I have a CDBCriteria here:
$criteria = new CDbCriteria;
$criteria->select = array('t.lastname', 't.name', 't.patronomic', 't.dob', 'n.nationality', 't.token', 'm.status');
$criteria->join = 'LEFT JOIN hrp_nationalities n ON (n.id = t.nationality_id) ';
$criteria->join .= 'LEFT JOIN hrp_marital_status m ON m.id = t.marital_status_id';
$criteria->condition = "t.`alive` = 1 AND t.`org_id` = ".$_SESSION['org_id'];
$criteria->order = 't.id DESC';
My question is why m.status and n.nationality are not retrieved into the resulting object?
If you are using the CDbCriteria on a model class eg $results = User::model()->findAll($criteria); then the result will contain only fields from user table, not the relations'. The reason is that when the resultant model objects are created there is no field declared for the relation columns in the model.. So you need to create fields in the model..
in your case nationality, status
Just write in your model
public $nationality;
public $status;
And if your model also has a field named status, use an alias for the relation's field status..
public $m_status;
$criteria->select = array('t.lastname', 't.name', 't.patronomic', 't.dob', 'n.nationality', 't.token', 'm.status as m_status');
I just remember I have answered an old similar question.. Read answer here: https://stackoverflow.com/a/11594530/1114536
Related
$criteria->select = 't.*,count(business_unit.id) as TotalBusinessUnits,count(users.id) as TotalUsers ,count(positions.id) as TotalPositions, count(skills.id) as TotalSkills , users.first_name , users.last_name, count(question_bank.id) as TotalQuestions';
$criteria->condition = "`t`.status = '1'";
$criteria->group = 't.id';
$criteria->order = 'created DESC';
$criteria->join = " inner join users on users.company_id = `t`.id";
$criteria->join .= " left join business_unit on business_unit.company_id = `t`.id";
$criteria->join .= " left join billingdetails on billingdetails.company_id = `t`.id";
$criteria->join .= " left join positions on positions.company_id = `t`.id";
$criteria->join .= " left join skills on skills.company_id = `t`.id";
$criteria->join .= " left join question_bank on question_bank.company_id = `t`.id";
It works fine and get all columns which I select.
But when I pass it in CActiveDataProvider it gets only this attributes.
return new CActiveDataProvider($this, array(
'criteria'=>$criteria,
'pagination' => $pages
));
How I select all columns?
In Yii if you are using as for sql, it needs a public variable to store the value in.
add all your custom column names as public variables on the model and all should be dandy.
so if you have $criteria->select = 't.*,count(business_unit.id) as TotalBusinessUnits, this will create the corresponding sql . but Yii does not recognise TotalBusinessUnits as a valid column on the table.
So if you add public $TotalBusinessUnits; in your model Yii has a place to store this value.
Also you should then add TotalBusinessUnits to your safe attributes rule so that Yii knows it safe to fetch.
public $TotalBusinessUnits;
public function rules(){
return array(
// your rules
array('TotalBusinessUnits','safe'),
);
}
public function search(){
$criteria->select = 't.*,count(business_unit.id) as TotalBusinessUnits';
// your criteria
return new CActiveDataProvider($this, array(
'criteria' => $criteria,
));
}
My code :
$criteria = new CDbCriteria();
// $criteria->select = array("id");
$criteria->with = array('userProfiles'=>array(
'select'=>'firstname'
));
$criteria->together = true;
$criteria->condition = "firstname like '%$q%' "
. "and (user_id not in (select id2 from friends where id1=$user_id) "
. "and user_id not in (select id1 from friends where id2=$user_id))";
$dataProvider = new CActiveDataProvider("Users", array(
'criteria' => $criteria
));
return $dataProvider;
Notes:
1- userProfiles relation is defined in User module
Issue:
It is loading data only from User table not also from the user_profiles table despite of providing select atribute 'select'=>'firstname'
I want data from both user and userProfile table.
Relation self::HAS_ONE can't be executed together with main query, try use join
$criteria->select = "*, user_profiles.firstname firstname";
$criteria->join = 'user_profiles ON user_profiles.user_id = users.id';
Something like this, but you should create firstname field in User AR to retrieve it.
Or change relation to HAS_MANY and check first entity of array.
together: whether the table associated with this relationship should be forced to join together with the primary table and other tables. This option is only meaningful for HAS_MANY and MANY_MANY relations.
Because you can't write query that will give you only one record for each joining record
SELECT * FROM main
INNER JOIN slave ON (slave.main_id = main.id limit 1) // will not work);
I try to get this mysql query to work with Yii model but i can't.
