Error trying to search a video AJAX - php

Question

I have created a code that allows you to search videos from the database. But everytime I write the video I want to search, in console, error appears... I really dont know why it doesnt print the result...
Could you help me?
I need help real fast
AJAX
$(document).ready(function($) {
var Search = function(title){ return $.post( "./include/php/busqueda_videos.php", { "title" : title }); }
$("#input_search").on('keyup', function(event) {
var output = "";
$(".videos_container").html("");
event.preventDefault();
var input = $("#input_search").val();
Search(input).done(function(response) {
if(response.success) {
$.each(response.videos, function(key, value) { var output = "<div class='video_main_container'><div class='video_container'><div class='video_thumb'><a data-id='"+value['id']+"'><img src='"+value['image']+"' alt='' /></a></div><div class='video_info'><p class='title'>"+value['title']+"</p><p class='usuario'>"+value['user']+"</p></div></div></div>"; });
$(".videos_container").html(output);
} else {
console.log("Error");
}
}).fail(function(jqXHR, textStatus, errorThrown) { console.log("Hubo un error"); });
});
});
PHP
<?php
if(isset($_POST['title'])) {
get_infvideo($_POST['title']);
} else {
$message = sprintf("No valid");
header($_SERVER['SERVER_PROTOCOL'] . ' ' . $message, true, 403);
}
function get_infvideo($title) {
$dsn = "mysql:host=localhost;dbname=tapehd;charset=utf8";
$usuario = "root";
$contraseña = "";
$conexion = new PDO($dsn, $usuario, $contraseña);
$resultado = null;
$jsondata = array();
$videos = array();
$text ="";
if($title!="") {
$title= explode(" ", $title);
for($i=0; $i<count($title);$i++) {
if($text!="") {
$text .= " AND (title LIKE '%".$title[$i]."%' or user LIKE '%".$title[$i]."%')";
} else {
$text .= " (titulo LIKE '%".$titulo[$i]."%' or user LIKE '%".$title[$i]."%')";
}
}
}
if($conexion){
$sql = "SELECT * FROM video WHERE ".$text;
if($resultado = $conexion->query($sql)) {
while($fila = $resultado->fetch()) {
$fila['id'] = $fila['id'];
$fila['user'] = $fila['user'];
$fila['image'] = $fila['image'];
$jsondata['success'] = true;
array_push($videos, $fila);
$jsondata['videos'] = $videos;
}
} else {
$jsondata['success'] = false;
$jsondata['message'] = $sql;
}
}
header('Content-type: application/json; charset=utf-8');
echo json_encode($jsondata, JSON_FORCE_OBJECT);
}
exit();
?>
The idea is to print the video (with his id, image, user, title) that you have searched...