Can someone help me how to specific pattern for preg_match function?
Every word in string must end with dot
First character of string must be [a-zA-Z]
After each dot there can be a space
There can't be two spaces next to each other
Last character must be a dot (logicaly after word)
Examples:
"Ing" -> false
"Ing." -> true
".Ing." -> false
"Xx Yy." -> false
"XX. YY." -> true
"XX.YY." -> true
Can you help me please how to test the string? My pattern is
/^(([a-zA-Z]+)(?! ) \.)+\.$/
I know it's wrong, but i can't figure out it. Thanks
Check how this fits your needs.
/^(?:[A-Z]+\. ?)+$/i
^ matches start
(?: opens a non-capture group for repetition
[A-Z]+ with i flag matches one or more alphas (lower & upper)
\. ? matches a literal dot followed by an optional space
)+ all this once or more until $ end
Here's a demo at regex101
If you want to disallow space at the end, add negative lookbehind: /^(?:[A-Z]+\. ?)+$(?<! )/i
Try this:
$string = "Ing
Ing.
.Ing.
Xx Yy.
XX. YY.
XX.YY.";
if (preg_match('/^([A-Za-z]{1,}\.[ ]{0,})*/m', $string)) {
// Successful match
} else {
// Match attempt failed
}
Result:
The Regex in detail:
^ Assert position at the beginning of a line (at beginning of the string or after a line break character)
( Match the regular expression below and capture its match into backreference number 1
[A-Za-z] Match a single character present in the list below
A character in the range between “A” and “Z”
A character in the range between “a” and “z”
{1,} Between one and unlimited times, as many times as possible, giving back as needed (greedy)
\. Match the character “.” literally
[ ] Match the character “ ”
{0,} Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
)* Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
This is my string:
stringa/stringb/123456789,abc,cde
and after preg_match:
preg_match('/(?<=\/).*?(?=,)/',$array,$matches);
output is:
stringb/123456789
How can I change my preg_match to extract the string after second slash (or after last slash)?
Desired output:
123456789
You can match anything other than a / as
/(?<=\/)[^\/,]*(?=,)/
[^\/,]* Negated character class matches anything other than , or \
Regex Demo
Example
preg_match('/(?<=\/)[^\/,]*(?=,)/',$array,$matches);
// $matches[0]
// => 123456789
This should do it.
<?php
$array = 'stringa/stringb/123456789,abc,cde';
preg_match('~.*/(.*?),~',$array,$matches);
echo $matches[1];
?>
Disregard everything until the last forward slash (.*/). Once the last forward slash is found keep all the data until the first comma((.*?),).
You don't need to use lookbehind, i.e.:
$string = "stringa/stringb/123456789,abc,cde";
$string = preg_replace('%.*/(.*?),.*%', '$1', $string );
echo $string;
//123456789
Demo:
http://ideone.com/IxdNbZ
Regex Explanation:
.*/(.*?),.*
Match any single character that is NOT a line break character «.*»
Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
Match the character “/” literally «/»
Match the regex below and capture its match into backreference number 1 «(.*?)»
Match any single character that is NOT a line break character «.*?»
Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
Match the character “,” literally «,»
Match any single character that is NOT a line break character «.*»
Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
$1
Insert the text that was last matched by capturing group number 1 «$1»
I have no experience with regular expressions whatsoever, hence my question.
I have a string which should look like this:
[1,24,2,59]
As the string can be manipulated by the user and hence changed, I want to check whether it is still following the same organization pattern, and only containing numbers,square brackets and commas.
