i generate link with
<a onclick="window.history.pushState('', '', '?id=<?php echo $row['id']; ?>');"
and it generated URL like this
http://localhost/dpmerzon/order.php?id=MT01
"MT01" is example id for every link i pressed
So can i get "MT01" value with (PHP) $_GET['id'] without submitting the URL ?
you have to use AJAX if you want to submit somthing in background
explaine more what you gona do may can i help you
Related
I've got a php script which builds a html table via echoing data, But i want to add a link onto one of the values and pass that value to the next page.
<td><a href='redirect.php'><?php $_SESSION['WR'] = $row['WorkOrdRef'];echo $row['WorkOrdRef'];?></a></td>
is the line in question but this will only pass the last value added to the table.
Oh, it doesnt work like this. the php code gets executed no matter if you click the link.
I guess the easiest way to do this is to pass it as a get parameter.
html page:
<?=$cellContent?>
redirect.php:
$clickedcell = $_GET['clickedcell']
now the $clickedcell will have the data from the previous page about what cell did the user click.
If you want to use session for some reason, you still have to pass it with GET or POST and store it after the user clicks.
hopefully this is understandable and good luck with your project.
you can change the session by get method also it is possible building by javascript
in the same page add this
if(isset($_GET["clicked"])){
$_SESSION['WR'] = $row['WorkOrdRef'];
$redirect'<META HTTP-EQUIV="REFRESH" CONTENT="0;URL='.$adres.'/"> ';
return $redirect;
}
and then change your url
<td><?php echo $row['WorkOrdRef'];?></td>
I am stuck in a problem and in need of support from you guys.
My problem is I want to pass a php variable(dynamically called through database in loop) to another div on the same page without page refresh
//This is a loop
<td><a class="linkright" href="#existingcase?case_id=<?php echo $row_mycases['case_id']; ?>"><?php echo $row_mycases['case_id']; ?></a></td>
//The div which should get the above php variable
<div class="tabright" id="existingcase">
<?php
$c_id = $_GET['case_id'];
echo $c_id;
?>
</div>
//the javascript code for calling divs on the same page
<script>
$(".linkright").click(function(){
$(".tabright").hide();
theDiv = $(this).attr("href");
$(theDiv).slideToggle();
});
</script>
It shows in the url like this index.php#existingcase?case_id=2012001 but never passes the case id to #existingcase. And also #existingcase div does not load either but without passing caseid value, #existingcase loads.
Any suggestions would be great.
I think you want to print clicked case_id in div without page load. To do this, you don't want to pass it using url. you can simply achieve it using javascript.
If your div id existingcase is just change your code like this below.
you are printing that same case_id as a text of anchor tag using $row_mycases['case_id'];. So, you can easily get that text using javascript and you can easily print it in your #existingcasediv.
<td><a class="linkright" href="#existingcase"><?php echo $row_mycases['case_id']; ?></a></td>
I don't know about your other scripts. in .linkright click function place this code like this
$(".linkright").click(function(){
$('#existingcase').text($(this).text()); //if your div id is existingcase it will print your case id.
});
try this code. And let me know the result.
SEE THIS FIDDLE DEMO
UPDATED:
To pass client side value to serverside without page reload, you can use jquery.post() method.
Place this PHP code at the top of your page.
<?php
if (isset($_POST['id'])) {
$caseid = $_POST['id'];
return print_r($caseid);
}
?>
$caseid will contain currently clicked case_id value. So, you can use this $caseid wherever you want in this page. If you click on the another case id, it will update with respect to currently clicked case_id
replace your js with below code,
$(".linkright").click(function () {
$(".tabright").hide();
theDiv = $(this).attr("href");
$(theDiv).slideToggle();
$.post("yourPHPFile.php", { //use your current php file name instead of "yourPHPFile.php"
id: $(this).text()
}, function (caseid) {
$('#existingcase').text(caseid);
});
});
id : $(this).text() means, get the current element .text() and assign it to $_POST variable name of id. It will post to yourPHPFile.php. And you can retrieve that value like $caseid = $_POST['id'];.
In function (caseid) {, caseid contains the value of $caseid. So, only in this code, I assigned $caseid = $_POST['id'];
By this you can directly print clicked case_id text to your #exixtingcase div.
Any values after # are not sent to the server. Since PHP is a server technology you php code will never see the values after #
<a class="linkright" href="#existingcase?case_id=<?php echo $row_mycases['case_id']; ?>">
try doing
<a class="linkright" href="existingcase?case_id=<?php echo $row_mycases['case_id']; ?>">
instead and your php code should fill the div.
In my understanding of your explanation I think you are making a mistake. You are trying to mix Javascript and PHP with out page refresh. This is not possible through your code as PHP is server side and only works on the server. You can't do href within the same page and expect PHP code inside this div to be executed. The PHP code will not be there. You can try "view source" in your browser and check it out.
