if($this->db->insert(table,$insert_array))
{?>
<script type="text/javascript">
$(function() {
$('#div1').show().delay(15000).fadeOut('fast');
})
</script>
<?php
}
I want to call this function $('#div1').show().delay(15000).fadeOut('fast'); if my if statement is true. Kindly help
Try like that:
if($this->db->insert(TBL_CAR,$insert_sql_array))
{?>
<script type="text/javascript">
$(function() {
$('#div1').show().delay(15000).fadeOut('fast');
})
</script>
<? } ?>
I will advise you write something like this:
<?php if($this->db->insert(TBL_CAR,$insert_sql_array)) :?>
<script type="text/javascript">
$(function() {
$('#div1').show().delay(15000).fadeOut('fast');
})
</script>
<?php endif ;?>
This should work perfectly well for you. I have implemented something of such on several ocassion
Try this
<?php
if($this->db->insert(TBL_CAR,$insert_sql_array)) {
?>
<script type="text/javascript">
jQuery('#div1').show().delay(15000).fadeOut('fast');
</script>
<?php
}
?>
Related
I am trying below code to load html content to jquery variable.
<html>
<body>
<div id="static-content"></div>
<?php
$static_content = file_get_contents('cms/content.php');
?>
<script>
$(document).ready(function($){
var static_content = '<?php echo $static_content; ?>';
$('#static-content').load(static_content);
});
</script>
</body>
</html>
I am reading the html from content.php and try to append to div.
Its not working for me. Can anyone please suggest me how to achieve this. Thanks
Try this ajax load concept. Link
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="static-content"> </div>
<script>
$(document).ready(function($) {
$('#static-content').load("content.php");
});
Please try this
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
</head>
<body>
<div id="static-content"></div>
<?php
$myfile = fopen("content.php", "r") or die("Unable to open file!");
$content = fread($myfile,filesize("content.php"));
fclose($myfile);
?>
<script>
$(document).ready(function($){
var static_content = '<?php echo $content; ?>';
console.log('htmltext ',static_content);
$('#static-content').html(static_content);
});
</script>
</body>
</html>
i want to send Get when the link clicked to receive the result in php code
and this what happened
this in php file working perfect
<html>
<a class="cc" href="#">click me</a>
<script src="js/jquery.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$(".cc").click(function () {
$(".body").load('page.php ')
})});
</script>
<section class="body"></section>
</html>
but when i put GET to the href didn't work just Flashing content
<html>
<a class="cc" href="?id=1">click me</a>
<script src="js/jquery.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$(".cc").click(function () {
$(".body").load('page.php ')
})});
</script>
<section class="body"></section>
</html>
In the second case, you really need to stop the <a> from following the link.
$(document).ready(function() {
$(".cc").click(function(e) {
e.preventDefault();
$(".body").load('page.php');
});
});
How to add jQuery function in PHP function File?
Example :
<script type="text/javascript" src="assets/js/jquery.min.js"></script>
<script type="text/javascript" src="assets/js/jquery.livequery.js"></script>
<script type="text/javascript" src="assets/js/jquery.timeago.js"></script>
<?php
class db{
public $db;
function get_news()
{
bla bla
}
}
When run the code, the jQuery is not working. Please help.
Thank you
You can't run jQuery function in PHP. You can run them from HTML. First close php:
?>
<script>
function get_news() { blabla; }
</script>
<?php
If this is not what you're looking for then there is no way for you to do what you're looking for.
This is a sample code,
<script type="text/javascript" src="assets/js/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
alert("Test");
});
</script>
<?php
echo "PHP code here";
?>
You can Echo jQuery function call to run it
<?php
echo "<script type=\"text/javascript\">
$(document).ready(function() {
alert(\"Test\");
});
</script>";
?>
I want to send id to php script.I think my code is ok, but when i click on tag i get this error:
Notice: Undefined index: id in C:\xampp\htdocs\domaci\cao.php on line 4
here is my html + ajax code :
<html>
<head>
<script type="text/javascript" src="jquery-1.11.1.js"></script>
<script type="text/javascript" language="javascript">
$(document).ready(function(){
$('a').click(function(){
$.post($(this).attr('href'), { id : $(this).attr('id') } );
});
});
</script>
</head>
<body>
<a href="cao.php" id="Barselona" >Barselona</a>
</br>
<a href="cao.php" id="Beograd" >Beograd</a>
</body>
</html>
and this is cao.php:
<html>
<body>
<?php
$id = $_POST['id'];
echo $id;
?>
</body>
</html>
i really need this to get to work, please help me :)
Your $.post ajax is fine. The issue is when the anchor is clicked, you don't preventDefault or return false, to stop the browser redirecting to cao.php. When it redirects to cao.php, it is a GET request, and so triggers the undefined index notice because there is no post data.
