I tried several options but they are not working, I have 2 pages, page.php and rating.php, on page.php, I have button with this link
< a href=”rating.php/go.php?id=$rows[$id]”>button</a>
, but on page rating.php I have a div with code.
<div id="review" ><?php echo $rows['id'];?></div>
I want that the $rows[$id]from the link rating.php/go.php?id=$rows[$id] could be displayed on div like this . How can I do that to see this $rows[$id] on div?
On page.php you are using < a href="rating.php?id=$rows[$id]">button</a>
If you want $rows[$id] in your rating.php use $_GET
<div id="review" ><?php echo $_GET['id'];?></div>
Read this tutorials too http://www.tutorialspoint.com/php/php_get_post.htm
you get a param from an url with that code snippet:
<div id="review"><?php echo $_GET['id']; ?></div>
the $row[$id] must be a value, it can't be an object
works as :
<div id="review"><?php echo $_GET['id']; ?></div>
Read this:
http://www.formget.com/php-post-get/
Related
I'd like to know if it's possible to open a page (id=26) at a specific position: .
At the front page i'm using this code at the php file to make the title link to the page
<a href="<?php echo get_page_link(26); ?>">
<?php if(!empty( $clean_biz_home_service_title ) ){ ?>
<h2>
<?php echo esc_html( $clean_biz_home_service_title); ?>
</h2>
</a>
Yes, you can use DOM selectors such as #maincontent. You would need to assign an ID to a section on the page and then append it to the trigger URL.
For ex: http://yourdomain.com/index.html#maincontent would take you to that div on the page.
First, in the content of that page (id=26), you need to add an id attribute to some tag, like so:
<div id="myposition">
...
</div>
Next, append #myposition after the get_page_link(26) call:
<a href="<?php echo get_page_link(26); ?>#myposition">
<?php if(!empty( $clean_biz_home_service_title ) ){ ?>
<h2>
<?php echo esc_html( $clean_biz_home_service_title); ?>
</h2>
</a>
And you are done.
<div name="position">
content
</div>
link
example:
if you click the link below you will open this page at #new-answer position
link
How do you change the logo to link to the home URL for all pages except one? I want one page to link to another page when the logo is clicked.
Here is the PHP code for the logo:
<div class="section-boxed section-header">
<?php do_action('pexeto_before_header'); ?>
<div id="logo-container">
<?php
$logo_image = pexeto_option('retina_logo_image') ? pexeto_option('retina_logo_image') : pexeto_option('logo_image');
if(empty($logo_image)){
$logo_image=get_template_directory_uri().'/images/logo#2x.png';
}
?>
<img src="<?php echo $logo_image; ?>" alt="<?php esc_attr(bloginfo('name')); ?>" />
</div>
What about creating a second section of PHP - with a slightly different DIV ID that is called when that paticular page is loaded, rather than this one which is called on all the other pages,
Copy, paste, change DIV ID <div id="logo-container2">, change link address.
In HTML - on the single page that takes them elsewhere - call
<div id="logo-container2">
Would that work?
Try to use template_tag is_page as condition
<div class="section-boxed section-header">
<?php do_action('pexeto_before_header'); ?>
<div id="logo-container">
<?php
$logo_image = pexeto_option('retina_logo_image') ? pexeto_option('retina_logo_image') : pexeto_option('logo_image');
if(empty($logo_image)){
$logo_image=get_template_directory_uri().'/images/logo#2x.png';
}
// Default logo url to home
$logo_url = esc_url(home_url('/');
// if is page about or id 5 anything inside is_page()
if(is_page('about') $logo_url = esc_url(home_url('about');
?>
<img src="<?php echo $logo_image; ?>" alt="<?php esc_attr(bloginfo('name')); ?>" />
</div>
I believe you should be able to use the get_permalink method to check which page you are on, and use an if statement to tell it what the href should be.
