Form action html to php - php

i have
<form action = "https://creator.zoho.com/api/xml/fileupload/scope=creatorapi&authtoken=**************" method="post" enctype="multipart/form-data">
<input type="text" name="applinkname" value="sample">
<input type="text" name="formname" value="Employee">
<input type="text" name="fieldname" value="File_upload">
<input type="text" name="recordId" value="1235667754455">
<input type="text" name="filename" value="profile.jpg" >
<input type="file" name="file">
<input type="submit" value="Update">
</form>
But i must send 2500 files, how can i transform this html to php, my problem is <input type="file" name="file">, how convert it to give a value in php ?
thanks you

You can use $_REQUEST['FILE']=$SOME VARIABLE;
And name is same what you use in your database
then apply enctype="multipart/form-data".

Related

Submitting an image alongside a form with one button

I have a regular form which submits to my database but I want to include a file upload in the form, so as to receive the form input in the expected table using PHP post and also receive the uploaded image.
Use <input type="file"> to include a file upload in the form.
Use something like this to send Files as well as other inputs to the processing page where you can access files and post variables.
<form action="#" method="post" enctype="multipart/form-data">
<input type="text" name="txtbox">
<br />
<input type="file" name="filebox">
<br />
<input type="submit" name="submit" value="submit">
</form>
When this is submitted you can access the data from $_FILES and $_POST
There are various input types in HTML just as the below:
<input type="button">
<input type="checkbox">
<input type="color">
<input type="date">
<input type="datetime-local">
<input type="email">
<input type="file">
<input type="hidden">
<input type="image">
<input type="month">
<input type="number">
<input type="password">
<input type="radio">
<input type="range">
<input type="reset">
<input type="search">
<input type="submit">
<input type="tel">
<input type="text">
<input type="time">
<input type="url">
<input type="week">
Each of the above inputs demand different conditions and formats to be satisfied.
For your query the answer is either:
<input type="file">
For webpages that require inputs in a file format. Or,
<input type="image">
For webpages requiring input in an image format.
For further details view the below link for help:
https://www.w3schools.com/html/html_form_input_types.asp

Values sent to PHP via POST are all empty strings

I have the following form:
<FORM action="http://url.to.mysite.com/doc.php" method="post">
<INPUT type="text" id="name">
<INPUT type="text" id="id">
<INPUT type="submit" value="Send">
</P>
</FORM>
Unfortunately, whatever is typed into the text fields, the PHP script receives only empty strings in every $_POST variable. All of the variables are set, just empty. What can be the cause of that?
You are missing the name properties in your html:
<FORM action="http://url.to.mysite.com/doc.php" method="post">
<INPUT type="text" name="name" id="name">
<INPUT type="text" name="id" id="id">
<INPUT type="submit" value="Send">
</FORM>
Only form elements with a name attribute will be sent to the PHP script (same with POST)
Try this:
<form action="http://url.to.mysite.com/doc.php" method="post">
<input type="text" id="name" name="name">
<input type="text" id="id" name="id">
<input type="submit" value="Send">
</form>
You need to add the name attribute to your input tags. Example: <input type="text" name="name" id="name" />

Why is this form making the fields and variables part of the process form?

I am doing this:
<form action="processform.php" type="post">
<input type="text" name="sample">
<input type="text" name="how">
<input type="checkbox" name="fields" value="fields">Something</input>
</form>
When the submit button is hit, this is what shows in the address bar of the process page:
https://www.domain.com/processform.php?sample=&how=&fields=
Change to <form method="post" />
change type="post" to method="post" for starters
The method attribute specifies the submission type (e.g. "get" or "post"), but you've used the type attribute...and this is incorrect. You need something like:
<form action="processform.php" method="post">
<input type="text" name="sample">
<input type="text" name="how">
<input type="checkbox" name="fields" value="fields">Something</input>
</form>
Your markup is wrong
Try
<form action="processform.php" method="post">
<input type="text" name="sample" value='VALUE' />
<input type="text" name="how" value='VALUE' />
<label for='fields'>Something</label>
<input id='fields' type="checkbox" name="fields" value="Something" />
</form>
<form action="processform.php" method="post">
type needs to be method

