PHP curl response string given and json_decode null [duplicate] - php

Question

This question already has answers here:
PHP json_decode() returns NULL with seemingly valid JSON?
(29 answers)
Closed 4 months ago.
I got a very strange problem.
I have a JSON webservice.
When i check it with this website http://www.freeformatter.com/json-formatter.html#ad-output
Everything is OK.
But when i load my JSON with this code :
$data = file_get_contents('http://www.mywebservice');
if(!empty($data))
{
$obj = json_decode($data);
switch (json_last_error()) {
case JSON_ERROR_NONE:
echo ' - JSON_ERROR_NONE';
break;
case JSON_ERROR_DEPTH:
echo ' - JSON_ERROR_DEPTH';
break;
case JSON_ERROR_STATE_MISMATCH:
echo ' - JSON_ERROR_STATE_MISMATCH';
break;
case JSON_ERROR_CTRL_CHAR:
echo ' - JSON_ERROR_CTRL_CHAR';
break;
case JSON_ERROR_SYNTAX:
echo "\r\n\r\n - SYNTAX ERROR \r\n\r\n";
break;
case JSON_ERROR_UTF8:
echo ' - JSON_ERROR_UTF8';
break;
default:
echo ' - Unknown erro';
break;
}
I got the error : SYNTAX ERROR
WHICH IS NOT HELP FULL AT ALL.
It is a nightmare.
I see that with PHP 5.5 i could use this function : http://php.net/manual/en/function.json-last-error-msg.php
(but i did not succeed to install PHP 5.5 yet, and i m not sure this function will give me more detail)

Answer 1

I faced the same issue, actually there are some hidden characters unseen and you need to remove it.
Here's a global code that works for many cases:
<?php
$checkLogin = file_get_contents("http://yourwebsite.com/JsonData");
// This will remove unwanted characters.
// Check http://www.php.net/chr for details
for ($i = 0; $i <= 31; ++$i) {
$checkLogin = str_replace(chr($i), "", $checkLogin);
}
$checkLogin = str_replace(chr(127), "", $checkLogin);
// This is the most common part
// Some file begins with 'efbbbf' to mark the beginning of the file. (binary level)
// here we detect it and we remove it, basically it's the first 3 characters
if (0 === strpos(bin2hex($checkLogin), 'efbbbf')) {
$checkLogin = substr($checkLogin, 3);
}
$checkLogin = json_decode( $checkLogin );
print_r($checkLogin);
?>

Answer 2

Removing the BOM (Byte Order Mark) is often-times the solution you need:
function removeBOM($data) {
if (0 === strpos(bin2hex($data), 'efbbbf')) {
return substr($data, 3);
}
return $data;
}
You shouldn't have a BOM, but if it's there, it is invisible so you won't see it!!
see W3C on BOM's in HTML
use BOM Cleaner if you have lot's of files to fix.

Answer 3

I solved this issue adding stripslashes to the string, before json_decode.
$data = stripslashes($data);
$obj = json_decode($data);

Answer 4

To put all things together here and there, I've prepared JSON wrapper with decoding auto corrective actions. Most recent version can be found in my GitHub Gist.
abstract class Json
{
public static function getLastError($asString = FALSE)
{
$lastError = \json_last_error();
if (!$asString) return $lastError;
// Define the errors.
$constants = \get_defined_constants(TRUE);
$errorStrings = array();
foreach ($constants["json"] as $name => $value)
if (!strncmp($name, "JSON_ERROR_", 11))
$errorStrings[$value] = $name;
return isset($errorStrings[$lastError]) ? $errorStrings[$lastError] : FALSE;
}
public static function getLastErrorMessage()
{
return \json_last_error_msg();
}
public static function clean($jsonString)
{
if (!is_string($jsonString) || !$jsonString) return '';
// Remove unsupported characters
// Check http://www.php.net/chr for details
for ($i = 0; $i <= 31; ++$i)
$jsonString = str_replace(chr($i), "", $jsonString);
$jsonString = str_replace(chr(127), "", $jsonString);
// Remove the BOM (Byte Order Mark)
// It's the most common that some file begins with 'efbbbf' to mark the beginning of the file. (binary level)
// Here we detect it and we remove it, basically it's the first 3 characters.
if (0 === strpos(bin2hex($jsonString), 'efbbbf')) $jsonString = substr($jsonString, 3);
return $jsonString;
}
public static function encode($value, $options = 0, $depth = 512)
{
return \json_encode($value, $options, $depth);
}
public static function decode($jsonString, $asArray = TRUE, $depth = 512, $options = JSON_BIGINT_AS_STRING)
{
if (!is_string($jsonString) || !$jsonString) return NULL;
$result = \json_decode($jsonString, $asArray, $depth, $options);
if ($result === NULL)
switch (self::getLastError())
{
case JSON_ERROR_SYNTAX :
// Try to clean json string if syntax error occured
$jsonString = self::clean($jsonString);
$result = \json_decode($jsonString, $asArray, $depth, $options);
break;
default:
// Unsupported error
}
return $result;
}
}
Example usage:
$json_data = file_get_contents("test.json");
$array = Json::decode($json_data, TRUE);
var_dump($array);
echo "Last error (" , Json::getLastError() , "): ", Json::getLastError(TRUE), PHP_EOL;

Answer 5

in my case:
json_decode(html_entity_decode($json_string));

Answer 6

After trying all the solution without the result this is the one worked for me.
Hope it will help someone
$data = str_replace('"', '"', $data);

Answer 7

I have the same problem, receiving JSON_ERROR_CTRL_CHAR and JSON_ERROR_SYNTAX.
This is my fix.
$content = json_decode(json_encode($content), true);

Answer 8

You haven't show your JSON but this sound like it could be an Invalid UTF-8 sequence in argument, most online validator wont catch it.
make sure your data is UTF-8 and also check if you have foreign characters.
You don't need PHP5 to see your error, use error_log() to log the problems.

