MY PHP doesn't update data. Here is my code:
<html>
<body>
<meta charset="utf-8">
<title>სატელეფონო ცნობარი</title>
<?php
include('connection.php');
if(isset($_GET['id'])) {
$id=$_GET['id'];
if(isset($_POST['submit'])) {
$tarigi=$_POST['addedon'];
$teleponi2=$_POST['tel2'];
$teleponi3=$_POST['tel3'];
$departamenti2=$_POST['department2'];
$departamenti3=$_POST['department3'];
$web=$_POST ['url'];
$email=$_POST['email'];
$address=$_POST['address'];
$comment=$_POST['comment'];
$query3=mysql_query("update phonebook set addedon='$tarigi', tel2='$teleponi2',tel3='$teleponi3', department2='$departamenti2' , department3='$departamenti3' url='$web', email='$email', address='$address', comment='$comment' where id=$id");
if($query3) {
header('location:listcnobari.php');
}
}
$query1=mysql_query("select * from phonebook where id='$id'");
$query2=mysql_fetch_array($query1);
?>
<fieldset style="width:325px;">
<form method="post" action="">
დამატების თარიღი:<input type="text" name="addedon" value="<?php echo $query2['addedon']; ?>" /><br />
ტელეფონი2:<input type="text" name="tel2" value="<?php echo $query2['tel2']; ?>" /><br />
ტელეფონი3:<input type="text" name="tel3" value="<?php echo $query2['tel3']; ?>" /><br>
დეპარტამენტი2:<input type="text" name="department2" value="<?php echo $query2['department2']; ?>" /><br />
დეპარტამენტი3:<input type="text" name="department3" value="<?php echo $query2['department3']; ?>" /><br />
ვებ.გვერდი:<input type="text" name="url" value="<?php echo $query2['url']; ?>" /><br />
ელ.ფოსტა:<input type="text" name="email" value="<?php echo $query2['email']; ?>" /><br />
მისამართი:<input type="text" name="address" value="<?php echo $query2['address']; ?>" /><br />
კომენტარი:<input type="text" name="comment" value="<?php echo $query2['comment']; ?>" /><br />
<input type="submit" name="submit" value="Update" />
</form>
<?php
}
?>
</body>
</html>
Change your query to
$query3=mysql_query("update phonebook set addedon='$tarigi', tel2='$teleponi2',
tel3='$teleponi3', department2='$departamenti2' , department3='$departamenti3', url='$web', email='$email',
address='$address', comment='$comment' where id=$id");
You missed a comma
department3='$departamenti3' url='$web'
You missed a comma.
change
department3='$departamenti3' url='$web'
to
department3='$departamenti3', url='$web'
Related
I am having trouble updating my database data. I put the data that I want to update but when I click on the "Update" button it does
nothing. I have called the file on another php file by using Update
It also shows this error
Notice: Undefined variable: fname in
C:\xampp\htdocs\project\change1.php on line 71
Can someone help me figure this issue, please?
<?php include("config.php"); ?>
<?php
if (isset($_GET['edit'])) {
$update = true;
$record = mysqli_query($con, "SELECT * FROM employee WHERE id='".$_GET['edit']."'");
$row = mysqli_fetch_array($record,MYSQLI_BOTH);
}
if (isset($_POST['update'])) {
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$password = $_POST['password'];
$addr = $_POST['addr'];
$phone = $_POST['phone'];
$id=$_GET['edit'];
$query = "UPDATE employee SET fname='".$fname."',lname='".$lname."',password='".$password."',addr='".$addr."',phone='".$phone."' WHERE id='".$id."'";
$result = mysqli_query($con,$query) or die ("problem inserting new record into database");
if($result){
header('location: show_db.php');
}
else {echo "Update not successful"; }
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Update Data</title>
</head>
<body>
Home
<br/><br/>
<input type="hidden" name="id" value="<?php echo $id; ?>">
Name:<input type="text" name="fname" value="<?php echo $fname ; ?>">
Surname:<input type="text" name="lname" value="<?php echo $lname; ?>">
Password:<input type="text" name="password" value="<?php echo $password; ?>">
Address:<input type="text" name="addr" value="<?php echo $addr; ?>">
Contact:<input type="text" name="phone" value="<?php echo $phone; ?>">
<input type="submit" name="update" value="Update">
</body>
</html>
Put the html inputs inside a form
<form name ="form1" method ="get" action="">
<input type="hidden" name="id" value="<?php echo $id; ?>">
Name:<input type="text" name="fname" value="<?php echo $fname ; ?>">
