PHP comparison operator not working in MySQL streak query - php

In attempting to calculate the longest goalscoring streak for a single player, I've hit a stumbling block with the >= PHP operator not performing as intended.
The data is presented in a table as follows:
date gls
------------------------
1980-08-16 2
1980-08-19 1
1980-08-23 1
1980-08-26 0
1980-08-30 1
1980-09-06 2
1980-09-13 0
... and so on
The PHP query I am using is as follows:
SELECT gls, MIN(date) as StartDate, MAX(date) as EndDate, COUNT(*) as Games
FROM (SELECT gls, date,
(SELECT COUNT(*)
FROM goalsengine G
WHERE G.gls <> GE.gls
AND G.date <= GE.date) as RunGroup
FROM goalsengine GE) A
WHERE gls>='1'
GROUP BY gls, RunGroup
ORDER BY Games
I formed the query this way in the belief that >= would tally up streaks where this player had scored one or more goals in a game. From the table above, the first three entries would represent a scoring run of three games, for example.
Instead, the query is returning streaks but only where a certain number of goals are scored i.e. despite scoring in the first three games, the first entry (where two goals were scored, not one) is ignored when the streak is returned.
To return the results, I am using the following:
while($row=mysql_fetch_assoc($result))
{
{$startrundate = date("d F Y",strtotime($row['StartDate']));}
{$endrundate = date("d F Y",strtotime($row['EndDate']));}
echo "<tr>";
echo "<td>".$row['Games']."</td>";
echo "<td class='tableprofile' style='text-align:right;'>".$startrundate." - ".$endrundate."</td>";
echo "</tr>";
$rowCount += 1;
}
By comparison, WHERE gls='0' is giving me the desired non-goalscoring streaks. I feel I have perhaps overlooked something straightforward but cannot see what.

I've managed to work out a solution to this particular issue and it works as far as I can tell, having counted some of the raw data out manually.
SELECT gls, MIN(date) as StartDate, MAX(date) as EndDate, COUNT(*) as Games
FROM (SELECT gls, date,
(SELECT COUNT(*)
FROM goalsengine G
WHERE IF(G.gls IN ('1','2','3','4','5'),1,0) <> IF(GE.gls IN ('1','2','3','4','5'),1,0)
AND G.date <= GE.date) as RunGroup
FROM goalsengine GE) A
WHERE gls IN ('1','2','3','4','5') GROUP BY IF(bg IN ('1','2','3','4','5'),1,0), RunGroup ORDER BY Games DESC LIMIT 3");
I admit it's not exactly pretty, but it's doing the job for now. I have gone to 5 in the calculation as that's the maximum number of goals scored in a single match with regards to this data set.

Related

Using a formulla through mysql queries: error

I have created a database of kittens where I need to use the following formula. In this regard I have two tables: birth and disposal.
Birth table contains id, dob, owner, date of purchase
disposal table contains id, date of disposal (dodisposal), cause of death, sold, treatment
I am now trying use a formula for the two table using the following MySQL query but it is not working.
Select birth.owner, (((select count(disposal.id) from disposal WHERE
dodisposal BETWEEN DATE_SUB(NOW(), INTERVAL 600 DAY) AND NOW()) /
(select count(birth.id) from birth where birth.id not in
(select disposal.id from disposal)
)
) * 100)
from birth left join disposal on
disposal.brandnumber = birth.id group by birth.owner
but I keep getting same results for all owners:
ie
rita : 79.6
sunita : 79.6
Smith : 79.6
The result I am expecting should be through the following formula:
Number of deaths in the current year / total number of live cats * 100
I found a solution to this problem by making two separate views and then their results using a MySQL query.
create view cats as select id, count(disposal.id) from disposal WHERE
dodisposal BETWEEN DATE_SUB(NOW(), INTERVAL 600 DAY) AND NOW()) as dead
create view livecates as select count(birth.id) from birth left join disposal on disposal.id = birth.id where birth.id not in (select disposal.id from disposal) as live
select livecats.id, (dead/live * 100) from livecats left join cats on livecats.id = cats.id group by livecats.id

