I have the following query:
SELECT DISTINCT id, title
FROM
((SELECT
DISTINCT offers.id AS id, offers.title AS title
FROM offers
INNER JOIN categories
ON offers.category=categories.title
WHERE categories.title="Fashion clothes"
GROUP BY offers.id
ORDER BY offers.id)
UNION ALL
(SELECT
DISTINCT offers.id AS id, offers.title AS title
FROM offers
INNER JOIN cities
ON offers.city=cities.title
WHERE cities.title="Australia"
GROUP BY offers.id
ORDER BY offers.id)) as subquery
I would like to fetch from the table offers the rows that have category=Fashion clothes and city=Australia but when I use Union it returns all the rows .
I don't know how to make it work. If anyone can help i would appreciate it.
You don't need a union for this. Just join all the tables and have both conditions in you where clause:
SELECT
DISTINCT offers.id AS id, offers.title AS title
FROM offers
INNER JOIN categories
ON offers.category=categories.title
INNER JOIN cities
ON offers.city=cities.title
WHERE categories.title="Fashion clothes" AND cities.title="Australia"
ORDER BY offers.id
As noted by RubahMalam you don't even need the joins as you are joining the tables by title, so the query can be simplified to:
SELECT
DISTINCT offers.id AS id, offers.title AS title
FROM offers
WHERE offers.category="Fashion clothes" AND offers.city="Australia"
ORDER BY offers.id
However, it would probably be best to have separate unique id's in all your tables and use those to join them in your queries, but that's another story.
You just need :
SELECT id,title
FROM offers
WHERE category = "Fashion clothes" OR city = "Australia"
GROUP BY id,title
ORDER BY offers.id
You don't even need INNER JOIN for this. And as patrickh003 said, you don't even need GROUP BY if id is unique column.
If you want both, then you can use aggregation and a having clause:
SELECT o.id, o.title
FROM offers o
WHERE o.category = 'Fashion clothes' AND o.city = 'Australia'
GROUP BY o.id, o.title
HAVING COUNT(*) = 2
ORDER BY o.id;
If you can have duplicates in the offers table, then you need COUNT(DISTINCT o.category) in the HAVING clause instead of COUNT(*).
Related
I'm trying to replace the value of "transfers.pickup_areas_group_id" and "transfers.drop_areas_group_id" with the values from the table "areas_group", using IDs
I'm using this query:
SELECT
transfers.id AS transfer_id,
transfers.name AS transfer_name,
transfers.pickup_areas_group_id AS transfer_pickup_areas_group_id,
transfers.drop_areas_group_id AS transfer_drop_areas_group_id,
transfers_pricing.vehicle_id AS vehicle_id,
transfers_pricing.date_start AS date_start,
transfers_pricing.date_end AS date_end,
transfers_pricing.price AS price
FROM transfers
INNER JOIN transfers_pricing ON transfers_pricing.transfer_id = transfers.id
I tried an extra INNER JOIN to replace the first value "transfers.pickup_areas_group_id", but I couldn't find a way to replace the second one "transfers.drop_areas_group_id"
I tried this query:
SELECT
transfers.id AS transfer_id,
transfers.name AS transfer_name,
transfers.pickup_areas_group_id AS transfer_pickup_areas_group_id,
areas_group.area_id AS pickup_area_ids,
transfers.drop_areas_group_id AS transfer_drop_areas_group_id,
transfers_pricing.vehicle_id AS vehicle_id,
transfers_pricing.date_start AS date_start,
transfers_pricing.date_end AS date_end,
transfers_pricing.price AS price
FROM transfers
INNER JOIN transfers_pricing ON transfers_pricing.transfer_id = transfers.id
INNER JOIN areas_group ON areas_group.id = transfers.pickup_areas_group_id
Thank you,
Basically, you need another join on areas_group; to disambiguate the two references to the same table, you need to use a table alias.
Actually, it is a good practice to use table aliases for all tables that come into play in the query: this makes the query shorter to read and write.
SELECT
t.id AS transfer_id,
t.name AS transfer_name,
t.pickup_areas_group_id AS transfer_pickup_areas_group_id,
ag1.area_id AS pickup_area_ids,
t.drop_areas_group_id AS transfer_drop_areas_group_id,
ag2.area_id AS drop_area_ids
tp.vehicle_id AS vehicle_id,
tp.date_start AS date_start,
tp.date_end AS date_end,
tp.price AS price
FROM transfers t
INNER JOIN transfers_pricing tp ON tp.transfer_id = t.id
INNER JOIN areas_group ag1 ON ag1.id = t.pickup_areas_group_id
INNER JOIN areas_group ag2 ON ag2.id = t.drop_areas_group_id
I have 3 tables - users, journals, journaltags. I select data from 3 tables using chosen tags.
