Get the $_POST varaible along with the associated $_FILES - php

Question

I have a form.When a user clicks on add a file. Two input fields are appended. One with the input name of the file to be uploaded and another with input field for the file itself
<form>
<label>File 1</label>
<input type="text" name="fileName[]"/>
<input type="file" name="file[]"/>
<label>File 2</label>
<input type="text" name="fileName[]"/>
<input type="file" name="file[]"/>
.
.
.
.
<input type="submit" value="submit"/>
How do i get the corresponding file name and the file together for insertion
Since the text field will be stored in $_POST variable and file in $_FILES

Answer 1

First your form needs to have the attribute enctype="multipart/form-data" like so:
<form type="post" enctype="multipart/form-data">
On submit: you can get both $_FILES and $_POST arrays.
To see what you have, try (if submitted):
echo '<pre>';
print_r($_POST);
print_r($_FILES);
echo '</pre>';
If your file field name attribute was "upload_pic", then your $_FILES array should look like:
Array
(
[upload_pic] => Array
(
[name] => name_of_file
[type] => file_type
[tmp_name] => temporary_name
[error] => 4
[size] => 0
)
)
I believe that gives you any info you need to insert to DB. (E.g. $filename = $_FILES['upload_pic']['name']), add it to the $_POST array and carry on with your insert query.
EDIT:
Re-reading your question, I see:
When a user clicks on add a file. Two input fields are appended. One
with the input name of the file to be uploaded and another with input
field for the file itself...
I was wondering why you need to manually construct a separate text input for the "fileName", since you can obtain it from the $_FILES array (as explained above).

Answer 2

Store what is in $_POST and what is in $_FILES in variables. then you need to open de file with fopen and fwrite the to the file the variable you retrieved from $_POST. Don't forget fclose the file when you are done.