I searched internet and I could not find a solution for the problem. I have a form and when I submit only text fields there is no problem. But when I add file input and submit the form I get undefined index error.
HTML CODE
<form method="post" action="add.php" enctype="multipart/form-data">
<input type="hidden" name="MAX_FILE_SIZE" value="10485760">
<input type="text" name="topic" style="width:300px;" value="cars" />
<input type="file" name="file1" id="file1" />
<input type="submit" name="submit" value="Add"/>
</form>
PHP CODE
if(isset($_POST['submit']))
{
// Form
}
else echo'NOOO';
This code always give NOOO when uploading file. I have controlled php.ini and upload is on.
Not every Browser sends the Submit button Value
you should check for your real Input values
if(isset($_POST['topic']))
{
// Form
}
else echo'NOOO';
if you want to check if your File is attched
use
$_FILE['file1']
instead of $_POST
Related
Form 1:
<?php
echo $this->upload_message;
?>
<form enctype="multipart/form-data" method="post" name="mfuploaderwp-uploadform" action="?uploadfile">
Upload file: <input name="mfuploadwp-filename" type="file">
<input class="mfuploadwp-submit" type="submit" value="Upload" name="submit"></form>
Form 2:
<?php
echo $this->upload_message;
?>
<form enctype="multipart/form-data" method="post" name="mfuploaderwp-uploadform" action="?uploadfile">
Upload file: <input name="mfuploadwp-filename" type="file">
<input class="mfuploadwp-submit" type="submit" value="Upload" name="submit"></form>
Is it possible to fetch which form is submitted without giving any extra attributes or so to above forms? The forms are created dynamically based on what user enter for amount number of forms. (In this case user has entered 2 forms)
I want to do this so $this->upload_message would be accurate only for the form that is used for uploading.
Alter the name tags on your <input type="submit"> buttons. Have one as name="submit" and the other as name="submit_two" (for example, bad naming convention), then process code as
if (isset($_POST['submit'])) {
// do stuff
} elseif (isset($_POST['submit_two'])) {
// do other stuff
}
Yes, it's possible.
The cleanest way, in my opinion, is to put an hidden input tag in each form:
<form enctype="multipart/form-data" method="post" name="mfuploaderwp-uploadform" action="?uploadfile">
<input type="hidden" name="active_form" value="1">
(...)
and
<form enctype="multipart/form-data" method="post" name="mfuploaderwp-uploadform" action="?uploadfile">
<input type="hidden" name="active_form" value="2">
(...)
then, in the page that process the form, you can check it in this way:
if( $_POST['active_form'] == 1)
{
(...)
}
elseif( $_POST['active_form'] == 2)
{
(...)
}
If your form is generated dynamically based on the user input(The forms are created dynamically based on what user enter for amount number of forms), in this case you can use three type of solution as far as I know,
You can introduce a new hidden field for each form based on the form number.
Eg:
Upload file: <input name="mfuploadwp-filename" type="file">
<input class="mfuploadwp-submit" type="submit" value="Upload" name="submit">
<input type="hidden" value="1" name="form_id"/>
</form>
in php
switch($_POST['form_id']) {
//the form data to be processed..
}
or
You can update the input field submit button naming based on the form number.
Eg:
Upload file: <input name="mfuploadwp-filename" type="file">
<input class="mfuploadwp-submit" type="submit" value="Upload" name="submit_{form_id}">
you can add a additional parameter in the form method.
...
So I have a simple form with some inputs in my codeigniter project:
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<input type="hidden" name="new_project" value="true"/>
<input type="text" placeholder="Nombre" name="nombre"/><br/>
<input type="text" placeholder="Cliente" name="cliente"/><br/>
<input type="submit" value="crear"/>
</form>
When I submit the form, I get the following message:
An Error Was Encountered
The URI you submitted has disallowed characters.
and in the address bar of my browser, the following appears:
http://mycodeigniterproject/index.php/projects/manage%20%3E%3Cinput%20type=
I already tried modifying this in my config.php file:
$config['permitted_uri_chars'] = '+=a-z 0-9?~%.,:_\-';
and
$config['enable_query_strings'] = TRUE;
Thanks for your attention
So I feel pretty stupid now. I was trying to submit a file without the multipart :S
here is the corrected code:
<?php echo form_open_multipart('projects/manage?pid='.$project->id);?>
<input type="file" name="userfile"/><br/>
<input type="submit" value="crear"/>
</form>
I was wondering whether it is possible to rename an image base on the form input file ID.
