I have two tables.
table 1 - with 500+ keywords
id
keyword
table 2
id
title
desc
content
...
I'm looking for best way to select all records from table 2, where title field contain one or more keywords from table 1. I think LIKE, REGEX isn't good choice due to performance. To first and the second table, I constantly add new records.
I would use concat and like like so:
SELECT * FROM table_2 AS t2
LEFT JOIN table_1 AS t1 ON t2.title LIKE CONCAT('%', t1.keyword, '%');
Check this SQL FIDDLE
Related
For example, lets say in column source I have the following entries
SourceFileEmbed122
SourceFile1333
SourceItem13366
PreLoadSource7755
And I do a query of SourceFile it should match row 1 and 2 and show me all the column data for that row, but if I search for example: PreLoadSource or SourceItem it shouldnt show anything, as there is only 1 row that has a similar entry.
Kinda like an if contains sort of thing.
Basically, I want to do something like:
SELECT source, COUNT(*) TotalCount FROM sources GROUP BY source HAVING COUNT(*) > 1 ORDER BY COUNT(*) DESC
But the query does LIKE instead of LIKE%...% (Like in PHPMyAdmin) which results in it only matching EXACT matches of each other, so stuff like:
row123/
row123
Wont match each other and will be ignored. But I want this to MATCH basically if row123's full text is ALSO all in another row's value, then match.
Lets say I have:
http://link.ext/dir123/file.mp3
http://link.ext/dir123
http://link.ext/dir123/file2.mp3
http://link.ext/dir123
The query should match .../file.mp3, .../file2.mp3 and ../dir123 because row 2 http://link.ext/dir123 is also in row 1, 3 and 4.
One way is doing a inner join with the same table,
if you need a simple count you can do something like that:
SELECT s1.source, COUNT(*)
FROM sources s1
INNER JOIN sources s2
ON s1.id <> s2.id AND s1.source LIKE CONCAT('%', s2.source, '%')
GROUP BY s1.source
One way to test for at least two matches is:
select s.*
from sources s
where s.source like '%<whatever>%' and
exists (select 1
from source s2
where s2.source like '%<whatever>%' and
s2.source <> s.source
);
I'm kind of noobie to this, but I'm trying to learn, I have two tables, the first one (NEWS) has all the information about posts of a blog, it has the follow structure:
* NEWS (TABLE 1)
- id_new
- id_category
- date
- ...etc
- **likes**
and I have a second table:
* LIKES (TABLE 2)
- id_like
- id_new
- id_user
- date
- ip_user
So, I want to select all the rows from TABLE 1 to display all the news but also i want to count the likes and get the COUNT of each new as like column.
This approach left joins the NEWS table to a subquery which finds the number of likes for each news story.
SELECT
t1.*,
COALESCE(t2.likes, 0) AS likes
FROM NEWS t1
LEFT JOIN
(
SELECT id_new, COUNT(*) AS likes
FROM LIKES
GROUP BY id_new
) t2
ON t1.id_new = t2.id_new
Note that here a story having no likes would not appear at all in the LIKES table and would receive a count of zero. Also note that I assume that every record in the LIKES table corresponds to a logical like. If not, then the query could be modified to count something else.
You can do it like this
SELECT table1.*, table2.*, count(table2.id_like) as like FROM news AS table1
INNER JOIN likes AS table 2 ON table1.id_new = table2.id_new;
OR
SELECT table1.*, table2.*, count(table2.id_like) as like FROM news AS table1
LEFT JOIN likes AS table 2 ON table1.id_new = table2.id_new;
you can use prepared statement
for example
$stmt = $pdo->prepare("SELECT count(*) FROM TABLE_1);
$stmt2 = $pdo->prepare("SELECT count(*) FROM TABLE_2);
//then execute
just read more on prepared statement
Try this
SELECT n, (SELECT count(*) FROM like l WHERE l.id_new = n.id_new) FROM news n
Use something like :
SELECT *, (SELECT COUNT(*) FROM LIKES WHERE LIKES.id_new =id_new) AS newsLikesCount FROM NEWS ORDER BY date;
This query would return all news and their number of likes
select n1.* , numberOfLikes.number_of_likes
from news n1
left join
(select n.id_news, count(l.id_like) as number_of_likes
from news n
left join likes l on n.id_news = l.id_new
group by n.id_news) numberOfLikes on n1.id_news = numberOfLikes.id_news
The important concepts here is understanding how two tables are joined together (1), how group by works(2), and how to aggregate l.id_likes using count(3).
(1). Left join preserves everything in the NEWS table and join them
with news link to the news.
(2). Then we group the rows base on id_news from the news. However,
mysql gets confused because it doesn't know what to do with id_like
from the likes table that we included in our select clause. Don't
worry my friend, This is where count comes in.
(3). We count the number of id_likes base for each id_news since we
are grouping the rows base on id_news.
I hope this helps. and welcome to StackOverfow. If you find this answer of any other answer helpful please mark it as the solution. That way it will help the community and fellow programmers in the future if they run into the same problem as you. Cheers.
Edit: to include all columns from news table we simply join the result from above back to the news table itself. and we select everything from the news table n1 and only number_of_likes from the result we created above.
I am having 3 tables (c19 , c19b2, g26) in a database
I want to write a SQL Query to search and display all fields of the matched record.
