yesterday i asked a question that how to select specific word from string which is having # sign with it.
someone told me this solution
$abc = "hello #john what are you doing";
$found = preg_match('/#([^-\s]*)/', $abc, $matches);
$name = null;
if ($found) {
$name = $matches[1];
}
it works like a charm but the problem is it only select first word with # sign if the string have alot of words like that. so now i need a loop which selects all the words in string which are having # sign with them.
Use can use preg_match_all to get all matches of your regular expression, not just the first one.
$abc = "hello #john what on earth are #stella and #steve doing";
$found = preg_match_all('/#([^-\s]*)/', $abc, $matches);
if ($found) {
foreach ($matches[1] as $name) {
echo "Name: $name", PHP_EOL;
}
}
Output:
Name: john
Name: stella
Name: steve
Related
I receive a string like this:
class1 fa-dollar class2 class3
Now, i need to check this string for a string/word containing fa-*. How can I manage that with PHP?
Wordwise as code
if(custom_strpos($myReceivedString, 'fa-')) {
echo $faStringOnly;
// output: 'fa-dollar'
}
Thanks in advance.
Let's start with two code examples:
$example = "class1 fa-dollar class2 class3";
if (preg_match_all('/(fa-\w+)/', $example, $matches)) {
foreach ($matches[0] as $match) {
print $match . "\n";
}
}
$moreThan1 = "class1 fa-dollar class2 fa-other class3";
if (preg_match_all('/(fa-\w+)/', $example, $matches)) {
foreach ($matches[0] as $match) {
print $match . "\n";
}
}
First example is your example. We're using preg_match_all to match all instances. In your example, there is only one. The regular expression match is /fa-\w+/ which says "this match begins with fa- and then has 1 or more word-based characters. (I made this assumption based on fa-dollar which I'm assuming are classes from Font Awesome.
The found matches are put into $matches and the exmaple code shows how you can loop through them.
To show that this works with more than one match, you can see the second example.
I would like to find part of a string and if true I want to ouput the whole of the string that it finds.
Below is an example:
$Towns = "Eccleston, Aberdeen, Glasgow";
$Find = "Eccle";
if(strstr($Find, $Towns)){
echo outputWholeString($Find, $Towns); // Result: Eccleston.
}
If anyone can shed some light on how to do this as well, and bare in mind that it will not be static values; the $Towns and $Find variables will be dynamically assigned on my live script.
Use explode() and strpos() as
$Towns = "Eccleston, Aberdeen, Glasgow";
$data=explode(",",$Towns);//
$Find = "Eccle";
foreach ($data as $town)
if (strpos($town, $Find) !== false) {
echo $town;
}
DEMO
You have to use strpos() to search for a string inside another one:
if( strpos($Towns, $Find) === false ) {
echo $Towns;
}
Note that you have to use "===" to know if strpos() returned false or 0.
The solution using preg_match function:
$Towns = "Eccleston, Aberdeen, Glasgow";
$Find = "Eccle";
preg_match("/\b\w*?$Find\w*?\b/", $Towns, $match);
$result = (!empty($match))? $match[0] : "";
print_r($result); // "Eccleston"
Assuming that you will always have $Towns separated by ", " then you could do something like this
$Towns = "Eccleston, Aberdeen, Glasgow";
$Find = "Eccle";
$TownsArray = explode(", ", $Towns);
foreach($TownsArray as $Town)
{
if(stristr($Find, $Town))
{
echo $Town; break;
}
}
The above code will output the Town once it finds the needle and exit the foreach loop. You could remove the "break;" to continue letting the script run to see if it finds more results.
Using preg_match(), it is possible to search for Eccle and return the Eccleston word.
I use the Pearl Compatible Regular Expression (PCRE) '#\w*' . $Find . '\w*#' in the code below and the demo code.
The # characters are PCRE delimiters. The pattern searched is inside these delimiters. Some people prefer / as delimiter.
The \w indicates word characters.
The * indicates 0 or more repetions of the previous character.
