This is probably relatively easy to do, but I'm new to twig and I'm frustrated.
I'm adapting code from this answer: https://stackoverflow.com/a/24058447
the array is made in PHP through this format:
$link[] = array(
'link' => 'http://example.org',
'title' => 'Link Title',
'display' => 'Text to display',
);
Then through twig, I add html to it, before imploding:
<ul class="conr">
<li><span>{{ lang_common['Topic searches'] }}
{% set info = [] %}
{% for status in status_info %}
{% set info = info|merge(['{{ status[\'display\'] }}']) %}
{% endfor %}
{{ [info]|join(' | ') }}
</ul>
But I'm getting:
Errno [8] Array to string conversion in
F:\localhost\www\twig\include\lib\Twig\Extension\Core.php on line 832
It's fixed when I remove this line, but does not display:
{{ [info]|join(' | ') }}
Any ideas how I can implode this properly?
** update **
Using Twig's dump function it returns nothing. It seems it's not even loading it into the array in the first place. How can I load info into a new array.
info is an array, so you should simple write
{{ info|join(', ') }}
to display your info array.
[info] is a array with one value : the array info.
You shouldn't really be building complex data structures inside of Twig templates. You can achieve the desired result in a more idiomatic and readable way like this:
{% for status in status_info %}
{{ status.display }}
{% if not loop.last %}|{% endif %}
{% endfor %}
You can user json_encode for serialize array as strig, then show pretty - build in twig
{{ array|json_encode(constant('JSON_PRETTY_PRINT')) }}
if need associative array:
{{info|json_encode(constant('JSON_PRETTY_PRINT'))|raw}}
Related
I have a problem with properties in (probably) Twig. I have controller in Symfony where getCategories(), getWords(), getTranslations() methods (from Doctrine) return the objects (relations). Every property in the controller is an array because I call findAll() method (from Doctrine again) which returns the array. Finally I return all the properties from controller to view (Twig file) where I try display the results by Twig for loop.
The problem is the Twig loop only iterates over flashcards property (I know why ;)) and I have no idea how to make many-properties iterating. I'd like the loop to iterate over all properties returned by the controller.
In the controller foreach loop I tried update the flashcards array with new associative keys such as: category, word and translation so that all the results returned by Doctrine (including relations) are stored in one flashcards property but then Symfony throws exceptions.
I wondered if create one array in the controller to which I would push the flashcards, cateogry, word and translation arrays and then return this one array to the view but I don't think this is good practice.
Here's the controller method code:
public function showAllCards()
{
$flashcards = $this->getDoctrine()->getRepository(Flashcards::class)
->findAll();
foreach ($flashcards as $flashcard) {
$category = $flashcard->getCategories()->getName();
$word = $flashcard->getWords()->getWord();
$translation = $flashcard->getTranslations()->getWord();
}
return $this->render('try_me/index.html.twig', [
'flashcards' => $flashcards,
'category' => $category,
'word' => $word,
'translation' => $translation
]);
}
Here's the Twig loop code:
{% for flashcard in flashcards %}
{{ word }}
<br>
{{ flashcard.pronunciation }}
<br>
{{ flashcard.exampleSentence }}
<br>
{{ category }}
<br>
{{ translation }}
<br>
{% endfor %}
I tried to execute the following controller code...
public function showMeAll()
{
$flashcards = $this->getDoctrine()->getRepository(Flashcards::class)
->findAll();
foreach ($flashcards as $flashcard) {
$flashcards['categories'] = $flashcard->getCategories()->getName();
$flashcards['words'] = $flashcard->getWords()->getWord();
$flashcards['translations'] = $flashcard->getTranslations()->getWord();
}
return $this->render('try_me/index.html.twig', [
'flashcards' => $flashcards,
]);
}
...with the following Twig loop...
{% for flashcard in flashcards %}
{{ flashcard.words }}
<br>
{{ flashcard.pronunciation }}
<br>
{{ flashcard.exampleSentence }}
<br>
{{ flashcard.categories }}
<br>
{{ flashcard.translations }}
<br>
{% endfor %}
...but then Symfony says:
An exception has been thrown during the rendering of a template ("Catchable Fatal Error: Object of class Proxies__CG__\App\Entity\Words could not be converted to string").
Could you give me some tips how to solve this problem, please? I'd like the Twig loop to iterates over many properties (flashcard, word, category, translation). Or write if there's a better solution, please.
Thank you in advance for every answer!
According to your snippets, I'm guessing you want something like the following:
{% for flashcard in flashcards %}
{% for word in flashcard.getWords() %}
{{ word }}<br />
{% endfor %}
{{ flashcard.getPronunciation() }}<br>
{{ flashcard.getExampleSentence() }}<br>
{% for category in flashcard.getCategories()() %}
{{ category.getName() }}<br />
{% endfor %}
{% for translation in flashcard.getTranslations() %}
{{ translation.getWord() }}<br />
{% endfor %}
{% endfor %}
Have a look at this section of the documentation. Basically if you had foo.bar, twig will test if bar is a public property of foo and if not test if there is a public getter, getBar, to fetch bar.
Some sidenotes in both of your loops, the values category, word and translation will only hold the last value of your flashcards, because you are overwriting the value each time.
I have an array of user records (0 indexed, from a database query), each of which contains an array of fields (indexed by field name). For example:
Array
(
[0] => Array
(
[name] => Fred
[age] => 42
)
[1] => Array
(
[name] => Alice
[age] => 42
)
[2] => Array
(
[name] => Eve
[age] => 24
)
)
In my Twig template, I want to get all the users where the age field is 42 and then return the name field of those users as an array. I can then pass that array to join(<br>) to print one name per line.