Surname:<input type="text" name="lname" value="<?php echo $lname; ?>">
Password:<input type="text" name="password" value="<?php echo $password; ?>">
Address:<input type="text" name="addr" value="<?php echo $addr; ?>">
Contact:<input type="text" name="phone" value="<?php echo $phone; ?>">
<input type="submit" name="update" value="Update">
</form>
Using php, i created an edit option that basically lets u change the data in the record. However, after clicking on submit, the data doesn't get saved on the table nor do i get any errors.. I am quite confused. Here r my codes:
<html>
<body>
<?php
include('db.php');
if (isset($_GET['Id'])) {
$Id=$_GET['Id'];
if (isset($_POST['submit'])) {
$Fname=$_POST['Fname'];
$Lname=$_POST['Lname'];
$Age=$_POST['Age'];
$Nationality=$_POST['Nationality'];
$PhoneNumber=$_POST['PhoneNumber'];
$Email=$_POST['Email'];
$query3=mysql_query("UPDATE `students` SET `Fname`='$Fname',`Lname`='$Lname',`Age`='$Age',`Nationality`='$Nationality',`PhoneNumber`='$PhoneNumber',`Email`='$Email' WHERE `Id`='$Id'");
if($query3) {
header('location:index1.php');
}
}
$query1=mysql_query("select * from students where Id='$Id'");
$query2=mysql_fetch_array($query1);
?>
<form method="post" action="">
First Name:<input type="text" name="name" value="<?php echo $query2['Fname']; ?>" /><br />
Last Name:<input type="text" name="name" value="<?php echo $query2['Lname']; ?>" /><br />
Age:<input type="text" name="age" value="<?php echo $query2['Age']; ?>" /><br />
Nationality:<input type="text" name="name" value="<?php echo $query2['Nationality']; ?>" /><br />
Phone Number:<input type="text" name="name" value="<?php echo $query2['PhoneNumber']; ?>" /><br />
Email:<input type="text" name="name" value="<?php echo $query2['Email']; ?>" /><br />
<br />
<input type="submit" name="submit" value="update" />
</form>
<?php
}
?>
</body>
</html>
I have a form which displays a blank page.The form details doesnt appear. It is a blank page. The form as to diplay the details such as membership no, month date, amount. But it is a blank page with no details displayed What is the problem with the code.
<?php
$username = "root";
$password = "";
$hostname = "localhost";
$db = "anthonys";
//connection to the database
$dbhandle = mysql_connect($hostname, $username, $password) or die("Unable to connect to MySQL");
mysql_select_db($db,$dbhandle) or die('cannot select db');
if(isset($_POST['update'])){
$uid=$_REQUEST['uid'];
$month=$_REQUEST['month'];
$date=$_POST['date'];
$amount=$_POST['amount'];
mysql_query("UPDATE payment SET uid='$uid',month ='$month', date='$date', amount='$amount' WHERE uid='$uid' and month='$month'") or die(mysql_error());
echo "<script>alert('Record Updated!!')</script>";
$myData= mysql_query("SELECT * FROM payment where uid='$uid' and month='$month'")or die(mysql_error());
while($record = mysql_fetch_assoc($myData))
{
?>
<section id="sheet" style="background-color: Transparent;">
<div id="content_inner">
<div id="col2">
<h2>PAYMENT RECEIPT</h2><br /><br />
<table border="0px" style="border-collapse:collapse; width:810px;" align="center">
<tr>
<td>
<form name="XIForm" id="XIForm" method="post" action="modifypay3.php">
<span style="float:right; width:500px;margin-top:-55px;">
<label type="text" name="uid" maxlength="50" size="30" class="label" >Membership No</label><br />
<input type="text" name="uid" value="<?php echo $record['uid'];?>"readonly><br /><br /></span>
<label type="text" name="month" maxlength="50" size="30" class="label">Month</label><br />
<input type="text" name="month" class="input" size="40" value="<?php echo $record['month']; ?>"> <br /><br />
<label type="text" name="date" maxlength="50" size="30" class="label">Date</label><br />
<input type="text" name="date" class="input" style="width:370px;" value="<?php echo $record['date']; ?>"><br /><br />
<label type="text" name="amount" maxlength="50" size="30" class="label">Amount Paid</label><br />
<input type="text" name="amount" class="input" size="39" value="<?php echo $record['amount']; ?>"> <br /><br />
<input type=hidden name=hidden value="<?php echo $record['uid'];?>"><br/><br/>
<input type="submit" name="submit" value="UPDATE" class="button" />
</form>
<?php }?>
<?php }?>
</body>
</html>
It's more secure to use PDO except mysql_connect.