So, the #\w*Eccle\w*# PCRE searches for an string containing Eccle surrounded by one or more word characters (letters)
<?php
$Towns = "Eccleston, Aberdeen, Glasgow";
$Find = "Eccle";
if (preg_match('#\w*' . $Find . '\w*#', $Towns, $matches)) {
print_r($matches[0]);
}
?>
Running code: http://sandbox.onlinephpfunctions.com/code/4e4026cbbd93deaf8fef0365a7bc6cf6eacc2014
Note: '#\w*' . $Find . '\w*#' is the same as "#\w*$Find\w*#" (note the surrounding single or double quotes). See this.
You were nearly there...
This is probably what you are looking for:
<?php
$Towns = "Eccleston, Aberdeen, Glasgow";
$Find = "Eccle";
if(stripos($Towns, $Find)) {
echo $Towns;
}
The output is: Eccleston, Aberdeen, Glasgow which is what I would call "the whole string".
If however you only want to output that partly matched part of "the whole string", then take a look at that example:
<?php
$Towns = "Eccleston, Aberdeen, Glasgow";
$Find = "Eccle";
foreach (explode(',', $Towns) as $Town) {
if(stripos($Town, $Find)) {
echo trim($Town);
}
}
The output of that obviously is: Eccleston...
Two general remarks:
the strpos() / stripos() functions are better suited here, since they return only a position instead of the whole matched string which is enough for the given purpose.
the usage of stripos() instead of strpos() performs a case insensitive search, which probably makes sense for the task...
my challange explained on the following example: The keyword combination "gaming notebook" is given.
I want to check whether the two keywords occur in a string. The challange is that the string could look like this:
"Nice Gaming Notebook"
"Notebook for Gaming"
"Notebook for extreme Gaming"
I want my function to return true for all of the three strings. There is a tolerance of 3-4 words that can be between the word combination and as the examples show, I want it to work if the keywords are switched.
So my approach was the following, but it does not seem to work:
$keyword = strtolower("gaming notebook");
$parts = explode(" ", $keyword);
$string = strtolower("Which notebook for good gaming performance");
//point to end of the array
end($parts);
//fetch key of the last element of the array.
$lastElementKey = key($parts);
//iterate the array
$searchExpression = "";
foreach($parts as $k => $v) {
if($k != $lastElementKey) {
$searchExpression .= $v . "|";
} else {
$searchExpression .= $v;
}
}
if(preg_match_all('#\b('. $searchExpression .')\b#', $string, $matches) > 0) {
echo "Jep, keyword combination is in string";
} else {
echo "No, keyword combination is not in string";
}
You want to use something like CMU Sphinx or a natural language index in your database. (See http://dev.mysql.com/doc/refman/5.7/en/fulltext-natural-language.html) Doing a quick search of php libraries turned up "nlp-tools/nlp-tools," however, I have never used a pure php solution to accomplish what you are trying to do.
The solution using preg_match_all and array_intersect functions:
$keywordStr = "gaming notebook";
$string = "Which notebook for good gaming performance,it's my notebook";
$keywords = explode(" ", $keywordStr);
$parts = implode("|", $keywords);
preg_match_all("/\b$parts\b/i", $string, $matches);
// matched items should contain all needed keywords
if (count($keywords) == count(array_intersect($keywords, $matches[0]))) {
echo "Jep, keyword combination is in string";
} else {
echo "No, keyword combination is not in string";
}
<?php
$keyword = strtolower("gaming notebook");
$string = strtolower("Which notebooks for good gaming performance");
function check($keyword,$string){
$parts = explode(' ',$keyword);
$result = false;
$pattern = implode('|',$parts);
preg_match_all("(\b{$pattern}\b)",$string,$matches);
if(isset($matches[0])){
return true;
}
return false;
}
var_dump(check($keyword, $string));
$reg = "/(?:\b$kw1(?:\s+\w+){0,4}\s+$kw2\b)|(?:\b$kw2(?:\s+\w+){0,4}\s+$kw1\b)/";
if (preg_match($reg, $string)) {
echo "OK\n";
} else {
echo "KO\n";
}
This will echo OK when the 2 keywords occur in the string, in any order and separated by at most 4 words.