get monthwise row count from datewise data in mysql

I have two tables:
table 1.a
id--entry_date-amount
============================
2---2016-04-14--$400
3---2016-04-14--$400
4----2017-07-14--$200
5---2017-07-14--$500
6---2017-05-14--$600
7----2017-06-18--$100
table 2.b
id--entry_date
===========================
2---2016-04-14--$230
3---2016-04-14--$230
4----2017-07-14--$567
5---2017-07-14--$600
6---2017-05-14--$560
7----2017-06-18--$90
8---2016-04-14--$100
from the two tables how can i get count with montwise
my desired result:
month_name--total(count form table a)--total(count form table b)--amount(table a)--amount(table b)
========================================================
April,16-----------2-------------------3---$800-$500
May,17-----------1-------------------1 --$600--$700
June,17-----------2-------------------2--$100--$800
July,17-----------2-------------------2---$700-$400
this is the demo data.
I want to show data from two tables in a single query month wise.
How can i do this?
I tried:
SELECT MONTHNAME(r.entry_date),r.a_total FROM(
SELECT
IFNULL((SELECT COUNT(tr.id) AS amount FROM a AS tr WHERE MONTH(tr.entry_date)=MONTH(t.entry_date)),0) AS a_total
,t.entry_date
FROM(SELECT tr.id,tr.entry_date
FROM a AS tr
WHERE DATE(tr.entry_date) BETWEEN '2017-07-01' AND '2018-06-30') t
GROUP BY MONTH(t.entry_date)) r
But takes 58 seconds for simple query. How can i make this in a simple query?
You can get the counts and sum from each table individually, then use UNION to combine the two result sets into one result set. Something like this :
SELECT Month_name,
SUM(aCount) AS aCount,
SUM(bCount) AS bCount,
SUM(aAmount) AS aAmount,
SUM(bAmount) AS bAmount
FROM
(
SELECT
MONTHNAME(a.entry_date) AS Month_name,
COUNT(a.id) AS aCount,
0 AS bCount,
SUM(a.amount) AS aAmount,
0 AS bAmount
FROM a
GROUP BY MONTHNAME(a.entry_date)
UNION ALL
SELECT
MONTHNAME(b.entry_date) AS Month_name,
0 AS aCount,
COUNT(b.id) AS bCount,
0 AS aAmount,
SUM(b.amount) AS bAmount
FROM b
GROUP BY MONTHNAME(b.entry_date)
) AS t
GROUP BY Month_Name;
live demo
user9131497 has a good design for the big picture. However, I would suggest stuff like this for handling the dates:
SELECT DATE_FORMAT(entry_date, "%M,%y") AS 'Month',
COUNT(*) AS 'aCount'
FROM a
GROUP BY LEFT(entry_date, 7) -- eg, "2017-03"
Try that to see what I mean.
Note that this will work beyond a year. Or did you need January values from all years to be combined?? -- That's what your solution and user9131497's will do. Mine keeps them separate.

Nested count() function with % percentage operation

I’m designing a program for my school to keep student attendance records. So far I have the following query working fine and now I would like to add an IF statement to perform a percentage operation when a certain condition is given. As it is, the query is using INNER JOIN to search for data from two different tables (oxadmain and stuattend) and it’s displaying the results well on a results table:
SELECT o.name
, o.year
, o.photoID
, o.thumbs
, s.ID
, s.studid
, s.date
, s.teacher
, s.subject
, s.attendance
FROM stuattend s
JOIN oxadmain o
ON s.studid = o.stuid
ORDER
BY name ASC
Now I would like to add an “if” statement that
1) finds when stuattend.attendance is = Absent, calculates the percentage of absences the students may have in any given period of time, and then stores that (%) value in “percentage” and
2) ELSE assigns the value of 100% to “Percentage”.
So far I’ve been trying with the following:
<?php $_GET['studentID'] = $_row_RepeatedRS['WADAstuattend']; ?>
SELECT oxadmain.name , oxadmain.year , oxadmain.photoID , oxadmain.thumbs , stuattend.ID , stuattend.studid , stuattend.date , stuattend.teacher, stuattend.subject , stuattend.attendance
CASE
WHEN stuattend.attendance = Absent THEN SELECT Count (studentID) AS ClassDays, (SELECT Count(*) FROM stuattend WHERE studentID = stuattend.studid AND Absent = 1) AS ClassAbsent, ROUND ((ClassAbsent/ClassDays)*100, 2) AS Percentage
ELSE
Percentage = 100
END
FROM stuattend INNER JOIN oxadmain ON stuattend.studid=oxadmain.stuid
ORDER BY name ASC
Any suggestions on how to do this well?
Thank you for your attention
The base idea would be:
select stuattend.studid, sum(stuattend.attendance = `absent`) / count(*)
from stuattend
group by stuaddend.studid;
This very much depends on exactly one entry per student and per day, and of course gets 0 if no absence and 1 if always absent.
To make this a bit more stable I would suggest to write a calendar day table, which simply keeps a list of all days and a column if this is a school day, so workday=1 means they should have been there and workday=0 means sunday or holiday. Then you could left join from this table to the presence and absence days, and even would give good results when presence is not contained in your table.
Just ask if you decide which way to go.