$sqltheme="SELECT users.id as uid, users.name, users.surname, users.avatar, journals.id, journals.author_id, journals.title, journals.text, journals.create_date, journaltags.name as jname FROM users
INNER JOIN journals ON users.id=journals.author_id
INNER JOIN journaltags ON journaltags.journal_id = journals.id WHERE journals.create_date LIKE ? AND journals.author_id=? AND (".$expression.") ORDER BY journals.id DESC LIMIT 10";
$stmtheme=$conn->prepare($sqltheme);
$stmtheme->execute($array);
But if two tags is the same for one journal then it is selected the same journal two times. How can I make DISTINCT journals.id. I tried GROUP BY journals.id but it didnt help.
If I understand correctly, your problem is that the journaltags table may have one or more rows with a duplicated journal_id and name column value, right?
You can simply add a distinct clause to your select statement, after the word SELECT:
SELECT DISTINCT users.id as uid, users.name, users.surname, users.avatar, journals.id, journals.author_id, journals.title, journals.text, journals.create_date, journaltags.name as jname FROM users
INNER JOIN journals ON users.id=journals.author_id
INNER JOIN journaltags ON journaltags.journal_id = journals.id WHERE journals.create_date LIKE ? AND journals.author_id=? AND (".$expression.") ORDER BY journals.id DESC LIMIT 10
The reason that your GROUP BY journals.id did not work, is because you had other columns that needed to be included in the grouping as well. Adding distinct is essentially a short way of writing group by [all selected columns]
I have a projects table and a tasks table I want to do a query that gets all projects and the sum of the time_spent columns grouped by project id. So essentially list all projects and get the total of all the time_spent columns in the tasks table belonging to that project.
With the query posted below I get the latest added time_spent column and not the sum of all the columns.. :S
Below is the query I have at the moment:
SELECT `projects`.`id`, `projects`.`description`, `projects`.`created`,
`users`.`title`, `users`.`firstname`, `users`.`lastname`, `users2`.`title`
as assignee_title, `users2`.`firstname` as assignee_firstname,
`users2`.`lastname` as assignee_lastname,
(select sum(tasks2.time_spent)
from tasks tasks2
where tasks2.id = tasks.id)
as project_duration
FROM (`projects`)
LEFT JOIN `users`
ON `users`.`id` = `projects`.`user_id`
LEFT JOIN `users` as users2
ON `users2`.`id` = `projects`.`assignee_id`
LEFT JOIN `tasks` ON `tasks`.`project_id` = `projects`.`id`
GROUP BY `projects`.`id`
ORDER BY `projects`.`created` DESC
Below is my projects table:
Below is my tasks table:
Thanks in advance!
Usually this query will help you.
SELECT p.*, (SELECT SUM(t.time_spent) FROM tasks as t WHERE t.project_id = p.id) as project_fulltime FROM projects as p
In your question, you don't say about users. Do you need users?
You are on right way, maybe your JOINs can't fetch all data.
This query should do it for you.
Note, whenever you do a group by you must include every column that you select from or order by. Some MySql installations don't prevent you from doing this, but in the end it results in an incorrect result set.
As well you should never do a query as part of your SELECT statement, known as a sub-query, as it will result in an equal amount of additional queries in relation to the number of rows returned. So if you got 1,000 rows back, it would result in 1,001 queries instead of 1 query.
SELECT
p.id,
p.description,
p.created,
u.title,
u.firstname,
u.lastname,
a.title assignee_title,
a.firstname assignee_firstname,
a.lastname assignee_lastname,
SUM(t.time_spent) project_duration
FROM
projects p
LEFT JOIN
users u ON
u.id = p.user_id
LEFT JOIN
users a ON
a.id = u.assignee_id
LEFT JOIN
tasks t ON
t.project_id = p.id
GROUP BY
p.id,
p.description,
p.created,
u.title,
u.firstname,
u.lastname,
a.title,
a.firstname,
a.lastname
ORDER BY
p.created DESC
I'm having a hard time figuring out and trying how to fix this.
Can you help me give a logic or idea how can get the ranking of each category for each branch based on sales?
For example:
Rank 1 for branch_code_id = 9 is Accicular since it has 300,000 sales
Rank 2 for branch_code_id = 9 is WLO since it has only 200,000
sales.
Same as with other branches. I only need the rank of category for each branch_code_id.
I can't figure out how to loop this one. Rank will be placed in the "r" column as you can see in the excel output.
By the way, here's the sql statement i used to get the result you see in the screenshot.
SELECT
a.id,
a.date,
a.branch_code_id,
SUM(b.amount),
c.category
FROM
sales_add_h AS a
INNER JOIN sales_add_i AS b ON a.id = b.sales_h_id
INNER JOIN control_panel_item_create AS c ON b.item_code_id = c.id
GROUP BY c.category, a.branch_code_id, b.amount
ORDER BY SUM(b.amount) DESC
Thanks Guys!