Explanation:
/
(?: : non capture group
\b$kw1 : keyword 1
(?:\s+\w+){0,4} : followed by 0 to 4 other word
\s+ : space(s)
$kw2\b : keyword 2
)
|
(?: : non capture group
\b$kw2 : keyword 2
(?:\s+\w+){0,4} : followed by 0 to 4 other word
\s+ : space(s)
$kw1\b : keyword 1
)
/
I have some problems with the preg_replace.
I would change the mentions in a links but the name isn't a username.
So in the name there are spaces, i found a good solution but i don't know to do it.
Sostantially i would that preg_replace the words that are between # and ,
For example:
#John Doeh, #Jenna Diamond, #Sir Duck Norman
and replace to
VAL
How do I do it?
I think that you want it like:
John Doeh
For this try:
$myString="#John Doeh, #Jenna Diamond, #Sir Duck Norman";
foreach(explode(',',$myString) as $str)
{
if (preg_match("/\\s/", $str)) {
$val=str_replace("#","",trim($str));
echo "<a href='user.php?name=".$val."'>".$val."</a>";
// there are spaces
}
}
Based on my assumption you want to remove strings which start with #Some Name, in a text like: #Some Name, this is a message.
Then replace that to an href, like: First_Name
If that is the case then the following regex will do:
$str = '#First_Name, say something';
echo preg_replace ( '/#([[:alnum:]\-_ ]+),.*/', '$1', $str );
Will output:
First_Name
I also added support for numbers, underscores and dashes. Are those valid in a name aswell? Any other characters that are valid in a #User Name? Those are things that are important to know.
Two methods:
<?php
// preg_replace method
$string = '#John Doeh, #Jenna Diamond, #Sir Duck Norman';
$result = preg_replace('/#([\w\s]+),?/', '$1', $string);
echo $result . "<br>\n";
// explode method
$arr = explode(',', $string);
$result2 = '';
foreach($arr as $name){
$name = trim($name, '# ');
$result2 .= ''.$name.' ';
}
echo $result2;
?>
I'm sure someone already asked this question, but after searching for more than 1 hour on google, I decided to ask my question here.
I want to itterate over an array excisting of different strings/texts.
These texts contain strings with both ##valuetoreplace## and #valuetoreplace#
I want to make to preg_matches:
$pattern = '/^#{1}+(\w+)+#{1}$/';
if(preg_match($pattern, $value, $matches, PREG_OFFSET_CAPTURE))
{
// do something with the #values#
}
AND
$pattern = '/^#{2}+(\w+)+#{2}$/';
if(preg_match($pattern, $value, $matches, PREG_OFFSET_CAPTURE))
{
//do something with the ##value##
}
This works great.
Now my only problem is as follows:
When i have a string like
$valueToMatch = 'proceding text #value#';
My preg_match cant find my value anymore (as i used a ^ and a $).
Question: how can i find the #value# and the ##value##, without having to worry if these words are in the middle of a (multi-line) value?
*In addition:
What i want is to find patterns and replace the #value# with a db value and a ##value## with a array value.
For example:
$thingsToReplace = 'Hello #firstname# #lastname#,
How nice you joined ##namewebsite##.';
should be
'Hello John Doe,
How nice you joined example.com.'
Try this: /##([^#]+)##/ and /#([^#]+)#/, in that order.
Maybe nice to know for other visitors how i did it:
foreach($personalizeThis as $key => $value)
{
//Replace ##values##
$patternIniData = '/#{2}+(\w+)#{2}/';
$return = 'website'; //testdata
$replacedIniData[$key] = preg_replace($patternIniData, $return, $value);
//Replace #values#
$pattern = '/#{1}+(\w+)#{1}/';
$return = 'ASD'; //testdata
$replacedDbData[$key] = preg_replace($pattern, $return, $replacedIniData[$key]);
}
return $replacedDbData;