The form is print only when you POST the form.
Please use below code and test, if you want this.
<?php
$username = "root";
$password = "";
$hostname = "localhost";
$db = "anthonys";
//connection to the database
$dbhandle = mysql_connect($hostname, $username, $password) or die("Unable to connect to MySQL");
mysql_select_db($db,$dbhandle) or die('cannot select db');
if(isset($_POST['submit'])){
$uid=$_REQUEST['uid'];
$month=$_REQUEST['month'];
$date=$_POST['date'];
$amount=$_POST['amount'];
mysql_query("UPDATE payment SET uid='$uid',month ='$month', date='$date', amount='$amount' WHERE uid='$uid' and month='$month'") or die(mysql_error());
echo "<script>alert('Record Updated!!')</script>";
};
$myData= mysql_query("SELECT * FROM payment where uid='$uid' and month='$month'")or die(mysql_error());
while($record = mysql_fetch_assoc($myData))
{?>
<section id="sheet" style="background-color: Transparent;">
<div id="content_inner">
<div id="col2">
<h2>PAYMENT RECEIPT</h2><br /><br />
<table border="0px" style="border-collapse:collapse; width:810px;" align="center">
<tr>
<td>
<form name="XIForm" id="XIForm" method="post" action="modifypay3.php">
<span style="float:right; width:500px;margin-top:-55px;">
<label type="text" name="uid" maxlength="50" size="30" class="label" >Membership No</label><br />
<input type="text" name="uid" value="<?php echo $record['uid'];?>"readonly><br /><br /></span>
<label type="text" name="month" maxlength="50" size="30" class="label">Month</label><br />
<input type="text" name="month" class="input" size="40" value="<?php echo $record['month']; ?>"> <br /><br />
<label type="text" name="date" maxlength="50" size="30" class="label">Date</label><br />
<input type="text" name="date" class="input" style="width:370px;" value="<?php echo $record['date']; ?>"><br /><br />
<label type="text" name="amount" maxlength="50" size="30" class="label">Amount Paid</label><br />
<input type="text" name="amount" class="input" size="39" value="<?php echo $record['amount']; ?>"> <br /><br />
<input type=hidden name=hidden value="<?php echo $record['uid'];?>"><br/><br/>
<input type="submit" name="submit" value="UPDATE" class="button" />
</form>
<?php }?>
</body>
</html>
Does anyone know how to search and show data without using submit button..because thats the only function i need to finish my code..can anyone help me? I dont want to use submit button cause it refreshes the page...I have the code for search already I need a function that after I search the data will show in the textboxes without using submit button.