I think the only way to solve your problem is to make AJAX call using Javascript, get the response and put wherever you want (without refreshing the page)
Hope this helps and excuse my English
EDIT : Here is a working example for making a simple AJAX call using Jquery.
Your table should be some thing like this:
<td>
<a class="linkright" href="#" data-id="<?php echo $row_mycases['case_id']; ?>"><?php echo $row_mycases['case_id']; ?></a>
</td>
You will notice I added "data-id" attribute. We will use this id in our AJAX call. Put this in your JS :
// Create Jquery ajax request
$("a.linkright").click( function() {
$.get("example.php", // Put your php page here
{ case_id : $(this).attr("data-id") }, // Get data, taken from the a tag
function(data) { // Call back function displays the response
$(".tabright").html("<p>" + data + "</p>");
}); // Get
}); // click event
}); // Document Ready
I tested the code and it is working. You will need to customize it to work for you. If all of this AJAX is new to you I suggest these links for you :
http://www.w3schools.com/ajax/default.ASP
http://learn.jquery.com/ajax/
I have used a form to submit an image id to the another page. I have done this rather than r than via url because it makes the url cleaner. However, when the user now reloads, it asks if they want to submit the form again. The won't know they have submitted a form, as far as they are aware they have simply clicked an image and been brought to a page that displays that image bigger.
Is there any way around this, that saves the image id the hidden form field has sent via the form, yet refreshes the page for the user?
HTML
<a class="gallery-img span4 js-img-submit" href="#">
<img src="img.jpg"/>
<form action="/image" method="post">
<input type="hidden" value="<?=$img['id']; ?>" name="image_id"/>
</form>
</a>
JQUERY
$('.js-img-submit').click(function(){
$(this).find('form').submit();
})
PHP
$image_id = isset($_POST['image_id']) ? $_POST['image_id'] : false;
Somehow the parameter needs to be send to the image page.
GET: You dont want that.
POST: You use that, but causes the refresh problem.
SESSION: Will be hidden, but cause troubles, when he opens multiple images, and then refreshing the first page.
So, i would to the following:
Use the hashtag, and load the image via javascript then. finally remove the hashtag:
MainPage:
<a class="gallery-img span4 js-img-submit" href="/image#<?=$img['id']; ?>">
<img src="img.jpg"/>
</a>
ImagePage:
<script language="javascript">
$(document).ready(function(){
var imgid = document.location.hash.slice(1);
document.location.hash = ""; //Remove
loadImage(imgid);
})
</script>
loadImage then needs to be the required javascript function.
The user might notice it for a split second. IF the user is not allowed to see, then your only way would be to use the PHP Session with seperate variables for every opened image-window.
You can do something like this:
$('.js-img-submit').click(function()
{
$.post("image.php", {id: $(this).find('input').val()});
})
On my website, I have a button which when clicked displays a feedback form in a popup window.
I need to pass the url in the PARENT window to a hidden field in the feedback form.
I tried:
<?php $url="http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']; ?>
<input type="hidden" id="addressBar" name="addressBar" value= "<?php echo $url ?>"/>
The problem with the above code is that it passes the url of the current window, in my case, the url of the feedback popup window.
How do I pass the url of the parent window to that hidden field?
Many thanks for your help
You can try $_SERVER['HTTP_REFERER'] instead of REQUEST_URI (it gives you current uri)
but keep in mind that it's not reliable...
$url = isset($_SERVER['HTTP_REFERER']) ? $_SERVER['HTTP_REFERER'] : 'some_default_page.php';
Another way could be something like this ...
$cur_page_url = "http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI'];
echo 'Feedback';
and then in popup.php just check if ref query string is set and retrieve its value.
So there's this hyperlink - it's happy being a hyperlink - it does not want to change to a button or a form element - it wants to stay a link!
But it would really help me if I could submit it via GET or POST (something which I switch on my pages due to design criteria). Is there ANY way that I can do this
thanks
Giles
You're in luck... clicking a hyperlink already does a GET request.
If you want to add query parameters, append them to the query string like so:
link text
Assuming you already have a form that you want to submit, you can use JavaScript to make the link submit the form:
<form id="myform">
...
</form>
Submit
As you do not want to go for form elements, there is no need of using POST method.
Simply, what you can do is:
Link
And in the page_location page,
<?php
$foo = $_GET['foo']; //here, assigns $foo = bar
// required actions
?>
Hope you get the solution! :)
I'll assume you're not really using the link as a link... that you want to submit a form with it. You'll want to keep the link inside the form you want to submit, and you can do this (jQuery):
$('#link').parents('form').attr('method', 'GET').submit();
or
$('#link').parents('form').attr('method', 'POST').submit();