I am using following query:
$query = "SELECT * FROM c19,c19b2,g26 WHERE armyno LIKE '%$searchTerm%'";
But it only works for table c19,
Data from the other 2 tables is not fetched.Each table has a field armyno
Please help me with this
Thank you.
Alright, you are not looking for a JOIN, but a UNION.
SELECT * FROM c19 WHERE armyno LIKE '%$searchTerm%'
UNION
SELECT * FROM c19b2 WHERE armyno LIKE '%$searchTerm%'
UNION
SELECT * FROM g26 WHERE armyno LIKE '%$searchTerm%'
That will let you query all three tables at the same time.
Which DB are you using? This would have worked in SQL Server. However, notice you are doing a cross join of every record to every record... usually you only want to match some records by restriction of a matching key, for example:
select
*
from a
left join b on b.somekey = a.somekey
left join c on c.someotherkey = b.someotherkey
In SQL server you can just say *, but I'm taking it that in your DB engine that didn't work, so try specifying which table. This may in some environments require aliasing as well:
select
a.*,
b.*,
c.*
from tableA as a
left join tableB as b on b.somekey = a.somekey
left join tableC as c on c.someotherkey = b.someotherkey
Generally, you should see the columns from the first table, followed by the columns from the second table, followed by columns from the third table for a given row. If you wanted to get all columns from all tables, but separately, then that would be 3 separate selects.
Lastly, if all 3 tables have "armyno" then I'd expect it to throw an ambiguous field error. In such case you'd want to specify which table's "armyno" field to filter on.
I have a table with around 15 columns. What I would like to be able to do, is select a range of IDs and have all column data that is the same, presented to me.
At the minute, I have it structured as the following:
SELECT id, col_a, col_b ... count(id)
FROM table
GROUP BY col_a, col_b ...
Which returns rows grouped together that have identical data within all the rows - which is half what I want, but ideally I would like to be able to get a single row with either the value (if it's the same for every row id) or NULL if there is a single difference.
I'm not sure that it is possible, but I would rather see if it's doable in an SQL query than write some looping logic for PHP to go through and check each row's similarity.
Thanks,
Dan
UPDATE:
Just to keep this up-to-date, I worked through the problem by writing a PHP function that would find which were duplicates and then display the differences. However I have now since made a table for each column, and made the columns as references to the other tables.
E.G. In MainTable, ColA now refers to the table ColA
I'm still solving the problem with the PHP for the time being, mainly as I think it still leaves the problem mentioned above, but at least now Im not storing duplicate information.
Its a hairy thing to do, but you could do it similarly to how David Martensson suggested, I would write it like this, however:
Select a.id, a.col1, a.col2, a.col3
FROM myTable a, myTable b
WHERE a.id != b.id
and a.col1 = b.col1
and a.col2 = b.col2
and a.col3 = b.col3
That would give you the ids that are unique, but each result would have the same values for columns 1, 2, and 3. However, I agree with some of the commenters to your question that you should consider an alternative data structure, as this could better take advantage of an RDBMS model. In that case you would want to have 2 tables:
Table name: MyTableIds
Fields: id, attrId
Table name: MyTableAttrs
Fields: attrId, attr1, attr2, attr3, ect
In general, if you have data that is going to be duplicated for multiple records, you should pull it into a second table and create a relationship so that you only have to store the duplicated data 1 time and then reference it multiple times.
Make a join to a subquery with the group by:
SELECT a.id, b.col_a, b.col_b ... b.count)
FROM table a
LEFT JOIN (
SELECT id, col_a, col_b ... count(id) "count"
FROM table GROUP BY col_a, col_b ...
)b on a.id = b.id
That way the outer will select all rows.
If you still want to group answers you could use a UNION instead
SELECT id, col_a ...
WHERE id NOT IN ("SUBQUERY WITH GROUP BY")
UNION
"SUBQUERY WITH GROUP BY"
Not the nicest solution but it should work
It seems doable from how I have understood your question.
And here's a possible pattern:
SELECT
/* GROUP BY columns */
col_A,
col_B,
...
/* aggregated columns */
CASE MIN(col_M) WHEN MAX(col_M) THEN MIN(col_M) ELSE NULL END,
CASE MIN(col_N) WHEN MAX(col_N) THEN MIN(col_N) ELSE NULL END,
...
COUNT(...),
SUM(...),
WHATEVER(...),
...
FROM ...
GROUP BY col_A, col_B, ...
SELECT DISTINCT business.name AS businessname
,business.description AS description
FROM business
, category
, sub_categories
WHERE business.cityID = '$city'
AND (category.name LIKE '%$name%'
OR sub_categories.name LIKE '%$name%')
AND business.status = 0
Pls the above SQL code is suppose to search a set of two tables the ones in the bracket and return the result, but for some reason, it's not doing so. What am i doing wrong?
Thank You.
Your query would produce a cartesian product. Depending on the size of your tables that could take a considerable amount of time.
Based on your clarification I'd use a subquery to check for matching categories, this way you don't have to use distinct in your query as it would only return each business once. I also suggest you to start with a decent SQL tutorial.
SELECT name AS businessname
,description AS description
FROM business
WHERE cityID = '$city'
AND status = 0
AND ( categoryID in (select id from category where name like '%$name%')
or subcategoryID in (select id from sub_categories where name like '%$name%')
)
Two things come to mind:
You are not joining any of the three tables together. Consider adding a few LEFT JOIN clauses.
You are selecting columns from only one table. If you wanted columns from other tables, you should add them to your SELECT clause.