How to process multiple forms using one php script

I have multiple forms and I have one php script that I want to use to process these forms but when I click on submit for any of the forms...the script is processed by the number of forms with the submit button named 'submitForm' in this case, the alert will show 3 times instead of once! What am I not doing right?
NB. I hope this makes much sense?
html code
<form action="" name="form1" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<form action="" name="form2" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<form action="" name="form3" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
php script
<?php
if (isset($_POST['submitForm'])) {
echo('<script>alert("Form Submitted")</script>');
}
?>
when I click on submit for any particular form, it submits all the forms.
this is not true.
Once your forms have proper formatting, your browser will submit only current one.
(and PHP has nothing to do here)
however, whole page will be reloaded, if you mean that. That is okay - when you submit a form, a page is intended to reload. If you need another behavior, you have to explain your wishes.
Also note that none of your text fields being sent to the server as they have no names.
I guess the question I should be asking is, how do I pass a particular form to php instead of writing multiple php scripts to handle each form!!!
well, it seems you want to ask how to distinguish these forms.
add a hidden field into each
<input type="hidden" name="step" value="1" />
and then in PHP
if ($_POST['step'] == 1) {
//first form
}
if ($_POST['step'] == 2) {
//second
}
This submits one form of many to php. Copy, paste, test, and study.
<?php
if (isset($_POST['submitForm'])) {
print_r($_POST);
}
?>
<form action="" name="form1" method="post">
<input type="text" value="" name="A" />
<input type="text" value="" name="B" />
<input type="text" value="" name="C" />
<input type="text" value="" name="D" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<form action="" name="form2" method="post">
<input type="text" value="" name="A" />
<input type="text" value="" name="B" />
<input type="text" value="" name="C" />
<input type="text" value="" name="D" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<form action="" name="form3" method="post">
<input type="text" value="" name="A" />
<input type="text" value="" name="B" />
<input type="text" value="" name="C" />
<input type="text" value="" name="D" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
Using a,b,c,d for the first form, e,f,g,h for the second form and i,j,k,l for the third form and submitting the second form yields the following output:
Array
(
[A] => e
[B] => f
[C] => g
[D] => h
[submitForm] => Submit Form
)
#Jay
Actually its not hard.
Once you supply form names, your work is done. the DOM does the rest.
write one php block to do your functions (create/update/retrieve/delete)
Whichever button is clicked, by default it submits only the elements enclosed together with it.
if(!empty($_POST)){
if(isset($_POST['submit'])){
print "<pre>";
var_dump($_POST); // write your code here as you would
print "<pre>";
}
}
try this with your form above.
I know this is an old post but here's how I solve this very problem.
All you need to do is make sure the submit buttons in each form have different names. Eg:
<form action="" name="form1" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm1" />
</form>
<form action="" name="form2" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm2" />
</form>
<form action="" name="form3" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm3" />
</form>
Then, you simply check which form's submit button was pressed.
<?php
if (isset($_POST['submitForm1'])) {
echo('<script>alert("Form 1 Submitted")</script>');
} elseif (isset($_POST['submitForm2'])) {
echo('<script>alert("Form 2 Submitted")</script>');
} elseif (isset($_POST['submitForm3'])) {
echo('<script>alert("Form 3 Submitted")</script>');
}
?>
If you need dynamic forms, you may try below code. While statement can be changed to fetch data from DB and use foreach instead. Hope you know this.
Here, I used while($n<10) for 10 dynamic forms.
You can also use tag as below if you need separate form names.
<form action="" name="form<?=$n?>" method="post">
This will create separate form names such as form1, form2, etc but not necessary here.
<?php
if (isset($_POST['submitForm'])) {
echo '<pre>';
print_r($_POST);
echo '</pre>';
}
$n=0;
while($n<10) {
$n++;
?>
<form action="" name="form1" method="post">
<input type="text" value="" name="A" />
<input type="text" value="" name="B" />
<input type="text" value="" name="C" />
<input type="text" value="" name="D" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<?php
}
?>
Sample page with output when I click row 5..

