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Closed 7 years ago.
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I'm pretty new to php and I have problem with 2 dimentional array. When I try to do this:
$tab[0][0] = "dupa0";
$tab[0][1] = "dupa1";
echo("$tab[0][0]");
It doesn't work. How can I print a single element from this array?
you have to remove the quotes:
echo($tab[0][0]);
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Closed 1 year ago.
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str_replace("~","af53261f02cbb39d10c6bb0e53d180da5fee7d3c4c784f632e35abcf33b08fdc","$encode");
How can we put the output of the str_replace() function into a variable?
you can try this:
$variable = str_replace("~","af53261f02cbb39d10c6bb0e53d180da5fee7d3c4c784f632e35abcf33b08fdc", "$encode");
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Closed 3 years ago.
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How can i echo PHP Get request with []?
example: value=ok¶ms[account]=123456
There is no problem with:
echo $value = $_GET["value"];
Not working with:
echo $account = $_GET["params[account]"];
echo $account = $_GET["params"]["account"];
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I have this pattern:
preg_replace_callback('##abc\((.*?)\)(.*?)#end.#is', ..
My template string:
$test = "#abc('test')<h1>test</h1>#end"; // not working
$test2 = "#abc('test')<h1>test</h1>#end "; // working
Why it doesn't work if there's no space after #end?
As #Rizier123 pointed out, this is the correct regex:
preg_replace_callback('##abc\((.*?)\)(.*?)#end#is', ..
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header("Location: {$TBDEV['baseurl']}/login.php?returnto=" . urlencode($_SERVER["REQUEST_URI"]));
Is it a variable? PHP reserved word? something to do with HTML?
It's a $_GET parameter. When you submit the code, the page receiving it will be able to use $_GET['returnto'] to return you to the page you're currently on.
Take some time to learn about $_GET
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Closed 8 years ago.
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I am using this as a reference
$jpsupp1 = '<?=$gamesss['jackpot']?>';
How can I use this without the 'jackpot' giving me t_string errors?
It should be:
$jpsupp1 = $gamesss['jackpot'];
You don't need <?= when you're already executing PHP code. That's used for embedding PHP in HTML.
Use double quotes
$jpsupp1 = "<?=$gamesss['jackpot']?>";
or
$jpsupp1 = "<?={$gamesss['jackpot']}?>";
Depending on what you want to store.