For example, if the age was 42 I would expect Twig to output:
Fred<br>
Alice
Is this possible to do in Twig out of the box, or would I need to write a custom filter? I'm not sure how to describe what I want in a couple of words so it may be that someone else has written a filter but I can't find it by searching.
Final solution was a mix of what has been posted so far, with a couple of changes. The pseudocode is:
for each user
create empty array of matches
if current user matches criteria then
add user to matches array
join array of matches
Twig code:
{% set matched_users = [] %}
{% for user in users %}
{% if user.age == 42 %}
{% set matched_users = matched_users|merge([user.name|e]) %}
{% endif %}
{% endfor %}
{{ matched_users|join('<br>')|raw }}
merge will only accept an array or Traversable as the argument so you have to convert the user.name string to a single-element array by enclosing it in []. You also need to escape user.name and use raw, otherwise <br> will be converted into <br> (in this case I want the user's name escaped because it comes from an untrusted source, whereas the line break is a string I've specified).
In twig you can merge the for ( .... in ....) with the if condition like :
{% for user in users if user.age == 42 %}
{{ user.name }}{{ !loop.last ? '<br>' }}
{% endfor %}
Edit: This syntax is deprecated, and we are advised to use |filter as a replacement for the for...if syntax.
Twig Filter: filter (The name of the filter is filter)
Twig Deprecated Features
You can apply a filter on the array you apply for loop on, like this:
{% for u in user|filter((u) => u.age == 42) -%}
<!-- do your stuff -->
{% endfor %}
{% for user in users %}
{% if user.age == 42 %}
{{ user.name|e }}<br>
{% endif %}
{% endfor %}
in alternative you can create an array of elements
{% set aUserMatchingCreteria %}
{% for user in users %}
{% if user.age == 42 %}
{% aUserMatchingCreteria = aUserMatchingCreteria|merge(user.name) %}
{% endif %}
{% endfor %}
{{ aUserMatchingCreteria|join('<br>') }}
Since Twig 2.10, the recommended way to conditionally exclude array elements is the filter filter. As was noted in some previous answers, loop.last has some issues, but you can simply flip the logic and use loop.first, which will work consistently:
{% for user in users|filter((u) => u.age == 42) %}
{{ loop.first ?: '<br/>' }}
{{ user.name|e }}
{% endfor %}
I have an array of states and a number like:
(state, count)
states=[
'ACT' => 25,
'NSW' => 45,
'VIC' => 18,
'SA' => 12
]
I'm trying to get the value for each state in twig (outside of a loop).
So for each state (as a dynamic parameter) I need to get the "count" value:
{{ attribute(states, state_name).count }}
or
{{ attribute(states, count)}}
but not working.
Any idea?
Edit:
This code is working but can't get the value out of the loop.
In this code I need to run the loop several times.
{% for state in states %}
{% if state.state_name == state_name %}
({{ state.count }})
{% endif %}
{% endfor %}
There is no variable named count, you only have a key-value array where the value is the count. You can simply use attribute to get the value:
{{ attribute(states, state_name) }}
or, as jeroen commented:
{{ states[state_name] }}
I`am rendering a twig template in symfony2 and its possible to get a variable with value of array type but i am trying to preview the variable and this error pops:
Array to string conversion ...
So my qustion is not how to print out the array, but is it possible in twig to disable this error, so when an array comes and it cannot be outputed, to set an empty value.
In config.yml, under twig i have set
strict_variables: false
But this dose not include printing arrays.
EDIT:
In controller I pass this array to twig, for example:
'data' => array(
'description' => array(
'desc1',
'desc2'
)
);
In twig I am trying to print {{ data['description'] }} and I got the following error:
Array to string conversion ...
This is the normal error that must pop, but I need if I try to print this a no error to pop but instead I need to print nothing(empty value), same way like trying to print an non existing variable with twig set with
strict_variables: false
ANSWER:
Make a custom function:
public function getFunctions()
{
return array(
'to_string' => new \Twig_Function_Method($this, 'toString')
);
}
public function toString($data) {
if(is_array($data)) {
return '';
}
return $data;
}
And in twig template:
{{ to_string(data['description']) }}
You have two desc: desc1 and desc2, what do you want to print? If both you have to use this notation (for instance)
{{ data['description'][desc1] }} - {{ data['description'][desc2] }}
More in general:
{% for desc in data['description'] %}
{{ desc }}
{% endfor %}
EDIT
Ok, now I got it (from your comment):
{% if data['description'] is iterable %}
//echo here an empty string
{% else %}
{{ data['description'] }}
{% endif %}
First of all, I know that the logic should be in the controller and not in the view and I keep it that way.
But in this particular situation I need to use preg_match within a ternary operation to set the css class of a div.
Example:
{% for list in lists %}
<div class="{{ (preg_match(list.a, b))>0 ? something : else }}"...>...</div>
{% endfor %}
How can I achieve the (preg_match(list.a,b))>0 condition in twig?
Thanks in advance
For those who came here from Google search results (like me).
There's containment operator that allows you to do something like this:
{{ 'cd' in 'abcde' }} {# returns true #}
You can't use preg_match() directly but there are ways to accomplish it:
if your list is an entity, add a method matches(): {{ (list.matches(b)) ? something : else }}
you could create a custom Twig extension function that uses preg_match() internally http://symfony.com/doc/master/cookbook/templating/twig_extension.html
Expanding from Serge's comment and is the correct answer.
In my example my string is "Message Taken - 12456756". I can then use |split to convert it into an array and use |replace to get ride of white space.
{% set mt = 'Message Taken' in d.note %}
{% if mt == true %}
{#.. you can then do something that is true#}
{% set mt_array = d.note|split('-') %}
{{ mt_array[0] }} | {{ mt_array[1]|replace({' ' : ''}) }}
{% endif %}
This would output my string but I now control two parts instead of 1.