php code:
<?php
if($_GET){
include('include/connect.php');
$batchcode = $_GET['code'];
$sql = mysql_query("SELECT aic,batchcode,address,name FROM tb_app WHERE batchcode = '".$batchcode."' ");
if($sql) {
while($rows = mysql_fetch_array($sql)){
$aic[] = $rows['aic'];
$name[] = $rows['name'];
$address[] = $rows['address'];
}
}
}else{
$aic = array(NULL,NULL,NULL,NULL);
$name = array(NULL,NULL,NULL,NULL);
$address = array(NULL,NULL,NULL,NULL);
}
?>
html code:
<html>
<head>
<title>test</title>
</head>
<body>
<form action="" method="get">
Search Batchcode:<input type="text" name="code" id="query" /><br />
<table>
<tr>
<td>
aic: <br />
<input type="text" name="optA1" value="<?php if(empty($aic[0])){$aic[0] = array(NULL);}else{echo $aic[0];} ?>" /> <br />
<input type="text" name="optA2" value="<?php if(empty($aic[1])){$aic[1] = array(NULL);}else{echo $aic[1];} ?>" /> <br />
<input type="text" name="optA3" value="<?php if(empty($aic[2])){$aic[2] = array(NULL);}else{echo $aic[2];} ?>" /> <br />
<input type="text" name="optA4" value="<?php if(empty($aic[3])){$aic[3] = array(NULL);}else{echo $aic[3];} ?>" /> <br />
</td>
<td>
Name List: <br />
<input type="text" name="optB1" value="<?php if(empty($name[0])){$name[0] = array(NULL);}else{echo $name[0];} ?>" /> <br />
<input type="text" name="optB2" value="<?php if(empty($name[1])){$name[1] = array(NULL);}else{echo $name[1];} ?>" /> <br />
<input type="text" name="optB3" value="<?php if(empty($name[2])){$name[2] = array(NULL);}else{echo $name[2];} ?>" /> <br />
<input type="text" name="optB4" value="<?php if(empty($name[3])){$name[3] = array(NULL);}else{echo $name[3];} ?>" /> <br />
</td>
<td>
Address: <br />
<input type="text" name="optC1" value="<?php if(empty($address[0])){$address[0] = array(NULL);}else{echo $address[0];} ?>" /> <br />
<input type="text" name="optC2" value="<?php if(empty($address[1])){$address[1] = array(NULL);}else{echo $address[1];} ?>" /> <br />
<input type="text" name="optC3" value="<?php if(empty($address[2])){$address[2] = array(NULL);}else{echo $address[2];} ?>" /> <br />
<input type="text" name="optC4" value="<?php if(empty($address[3])){$address[3] = array(NULL);}else{echo $address[3];} ?>" /> <br />
</td>
</form>
</body>
</html>
script code:
<!--search function code-->
<script type="text/javascript">
$(document).ready(function(){
$("#query").autocomplete({
source : 'search.php',
select : function(event,ui){
$("#query").html(ui.item.value);
}
});
});
</script>
search.php page code:
<?php
$q = $_GET['term'];
mysql_connect("localhost","root","");
mysql_select_db("test");
$query = mysql_query("SELECT DISTINCT batchcode FROM tb_app WHERE batchcode LIKE '$q%'");
$data = array();
while($row = mysql_fetch_array($query)){
$data[]=array('value'=>$row['batchcode']);
}
echo json_encode($data);
?>
In your html you need to create a link or a simple button and give it a class or id.
Then in javascript add click event listener and perform an ajax call.
search here
And in your javascript
$( "#mysubmit" ).click(function() {
// read query field value
// Perform ajax call
});
Hope this is going to help you.
You can also do:
$( "#query" ).change(function() {
var sendMe = $.post("search.php");
sendMe.done(function(data) {
$( "#query" ).html(data);
});
});
can anyone help me find the code thats causing my code not to work? my code wont update... ive been debuging this code for 3hours already stil cant fix it :(...i need your help guys.
php code:
<?php
if(isset($_GET['gogo'])){
include('include/connect.php');
$batchcode = $_GET['code'];
$sql = mysql_query("SELECT * FROM score WHERE batchcode = '".$batchcode."' ");
if($sql) {
while($rows = mysql_fetch_array($sql)){
$id[] = $rows['id'];
$name[] = $rows['name'];
$score1[] = $rows['score1'];
$score2[] = $rows['score2'];
$other_qual[] = $rows['score3'];
$interview[] = $rows['score4'];
$total[] = $rows['total'];
}
}
}
?>
<?php
if(isset($_POST['update'])){
include('include/connect.php');
//1
$u1id = $_POST['id1'];
$u1name = $_POST['name1'];
$u1score1 = $_POST['optA1'];
$u1score2 = $_POST['optB1'];
$u1other_qual = $_POST['other_qual1'];
$u1interview = $_POST['interview1'];
$u1total = $_POST['total1'];
//2
$u2id = $_POST['id2'];
$u2name = $_POST['name2'];
$u2score1 = $_POST['optA2'];
$u2score2 = $_POST['optB2'];
$u2other_qual = $_POST['other_qual2'];