PHP/HTML form submission

I have the HTML and PHP code
<form name="addaserver" method="post" action="addaserver.php">
<p>Server Name<form method="post">
<input name="servername" type="text" /></form>
<p>Description<form method="post">
<input name="description" type="text" /></form>
<p>Server IP<form method="post">
<input name="ip" type="text" /></form>
<p>Tags (ex: "pvp, economy, fun")<form method="post">
<input name="tags" type="text" /></form>
<form method="post">
<input name="submitserver" type="submit" value="submit" /></form>
</p>
and
(addaserver.php)
$servername=$_POST['servername'];
$desc=$_POST['description'];
$ip=$_POST['ip'];
$tags=$_POST['tags'];
Obviously I'm trying to get the data from the forms...however when I click "submit" it just reloads the page the forms are on. It's probably just some simple error, but I can't figure out what's wrong D:
You're supposed to define only one form, not one for each input:
<form name="addaserver" method="post" action="addaserver.php">
inputs, inputs, inputs, submit
</form>
First thing I see wrong is that you have two separate form tags in the same HTML.
The second one is pretty much useless as it provides no data to any target or action. I would restructure your HTML to be more like this and try it;
<form name="addaserver" method="post" action="addaserver.php">
<p>Server Name<form method="post">
<input name="servername" type="text" /></p>
<p>Description<form method="post">
<input name="description" type="text" /></p>
<p>Server IP<form method="post">
<input name="ip" type="text" /></p>
<p>Tags (ex: "pvp, economy, fun")
<input name="tags" type="text" /></p>
<p><input name="submitserver" type="submit" value="submit" /></p>
</form>
Also take note of the fact that I got rid of all your closing form tags as they would have caused issues too. You only need one closing tag at the very outside most segment of your form's body as shown in the code sample too.
You have way too many <form method="post"> tags in your code.
Your code should start with <form method="post"> and end with </form>, but in between there should only be input fields.
You define action to 'addaserver.php' in the first <form> tag, but the submission button is after a different <form> tag so it doesn't respect that initial target you are setting.
You seem to be enclosing all your input element in different tags. a Form tag is a collection of Form elements that will have their values submitted when the form is submitted. And if you do not specify the action attribute on a form it will (as you say) reload the page. So in the above example if you remove all the tags surrounding the input tags and put them all under the same tag you should get your information posted
Look at http://www.w3schools.com/html/html_forms.asp and http://www.tizag.com/phpT/examples/formex.php for examples on how to do this.
Hope that makes sense.
You only need one form tag for the whole form to submit
<form name="addaserver" method="post" action="addaserver.php">
<p>Server Name
<input name="servername" type="text" /></p>
<p>Description
<input name="description" type="text" /></p>
<p>Server IP<form method="post">
<input name="ip" type="text" /></p>
<p>Tags (ex: "pvp, economy, fun")
<input name="tags" type="text" />
<input name="submitserver" type="submit" value="submit" /></form>
</p>
You're nesting extra form tags throughout your form. You only need one form tag. All of the inputs go inside it.
<form name="addaserver" method="post" action="addaserver.php">
<p>Server Name</p>
<input name="servername" type="text" />
<p>Description<</p>
<input name="description" type="text" />
<p>Server IP</p>
<input name="ip" type="text" />
<p>Tags (ex: "pvp, economy, fun")</p>
<input name="tags" type="text" />
<input name="submitserver" type="submit" value="submit" />
</form>
Try this instead:
<form name="addaserver" method="post" action="addaserver.php">
<p>Server Name: <input name="servername" type="text" /></p>
<p>Description: <input name="description" type="text" /></p>
<p>Server IP: <input name="ip" type="text" /></p>
<p>Tags (ex: "pvp, economy, fun")<input name="tags" type="text" /></p>
<p><input name="submitserver" type="submit" value="submit" /></p>
</form>

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