Add return false or preventDefault:
$('a').click(function(e){
e.preventDefault();
$.post($(this).attr('href'), { id : $(this).attr('id') } );
});
Look at your browser's console (F12) on the Network tab, to see the response of the ajax.
Try it now.
$(document).ready(function(){
$('a').click(function(){
$.post($(this).attr('data-url'), { id : $(this).attr('id') } );
});
});
</script>
</head>
<body>
<a href="#" data-url="cao.php" id="Barselona" >Barselona</a>
</br>
<a href="#" data-url="cao.php" id="Beograd" >Beograd</a>
</body>
</html>
Your link redirects you, so simpe do this:
e.preventDefault();
Also its better to have variables (for future), here is EXAMPLE
Try this one will work for you:
<html>
<head>
<script type="text/javascript" src="jquery-1.11.1.js"></script>
<script type="text/javascript" language="javascript">
$(document).ready(function(){
$('a').click(function(){
$.post('cao.php', { id : $(this).attr('id') },function(data){
alert(data);
});
});
});
</script>
</head>
<body>
<a href="#" id="Barselona" >Barselona</a>
</br>
<a href="#" id="Beograd" >Beograd</a>
</body>
</html>
AT cao.php page
<?php
$id = $_POST['id'];
echo $id;die;
?>
just try print_r($_POST) in cao.php & check the values are posting
$id=$_POST["id"];
In this code which I am posting i have one problem. I want my PHP variable to be stored in JavaScript variable but it shows error. The code is below.
<?php
$name="anurag singh";
echo '
<html>
<head>
<script type="text/javascript" src="jquery-2.0.2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var name1=.$name.";"
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
});
</script>
</head>
<body>
<h1>This is the demo!</h1>
<h2>In echo we can add more than one statements</h2>
</body>
</html>
';
?>
Now when I am assigning $name to the variable name1 than I get an syntax error. Please let me know what changes I have to make. So that I get the value of the PHP variable $name stored in JavaScript variable name1.
In javascript with echo version: var name1= "'.$name.'";
<?php
$name = "anurag singh";
echo '
<html>
<head>
<script type="text/javascript" src="jquery-2.0.2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var name1= "'.$name.'";
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
});
</script>
</head>
<body>
<h1>This is the demo!</h1>
<h2>In echo we can add more than one statements</h2>
</body>
</html>
';
?>
And you can use like var name1= "<?php echo $name; ?>"; seperated html and php
<?php
$name="anurag singh";
?>
<html>
<head>
<script type="text/javascript" src="jquery-2.0.2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var name1= "<?php echo $name; ?>";
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
});
</script>
</head>
<body>
<h1>This is the demo!</h1>
<h2>In echo we can add more than one statements</h2>
</body>
</html>
<?php
$name="anurag singh";
echo '
<html>
<head>
<script type="text/javascript" src="jquery-2.0.2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var name1='.$name.'";"
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
});
</script>
</head>
<body>
<h1>This is the demo!</h1>
<h2>In echo we can add more than one statements</h2>
</body>
</html>
';
?>
echo it into a script tag
echo '<script> var name = '.$name.';</script>';
You can do it this way -
<?php $name="anurag singh"; ?>
<html>
<head>
<script type="text/javascript" src="jquery-2.0.2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var name1="<?php echo $name ?>";
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
});
</script>
</head>
<body>
<h1>This is the demo!</h1>
<h2>In echo we can add more than one statements</h2>
</body>
</html>
You are pasing string $ame not variable as because you have used '...' this let the php know that its string no more variables inside this string.
<?php
$name="anurag singh";
?>
<html>
<head>
<script type="text/javascript" src="jquery-2.0.2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var name1=<?pgp echo $name ?>;
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
});
</script>
</head>
<body>
<h1>This is the demo!</h1>
<h2>In echo we can add more than one statements</h2>
</body>
</html>
try this
$(document).ready(function(){
var name1="'.$name.'";
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
you can assign this value like var name= "'. $name.'";