Inserting form values in multiple row using php empty fields - php

I need a little help. I have the following code. I wish that when all fields are not completed, not to introduce the empty fields in the database. Just upload the completed them.
for($i = 0; $i <count($_POST)+3; $i++){
mysql_query("INSERT INTO `predare`(`id_factura`,`id_student`, `id_produs`, `cantitate`)
VALUES('".$_POST['id_factura'][$i]."','".$_POST['id_student'][$i]."', '".$_POST['id_produs'][$i]."', '".$_POST['cantitate'][$i]."');");
}
<input class="input-1" name="cantitate[]" id="cantitate" value="">
<input class="input-1" name="id_factura[]" id="id_factura" value="">
<input class="input-1" name="id_student[]" id="id_student" value="">
<input class="input-1" name="id_produs[]" id="id_produs" value="">

Here's how I would suggest doing it. First initialize your SQL string and a separator (for inserting multiple records with one query.)
$sql = "INSERT INTO `predare` (`id_factura`,`id_student`, `id_produs`, `cantitate`) VALUES ";
$separator = '';
Then loop over the submitted rows and append to the SQL string if the rows have all four values.
for ($i = 0; $i < count($_POST['cantitate']); $i++) {
$values = array();
foreach (array('id_factura', 'id_student', 'id_produs', 'cantitate') as $column) {
// only add values to the $values array if something has been entered
// (empty fields will be present as '', which evaluates to false)
if ($_POST[$column][$i]) $values[] = $_POST[$column][$i];
}
if (count($values) == 4) { // only add the values to the SQL if all fields are present
$sql .= "$separator ('" . implode("','", $values) . "')";
$separator = ',';
}
}
Then you can execute the SQL statement to insert all the complete records at once.
If you wanted to include incomplete (but not empty) rows, you could use
if ($values) {... instead of if (count($values) == 4) {...
One benefit to setting it up this way is that it would be easier to convert the code to use a better database extension (such as PDO) with prepared statements instead of concatenating the values into the SQL like this.

You need to go through the $_POST['id_factura'] array and You need to check the values before the insert statement like this:
for($i = 0; $i <count($_POST['id_factura']); $i++){
if(isset($_POST['id_factura'][$i]) && isset($_POST['id_student'][$i]) && isset($_POST['id_produs'][$i]) && isset($_POST['cantitate'][$i])){
mysql_query("INSERT INTO `predare`(`id_factura`,`id_student`, `id_produs`, `cantitate`)
VALUES('".$_POST['id_factura'][$i]."','".$_POST['id_student'][$i]."', '".$_POST['id_produs'][$i]."', '".$_POST['cantitate'][$i]."');");
}
}
Or you can check if the integer values are greater then 0...

Related

Inserting multiple values from Checkbox into 4 Columns

I'm a little confused here. I want to add 4 values to the db. Exept if the user only add < 4.
DB columns are:
ticket1, ticket2, ticket3, ticket4
There are multiple checkboxes 1-19.
<input class='' id='cbx' value='1' name='check_num[]' type='checkbox'/><label>1</label>
My code is...
if(!empty($_POST['check_num'])) {
foreach($_POST['check_num'] as $key => $value) {
//i just need the ARRAY or something to divide the numbers in peaces to put on the db.
}
} else {
echo "empty";
}
I'd use something like this, but there are plenty of alternatives.
if(!empty($_POST['check_num'])) {
$count = count($_POST['check_num']);
if($count <= 4){
$columns = "";
$values = "";
$i = 1;
while($i <= $count){
$columns .= "ticket".$i.", ";
$params .= "?, ";
$types .= "i";
$i++;
}
$columns = substr($columns, 0, 2);
$params = substr($columns, 0, 2);
$stmt = $mysqli->prepare("INSERT INTO [table_name] (".$columns.") VALUES (".$params.");";);
mysqli_stmt_bind_param($stmt, $types, ...$_POST['check_num']);
mysqli_stmt_execute($stmt);
}
else{
echo "Too many selections";
}
}
else{
echo "empty";
}
I haven't used anything but PDO for prepared in php in several years. Might be my bias but I'd recommend the switch, this seemed more complicated to me. You may need to update the portions using mysqli prepare and bind I haven't tested this code at all, just wrote it in the answer.
I also assumed each column was an integer type, and of course, update to use your table name in the query.
I added the substr() functions to remove trailing ", " from last entry of each, you could also check if $i == $count before those assignments, and use a different assignment set without the trailing ", " inside that if() with the current assignments in the following else. The $i++ would obviously be outside this if()/else.

