Mysql display rows as columns [duplicate] - php

Question

This question already has an answer here:
MySql Transpose Row into Column and Column into Row [duplicate]
(1 answer)
Closed 7 years ago.
I want to display rows as columns.
This is mysql table called Term
|Name ||Year ||HTML ||CSS ||Js ||
|Year1 ||2013-08-30||90 ||70 ||70 ||
|Year2 ||2014-08-30||100 ||65 ||80 ||
|Year3 ||2015-08-30||80 ||95 ||90 ||
What I want is to display as columns like this
|Subject||Year1 ||Year2 ||Year3 ||
|HTML ||90| ||100 ||80 ||
|CSS ||70| ||65 ||95 ||
|JS ||70| ||80 ||90 ||
Code
<tr>
<th>Code</th><th>Subject</th><th>year1</th>
<th>year2</th><th>year3</th>
</tr>
<?php
$query = mysql_query("SELECT * FROM term WHERE Stdid='$id'");
while ($row = mysql_fetch_assoc($query)) {
foreach($row as $key => $value) {
?>
<tr>
<th><?php echo $key ?></th>
<th><?php echo $value?></th>
<th>99</th><th>00</th>
</tr>
<?php } } } ?>
</table>
My result only works for the first year
|Subject||Year1 ||Year2 ||Year3||
|HTML ||90| ||? ||? ||
|CSS ||70| ||? ||? ||
|JS ||70| ||? ||? ||

Answer 1

You first need to transpose all data in a temporary array before you can output it again. I'll give you 2 methods to do this.
Method 1: just fetch every row and switch the row index by the column index:
<table>
<tr>
<th>Subject</th>
<th>year1</th>
<th>year2</th>
<th>year3</th>
</tr>
<?php
$mysqli = new mysqli('localhost', 'user', 'pass', 'database');
$id = 1;
$report = array();
$columnIndex = 0;
$query = $mysqli->query("SELECT HTML, CSS, Js FROM term WHERE Stdid='$id'");
while ($results = $query->fetch_assoc()) {
foreach ($results as $course => $score) {
$report[$course][$columnIndex] = $score;
}
$columnIndex++;
}
foreach ($report as $course => $results) { ?>
<tr>
<th><?php echo $course; ?></th>
<?php foreach ($results as $score) { ?>
<th><?php echo $score; ?></th>
<?php } ?>
</tr>
<?php } ?>
</table>
Method 2: Fetch all rows in an array, so it becomes an array of arrays and use array_map with callback NULL to transpose it (See example 4 at http://php.net/manual/en/function.array-map.php).
You need to add the course names in the initial array to include them in the end result.
<table>
<tr>
<th>Subject</th>
<th>year1</th>
<th>year2</th>
<th>year3</th>
</tr>
<?php
$mysqli = new mysqli('localhost', 'user', 'pass', 'database');
$id = 1;
$data = array(array('HTML', 'CSS', 'Js'));
$query = $mysqli->query("SELECT HTML, CSS, Js FROM term WHERE Stdid='$id'");
while ($row = $query->fetch_assoc())
{
$data[] = $row;
}
$data = call_user_func_array('array_map', array_merge(array(NULL), $data));
?>
<?php
foreach ($data as $row): ?>
<tr>
<?php foreach ($row as $value): ?>
<th><?php echo $value?></th>
<?php endforeach; ?>
</tr>
<?php endforeach; ?>
</table>

Answer 2

Try this.
<table width = "1093" align="center" bgcolor="pink">
<tr align="center">
<td colspan="6"><h2>View Term</h2></td>
</tr>
<tr align="center" bgcolor="">
<th>S.N</th>
<th>Subject</th>
<th>Year 1</th>
<th>Year 2</th>
<th>Year 3</th>
</tr>
<?php
$db = mysqli_connect("localhost","root","YOURPASSWORD","YOURDATABASE");
if (mysqli_connect_errno())
{
echo"The Connection was not established" . mysqli_connect_error();
exit();
}
$get_term = "SELECT * FROM term WHERE Stdid='$id'";
$run_term = mysqli_query($db,$get_term);
$i =0 ;
while ($row=mysqli_fetch_array($run_term ))
{
// Get data from database.
// Change the input in $row[''] if the name of column is different in your tble "term".
$subject=$row['subject'];
$year1=$row['year1'];
$year2=$row['year2'];
$year3=$row['year3'];
$i++;
?>
<tr align="center">
<td> <?php echo $i;?></td>
<td><?php echo $subject;?></td>
<td><?php echo $year1;?></td>
<td><?php echo $year2;?></td>
<td><?php echo $year3;?></td>
</tr>
<?php }?>
</table>