get first x rows using in() - php

Question

It's not a duplicate question because I saw and didn't find my answer in those questions.
Table example :
id type title
1 3 sth1
2 4 sthelse
3 3 sth2
4 3 sth3
5 4 sth4
6 4 sth5
I want to get 2 first rows of each type. like this:
id type title
1 3 sth1
3 3 sth2
2 4 sthelse
5 4 sth4
I played with group_by nd limit but look at this forexample:
SELECT * FROM `example` WHERE type IN(3, 4) LIMIT 2;
It gives me :
id type title
1 3 sth1
2 4 sthelse
and by using group_by(type) it gives only 1 row from each type.
Note: I don't want to make a loop for that in php that it will be about 15 or 20 queries but if it can be done using 1 query that's nice.

Answer 1

Here ist a sample how you can do it.
1) sort all results by type
2) then count the row of each type
3) get only ROWs where recno < 3
SELECT
#nr:=IF(#lastid = e.TYPE , #nr:=#nr+1 ,1) AS recno,
#lastid:=TYPE AS last_type, e.*
FROM `example`e,
(SELECT #lastid:=0, #nr:=0) tmp
WHERE TYPE IN(3, 4)
HAVING recno < 3
ORDER BY TYPE;
Result:
MariaDB [tmp]> SELECT
-> #nr:=IF(#lastid = e.TYPE , #nr:=#nr+1 ,1) AS recno,
-> #lastid:=TYPE AS last_type, e.*
-> FROM `example`e,
-> (SELECT #lastid:=0, #nr:=0) tmp
-> WHERE TYPE IN(3, 4)
-> HAVING recno < 3
-> ORDER BY TYPE;
+-------+-----------+----+------+---------+
| recno | last_type | id | type | title |
+-------+-----------+----+------+---------+
| 1 | 3 | 1 | 3 | sth1 |
| 3 | 3 | 3 | 3 | sth2 |
| 1 | 4 | 2 | 4 | sthelse |
| 3 | 4 | 5 | 4 | sth4 |
+-------+-----------+----+------+---------+
4 rows in set (0.00 sec)