How to pass multiple variables in foreach php

I'd like to pass multiple variables in a foreach loop to add the value from $array_sma[] into my database. But so far I can only insert the value from $short_smas, while I'd also like to insert the values from $mid_smas. I have tried nested foreach but it's multiplying the values.
$period = array(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15);
$sma = array(6,9);
foreach ($sma as $range) {
$sum = array_sum(array_slice($period, 0, $range));
$result = array($range - 1 => $sum / $range);
for ($i = $range, $n = count($period); $i != $n; ++$i) {
$result[$i] = $result[$i - 1] + ($period[$i] - $period[$i - $range]) / $range;
}
$array_sma[] = $result;
}
list($short_smas,$mid_smas)=$array_sma;
foreach ($short_smas as $short_sma) {
$sql = "INSERT INTO sma (short_sma)
VALUES ('$short_sma') ";
if ($con->query($sql) === TRUE) {
echo "New record created successfully<br><br>";
} else {
echo "Error: " . $sql . "<br>" . $con->error;
}
}
The code in my question works fine i.e. the value from the first sub array ($short_smas) of $array_sma[] gets inserted into the column short_sma of my msql database. The problem I have is when I try to insert the second sub array $mid_smas (see list()) from $array_sma[] in my second column of my database call mid_sma.
I think this is closed to what I want to achieve but still nothing gets inserted in the DB, source: php+mysql: insert a php array into mysql
I don't have any mysql syntax error.
$array_sma[] = $result;
$sql = "INSERT INTO sma (short_sma, mid_sma) VALUES ";
foreach ($array_sma as $item) {
$sql .= "('".$item[0]."','".$item[1]."'),";
}
$sql = rtrim($sql,",");
Main problem is that $short_smas and $mid_smas have different size. Moreover they are associative arrays so either you pick unique keys from both and will allow for empty values for keys that have only one value available or you pick only keys present in both arrays. Code below provides first solution.
// first lets pick unique keys from both arrays
$uniqe_keys = array_unique(array_merge(array_keys($short_smas), array_keys($mid_smas)));
// alternatively we can only pick those present in both
// $intersect_keys = array_intersect(array_keys($short_smas),array_keys($mid_smas));
// now lets build sql in loop as Marcelo Agimóvel sugested
// firs we need base command:
$sql = "INSERT INTO sma (short_sma, mid_sma) VALUES ";
// now we add value pairs to coma separated list of values to
// insert using keys from prepared keys array
foreach ($uniqe_keys as $key) {
$mid_sma = array_key_exists($key, $mid_smas)?$mid_smas[$key]:"";
$short_sma = array_key_exists($key, $short_smas)?$short_smas[$key]:"";
// here we build coma separated list of value pairs to insert
$sql .= "('$short_sma', '$mid_sma'),";
}
$sql = rtrim($sql, ",");
// with data provided in question $sql should have string:
// INSERT INTO sma (short_sma, mid_sma) VALUES, ('3.5', ''), ('4.5', ''), ('5.5', ''), ('6.5', '5'), ('7.5', '6'), ('8.5', '7'), ('9.5', '8'), ('10.5', '9'), ('11.5', '10'), ('12.5', '11')
// now we execute just one sql command
if ($con->query($sql) === TRUE) {
echo "New records created successfully<br><br>";
} else {
echo "Error: " . $sql . "<br>" . $con->error;
}
// don't forget to close connection
Marcelo Agimóvel also suggested that instead of multiple inserts like this:
INSERT INTO tbl_name (a,b,c) VALUES (1,2,3);
its better to use single:
INSERT INTO tbl_name
(a,b,c)
VALUES
(1,2,3),
(4,5,6),
(7,8,9);
That's why I append value pairs to $sql in foreach loop and execute query outside loop.
Also its worth mentioning that instead of executing straight sql its better to use prepared statements as they are less prone to sql injection.

