Get data from MySQL database table by specific field in url - php

Question

Im new to PHP MySQL. Im developing a songbook site.
I want to create tables alphabetically in separate pages for each alphabet.
When a user click an alphabet in the menu it will direct to this page site/publicsearch.php?browse=a
This is the database :
| ID | TITLE | ARTIST | CATEGORY | ALPHABET |
+----------------------------------------------------+
| 1 | Amazing love | XXXXXX | Love | a |
| 2 | Above all | XXXXXX | Worship | a |
| 3 | BXXXX | XXXXXX | Love | b |
| 4 | BXXXX | XXXXXX | Worship | b |
I pull the above database table like this : It works fine.
<?php
$servername = "localhost";
$username = "xxxxxxx";
$password = "xxxxxxxx";
$db_name = "xxxxxxxxxxx";
// Create connection
$conn = new mysqli($servername, $username, $password, $db_name);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
echo "Connected successfully";
exit();
}
// Attempt select query execution
$sql = "SELECT * FROM lyrics_a";
if($result = mysqli_query($conn, $sql)){
if(mysqli_num_rows($result) > 0){
echo "<table class='table'>";
echo "<tr>";
echo "<th>#</th>";
echo "<th>Title</th>";
echo "<th>artist</th>";
echo "<th>cateogry</th>";
echo "</tr>";
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td> " . $row['eng_title'] . " " . $row['tel_title'] . " </td>";
echo "<td>" . $row['artist'] . "</td>";
echo "<td>" . $row['category'] . "</td>";
echo "</tr>";
}
echo "</table>";
// Close result set
mysqli_free_result($result);
} else{
echo "No records matching your query were found.";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
// Close connection
mysqli_close($link);
?>
I need separate alphabetical tables like this :
Alphabet "a" table results `site/publicsearch.php?browse=a`
| ID | TITLE | ARTIST | CATEGORY | ALPHABET |
+----------------------------------------------------+
| 1 | Amazing love | XXXXXX | Love | a |
| 2 | Above all | XXXXXX | Worship | a |
Alphabet "b" table results `site/publicsearch.php?browse=b`
| ID | TITLE | ARTIST | CATEGORY | ALPHABET |
+----------------------------------------------------+
| 3 | BXXXX | XXXXXX | Love | b |
| 4 | BXXXX | XXXXXX | Worship | b |
I tried the below code doesn't work.
<?php
$servername = "localhost";
$username = "xxxxxx";
$password = "xxxxxxx";
$db_name = "xxxxxxxxx";
// Create connection
$conn = new mysqli($servername, $username, $password, $db_name);
// Check connection
if ($conn->connect_error){
die("Connection failed: " . $conn->connect_error);
}
$alphabet = $_GET['alphabet'];
$id = mysqli_real_escape_string($conn,$id);
$query = "SELECT * FROM `lyrics` WHERE `alphabet`='" . $alphabet . "'";
$result = mysqli_query($conn,$query);
while($row = mysqli_fetch_array($result)) {
echo "<br><br>";
echo $row['id'];
echo $row['title'];
echo $row['lyrics'];
echo $row['alphabet'];
}
?>
I'm newbie. Please help. Thank you.

Answer 1

$alphabet = $_GET['alphabet'];
$id = mysqli_real_escape_string($conn,$id);
$query = "SELECT * FROM `lyrics` WHERE `alphabet`='" . $alphabet . "'";
replace with:
$alphabet = mysqli_real_escape_string($conn,$_GET['browse']);
$query = "SELECT * FROM `lyrics` WHERE `alphabet`= '" . $alphabet . "' ";

Answer 2

You propose the following URL: publicsearch.php?browse=a
But in your script you are using the request parameter $_GET['alphabet']
In addition, you don't need a separate column alphabet in your database, you can use SQL's LIKE:
$letter = $_GET['browse'];
$sql = "SELECT * FROM `lyrics` WHERE title LIKE '{$letter}%'"