Using multiple database in one php script - php

Question

This first part work very well in other script of mine. But in this example the script simply skip this part and goes to the end and execute the last query..
I don't know what I'm doing wrong because I do it exactly same yet it doesn't work. This is full script.
for ($i = 1; $i <= $numofservers; $i++)
{
if($servers[$i][1] == $server)
{
$srv = $i;
$connect = mysql_connect($servers[$srv][3], $servers[$srv][4], $servers[$srv][5]) or die('Could not connect: ' . mysql_error());
mysql_select_db($servers[$srv][6]);
}
}
$sql = mysql_query("SELECT * FROM db_users WHERE username = '".$nick."'") or die('Nick na serveru Neexistuje!' . mysql_error());
$sql = mysql_fetch_array($sql);
$balance = $sql['donate_balance'];
$steamid = $sql['steam_id'];
$balance = $balance + $price_sms;
$money = mysql_query("UPDATE db_users SET `donate_balance`='". $balance ."' WHERE steam_id = '".$steam_id."'");
<?php
$db_site_name = ''; // db connection name
$db_site_password = '';
$db_site_username = 'root'; // username of connection
$db_site_ip = '127.0.0.1:3306';
$link = mysql_connect($db_site_ip, $db_site_username, $db_site_password) or die('Could not connect: ' . mysql_error());
mysql_select_db($db_site_name) or die('Not connected<br>');
$serversquery = mysql_query("SELECT * FROM db_servers ORDER BY id");
$numofservers = 0;
while ($servers_array = mysql_fetch_array($serversquery))
{
$numofservers++;
$servers[$numofservers] = array(
$servers_array['id'],
$servers_array['name'],
$servers_array['about'],
$servers_array['server_ip'],
$servers_array['server_username'],
$servers_array['server_password'],
$servers_array['server_name'],
$servers_array['server_admin_rank'],
$servers_array['donate_factor']
);
}
if (isset($_GET["request"])){
$request_sms = ($_GET["request"]);
$status = ($_GET["status"]);
$message = ($_GET["message"]);
$request = mysql_query("UPDATE `sms_confirm` SET `status` = '".$status."' WHERE `sms_id` = '".$request_sms."'");
$findid = mysql_query("SELECT * FROM `sms_confirm` WHERE `sms_id` = '".$request_sms."' LIMIT 1") or die(mysql_error()); ;
$query = mysql_fetch_array($findid);
if ($query['status'] == 'DELIVERED' AND $query['added'] == 'false'){
$price_sms = $query['cena'];
$nick = $query['nick'];
$server = $query['server'];
for ($i = 1; $i <= $numofservers; $i++)
{
if($servers[$i][1] == $server)
{
$srv = $i;
$connect = mysql_connect($servers[$srv][3], $servers[$srv][4], $servers[$srv][5]) or die('Could not connect: ' . mysql_error());
mysql_select_db($servers[$srv][6]);
}
}
$sql = mysql_query("SELECT * FROM db_users WHERE username = '".$nick."'") or die('Nick na serveru Neexistuje!' . mysql_error());
$sql = mysql_fetch_array($sql);
$balance = $sql['donate_balance'];
$steamid = $sql['steam_id'];
$balance = $balance + $price_sms;
$money = mysql_query("UPDATE db_users SET `donate_balance`='". $balance ."' WHERE steam_id = '".$steam_id."'");
$link = mysql_connect($db_site_ip, $db_site_username, $db_site_password) or die('Could not connect: ' . mysql_error());
mysql_select_db($db_site_name) or die('Not connected<br>');
//this executes fine
$request = mysql_query("UPDATE `sms_confirm` SET `added` = 'true' WHERE `sms_id` = '".$request_sms."'");
}
}
//Header("HTTP/1.1 204 NO_CONTENT");
//Header("Content-type: text/plain");
?>

Answer 1

First of all, don't use mysql_* functions. It's deprecated and will be removed.
And if you want to use more than one database connection, you have to pass link to it to every function that will contact with your databases.
Eg, check here (second parameter).
Sample code
$link = mysql_connect($db_site_ip, $db_site_username, $db_site_password);
mysql_select_db($db_site_name, $link);
mysql_query($query, $link);