Getting value from dropdown and use it in query - php

Question

i am having trouble in deleteing values from my database using php can someone help me plsss this is for my project
this is where i get the value
<select name="fname" id='mySelect' value='Foodname'>
and this is what i want to do after i submit it
if(isset($_POST['submit']))
{
$food = $_POST['fname'];
echo $food;
if($food=='')
{
echo"<script>alert('Please Dont Leave any Blanks')</script>";
}
else
{
sqldel="DELETE FROM menu WHERE food = $food;";
}
}

Answer 1

This is how your complete code should be look like. Hope it helps!!!
<form name="" method="post" action="">
<select name="fname" id='mySelect' value='Foodname'>
<option value="">select</option>
<option value="option1">option1</option>
<option value="print server, printer">print server, printer</option>
</select>
<input type="submit" name="submit" value="submit" />
</form>
<?php
//Check if Form is submitted
if(isset($_POST['submit']))
{
//Store submitted value in variable
$food = $_POST['fname'];
echo $food;
//Check if the submitted value is blank or not
if($food=='')
{
//User submitted blank value - so throw an error
echo"<script>alert('Please Dont Leave any Blanks')</script>";
}
else
{
/*user selected a valid value in drop down so we are in else part*/
//This is your database configuration settings
$servername = "localhost";
$username = "root";
$password = "password";
$dbname = "yourDBName";
// Create connection - here you are doing database connection
$conn = new mysqli($servername, $username, $password, $dbname);
/* Check connection - If you database configuration settings are wrong it will throw an error and stop there itself and wont execute your further code*/
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
/*Now Check if record exists in db for the selected value. If record exists in database than only we can delete record.*/
$sql = "SELECT id FROM menu WHERE food = '".$food."'";
$result = $conn->query($sql);
/*check if select query return a row greater than 0, implies record exists in table */
if ($result->num_rows > 0) {
/*Record exists in database so - sql to delete a record*/
$delete_sql = "DELETE FROM menu WHERE food = '".$food."' ";
/*this will execute the delete query, if it return true we will show success alert else throw an error*/
if ($conn->query($delete_sql) === TRUE) {
echo"<script>alert('Record deleted successfully')</script>";
} else {
echo "Error deleting record: " . $conn->error;
}
} else {
echo"<script>alert('No record found for the seleted item')</script>";
}
//Close database connection
$conn->close();
}
}
?>

Answer 2

just remove ; after query and put single quote around variable $food
sqldel="DELETE FROM menu WHERE food = $food;";
shoulb be
sqldel="DELETE FROM menu WHERE food = '$food'";

Answer 3

Here is a fix for your query:
$sqldel = "DELETE FROM menu WHERE food = '".$food."'";

Answer 4

You need to put quotes around $food.
$sqldel="DELETE FROM menu WHERE food = '$food';";