How to fetch value from mysql to dropdown list? - php

Question

i am newbie to PHP and MySql. I'm working on small project, some part of this project i have to deal with form and get value back to the field when i need to edit the text. Here's is what i meant
//dropdown list in Create
<select name="color">
while($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
echo '<option>'.$row['colors'].'</option>';
}
</select>
<input type="submit" name="submitcolor"/>
//dropdown list in Edit
<select name="color" value="???????">
</select>
i have no problem submit the value to MySql. The problem is, how to fetch the value back to dropdown list, so i don't have to click and search the value.
Thank you for your suggestion.

Answer 1

Try this
<//dropdown list in Create
<select name="color">
<?php
while($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
echo '<option value="'.$row['colors'].'">'.$row['colors'].'</option>';
}
?>
</select>
<input type="submit" name="submitcolor"/>
//dropdown list in Edit
<select name="color">
<?php
$color = 'some value you fetched from database';
while($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
$selected = '';
if($color == $row['colors']) {
$selected = 'selected';
}
echo '<option value="'.$row['colors'].'" '.$selected.'>'.$row['colors'].'</option>';
}
?>
</select>
You need to have a value in 'option' tag. And on editing, compare the exisiting 'color' value with the edit selectbox value

Answer 2

this is how you can fill a drop down with mysql results
<select name="name">
<?php
$count = count($name);
for ($i = 0; $i < $count; $i++){
"<option $type[$i]['name'] </option>';
}
?>
</select>