You can use this regex in preg_match to validate your input:
'/\[\d+(,\d+)*\]/'
\[ matches the character [ literally
\d+ match a digit [0-9]
Quantifier: Between one and unlimited times, as many times as possible, giving back as
needed [greedy]
1st Capturing group (,\d+)*
Quantifier: Between zero and unlimited times, as many times as possible, giving back as
needed [greedy]
Note: A repeated capturing group will only capture the last iteration. Put a capturing
group around the repeated group to capture all iterations or use a non-capturing group
instead if you're not interested in the data
, matches the character , literally
\d+ match a digit [0-9]
Quantifier: Between one and unlimited times, as many times as possible, giving back as
needed [greedy]
\] matches the character ] literally
'/^\[\d+(,\d+)*\]$/'
Same as the other answer, except it requires the whole string to match, otherwise a valid substring would suffice (e.g. "bla bla [1,3] bla bla")
'/^\[([1-9]\d+|\d)(,([1-9]\d+|\d))*\]$/'
Same, but numbers must have leading zeros removed, so "[12]" is OK but "[012]" is not.
'/^\s*\[\s*([1-9]\d+|\d)(\s*,\s*([1-9]\d+|\d))*\s*\]\s*$/'
Allows white spaces, e.g. " [ 1 , 12 , 12 ] " will be accepted but not "[1 2]".
how to extract a number with decimal (dot and comma) from a string (e.g. 1,120.01) ?
I have a regex but doesn't seem to play well with commas
preg_match('/([0-9]+\.[0-9]+)/', $s, $matches);
The correct regex for matching numbers with commas and decimals is as follows (The first two will validate that the number is correctly formatted):
decimal optional (two decimal places)
^[+-]?[0-9]{1,3}(?:,?[0-9]{3})*(?:\.[0-9]{2})?$
Debuggex Demo
Explained:
number (decimal optional)
^[+-]?[0-9]{1,3}(?:,?[0-9]{3})*(?:\.[0-9]{2})?$
Options: case insensitive
Assert position at the beginning of the string «^»
Match a single character present in the list below «[+-]?»
Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
The character “+” «+»
The character “-” «-»
Match a single character in the range between “0” and “9” «[0-9]{1,3}»
Between one and 3 times, as many times as possible, giving back as needed (greedy) «{1,3}»
Match the regular expression below «(?:,?[0-9]{3})*»
Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
Match the character “,” literally «,?»
Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
Match a single character in the range between “0” and “9” «[0-9]{3}»
Exactly 3 times «{3}»
Match the regular expression below «(?:\.[0-9]{2})?»
Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
Match the character “.” literally «\.»
Match a single character in the range between “0” and “9” «[0-9]{2}»
Exactly 2 times «{2}»
Assert position at the end of the string (or before the line break at the end of the string, if any) «$»
Will Match:
1,432.01
456.56
654,246.43
432
321,543
Will not Match
454325234.31
324,123.432
,,,312,.32
123,.23
decimal mandatory (two decimal places)
^[+-]?[0-9]{1,3}(?:,?[0-9]{3})*\.[0-9]{2}$
Debuggex Demo
Explained:
number (decimal required)
^[+-]?[0-9]{1,3}(?:,?[0-9]{3})*\.[0-9]{2}$
Options: case insensitive
Assert position at the beginning of the string «^»
Match a single character present in the list below «[+-]?»
Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
The character “+” «+»
The character “-” «-»
Match a single character in the range between “0” and “9” «[0-9]{1,3}»
Between one and 3 times, as many times as possible, giving back as needed (greedy) «{1,3}»
Match the regular expression below «(?:,?[0-9]{3})*»
Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
Match the character “,” literally «,?»
Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
Match a single character in the range between “0” and “9” «[0-9]{3}»
Exactly 3 times «{3}»
Match the character “.” literally «\.»
Match a single character in the range between “0” and “9” «[0-9]{2}»
Exactly 2 times «{2}»
Assert position at the end of the string (or before the line break at the end of the string, if any) «$»
Will Match:
1,432.01
456.56
654,246.43
324.75
Will Not Match:
1,43,2.01
456,
654,246
324.7523
Matches Numbers separated by commas or decimals indiscriminately:
^(\d+(.|,))+(\d)+$
Debuggex Demo
Explained:
Matches Numbers Separated by , or .