Try this query
SELECT
#rn:=if(#prv=branch_code_id, #rn+1, 1) as rId,
#prv:= branch_code_id as branch_code_id,
val,
id,
date,
category
FROM
(SELECT
a.id,
a.date,
a.branch_code_id,
SUM(b.amount) as val,
c.category
FROM
sales_add_h AS a
INNER JOIN
sales_add_i AS b ON a.id = b.sales_h_id
INNER JOIN
control_panel_item_create AS c ON b.item_code_id = c.id
GROUP BY
c.category, a.branch_code_id, b.amount
ORDER BY
a.branch_code_id, SUM(b.amount) DESC)tmp
JOIN
(SELECT #rn:=0, #prv:=0)t
SQLFIDDLE to understand how ranking works.
I have done ranking for each branch_id as you have mentioned, if you want to rank for each category in a particular branch than you need to add another variable which stores the category and compare it within the if clause and also need to sort data within inner query accordingly order by c.category, a.branch_code_id, SUM(b.amount) DESC
I have two tables called 'events' and 'topics' each table can have many comments.
What I need to do is list all the events and topics with the amount of comments for each row. I've managed to return all the topics, which works great but I don't know how I can add the events table to the MySql. The comments and events table fields are listed below. Can anyone help me with this query?
Events:
ID
Event_Name
Comments:
post_id <-- the releated id for either the events or topics table
table <-- The table that the row belongs to so either topics or events
SELECT
t.id, t.title, c.created_at,
IF(ISNULL(c.allComments), 0, c.allComments) AS totalComments
FROM topics AS t
LEFT OUTER JOIN (
SELECT created_at, post_id, COUNT(*) AS allComments
FROM comments
GROUP BY post_id
) AS c ON c.post_id = t.id
ORDER BY tc.created_at DESC, c.allComments DESC
Sounds like events and topics should be the same table.
Still, I think we can do this with a UNION. Events and Topics have the same columns i hope? (Or at least the same important ones?)
(SELECT c.table as event_or_topic, e.*, count(C.table), MAX(C.created_at) as latest_c
FROM events E LEFT JOIN comments C on (C.post_id = E.id)
WHERE C.table = 'Events'
GROUP BY C.post_id)
UNION
(SELECT c.table as event_or_topic, t.id*, count(C.table), MAX(C.created_at) as latest_c
FROM topics T LEFT JOIN comments C on (C.post_id = E.id)
WHERE C.table = 'Topics'
GROUP BY C.post_id)
ORDER BY latest_c
Notice that the ORDER BY applies to the whole UNION, not the individual SELECTs.
The use of LEFT JOIN should allow those rows without Comments to still show. I think the problem is that we have parts of our select dependent on comments (ie - C.table, ordering on last comment, etc). The count should be fine - will just be zero if there are no comments.
You might need to change the SELECT part slightly. I'd like to display C.table so you know whether a row is a topic or event, but im afraid it might screw up the count. Do you need anything from comments besides the count? You use some columns other than post_id and table in your query that you neglected to explain in your question.
You still have columns I don't know what they are, like Comment's zoneTable
Try this:
SELECT
t.id, t.title, c.created_at, COUNT(c.allComments) AS totalComments
FROM topics AS t LEFT JOIN comments c ON t.id=c.post_id
GROUP BY t.id ORDER BY tc.created_at DESC, c.allComments DESC
If I understand your question you have 3 tables:
-Events
-Topics
-Comments
If that is true something like this should extract all the data:
SELECT *
FROM events,topics
LEFT JOIN comments ON post_ID = ID
ORDER BY date DESC
Hope i'm along the right lines!
W.
I've got it working. If anyone knows of a better and an efficient way of doing this, then please let me know:
(SELECT t.id, t.title, tc.dateCreated AS commentDate,
IF(ISNULL(tc.allComments), 0, tc.allComments) AS totalComments,
t.LastActive as dateChanged
FROM Events AS t
LEFT OUTER JOIN (
SELECT MAX(created_at) AS dateCreated, post_id,
COUNT(*) AS allComments
FROM comments
GROUP BY post_id
) AS tc ON tc.post_id = t.id)
UNION
(SELECT t.id, t.title, tc.dateCreated AS commentDate,
IF(ISNULL(tc.allComments), 0, tc.allComments) AS totalComments,
t.LastActive as dateChanged
FROM topics AS t
LEFT OUTER JOIN (
SELECT MAX(created_at) AS dateCreated, post_id,
COUNT(*) AS allComments
FROM comments
GROUP BY post_id
) AS tc ON tc.post_id = t.id)
ORDER BY commentDate DESC, dateChanged DESC, totalComments DESC