While converting date format from mm-dd-yy hh:ii:ss to yy-mm-dd hh:ii:ss format using below code.
<?php
echo $start_date = date("Y-m-d H:i:s",strtotime("10-14-2015 00:00:00"));
?>
But the result is
1970-01-01 05:30:00
If it is not a proper way to use date ,provide me alternate way
First check this answer whats the difference between dates over here and simply use str_replace like as
echo $start_date = date("Y-m-d H:i:s",strtotime(str_replace("-","/","10-14-2015 00:00:00")));
Or you can also use DateTime::createFromFormat over like as
$date = DateTime::createFromFormat("m-d-Y H:i:s","10-14-2015 00:00:00");
echo $date->format('Y-m-d');
Demo
Read the manual: http://php.net/manual/en/function.strtotime.php
and also specify your PHP version.
It has a nice example on checking if strtotime conversion was successfull:
if (($timestamp = strtotime($str)) === false) {
And this conversion is very critical, it supports only limited number of formats that should be specified very precisely in order days/months/years, and separators / or - or :
So you have to pick the format that you will support from following list:
http://php.net/manual/en/class.datetime.php
Be sure to create culturally aware code (e.g. US/UK/... format)
Please write your code as below:
echo $start_date = date("Y-m-d H:i:s",strtotime("10/14/2015 00:00:00"));
Related
My API outputs the DateTime in the following format:
2018-06-17T09:07:00Z
How do I display this in a more meaningful way, say, 17/06/2018.
I looked at the Manual: http://php.net/manual/en/datetime.formats.date.php however still wasn't able to find a way to achieve this.
$eventStart = "2018-06-17T09:07:00Z";
You can format it like the below code in PHP:
echo date('d/m/Y', strtotime('2018-06-17T09:07:00Z'));
Use Below code.
date('d/m/Y', strtotime('2018-06-17T09:07:00Z'));
Use Date Format :
$inputDate = "2018-06-17T09:07:00Z";
echo date('d/m/Y', strtotime($inputDate));
Convert the string in time and then format the date which you want
Date-Format option
$date = '2018-06-17T09:07:00Z';
echo date('d/m/Y', strtotime($date));
Format the date, but first convert the string to time.
echo date('d/m/Y', strtotime($inputDate));
I'm programming a site about genealogy, I used the date input to acquire dates, and
$datamm= strftime('%Y-%m-%d', strtotime($_POST['datamm']));
to convert the dates for the database, but the minimum value that I can get is 1970-01-01. I need to acquire dates between 1500 and current day.
What can I do to solve the problem?? I prefer procedural solution if it is possible.
Here is an example,
<?php
$date = new DateTime( '01-01-1950' );
echo $date->format( 'Y-m-d' );
?>
DateTime is great, you can do all sorts once you understand it.
For instance, this will add a year and echo the start and end dates,
<?php
$date = new DateTime( '01-01-1950' );
echo $date->format( 'Y-m-d' )."\n";
$date->modify( '+1 years' );
echo $date->format( 'Y-m-d' );
?>
If you know that in which format your date is coming from input then you can try:
$datamm = DateTime::createFromFormat('j-M-Y', $_POST['datamm']);//You know that date is coming in j-M-Y format
echo $date->format('Y-m-d'); // You can save in Y-m-d format in database
if you are taking timestamp as input then :
$date = date('Y-m-d',$_POST['datamm']);//you are taking timestamp like : 30000000000 as an input
echo $date;//make in database in Y-m-d format
I hope it helps
Try this, use createFromFormat
// pass your date format
$date = DateTime::createFromFormat('d M Y','17 Jan 1500');
echo $date->format('Y-m-d');
DEMO
You should probably focus on using some 3rd party library instead of official PHP's datetime functions.
For example, for your advanced date-time manipulating requirements, a good alternative for PHP's standard datetime would be moment.php
It's inspired by moment.js library whose goal is to fix common date-time programming issues, and bring standardization to higher level.
You can obtain it via composer like:
{
"require": {
"fightbulc/moment": "*"
}
}
Or via github for manual installation.
To parse various input date consult a manual, below is example:
$m = new \Moment\Moment('1503-04-25T03:00:00', 'CET');
There is also other alternatives to explore, for example:
https://github.com/swt83/php-date
I have much data with several timestamps and I just recognized that some are in "dd.mm.YYYY" which works very well with date("Y-m-d", strtotime($input)); but some are in "dd.mm.YY" and this does not work anymore - it always returns the current date.
My problem is that my data is too huge to fix this problem manually by editting. Is there any way to get the YYYY-mm-dd out of mm.dd.YY ?
Here you go...
$date = "20.02.71"; // sample date... (common German format)
$date = DateTime::createFromFormat('d.m.y', $date);
echo $date->format('Y-m-d');
will result in:
1971-02-20
Create a DateTime object, then format it to anything you want...
Well you can replace the . by -, you could do something like the following:
$date = str_replace(".", "-", "mm.dd.YY")
This would return
mm-dd-YY
You could use date_parse_from_format which would convert any formate into the formate you specify.
date_parse_from_format("y-m-d", $date);
It returns an array with very useful information like month, year etc.
I am using this, but it's not working for date 2012,02,26:
$theDate = "2012,02,26";
$timeStamp = StrToTime($theDate);
$in6days = StrToTime('+6 days', $timeStamp);
$newdate = date("{$theDate}", strtotime('+1 day', strtotime($in6days)));
echo "$newdate";
showing 2012,02,32
I don't think that 2012,02,26 is a valid format that strtotime() will accept. Valid date formats are listed here: PHP: Date Formats
In order to check if the strToTime function works or not , try:
echo $timeStamp;
If you get false then you should use another data format as christophmccann recommended,
for instance:
$theData = "02/16/2012"; //or the next one
$theData = "30-6-2008";
You should be working internally with widely used date formats - either unix timestamp or RFC 2822 if you have good reason to. Use date() to reformat your date according to your own display requirements if you wish (see php.net/date).
So, you can show today in your preferred date format using echo date('Y,m,d');
I have a date in this format:
24-12-2010 // DAY - MONTH - YEAR
I need to get it in this format:
1995-12-31T23:59:59.999Z // The Z is for the TimeZone I think.
Check this link out:
http://lucene.apache.org/solr/api/org/apache/solr/schema/DateField.html
The above link is the way I need the date.
I am using PHP now, so this needs to be with PHP.
How can I convert these dates the easiest way?
Thanks
That is an ISO8601 format date; the following is what you want.
gmdate('Y-m-d\TH:i:s\Z', strtotime($date_value));
You can do something like that:
$dateTime = new DateTime($myDate);
$formatted = $dateTime->format("Y-m-d\TH:i:s.z\Z");
The mentioned solution with:
$dateTime->format(DateTime::W3C);
$dateTime->format(DateTime::ISO8601);
does return strings like:
2012-11-28T17:21:11+0100
which cannot be parsed, at least with newer Solr versions.
I wouldn't use gmdate if you need to support timezones. The DateTime implementation is well done, and is also available for functional programming.
http://php.net/manual/en/class.datetime.php
http://php.net/manual/en/ref.datetime.php
You can use the DateTime class
$dateTime = new DateTime();
$dateTime.setDate(24, 12, 2010);
$output = $dateTime.format(DateTime::W3C);
// Output now is your date in W3C format.
use the date ( string $format [, int $timestamp ] ) function of php!
In second paramter use http://php.net/manual/en/function.strtotime.php to get the timestamp from strings
$date = strtotime('24-12-2010');
$new_date = gmDate("Y-m-d\TH:i:s.z\Z",$date);