SELECT COUNT( qhc.countries_id) AS counter, q.question, co.name
FROM questions AS q , countries as co, questions_has_countries AS qhc
WHERE qhc.questions_id = q.id
AND co.id = qhc.countries_id
GROUP BY question
HAVING counter = 2
So far i have this, but somehow thou it seems ok, it doesnt work :
$criteria = new CDbCriteria();
$criteria->select = 'question, COUNT(countries_id) as counter';
$criteria->with = array('countries', 'categories');
$criteria->addInCondition('countries.id' , $_POST['Questions']['countries']);
$criteria->group = 'question';
$criteria->having = ('counter = 1');
$model = Questions::model()->findAll($criteria)
Pls help, I'am pretty new to Yii framework.
Thanks.
Sql from the log :
SELECT `t`.`question` AS `t0_c1`,
COUNT(countries_id) as counter, `t`.`id` AS `t0_c0`, `countries`.`id` AS
`t1_c0`, `countries`.`name` AS `t1_c1`, `categories`.`id` AS `t2_c0`,
`categories`.`name` AS `t2_c1` FROM `questions` `t` LEFT OUTER JOIN
`questions_has_countries` `countries_countries` ON
(`t`.`id`=`countries_countries`.`questions_id`) LEFT OUTER JOIN `countries`
`countries` ON (`countries`.`id`=`countries_countries`.`countries_id`)
LEFT OUTER JOIN `questions_has_categories` `categories_categories` ON
(`t`.`id`=`categories_categories`.`questions_id`) LEFT OUTER JOIN
`categories` `categories` ON
(`categories`.`id`=`categories_categories`.`categories_id`) WHERE
(countries.id=:ycp0) GROUP BY question HAVING (counter = 2). Bound with
:ycp0='1'
You have done most of work. Now you need to call the $criteria into model. Just like this
$rows = MODEL ::model()->findAll($criteria);
Where MODEL is model class of table which you want to apply criteria on.
To learn more about this you can follow this CActiveRecord Class.
Try to set together in CDbCriteria
...
$criteria->together = true;
$model = Question::model()->findAll($criteria);
when you use "as counter", your model must have a property named "counter" or it will not load it into your model.
if you don't have a property named "counter", try using another one of your models property that you are not selecting right now : "as someColumn"
and use condition or addCondition or .. instead of having
cheers
I am trying to do a Join query using CDBCriteria in Yii framework. The issue is the join query works successfully but it does not display the columns from other tables.
I am doing in the following way
$criteria = new CDbCriteria;
$criteria->order = 't.id desc';
$criteria->select = '*';
$criteria->join = ' INNER JOIN table2 INNER JOIN table3 INNER JOIN table4';
When i run this, I can see only the mail table1 columns displayed. Other columns are not shown.
In my model class, I have the relation has
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'user' => array(self::BELONGS_TO, 'DmPhoneUser', 'user_id'),
'command' => array(self::BELONGS_TO, 'DmOtaCommand', 'command_id'),
'partner' => array(self::BELONGS_TO, 'DmPartner', 'partner_id'),
);
}
********************************************************
public function actionGetHistory($start, $per_page)
{
$partner_id = '10';
$criteria = new CDbCriteria;
$criteria->order = 't.history_id desc';
$criteria->select = 't.*, table2.*';
$criteria->join = ' INNER JOIN table2 ON t.command_id = table2.command_id';
$result = Table_1_class::model()->with('command')->findAll();
$history_data = CJSON::encode($result);
echo $history_data;
}
here command_id is common in table1 and table2.
This is how I am using the criteria code.
As I said, Yii's Active Record implementation will only use columns which are defined in the table itself or the tables you are linking to through with, not arbitrary columns you return in the resultset.
Solution 1: Define a relation to table2, add that relation to with, and get rid of join. Then you'll probably need to convert each returned object to an array - CJSON::encode will not handle a model with relations well.
Solution 2: Use Yii::app()->db->createCommand("SQL query")->queryAll(); instead of Active Record. This will produce an array of arrays, which CJSON::encode will have no problem with.
How I can write the query
SELECT *
FROM doc_docs dd
JOIN doc_access da
ON dd.id=da.doc_id
AND da.user_id=7
with CDbCriteria syntax?
You actually cant completely write that since you have to apply the criteria to an activerecord model to obtain the primary table, but assuming you have a DocDocs model you can do it like this:
$oDBC = new CDbCriteria();
$oDBC->join = 'LEFT JOIN doc_access a ON t.id = a.doc_id and a.user_id = 7';
$aRecords = DocDocs::model()->findAll($oDBC);
Although it might be a lot easier if you give your DocDocs model a relation with doc_access, then you don't have to use the dbcriteria:
class DocDocs extends CActiveRecord
{
...
public function relations()
{
return array('access' => array(self::HAS_MANY, 'DocAccess', 'doc_id');
}
...
}
$oDocDocs = new DocDocs;
$oDocDocs->id = 7;
$aRecords = $oDocDocs->access;
Should give you a fairly good idea how to start...