<form action="upload_file.php" enctype="multipart/form-data" method="post">
<input id="picture_01" type="file">
<input id="picture_02" type="file">
<input id="picture_03" type="file">
<input id="picture_04" type="file">
<input name="submit" type="submit" value="Submit">
</form>
I want that if the image is uploaded from input 4 it will be renamed to 'picture_04', if it is from input form 2 it will be renamed to 'picture_02'. Not sequencially but according to the input form box.
I haven't managed to do this despite the various trial and errors.
I would use separate forms for each input. This way you could use a hidden input like:
<form action="upload_file.php" enctype="multipart/form-data" method="post">
<input type='hidden' name='picture_03_file' value="picture_03" />
<input type='file' name='picture_03_name' />
</form>
<form action="upload_file.php" enctype="multipart/form-data" method="post">
<input type='hidden' name='picture_04_file' />
<input type='file' name='picture_04_name' value="picture_04" />
</form>
This way your PHP code would look like:
$imgName = $_POST['picture_04_name'];
// Do file upload here
You need to name your inputs:
<input id="picture_01" name="picture_01" type="file">
etc.
Then in PHP you retrieve the image with the $_FILES array, like $_FILES['picture_01'] or by simply looping through $_FILES.
foreach( $_FILES as $input_name=>$file)
{
// $input_name is the name used as the form input name
// $file is an array with the following keys: name, type, tmp_name, error, size.
}
Of course the manual is always a good read http://www.php.net/manual/en/features.file-upload.post-method.php
I have read the answer to this question, to execute PHP scripts with the click of a button. But what if I have a "nested button", like this :
<?php
if(!empty($_POST['act'])) {
echo "Ready to rock!";
$someVar = "Rock n Roll";
if(!empty($_POST['act2'])) {
echo $someVar;
} else {
?>
<form method="POST" action="">
<input type="hidden" name="act2" value="run">
<input type="submit" value="Rock It!">
</form>
<?php
}
} else {
?>
<form method="POST" action="">
<input type="hidden" name="act" value="run">
<input type="submit" value="Show It!">
</form>
<?php } ?>
I heard my problem can be solved with jQuery, but I no idea.
anyone please.
To execute a script on the server you use the action property of your form:
<form method="POST" action="myscript.php">
When clicking a input type="submit" the browser will go to to action of the form surrounding the input type="submit"
Nesting is not a issue, as the browser always will look for the 'surrounding' form.
Problem is in second form, so it will never calls in this code, because it fails in first $_POST variable IF statement, because in second form you do not POST variable "act". so you need to add it
<form method="POST" action="">
<input type="hidden" name="act" value="run">
<input type="hidden" name="act2" value="run">
<input type="submit" value="Rock It!">
</form>
with this form you should see echo $someVar;
p.s. if form action property is emtpy, by default it submits form to the same php script
Just like #DTukans said here, you need the hidden field. If you would post the second form, the value of act will be lost if you are not having a hidden field with the value of act from the first form.
In php you can also check which submit button you submitted by giving the input[type="submit"] a name, such as <input type="submit" name="form2">, then you could check if you submitted that form by:
if (isset($_POST['form2'])) {}, but this is not the case here.
Use the hidden input and you will be good to go.
I am trying to upload a file using php,and i need to pass a value like id or some thing with the from the upload form page to the file that have php code plz look at this code:
<form name = "file" enctype="multipart/form-data" action="uploadpp.php" method="POST">
Please choose a file: <input name="uploaded" type="file" /><br />
<input type=button name="Submit" value="Submit" />
</form>
can i send the value with the same post array??
thanks in advance.
You can use hidden form fields:
<input type="hidden" name="foo" value="bar" />
So in PHP, $_POST['foo'] would give you "bar"
Alternatively you can add them as "GET parameters" into the form's action attribute:
<form ... action="uploadpp.php?foo=bar" ...>
And access that with $_GET['foo']