Why it failed to pass the value? - php

Question

I have a page called MemberArea.php that use bootstrap tab to change its content according to div id.
<div id="tabs-1" class="tab-pane fade in active">
<div class="tabbable tabs-left">
<br />
<ul class="nav nav-tabs" id="maincontent" role="tablist">
<li class="active"><a data-toggle="tab" href="#tabs-5" role="tab">Basic Information</a></li>
<li><a data-toggle="tab" href="#tabs-6" role="tab">View Team</a></li>
</ul>
<div class="tab-content">
<div id="tabs-5" class="tab-pane active">
<?php include("information.php"); ?>
</div>
<div id="tabs-6" class="tab-pane">
<?php include("viewTeam.php"); ?>
</div>
<div id="tabs-14" class="tab-pane">
<?php include("EditSinging.php"); ?>
</div>
<div id="tabs-15" class="tab-pane">
<?php include("EditSpeech.php"); ?>
</div>
<div id="tabs-16" class="tab-pane">
<?php include("EditStory.php"); ?>
</div>
</div>
</div>
In ViewTeam, it's to display all registered team
<?php
$query="select * from etj12singing where etj12id=$id AND etj12Pay ='Yes' ";
$result =mysql_query($query);
while($row= mysql_fetch_array($result))
{
$SIidnumber=$row['etj12idnum'];
$SIidtype = $row['etj12idtype'];
$SIfullName = $row['etj12fullname'];
$SIgender = $row['etj12gender'];
$SIemail = $row['etj12email'];
$SIphone = $row['etj12phone'];
$SIvege = $row['etj12vege'];
$SIpay = $row['etj12Pay'];
$SIidsinging = $row['etj12idsinging'];
?>
<tr>
<td><?php echo $SIidnumber; ?></td>
<td><?php echo $SIidtype; ?></td>
<td><?php echo $SIfullName; ?></td>
<td><?php echo $SIgender; ?></td>
<td><?php echo $SIemail; ?></td>
<td><?php echo $SIphone; ?></td>
<td><?php echo $SIvege; ?></td>
<td><?php echo $SIpay; ?></td>
<td>
<a data-toggle="tab" href="?idSIE=<?php echo $SIidsinging; ?>#tabs-14" role="tab">
<input type="submit" value="Edit" class="btn-warning"/>
</td>
</tr>
My problem is I cannot pass the value to tabs-14(EditSinging.php)
Here is how i get the value in tabs-14(EditSinging.php)
$idsinging=$_GET['idSIE'];
UPDATE
Here is the code in EditSinging.php
PHP :
$idinst = $_SESSION['id'];
$idsinging=$_POST['idSIE'];
$query = "SELECT * FROM etj12singing WHERE etj12id=$idinst AND etj12idsinging=$idsinging";
$result = mysql_query($query);
if($row=mysql_fetch_array($result))
{
$idNum = $row['etj12idnum'];
$idtype = $row['etj12idtype'];
$fullname = $row['etj12fullname'];
$gender = $row['etj12gender'];
$email = $row['etj12email'];
$phone = $row['etj12phone'];
$vege = $row['etj12vege'];
}
Below is the form to edit the value that i got from the query above
<table style="width:100%;height:auto;border-spacing:10px;border-collapse:separate">
<tr>
<td>Id Number<br/>
<span style="font-style:italic;">(Nomor Identitas)</span>
</td>
<td>
<input type="text" id="IdNumber" name="IdNumber" value="<?php echo $idNum; ?>" class="textbox_register"/>
<input type="hidden" name="idSIC" value="<?php echo $idsinging; ?>" class="textbox_register"/>
<br/><label id="err1" class="error"></label>
</td>
</tr></table>

Answer 1

In your ViewTeam file the query:
$query="select * from etj12singing where etj12id=$id AND etj12Pay ='Yes' ";
this content ($id) witch not defined in file;
you must give the string (id) a value.
so your query return null results.
I think this is the problem you have.