Send only filled inputs values to database via SQL

I have dozens of inputs in an HTML table one can use to enter numerical values. When submit button is pressed all inputs values are added to their corresponding column in the SQL table via post method. Value of <input name="A1> will be sent to column A1 in SQL table, <input name="A2> to column A2, and so on.
I'm currently using something like this (but with dozens of parameters) to insert data in my table :
$sql = "INSERT INTO all_stats_table (A1, A2, A3) VALUES ($A1, $A2, $A3)";
Problem with this approach is that every input needs to be filled or it will result in an SQL error. I initially used php to set all empty inputs value to 0 before sending everything to database, but I don't think this method is the most efficient way to go.
I would rather like to dynamically check which inputs are actually filled and only send their values to the table instead of converting every empty input value to 0 and having to send everything to the database.
I've already set all default values to 0 in SQL, but I don't know how to only send filled input values via SQL. I tried using a php foreach loop but I'm definitely having trouble finding the right SQL syntax.
Is what I'm trying to do possible ? If not, what would be the best practice to make this process more efficient ?
Thank you for your help
EDIT : attempt to adapt akash raigade's great solution to non-numbered SQL columns :
HTML :
<input name='name'>
<input name='address'>
<input name='age'>
PHP :
$Field_list = array ('name','address','age');
$field_string = '';
$input_string = '';
foreach ($_POST as $userInfo=>$userInfo_value) {
if (isset($userInfo)) {
if ($field_string == '') {
$field_string = $field_string.$userInfo; //problem here ?
$input_string = $userInfo_value; //problem here ?
}
else {
$field_string = $field_string.','.$userInfo; //problem here ?
$input_string = $input_string.','.$userInfo_value; //problem here ?
}
}
}
$sql = "INSERT INTO protocole_test (".$field_string.") VALUES (".$input_string.")";
echo $sql ; //check query formed
[Upgraded version]
Basic idea is that we keep NAME attribute of INPUT same as table column-name where it is gonna be stored.Then with help of input tag name and value which are filled we prepare SQL statement which have only required (FILLED) columns and values.
For given example consider following MYSQL table :
sr.no.|name|age|gender
CODE [Tested]:
<input name="name" >
<input name="age" >
<input name="gender" >
<input type='submit'>
<?php
$field_string ='';
$input_string='';
foreach ($_POST as $userInfo=>$userInfo_value){
if($userInfo_value !=''){
echo $userInfo."->".$userInfo_value;
if ($field_string == '') {
$field_string = $field_string.$userInfo;
$input_string = $userInfo_value;
}
else {
$field_string = $field_string.','.$userInfo;
$input_string = $input_string.','.$userInfo_value;
}
}
}
$sql = "INSERT INTO protocole_test (".$field_string.") VALUES (".$input_string.")";
echo $sql ; //check query formed
?>
[original answer]Have a look at following code :
<input name='a1' id='input_for_name'>
<input name='a2' id='input_for_class'>
<input name='a3' id='input_for_seat.no'>
.
.
<input name='an' id='input_for_n'>
Now
<?php
//you must be having field list to be inserted i.e
//INSERT INTO all_stats_table >>>(A1, A2, A3)<<< VALUES ($A1, $A2, $A3)
//A1,A2,A3 is field list here
//so save them into an array.
$Field_list = array ('A1','A2','A3',.......'An');
//Now get which input_field is inputted by :
$i=0;
$field_string = '';
$input_string = '';
for($i<n){
if(isset($_POST['a'.$i])){
if ($field_string == ''){
$field_string = $field_string.$Field_list[$i];
$input_string = $_POST['a'.$i];
}
else {
$field_string = $field_string.','.$Field_list[$i];
$input_string = $input_string.','.$_POST['a'$i];
}}}
$sql = "INSERT INTO (".$field_string.") VALUES (".$input_string.")";
//to check query formed
echo $sql ;
?>
Explanation :
We check which input field is FILLED , if it is field we add its FIELD into FIELD LIST and ITS VALUE in INPUT LIST finally we GENERATE SQL STATEMENT.
Just check if they are not defined or empty, and if so, define them.
if ( (!isset($_POST['A1'])) || (empty($_POST['A1']) ){
$A1 = '0';
} else {
$A1 = $_POST['A1'];
}
I'm not able to test this and it may need some debugging, but you could create a function, then call the function for each input. Something like...
function chkinput($input){
if ( (!isset($_POST[$input])) || (empty($_POST[$input]) ){
$$input = '0';
} else {
$$input = $_POST[$input];
}
return $$input;
}
// You could potentially loop through the post array
// but here I just call the function once per input
chkinput('A1');
chkinput('A2');
...
chkinput('A12');
You loop through the $_POST array and check if it has a value. If it does concatenate it to an variable. Like this:
$fields = "";
$values = "";
foreach($_POST as $key=>$value){
if($value != ''){
if($value != end($_POST)){
$fields .= $key . ", ";
$values .= "'" . $value . "', ";
}else{
$fields .= $key;
$values .= "'" . $value . "'" ;
}
}
}
$sql = INSERT INTO protocole_test ($fields) VALUES ($values) ;
Your SQL would look like :
INSERT INTO protocole_test (A1, A2, A3) VALUES ('A1', 'A2', 'A3')

