php - compare multi arrays and output in order - php

Question

I have two arrays:
Array 1:
$art_style = ['Title1','Title2','Title3'];
Array 2:
array(
'name' => array('Title1', 'Title3', 'Title2'),
'value' => array('2,0x1,0', '2,5', '15,0'
);
I need to compare Array 2 "name" with Array 1 and output the values from Array 2 in the order of Array 1.
So the output in this case would be:
2,0x1,0 - 15,0 - 2,5
Any Idea how I could achieve that?

Answer 1

Try something like this:
// Array1 order
foreach ($art_style as $key => $value) {
if(in_array($value,$array2['name']))
echo $array2['value'][$key];
}
// Array2 order
foreach ($array2['name'] as $key => $value) {
if(in_array($value,$art_style))
echo $array2['value'][$key];
}

Answer 2

Little Long Method. But, It Worked.
<?
$array1 = ['Title1','Title2','Title3'];
$array2=array(
'name' => array('Title1', 'Title3', 'Title2'),
'value' => array('2,0x1,0', '2,5', '15,0')
);
$SizeofArray2=sizeof($array2['name']);
for($i=0;$i<$SizeofArray2;$i++)
{
$Array2Value= $array2['name'][$i];
for($j=0;$j<sizeof($array1);$j++)
{
if($Array2Value==$array1[$j])
{
if($j==$i)
{
echo " ".$array2['value'][$i];
}
if($j!=$i)
{
echo " -".$array2['value'][$i];
}
}
}
}
?>
Output: 2,0x1,0 -2,5 -15,0

Answer 3

try this:
$art_style = array('Title1','Title2','Title3');
$array2 = array(
'name' => array('Title1', 'Title3', 'Title2'),
'value' => array('2,0x1,0', '2,5', '15,0')
);
foreach ($art_style as $style) {
foreach ($array2['name'] as $id => $name) {
if ($name == $style) {
echo $array2['value'][$id].' - ';
break;
}
}
}