How to calculate difference between values coming from the same row in mysql

I am trying to calculate the difference of values list coming from a database.
I would like to achieve it using php or mysql, but I do not know how to proceed.
I have a table named player_scores. One of its rows contains the goals scored.
Ex.
pl_date pl_scores
03/11/2014 18
02/11/2014 15
01/11/2014 10
I would like to echo the difference between the goals scored during the matches played in different dates.
Ex:
pl_date pl_scores diff
03/11/2014 18 +3
02/11/2014 15 +5
01/11/2014 10 no diff
How can I obtain the desired result?
You seem to want to compare a score against the score on a previous row.
Possibly simplest if done using a a sub query that gets the max pl_date that is less than the pl_date for the current row, then joining the results of that sub query back against the player_scores table to get the details for each date:-
SELECT ps1.pl_date, ps1.pl_scores, IF(ps2.pl_date IS NULL OR ps1.pl_scores = ps1.pl_scores, 'no diff', ps1.pl_scores - ps1.pl_scores) AS diff
FROM
(
SELECT ps1.pl_date, MAX(ps2.pl_date) prev_date
FROM player_scores ps1
LEFT OUTER JOIN player_scores ps2
ON ps1.pl_date > ps2.pl_date
GROUP BY ps1.pl_date
) sub0
INNER JOIN player_scores ps1
ON sub0.pl_date = ps1.pl_date
LEFT OUTER JOIN player_scores ps2
ON sub0.prev_date = ps2.pl_date
There are potentially other ways to do this (for example, using variables to work through the results of an ordered sub query, comparing each row with the value stored in the variable for the previous row)
SELECT score FROM TABLE WHERE DATE = TheDateYouWant
$score = $data['score'];
SELECT score FROM TABLE WHERE date = dateYouWant
$difference = $score - $data['score'];
Something like this?
You could use two queries, one to get the value to use in the comparison (in the example below is the smaller number of scores) and the second one to get the records with a dedicated column with the difference:
SELECT MIN(pl_scores);
SELECT pl_date, pl_scores, (pl_scores - minScore) as diff FROM player_scores;
Or, using a transaction (one query execution php side):
START TRANSACTION;
SELECT MIN(Importo) FROM Transazione INTO #min;
SELECT Importo, (Importo - #min) as diff FROM Transazione;
select *,
coalesce(
(SELECT concat(IF(t1.pl_scores>t2.pl_scores,'+',''),(t1.pl_scores-t2.pl_scores))
FROM tableX t2 WHERE t2.pl_date<t1.pl_date ORDER BY t2.pl_date DESC LIMIT 1)
, 'no data' ) as diff
FROM tableX t1
WHERE 1
order by t1.pl_date DESC

Counting payment from date range in MySQL

I want to count payment within selected date, but i can't figure it out how to do it.
Here is the example data from the my table
id starts_from payment_per_day
=======================================
1 2012-01-01 10,000.00
2 2012-01-15 10,500.00
3 2012-02-01 11,000.00
4 2012-02-15 11,500.00
5 2012-03-01 12,000.00
How do i count total payment from 2012-01-21 to 2012-02-20 ?
The total payment should be 338,500
from 2012-01-21 to 2012-01-31 = 11 days * 10,500
from 2012-02-01 to 2012-02-14 = 14 days * 11,000
from 2012-02-15 to 2012-02-20 = 6 days * 11,500
But if i do :
SELECT SUM(payment_per_day) as total FROM table
WHERE starts_from BETWEEN '2012-01-21' AND '2012-02-20'
the result is only 22,500
Any ideas ?
SELECT SUM(payment_per_day) as total FROM table
WHERE starts_from BETWEEN '2012-01-21' AND '2012-02-20';
I would first expand the range into the list of dates, then use the following query:
SELECT SUM(p1.payment_per_day)
FROM dates d
INNER JOIN payments p1 ON p1.starts_from <= d.date
LEFT JOIN payments p2 ON p2.starts_from <= d.date
AND p2.starts_from > p1.starts_from
WHERE p2.id IS NULL
You could obtain the list from the range with the help of a numbers table, like this:
SELECT DATE_ADD(#date_from, INTERVAL num DAY)
FROM numbers
WHERE num BETWEEN 0 AND DATEDIFF(#date_to, #date_from)
A numbers table is a thing worth having as it can be useful in many situations, so consider providing yourself with one. Here's a very simple script to create and initialise a numbers table:
CREATE TABLE numbers AS SELECT 0 AS num;
SET #ofs = (SELECT COUNT(*) FROM numbers); INSERT INTO numbers SELECT #ofs + num FROM numbers;
SET #ofs = (SELECT COUNT(*) FROM numbers); INSERT INTO numbers SELECT #ofs + num FROM numbers;
SET #ofs = (SELECT COUNT(*) FROM numbers); INSERT INTO numbers SELECT #ofs + num FROM numbers;
… /* repeat as necessary, each line doubles the number of rows in the table */
But, of course, you can use a loop instead.
Here's my complete testing environment on SQL Fiddle (for anyone to play with).
It seems that it is almost impossible to do query like that, counting total each day payment within selected date.
So i work around by selecting data from all starts_from dates until <= 2012-02-20 and then picking last starts_from date which is less than 2012-01-21 (that is 2012-01-15) in order to get payment_per_day 10,500.00
Thank you for viewing my question :)

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