How to add a link in php [duplicate] - php

This question already has answers here:
PHP parse/syntax errors; and how to solve them
(20 answers)
Closed 7 years ago.
Hi I'm kind of new to the site and to php. I am trying to make a code which tells hello to a user if logged in or displays the Register/Login form if the user is logged out. Following is the code for it :
<?php if(empty($_SESSION['user']))
{echo " <a href=register.php >Register </a> Or <a href=login.php>Login</a>" ;
}
else{
Hello htmlentities($_SESSION['user']['username'], ENT_QUOTES, 'UTF-8'); you currently have $_SESSION['user']['point']; points !
}. ?>
But it gives me an error :
PHP Error Message
Parse error: syntax error, unexpected T_STRING in /home/a3897717/public_html/index1.php on line 63
And the 63rd line is this one :
Hello htmlentities($_SESSION['user']['username'], ENT_QUOTES, 'UTF-8'); you currently have $_SESSION['user']['point']; points !
Please if anyone can help me, Please help !
Thanks in advance ! This not the duplicate i just want someone to tell me where i am wrong and correct that mistake .

You missed a echo before your output string:
echo "Hello " . htmlentities($_SESSION['user']['username'], ENT_QUOTES, 'UTF-8');
echo "you currently have " . $_SESSION['user']['point'];
echo "points !";

You're messing up with the concatenation.
Change this:
echo "<a href=register.php >Register </a> Or <a href=login.php>Login</a>";
to this:
echo "<a href='register.php'>Register </a> Or <a href='login.php'>Login</a>";
and this:
Hello htmlentities($_SESSION['user']['username'], ENT_QUOTES, 'UTF-8'); you currently have $_SESSION['user']['point']; points !
to this:
echo "Hello " . htmlentities($_SESSION['user']['username'], ENT_QUOTES, 'UTF-8') . "you currently have " . $_SESSION['user']['point'] . "points!";
EDIT:
Since I could not find a online PHP/HTML compiler, to show that the above code works I have attached a picture:
Note: It is obvious that the error is shown as the sessions are not
defined and neither was the core problem of this question.

Related

How to use link (href) in specific part at php echo? [duplicate]

This question already has answers here:
Add PHP variable inside echo statement as href link address?
(8 answers)
Closed 3 years ago.
I want to make underline at specific part using href in php.
Please help..
Here is my code..
echo "Welcome " . $row1['name'] . "Sir ";
//I want to make underline only this part: $row1['name'];
You can actually put anchor tag directly inside your php echo
echo "Welcome <a href='#yourlink'>" . $row1['name'] . "</a> Sir ";
<?php
echo " Welcome <a href='hyperlink'>" . $row1['name'] . "</a> Sir ";
?>
This will work, without any flow

How to display quote marks within an If statement [duplicate]

This question already has answers here:
Reference - What does this error mean in PHP?
(38 answers)
Closed 5 years ago.
I have the below code with a shortcode for a contact form within an if statement, but the contact form doesn't show. I think its because I have displayed quote marks in the wrong place, but i'm a bit confused as to where they should go
My code is:
<?php
if ($postid == "page-international.php" or $postid == "page-international-training.php" or $postid == "page-international-courses.php" or $postid == "page-international-training-course-detail.php") {
echo "<div class='get-ebook'><img class='close-ebook' src='https://www.pescado.co.uk/wp-content/themes/entyce/images/close-button-get.png' /><p class='title'><strong>Is your <br>scaffolding safe?</strong></p><span class='img'><img src='http://dev14.entycestudio.co.uk/wp-content/themes/custom/images/get-ebook.png' />
</span><?php echo do_shortcode('[contact-form-7 id='6664' title='ebook']' ); ?>
</div>";
} else {
echo "";
}
?>
If anyone could help, or point me in the right direction, it would be greatly appreciated :-)
Thanks
your problem might be the fact you have do_shortcode in a echo ""; try removing it from there. like so
echo "<div class='get-ebook'><img class='close-ebook'
src='https://www.pescado.co.uk/wp-content/themes/entyce/images/close-
button-get.png' /><p class='title'><strong>Is your <br>scaffolding
safe?</strong></p><span class='img'><img
src='http://dev14.entycestudio.co.uk/wp-content/themes/custom
/images/get-ebook.png' />
</span>";echo do_shortcode('[contact-form-7 id="6664" title="ebook"]' );
echo "</div>";
} else {
echo "";
}

php can't find syntax error in echo line [duplicate]