Multiple records inserting into MySql from PHP form

I think I've got a tiny mistake in my code so when I try to add two records to MySQL database it adds them both, but at the moment its only adding the second row that should be inputted. SO for example I have two RefTitle fields, two RefSurname fields and so on!
Some PHP Code:
<?php
if(empty($err)) {
for($i = 0; $i < 2; $i++)
{
$RefTitle = $_POST['RefTitle'][$i];
$RefSurname = $_POST['RefSurname'][$i];
$RefForenames = $_POST['RefForenames'][$i];
$RefInstitute = $_POST['RefInstitute'][$i];
$RefEmail = $_POST['RefEmail'][$i];
$RefTelephone = $_POST['RefTelephone'][$i];
$EmailOK = $_POST['EmailOK'][$i];
$sql_insert = "INSERT into `referees`
(`RefTitle`,`RefSurname`,`RefForenames`,`RefInstitute`, `RefEmail`,
`RefTelephone`,`EmailOK`)
VALUES
('$RefTitle','$RefSurname','$RefForenames','$RefInstitute','$RefEmail',
'$RefTelephone','$EmailOK'
)
"; ?>
I have the [] after each name field in my html form.
Thanks
Here's what I think is happening.
In the loop, you're adding the current query to a string, overwriting the previous query. After the loop ends, you run mysql_query but this will only run on the last query generated by the loop.
You have two ways to fix this:
Execute the query within the loop on every iteration. Pseudo code:
for ($i = 1 to 100)
{
$query = //build your query;
mysql_query($query);
}
Alternatively, (and the better way) is to use a value list in your insert statement.
An insert with a list of values looks like this
INSERT INTO table VALUES (1,2,3), (4,5,6), (7,8,9)
So, (pseudo code again)
$query = "INSERT INTO table VALUES ";
for ($i = 1 to 100)
{
$query .= " (";
$query .= "" //comma seperate the values of the current iteration
$query .= "),";
}
//after loop ends, remove the trailing extraneous comma
// execute the entire query at once
mysql_query($query);

MySQL INSERT - Using a for() loop with query & do non-set values insert as "" by default?

I have two arrays with anywhere from 1 to 5 set values. I want to insert these values into a table with two columns.
Here's my current query, given to me in another SO question:
INSERT INTO table_name (country, redirect)
VALUES ('$country[1]', '$redirect[1]'),
('$country[2]', '$redirect[2]'),
('$country[3]', '$redirect[3]'),
('$country[4]', '$redirect[4]'),
('$country[5]', '$redirect[5]')
ON DUPLICATE KEY UPDATE redirect=VALUES(redirect)
I'm a little concerned however with what happens if some of these array values aren't set, as I believe the above assumes there's 5 sets of values (10 values in total), which definitely isn't certain. If a value is null/0 does it automatically skip it?
Would something like this work better, would it be a lot more taxing on resources?
for($i = 0, $size = $sizeof($country); $i <= size; $i++) {
$query = "INSERT INTO table_name (country, redirect) VALUES ('$country[$i]', '$redirect[$i]) ON DUPLICATE KEY UPDATE redirect='$redirect[$i]'";
$result = mysql_query($query);
}
Questions highlighted in bold ;). Any answers would be very much appreciated :) :)!!
Do something like this:
$vals = array()
foreach($country as $key => $country_val) {
if (empty($country_val) || empty($redirect[$key])) {
continue;
}
$vals[] = "('" . mysql_real_escape_string($country_val) . "','" . mysql_real_escape_string($redirect[$key]) . "')";
}
$val_string = implode(',', $vals);
$sql = "INSERT INTO .... VALUES $val_string";
That'll built up the values section dynamically, skipping any that aren't set. Note, however, that there is a length limit to mysql query strings, set by the max_allowed_packet setting. If you're building a "huge" query, you'll have to split it into multiple smaller ones if it exceeds this limit.
If you are asking whether php will automatically skip inserting your values into the query if it is null or 0, the answer is no. Why dont you loop through the countries, if they have a matching redirect then include that portion of the insert statement.. something like this: (not tested, just showing an example). It's one query, all values. You can also incorporate some checking or default to null if they do not exist.
$query = "INSERT INTO table_name (country, redirect) VALUES ";
for($i = 0, $size = $sizeof($country); $i <= size; $i++) {
if(array_key_exists($i, $country && array_key_exists($i, $redirect)
if($i + 1 != $size){
$query .= "('".$country[$i]."', '".$redirect[$i]).",";
} else $query .= "('".$country[$i]."', '".$redirect[$i].")";
}
}
$query .= " ON DUPLICATE KEY UPDATE redirect=VALUES(redirect);"
$result = mysql_query($query);

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