PHP quit after I update an associative array - php

Question

I have a really weird problem, I am doing a script that executes a symfony command.
Here it is :
<?php
$checkname = 'symfony_checker';
$sensu_ip = '192.168.13.000';
$port = 3002;
function write_to_sensu($json)
{
echo('writing');
try
{
$fp = fsockopen($sensu_ip, $port, $errno, $errstr, 10);
if ($fp)
{
fwrite($fp, $json);
fclose($fp);
}
}
catch (Exception $E)
{
}
}
ini_set('max_execution_time', 0);
require_once dirname(__DIR__).'/app/bootstrap.php.cache';
require_once dirname(__DIR__).'/app/AppKernel.php';
use Symfony\Bundle\FrameworkBundle\Console\Application;
use Symfony\Component\Console\Input\ArrayInput;
use Symfony\Component\Console\Output\BufferedOutput;
$input = new ArrayInput(array(
'command' => 'security:check',
'--format' => 'json',
));
$output = new BufferedOutput();
$kernel = new AppKernel('dev', true);
$application = new Application($kernel);
$application->setAutoExit(false);
$application->run($input, $output);
$payload = array(
'name' => $checkname,
"status" => 0
);
$payload = json_encode($payload);
$arr = json_decode($output->fetch());
$vulnerabilites = array();
foreach ($arr as $key => $errors)
{
$var = 0;
foreach ($errors as $error)
{
if ($var == 1)
{
foreach ($error as $key => $one)
array_push($vulnerabilites, $key);
}
$var++;
}
}
$vulnerabilites = implode(' ', $vulnerabilites);
$payload['output'] = 'Vulnerabilities found : ' . $vulnerabilites;
dump($vulnerabilites);
write_to_sensu($payload);
Problem is that the program leave at the line :
$payload['output'] = 'Vulnerabilities found : ' . $vulnerabilites;
If I comment this line the code continue fine and goes to my function write to sensu.
If I just update $payload['output'] with a random string it doesn't work either.
Every time I try to update payload, the program quit! Anywhere in the code.
Have any idea why ?

Answer 1

You are converting $payload into a string with the line
$payload = json_encode($payload);
so you cannot use it as an array anymore. Either assign the result of json_encode() to another variable, or update your array before the conversion.

Answer 2

You've already encoded your array to JSON before you attempt to add the vulnerabilities. So you're treating a string as an associative array.
You just need to move your line
$payload = json_encode($payload);
to after this line:
$payload['output'] = 'Vulnerabilities found : ' . $vulnerabilites;