Multiple INSERT INTO MySQL from $_POST array - php

Question

I am receiving the following arrays from a form:
array (size=1)
'checkbox' =>
array (size=2)
0 => string '14' (length=2)
1 => string '13' (length=2)
2 => string '15' (length=2)
array (size=1)
'id' => string '1' (length=1)
I need to build a query looking like this:
$sql = "INSERT INTO table(column1,column2) VALUES (14,1),(13,1),(15,1)";
And the first array will be different every time based on the checked checkboxes.

Answer 1

Well, you can try looping with a foreach on that array. So let's say you have named your checkboxes as name="checkbox[]".
Then on the page where you are processing the $_POST vars you can do
$sql = "INSERT INTO table(column1,column2) VALUES (?,?)";
$stmt = $mysqli->prepare($sql);
foreach ($_POST['checkbox'] as $box) {
//process each checkbox here
$stmt->bind_param('ss', $box, $otherValue);
$stmt->execute();
}
This is just a pseudo-code to get you started.
You can find more info on prepared statements here: http://php.net/manual/en/mysqli-stmt.bind-param.php

Answer 2

// Create an empty array to store each checkbox value
$values = array();
if(is_array($_POST['checkbox'])){
foreach($_POST['checkbox'] as $checkbox){
foreach($checkbox as $key => $value){
// add each checkbox value to an array
$values[] = ($value,$_POST['id']);
}
}
}
// if the array has values..
if(count($values)){
// implode the values into a string..
$sqlValues = implode(',',$values);
// ..and use that string in the query
$sql = "INSERT INTO table(column1,column2) VALUES $sqlValues";
}