
$db_name = "project";
$conn = new mysqli($host, $username, $password, $db_name);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
return $conn;
}
function getID(){
$id = $_GET['id'];
return $id;
}
$login =$_SESSION['login'];
$conn =connectionDB();
$idCar = getID();
echo $idCar;
$sqluser = "SELECT ID_USER FROM login_table WHERE LOGIN = $login";
if($result->num_rows > 0)
$result = $conn->query($sqluser);
{
while($row = $result->fetch_assoc())
{
$sql = "INSERT INTO cart (id_user) VALUES ('".$row['ID_USER']."')";
}
}else echo"error";
?>
THIS IS THE CODE OF SIDE WITH PRODUCT
Please see change near your IF loop
$sqluser = "SELECT ID_USER FROM login_table WHERE LOGIN = $login";
$result = $conn->query($sqluser); //check result first
if($result->num_rows > 0) //get number of rows
{
while($row = $result->fetch_assoc())
{
$sql = "INSERT INTO cart (id_user) VALUES ('".$row['ID_USER']."')";
}
}else echo"error";
<?php
$username = "username";
$password = "password";
$hostname = "localhost";
$database = "database";
//connection to the database
$dbhandle = mysql_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
$selected = mysql_select_db($database,$dbhandle)
or die("Could not select database");
$id = 0;
if(isset($_GET['Day'])){ $id = (int)$_GET['Day']; }
if(!$id){
$query = "SELECT * FROM `TimeTable`";
} else {
$query = "SELECT * FROM `TimeTable` WHERE `Day`='".$id."'";
}
$result = mysql_query($query);
$rows = array();
while($r = mysql_fetch_assoc($result)) {
$rows[] = $r;
}
or die(mysql_error());
print json_encode($rows);
?>
This code worked previously, but has now stopped, and is producing Parse error: syntax error, unexpected T_LOGICAL_OR in /Directory/TimeTable.php on line 27
I am also looking to add more parameters, (eg: Where Day = $id and Year = $Year )
while($r = mysql_fetch_assoc($result)) {
$rows[] = $r;
}
or die(mysql_error());
This is a syntax error, doesn't know what to do with that or die() statement. Change to this:
$result = mysql_query($query);
if (!$result) {
die('Error');
}
while(...) {
}
I have looked up the new mysql functions an have changed to mysqli.
<?php
$username = "username";
$password = "password";
$hostname = "localhost";
$database = "database";
$link = mysqli_connect($hostname, $username, $password, $database);
if(mysqli_connect_errno()){
echo mysqli_connect_error();
}
$id= 0;
if(isset($_GET['Day'])){ $id=(int)$_GET['Day']; }
$year = 0;
if(isset($_GET['Year'])){ $year=(int)$_GET['Year'];}
if(!$id){
$query = "SELECT * FROM TimeTable";
} else {
if (!year) {
$query = "Select * FROM TimeTable";
} else {
$query = "SELECT * FROM TimeTable WHERE Day=$id AND Year=$year";
}
}
$rows = array();
//Perform JSON encode
if($result = mysqli_query($link, $query)){
while($r = mysqli_fetch_assoc($result)){
$rows[] = $r;
}
}
print json_encode($rows);
?>
The following code always displays
rows = 0
eventhough the table contains Ravi in the field 'to'. Does anyone know what is wrong with this code?
<?php
$response = array();
$con = mysql_connect("localhost","root","");
if(!$con) {
die('Could not connect: '.mysql_error());
}
mysql_select_db("algopm1",$con);
//if (isset($_POST['to'])) {
$to = "Ravi";
$result = mysql_query("SELECT *FROM `events` WHERE to = '$to'");
if (!empty($result)) {
if (mysql_num_rows($result)>0) {
$result = mysql_fetch_array($result);
echo $result["to"] + " " + $result["from"];
} else {
echo 'rows = 0';
}
} else {
echo 'empty for Ravi';
}
//} else {
//}
?>
to is a reserved word in MySQL, if you want to use it you must encase it in backticks:
.... WHERE `to` = ...
I have not look at your code but I recommend looking at
http://php.net/manual/en/intro.mysql.php
this before you continue to use mysql and not mysqli. It isn't that different but mysqli seems to have a wrapper over mysql and uses the "->" to instantiate new classes for a connection. If that makes any sense.
Try this:
<?php
$response = array();
$con = mysql_connect("localhost","root","");
if(!$con) {
die('Could not connect: '.mysql_error());
}
mysql_select_db("algopm1",$con);
//if (isset($_POST['to'])) {
$to = "Ravi";
$result = mysql_query("SELECT *FROM `events` WHERE `to` = '$to'");
if (!empty($result)) {
if (mysql_num_rows($result)>0) {
$row = mysql_fetch_array($result);
echo $row["to"] + " " + $row["from"];
} else {
echo 'rows = 0';
}
} else {
echo "empty for $to";
}
//} else {
//}
?>
MYSQLI version + some adjustments:
<?PHP
$host = "localhost";
$user = "root";
$password = "";
$database="algopm1";
$link = mysqli_connect($host, $user, $password, $database);
IF (!$link){
echo ("Unable to connect to database!");
}
ELSE {
$query = "SELECT *FROM `events` WHERE `to` = '$to'";
$result = mysqli_query($link, $query);
if (mysql_num_rows($result)>0) {
while($row = mysqli_fetch_array($result, MYSQLI_BOTH)){
echo $row["to"]. "+". $row["from"];
}
}
ELSE {
echo 'rows = 0';
}
}
mysqli_close($link);
?>
I would like to credit #njk and #Wezy for their contribution with regard to the reserved word to in mysql. The WHILE loop is not necessary if the table events can only contain one "to" in this case "Ravi". I suspect that the number of events can be greater than one.
#Wezy has a point but let's do the troubleshooting:
As #JonathanRomer in his comment suggested, do:
$result = mysql_query("SELECT *FROM `events` WHERE `to` = '$to'") or die(mysql_error());
What does it say? Does it fail at all?
Or, just before mysql_query do:
die("SELECT *FROM `events` WHERE `to` = '$to'");
this will print faulty query being executed. Next, fire up mysql console or PHPMyAdmin and try executing this query manually.
Again, what does it say?
Actually, my main purpose was to encode this message and receive it on a mobile device by using JSON. This is the full code. For normal checking purpose, instead of using json_encode(*), the values can be displayed individually. This is the solution I got and it is working perfectly for receiving the data in an android app on which I am working.
<?php
$host = "localhost";
$user = "root";
$password = "";
$database="algopm1";
$response = array();
$mysqli = new mysqli($host, $user, $password, $database);
if (mysqli_connect_errno()){
$response["success"] = 0;
$response["message"] = mysqli_connect_error();
echo json_encode($response);
}
if(isset($_POST['to'])) {
$to = $_POST['to'];
$query = "SELECT *FROM `events` WHERE `to` = '$to'";
if($stmt = $mysqli->prepare($query)) {
$stmt->execute();
$stmt->store_result();
$i = 0;
if($stmt->num_rows > 0) {
$stmt->bind_result($rowto, $rowfrom, $rowevent);
$response["events"] = array();
while($stmt->fetch()) {
$events = array();
$events["to"] = $rowto;
$events["from"] = $rowfrom;
$events["event"] = $rowevent;
array_push($response["events"], $events);
}
$response["success"] = 1;
echo json_encode($response);
} else {
$response["success"] = 0;
$response["message"] = "No events found";
echo json_encode($response);
}
$stmt->close();
}
} else {
$response["success"] = 0;
$response["message"] = "Required fields are missing";
echo json_encode($response);
}
$mysqli->close();
?>