display text if in mysql there is a number - php

Question

I have a database with 4 columns, id, user, vipplan and expire.
What i want to do, is this:
i have my vipplan table, and:
if number 0 is in database: then display "N/A"
if number 1 is in database: then display "Sr.Pro"
if number 2 is in database: then display "No seas"
if number 3 is in database: then display "Level0"
But i do not know how to do it, i post my code:
<?php
echo "<h2>Resultados:</h2><p>";
if(isset($_POST['user']))
{
$find = $_POST['user'];
if ($find == "")
{
echo "<p>Olvidaste poner tu usuario -.-!!!";
exit;
}
mysql_connect("localhost", "root", "2513") or die(mysql_error());
mysql_select_db("invasionvip") or die(mysql_error());
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);
$iname = mysql_query("SELECT * FROM users WHERE usuario LIKE '%$find%'")
or die(mysql_error());
while($result = mysql_fetch_array( $iname ))
{
echo "id:" .$result['id'];
echo "<br>";
echo "usuario:".$result['usuario'];
echo "<br>";
echo "Plan VIP:".$result['planvip'];
echo "<br>";
echo "Vencimiento :".$result['vencimiento'];
echo "<br>";
}
$anymatches = mysql_num_rows($iname);
if ($anymatches == 0)
{
echo "Sorry, but we can not find an entry to match your query...<br><br>";
}
echo "<b>Searched For:</b> " .$find;
}
?>
and my form is very simple:
<form class="pure-form" method="post" action="user.php">
<center>Aqui podrás ver tus servicios activos, como V.I.P, vehiculos, skins, etc.</center><br/>
<span style="text-align:left;font-size:25px;">Usuario: </span>
<input type="text" name="user">
<button type="submit" class="pure-button">Search</button>
</form>
thank you, :)

Answer 1

I believe what you are after is a case select. You should put this in the select line of your query.

Answer 2

there are multiple way that you can achieve this ourput
i thing the easiest way is switch statement second if else if and else third one is array notation which #b0s3 define earlier.
Switch example
switch(expression) {
case 1:
echo "Sr.Pro";
break;
case 2:
echo "No seas";
break;
case 3:
echo "Level0";
break;
default:
echo "N/A";
}
if else example
if( $databaseValue == 1 ){
echo "Sr.Pro";
}else if( $databaseValue == 2 ){
echo "No seas";
}else if( $databaseValue == 3 ){
echo "Level0";
}else{
echo "N/A";
}
Array Example
$yourValues = ['N/A', 'Sr.Pro', 'No seas', 'Level0'];
echo $yourValues[$databaseValue];
now it's up to your which one you like to use

Answer 3

You can use the "case" expression in the mysql select line.
This is a switch statement that allows you to return an arbitrary value for different conditions.
SELECT
CASE number
WHEN 0 THEN "N/A"
WHEN 1 THEN "Sr.Pro"
WHEN 2 THEN "No seas"
WHEN 3 THEN "Level0"
END CASE
FROM table_exemple