<a href="<?= (get_permalink() == '/my-page') ? esc_url(home_url('/go-to-page')) : esc_url(home_url('/')); ?>">
Haven't tested this, but it should work.
I have this site:
link
I installed the plugin Types and tried this code to display the value field in a div.
<div class="selectat">
<div>
<?php $variable = do_shortcode("[types field='descriere' ]");?>
<?php echo $variable;?>
</div>
</div>
My field is called descriere..I put a picture to see more clearly.
Unfortunately this blank although I do not see anything on the site and basically my div is empty ..
It is wrong the way I wrote the code?
I must call another function?
You can help me solve this problem please?
Thanks in advance!
You dont need to use any shortcode you could use
<div class="selectat">
<div>
<?php $variable = the_field( 'descriere' );
<?php echo $variable;?>
</div>
</div>
But if you want to echo the code straight away you can just use get_field('') which echos the value straight to the page.
<div class="selectat">
<div>
<?php $variable = get_field( 'descriere' );
</div>
</div>
I have a PHP page with HTML content in it. Now I run some PHP codes between HTMLs and I get some results. The fact is, when I try to get a respond from this page by AJAX it'll show me the whole page content and plus the result I was looking for. What can I do to prevent the page from writing extra content. I know whenever something get printed on page it'll go as respond to the AJAX call but I want a way to somehow fix this.
My page file (name: page.php):
<?php echo $Content->GetData('HEADER'); ?>
<div id="Content">
<div id="Page">
<?php if($Content->GetData('PAGE','IS_TRUE')) : ?>
<?php if(NULL !== $Content->GetData('PAGE','TITLE')) : ?>
<?php echo $Content->GetPlugins("Page:" . $Content->GetData('PAGE','ID') . ",BeforeTitle"); ?>
<div id="Title" dir="rtl">
<?php echo $Content->GetData('PAGE','TITLE'); ?>
</div>
<?php echo $Content->GetPlugins("Page:" . $Content->GetData('PAGE','ID') . ",AfterTitle"); ?>
<?php endif; ?>
<div id="Content" dir="rtl">
<div style="float: right; width: 966px; padding: 6px">
<?php echo $Content->GetPlugins("Page:" . $Content->GetData('PAGE','ID') . ",BeforeContent"); ?>
<?php echo $Content->GetData('PAGE','CONTENT'); ?>
<?php echo $Content->GetPlugins("Page:" . $Content->GetData('PAGE','ID') . ",AfterContent"); ?>
</div>
</div>
<?php else : ?>
<div id="Content" dir="rtl">
<div style="float: right; width: 966px; padding: 6px">
There is no page like this in our archives.
</div>
</div>
<?php endif; ?>
</div>
</div>
<?php echo $Content->GetData('FOOTER'); ?>
If I write an address in my browser like this localhost/cload/blog?action=rate it'll go through my redirection list and show the page.php with blog plugin loaded. The problem is I want to call my blog plugin by AJAX through this address but it will first render the page data.
Sorry if this is messy.
I'd suggest modifying page.php to be some functions, primarily a data processing function, and then an output function. Then, when you load the page, put a check in for whether it's an AJAX request, and if so, echo the data you want as JSON, otherwise render the page using the output function.
Alternatively, you could create a second, separate page, but that could be more difficult to maintain than a single file.
Yes, you should check whether your request is a ajax request, if it is so you should change your response to return only the result whatever want.
This php code will give an rough idea on this.
if($request->isXmlHttpRequest()){
return new Response(json_encode($data_array));
}
Hope this will help.
In hiddenModalContent div is it possible to display the database value as once thickbox is opening it just showing nothing
<?php
foreach($this->list_details as $key=>$details)
{?>
<div class="sc_content_subheading"><? echo $this->escape($details['list_name'])?></div>
<div id="hiddenModalContent" style="display:none;">
<span class="content_subheading">List name </span><? echo $details['list_name'];?><br/>
</div>
<?php }?>
It seems all you are only outputting the list name. What else in the array would you like to show?