PHP MYSQL Insert dynamic array into database - php

Question

The dynamic HTML form (with some js help) and PHP script below insert user entered values into MySQL successfully, except that all rows from the form are placed in one row on the database. What am I doing wrong?
Dynamic form HTML:
<table id="dataTable" class="form" border="4">
<tbody style="font-size:8pt">
<th>
<td align="center">Company</td>
<td align="center">Project</td>
<td align="center">Sub-Project</td>
<td align="center">Change From</td>
<td align="center">Change To</td>
<td align="center">Activity</td>
<td align="center">Responsible</td>
<td align="center">Dur</td>
</th>
<tr >
<p>
<td><input type="checkbox" required="required" name="chk[]" checked="checked" /></td>
<td><input style="width:100px" type="text" readonly="readonly" name="coa[]" value="<?php echo $co; ?>">
</td>
<td>
<select name="Projectname[]" style="font-size:10pt">
<option selected="selected" required="required">Select project</option>
<?php
foreach($proj as $item){
?>
<option value="<?php echo $item; ?>"><?php echo $item; ?></option>
<?php
}
mysqli_close($conn);
?>
</select>
</td>
<td><input style="width:100px" type="text" required="required" name="Subproj[]"></td>
<td><input style="width:130px" type="text" required="required" name="Changefrom[]"></td>
<td><input style="width:130px" type="text" required="required" name="Changeto[]"></td>
<td><input style="width:300px" type="text" required="required" name="Activity[]"></td>
<td><input style="width:90px" type="text" required="required" name="Resp[]"></td>
<td><input type="text" required="required" class="small" name="Durest[]"></td>
</p>
</tr>
</tbody>
</table>
PHP script:
<?php
include("../../db_conn_ci_i.php");
if(isset($_POST)==true && empty($_POST)==false){
$co=$_POST['co'];
$chkbox = $_POST['chk'];
$Projectname=$_POST['Projectname'];
$Subproj=$_POST['Subproj'];
$Changefrom=$_POST['Changefrom'];
$Changeto=$_POST['Changeto'];
$Activity=$_POST['Activity'];
$Resp=$_POST['Resp'];
$Durest=$_POST['Durest'];
}
$pco=implode(',',$co);
$pa=implode(',',$Projectname);
$pb=implode(',',$Subproj);
$c=implode(',',$Changefrom);
$d=implode(',',$Changeto);
$e=implode(',',$Activity);
$f=implode(',',$Resp);
$g=implode(',',$Durest);
$sql=" INSERT INTO projects (co,Projectname,Subproj,Changefrom,Changeto,Activity,Resp,Durest)
VALUES ('.$pco.','.$pa.','.$pb.','.$c.','.$d.','.$e.','.$f.','.$g.') ";
$query = mysqli_query($conn,$sql);
etc,etc
?>
Any advice?
Thank you.

Answer 1

You have added an extra column but not added a value for it. Since you are inserting seven columns with eight values, that's why it's not working for you. Your insert query is like below.
$sql=" INSERT INTO projects (Projectname,Subproj,Changefrom,Changeto,Activity,Resp,Durest)
VALUES ('.$pa.','.$pb.','.$c.','.$d.','.$e.','.$f.','.$g.') ";
$query = mysqli_query($conn,$sql);