This question already has answers here:
PHP parse/syntax errors; and how to solve them
(20 answers)
Closed 5 years ago.
So I am getting the following parse error when this file loads:
Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE),
expecting identifier (T_STRING) or variable (T_VARIABLE) or number
(T_NUM_STRING)
I have tried everything to work out why and I narrowed it down to the
href=\"start.php?id=<?php echo $res['id'] ?>\"
section of the code. I am sure I left out a ' or " but unsure where as
it all makes sense to me. Can anyone with a keener eye see where I am
going wrong? Thank you.
My code:
<td>
<?php if($res['ndaSent'] == "No") {
echo "<span class=\"buttonTestDisabled\"> Start Test</span>";}
else {
echo "<a class=\"buttonTest\" href=\"start.php?id=<?php echo $res['id']
?>\">Start Test</a> ";}
?>
</td>
Take a look at that. You can't use echo command inside of an echo " " line. Try using ' inside and not \ may help you too from confusion.
<?php if($res['ndaSent'] == "No") {
echo "<span class='buttonTestDisabled'> Start Test</span>";
}else{
echo "<a class='buttonTest' href='start.php?id=".$res['id'].">Start Test</a>';}
?>
</td>

php if then else statement syntax error somewhere [duplicate]

This question already has answers here:
PHP parse/syntax errors; and how to solve them
(20 answers)
Closed 5 years ago.
So I am getting the following parse error when this file loads:
Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE),
expecting identifier (T_STRING) or variable (T_VARIABLE) or number
(T_NUM_STRING)
I have tried everything to work out why and I narrowed it down to the
href=\"start.php?id=<?php echo $res['id'] ?>\"
section of the code. I am sure I left out a ' or " but unsure where as it all makes sense to me. Can anyone with a keener eye see where I am going wrong? Thank you.
My code:
<td>
<?php if($res['ndaSent'] == "No") {
echo "<span class=\"buttonTestDisabled\"> Start Test</span>";}
else {
echo "<a class=\"buttonTest\" href=\"start.php?id=<?php echo $res['id'] ?>\">Start Test</a> ";}
?>
</td>
echo "<a class=\"buttonTest\" href=\"start.php?id=<?php echo $res['id'] ?>\">Start Test</a> ";
}
Is incorrect, you are closing the PHP code before you are done with the PHP code. And $res['id'] cannot be in your echo like that, you should interpolate the variable correctly in the string. Remove the starting and closing tag inside the echo like this:
echo "<a class=\"buttonTest\" href=\"start.php?id={$res['id']}\">Start Test</a> ";
Please check this awesome guide on how to fix these kind of syntax errors.
You cant had snippet in echo use simple string concatenation
<td>
<?php if($res['ndaSent'] == "No") {
echo "<span class=\"buttonTestDisabled\"> Start Test</span>";}
else {
echo "<a class=\"buttonTest\" href=\"start.php?id=".$res['id']."\">Start Test</a> ";}
?>
</td>
Try this
echo "<a class=\"buttonTest\" href=\"start.php?id=" . $res['id'] . " \">Start Test</a> ";}

PHP include() gets error [duplicate]

This question already has answers here:
PHP parse/syntax errors; and how to solve them
(20 answers)
Closed 6 years ago.
I have 35.php that includes common menu for my website. 36.php page should display the menu by using include()
Why doesn't this work?
My error:
35.php is shown below;
<?php
echo "Home
PHP
HTML
CSS <br />";
?>
36.php is shown below;
enter code here
<html>
<body>
<?php include("35.php"); ?>
<p>About Menu is imported from 35.php file</p>
</body>
</html>
You missused the ". They include the string but you also used them for the href. But that closes the string
echo "<a href="
This is where the String ends for PHP and it wants either a ; fo finish the statement or a . to connect it to another string.
So this is what you could to to solve it:
echo 'Home
PHP
HTML
CSS <br />';
With switching the "to a ' The string symbol is now the ' and therefor the " can be used int he string normaly.
Otherwise you could also escape the " like this \" inside the string:
echo "Home ...

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