Answer 9

I had the same issues. I took the following steps:
changed the JSON text encoding
$json = utf8_encode($json);
I then viewed the plain text before decoding. I found crazy symbols like
ï
then I just stripped it off
$json = str_replace(array('ï',''), '',$json);
and I successfully decoded my JSON

Answer 10

please first clean json data and then load.

Answer 11

A JSON string must be double-quoted, the JSON isn't valid because you don't need to escape ' character.
char = unescaped /
escape (
%x22 / ; " quotation mark U+0022
%x5C / ; \ reverse solidus U+005C
%x2F / ; / solidus U+002F
%x62 / ; b backspace U+0008
%x66 / ; f form feed U+000C
%x6E / ; n line feed U+000A
%x72 / ; r carriage return U+000D
%x74 / ; t tab U+0009
%x75 4HEXDIG ) ; uXXXX U+XXXX
The ' is not in the list.
See this list of special character used in JSON:
\b Backspace (ascii code 08)
\f Form feed (ascii code 0C)
\n New line
\r Carriage return
\t Tab
\" Double quote
\\ Backslash character
Check out this site for more documentation.

Answer 12

I faced this issue as well and it was so frustrating for me. after hours of trying different solutions on the internet. I noticed that the encoding of the file is in UTF-8 with BOM as var_dump() was echoing a weird character  before the JSON.
I converted the sample.json file I was working with from UTF-8 with BOM to UTF-8 ... In VS CODE add the below to your settings.json or make sure the below settings code is as seen below (so that any file you create will be encoded in UTF-8 by default;
"files.encoding": "utf8",
Then you'll see something like the below screenshot on your VSCode toolbar. (For json_decode() to work, the file has to be encoded in UTF-8)
But in my case, the JSON file I created was having a UTF-8 with BOM encoding which is why when I was doing json_decode($json, true) it was returning null (Syntax Error when I var_dump(json_last_error_msg()) )
Click on the UTF-8 with BOM, then you will get the dropdown,
Click Save with Encoding,
You should get the below screenshot, then you click on UTF-8.
That will resave your file with UTF-8 encoding and you can go ahead and check your code. json_decode() will work fine. Can't believe I spent hours trying to figure out what could be wrong.
Happy Coding!

Answer 13

I faced the same issue, The reason is the responsed texts look like a json, but it is actually a text in HTML format. You can echo your text (json look-alike) in JSON format, to see what is actual inside:
$response = file_get_contents('http://www.mywebservice');
header('Content-Type: application/json');
echo $response;
This function file_get_contents will return some extra HTML codes.
In my case, I remove those unwanted characters :
$response = str_replace('<head></head><body><pre style="word-wrap: break-word; white-space: pre-wrap;">', '',$response );
$response = str_replace('</pre></body>', '',$response );
Here is the complete code:
$response = file_get_contents('http://www.mywebservice');
$response = str_replace('<head></head><body><pre style="word-wrap: break-word; white-space: pre-wrap;">', '',$response );
$response = str_replace('</pre></body>', '',$response );
$response = json_decode($response);
header('Content-Type: application/json');
$error = json_last_error_msg() ;
echo $error;
if ($error == null){echo "This is truly a JSON : <br>"}
echo $response;

Answer 14

One problem from my side, is that there were some invalid numbers starting with 0, Ex: "001", "002", "003".
"expectedToBeReturned":1,
"inventoryNumber":001,
"remindNote":"",
Replace 001 with 1 and it works.

Answer 15

I had same issue. For me it was causing by echo "<br/><pre>". I was trying to pass json string to another php file using exit(json_encode(utf8ize($resp_array))); At the beginning of file i had decleared break line tag... So this was error for me. Removing this break line tag , i was able to decoding my json string an other php file..

Answer 16

I had same issue. For me it was causing by echo "<br/><pre>".
I was trying to pass json string to another php file using :
exit(json_encode(utf8ize($resp_array)));
At the beginning of file I had decleared break line tag... So this was error for me. Removing this break line tag , I was able to [...]

Answer 17

This code worked for me.
Basically it removes hidden characters.
function cleanString($val)
{
$non_displayables = array(
'/%0[0-8bcef]/', # url encoded 00-08, 11, 12, 14, 15
'/%1[0-9a-f]/', # url encoded 16-31
'/[\x00-\x08]/', # 00-08
'/\x0b/', # 11
'/\x0c/', # 12
'/[\x0e-\x1f]/', # 14-31
'/x7F/' # 127
);
foreach ($non_displayables as $regex)
{
$val = preg_replace($regex,'',$val);
}
$search = array("\0","\r","\x1a","\t");
return trim(str_replace($search,'',$val));
}