If isset statement not bringing up an input field - php

Question

I have the following code where I am trying to get the 'Finalize Draft Order' submit button to only appear if the 'Create Draft Order' button has been pressed/set. Right now, the button does not show up after I hit the Create Draft Order button. It only displays if I take it out of the if(isset function.
What am I doing wrong?
<form method="POST" name="form">
<input type="submit" value="Create Draft Order" name="shuffle">
</form>
Shuffled results: <br>
<div class="main-bag">
<div class="shuffle_results" id="results"></div>
<form method="post">
<?php
$count = 0;
foreach ($array as $result) :
$count++;
$shuffle_count = $count;
$shuffle_firstname = htmlentities($result['firstname']);
$shuffle_lastname = htmlentities($result['lastname']);
$shuffle_id = htmlentities($result['id']);
$shuffle_username = htmlentities($result['username']);
$shuffle_email = htmlentities($result['email']);
?>
<input type="hidden" name="count[]" value="<?php echo $shuffle_count; ?>">
<input type="hidden" name="firstname[]" value="<?php echo $shuffle_firstname; ?>">
<input type="hidden" name="lastname[]" value="<?php echo $shuffle_lastname; ?>">
<input type="hidden" name="id[]" value="<?php echo $shuffle_id; ?>">
<input type="hidden" name="username[]" value="<?php echo $shuffle_username; ?>">
<input type="hidden" name="email[]" value="<?php echo $shuffle_email; ?>">
<?php
endforeach;
// only show this button if we have done a shuffle
if ( isset($_POST['shuffle'] ) ) :
echo '<input type="submit" value="Finalize Draft Order" name="insert">';
endif;
?>
UPDATE:
$array = array();
while ($row = mysqli_fetch_assoc($query)) {
$array[] = array(
'id' => $row['id'],
'firstname' => $row['firstname'],
'lastname' => $row['lastname'],
'username' => $row['username'],
'email' => $row['email']
);
if (isset($_POST['shuffle'])) {
}
}
shuffle($array);
echo json_encode($array);

Answer 1

I don't think $_POST['shuffle'] is set. instead of using the submit button for it change your code to:
<form method="POST" name="form">
<input type="hidden" name="shuffle" value="true">
<input type="submit" value="Create Draft Order">
</form>
I'm pretty sure submit's name doesn't count for the POST values.

Answer 2

I don't know what version of PHP meame69 and ScottyMcGready are using, but you very much CAN check to see if the button was clicked by checking for the isset($_POST["submit"]) is true.
http://www.learningaboutelectronics.com/Articles/How-to-check-if-the-submit-button-is-clicked-in-PHP.php
I cannot comment yet, but I will edit this once I figure out what's wrong with Becky's code.

Answer 3

Here's you're issue. Your input button is named shuffle, which is not passed when submitting. If you add a new hidden input element with the name "shuffle" that will pass it through.
edit:
You've said in your question its after the create draft button is pressed. Therefore as per your example:
<form method="POST" name="form">
<input type="submit" value="Create Draft Order" name="form">
<input type="hidden" name="shuffle" value="1">
</form>
Shuffled results: <br>
<div class="main-bag">
<div class="shuffle_results" id="results"></div>
<form method="post">
<?php
$count = 0;
foreach ($array as $result) :
$count++;
$shuffle_count = $count;
$shuffle_firstname = htmlentities($result['firstname']);
$shuffle_lastname = htmlentities($result['lastname']);
$shuffle_id = htmlentities($result['id']);
$shuffle_username = htmlentities($result['username']);
$shuffle_email = htmlentities($result['email']);
?>
<input type="hidden" name="count[]" value="<?php echo $shuffle_count; ?>">
<input type="hidden" name="firstname[]" value="<?php echo $shuffle_firstname; ?>">
<input type="hidden" name="lastname[]" value="<?php echo $shuffle_lastname; ?>">
<input type="hidden" name="id[]" value="<?php echo $shuffle_id; ?>">
<input type="hidden" name="username[]" value="<?php echo $shuffle_username; ?>">
<input type="hidden" name="email[]" value="<?php echo $shuffle_email; ?>">
<?php
endforeach;
// only show this button if we have done a shuffle
if ( isset($_POST['shuffle'] ) ) :
echo '<input type="submit" value="Finalize Draft Order" name="insert">';
endif;
?>