^(\d+(.|,))+(\d)+$
Options: case insensitive
Match the regular expression below and capture its match into backreference number 1 «(\d+(.|,))+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Note: You repeated the capturing group itself. The group will capture only the last iteration. Put a capturing group around the repeated group to capture all iterations. «+»
Match a single digit 0..9 «\d+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the regular expression below and capture its match into backreference number 2 «(.|,)»
Match either the regular expression below (attempting the next alternative only if this one fails) «.»
Match any single character that is not a line break character «.»
Or match regular expression number 2 below (the entire group fails if this one fails to match) «,»
Match the character “,” literally «,»
Match the regular expression below and capture its match into backreference number 3 «(\d)+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Note: You repeated the capturing group itself. The group will capture only the last iteration. Put a capturing group around the repeated group to capture all iterations. «+»
Match a single digit 0..9 «\d»
Will Match:
1,32.543,2
5456.35,3.2,6.1
2,7
1.6
Will Not Match:
1,.2 // two ., side by side
1234,12345.5467. // ends in a .
,125 // begins in a ,
,.234 // begins in a , and two symbols side by side
123,.1245. // ends in a . and two symbols side by side
Note: wrap either in a group and then just pull the group, let me know if you need more specifics.
Description: This type of RegEx works with any language really (PHP, Python, C, C++, C#, JavaScript, jQuery, etc). These Regular Expressions are good for currency mainly.
You can use this regex: -
/((?:[0-9]+,)*[0-9]+(?:\.[0-9]+)?)/
Explanation: -
/(
(?:[0-9]+,)* # Match 1 or more repetition of digit followed by a `comma`.
# Zero or more repetition of the above pattern.
[0-9]+ # Match one or more digits before `.`
(?: # A non-capturing group
\. # A dot
[0-9]+ # Digits after `.`
)? # Make the fractional part optional.
)/
Add the comma to the range that can be in front of the dot:
/([0-9,]+\.[0-9]+)/
# ^ Comma
And this regex:
/((?:\d,?)+\d\.[0-9]*)/
Will only match
1,067120.01
121,34,120.01
But not
,,,.01
,,1,.01
12,,,.01
# /(
# (?:\d,?) Matches a Digit followed by a optional comma
# + And at least one or more of the previous
# \d Followed by a digit (To prevent it from matching `1234,.123`)
# \.? Followed by a (optional) dot
# in case a fraction is mandatory, remove the `?` in the previous section.
# [0-9]* Followed by any number of digits --> fraction? replace the `*` with a `+`
# )/
The locale-aware float (%f) might be used with sscanf.
$result = sscanf($s, '%f')
That doesn't split the parts into an array though. It simply parses a float.
See also: http://php.net/manual/en/function.sprintf.php
A regex approach:
/([0-9]{1,3}(?:,[0-9]{3})*\.[0-9]+)/
This should work
preg_match('/\d{1,3}(,\d{3})*(\.\d+)?/', $s, $matches);
Here is a great working regex. This accepts numbers with commas and decimals.
/^-?(?:\d+|\d{1,3}(?:,\d{3})+)?(?:\.\d+)?$/
How would I write a php preg_match() in php to pick out the 250 value. I have a large string of html code that I want to pick the 250 out of and I can't seem to get the regular expression right.
This is the html pattern I want to match - note that I want to extract the integer where the 250 is:
<span class="price-ld">H$250</span>
I have been trying for hours to do this and I can't get it to work lol
preg_match('/<span class="price-ld">H$(\d+)<\/span>/i', $your_html, $matches);
print "Its ".$matches[1]." USD";
The regex actually depends on your code. Where are you exactly searching for?
This is the regex you're looking for:
(?<=<span class="price-ld">H\$)\d+(?=</span>)
You can see the results here.
And here's the explanation:
Options: case insensitive; ^ and $ match at line breaks
Assert that the regex below can be matched, with the match ending at this position (positive lookbehind) «(?<=<span class="price-ld">H\$)»
Match the characters “<span class="price-ld">H” literally «<span class="price-ld">H»
Match the character “$” literally «\$»
Match a single digit 0..9 «\d+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Assert that the regex below can be matched, starting at this position (positive lookahead) «(?=</span>)»
Match the characters “</span>” literally «span>»