$u2interview = $_POST['interview2'];
$u2total = $_POST['total2'];
//1
mysql_query("UPDATE score SET score1='$u1score1', score2='$u1score2', total='$u1total' WHERE id='$u1id'");
//2
mysql_query("UPDATE score SET score1='$u2score1', score2='$u2score2', total='$u2total' WHERE id='$u2id'");
header("Location: index.php");
}
?>
html code:
<form method="get">
<form method="post">
Search batchcode: <input type="text" name="code" id="query" /><input type="submit" value="Go" name="gogo" /><br />
<table>
<tr>
<td>
ID: <br />
<input type="text" name="id1" value="<?php if(empty($id[0])){$id[0] = array(NULL);}else{echo $id[0];} ?>" readonly /> <br />
<input type="text" name="id2" value="<?php if(empty($id[1])){$id[1] = array(NULL);}else{echo $id[1];} ?>" readonly /> <br />
</td>
<td>
Name: <br />
<input type="text" name="name1" value="<?php if(empty($name[0])){$name[0] = array(NULL);}else{echo $name[0];} ?>" readonly /> <br />
<input type="text" name="name2" value="<?php if(empty($name[1])){$name[1] = array(NULL);}else{echo $name[1];} ?>" readonly /> <br />
</td>
<td>
Score 1: <br />
<input type="text" name="optA1" value="<?php if(empty($score1[0])){$score1[0] = array(NULL);}else{echo $score1[0];} ?>" onchange="optTotal1()" /> <br />
<input type="text" name="optA2" value="<?php if(empty($score1[1])){$score1[1] = array(NULL);}else{echo $score1[1];} ?>" onchange="optTotal2()" /> <br />
</td>
<td>
Score 2: <br />
<input type="text" name="optB1" value="<?php if(empty($score2[0])){$score2[0] = array(NULL);}else{echo $score2[0];} ?>" onchange="optTotal1()" /> <br />
<input type="text" name="optB2" value="<?php if(empty($score2[1])){$score2[1] = array(NULL);}else{echo $score2[1];} ?>" onchange="optTotal2()" /> <br />
</td>
<td>
Other Qualification: <br />
<input type="text" name="other_qual1" value="<?php if(empty($other_qual[0])){$other_qual[0] = array(NULL);}else{echo $other_qual[0];} ?>" readonly /> <br />
<input type="text" name="other_qual2" value="<?php if(empty($other_qual[1])){$other_qual[1] = array(NULL);}else{echo $other_qual[1];} ?>" readonly /> <br />
</td>
<td>
Interview: <br />
<input type="text" name="interview1" value="<?php if(empty($interview[0])){$interview[0] = array(NULL);}else{echo $interview[0];} ?>" readonly /> <br />
<input type="text" name="interview2" value="<?php if(empty($interview[1])){$interview[1] = array(NULL);}else{echo $interview[1];} ?>" readonly /> <br />
</td>
<td>
Total: <br />
<input type="text" name="total1" value="<?php if(empty($total[0])){$total[0] = array(NULL);}else{echo $total[0];} ?>" readonly onKeyUp="optTotal1()" /> <br />
<input type="text" name="total2" value="<?php if(empty($total[1])){$total[1] = array(NULL);}else{echo $total[1];} ?>" readonly onKeyUp="optTotal2()" /> <br />
</td>
</tr>
</table>
<input type="submit" value="update" name="update" />
</form>
</form>
You cannot do a GET and POST at the same time. Use one or the other..
In your HTML remove the <form method="get"> and the corresponding </form> and just use POST. (<form method="post">)
See this: Post and get at the same time in php
So then in your PHP, change GET to POST like so:
if(isset($_POST['gogo'])){
include('include/connect.php');
$batchcode = $_POST['code'];
$sql = mysql_query("SELECT * FROM score WHERE batchcode = '".$batchcode."' ");
...
EDIT:
Or alternatively, you could keep your php code the same the way you have it and just make it 2 seperate forms in your HTML,.. The search form using GET and the other form using POST
So HTML would be this:
<form method="get">
Search batchcode: <input type="text" name="code" id="query" /><input type="submit" value="Go" name="gogo" /><br />
</form>
<form method="post">
<table>
<tr>
<td>
ID: <br />
<input type="text" name="id1" value="<?php if(empty($id[0])){$id[0] = array(NULL);}else{echo $id[0];} ?>" readonly /> <br />
<input type="text" name="id2" value="<?php if(empty($id[1])){$id[1] = array(NULL);}else{echo $id[1];} ?>" readonly /> <br />
</td>...
...
</form>
If your code won't update then it is very likely you are updating the wrong files. Make sure that you are updating the files on the server or even better updating the files on your local drive and then uploading them to the server.
Check that you have permissions to upload to the correct place too. Might be that your uploads are failing because of bad permissions.