I'm trying to make a quiz that will show the person who take it the average of the number of answer they got right. For example: if they have 2 right it would display 66%. Can someone please explain to me how I can do something like this.
<!DOCTYPE html>
<html>
<head>
<title>Question</title>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css" rel="stylesheet">
</head>
<body style="background-color:lightblue">
<h1 style="text-align:center;color:white"> Answer these Questions</h1>
<div class="container" style="margin-top: 50px">
<?php
$numcorrect=0;
// If the submit button has been pressed
if(isset($_POST['submit']))
{
// Check answer
if($_POST['answer'] == 21)
{
$numcorrect= ($numcorrect + 1);
}
if($_POST['answer1'] == 46)
{
$numcorrect= ($numcorrect + 1);
}
if($_POST['answer2'] == 2468)
{
$numcorrect= ($numcorrect + 1);
}
$average=$numcorrect/count ($numcorrect);
echo "<h1>Your Average is {$_POST['$Average']}</h1>";
}
?>
<!-- Quiz Form -->
<form method="post" action="questionassign1.php">
<ol>
<div class="form-group">
<h3><li>How old am I ?</li></h3>
<input name="answer" type="text" class="form-control" />
<h3><li>How old is my Mom?</li></h3>
<input name="answer1" type="text" class="form-control" />
<h3><li>What is my favorite number?</li></h3>
<input name="answer2" type="text" class="form-control" />
</li>
</div>
</ol>
<input name="submit" type="submit" value="Check answer" class="btn btn-primary" />
</form>
</div>
</body>
</html>
Use this code:
<?php
$numcorrect = 0;
// If the submit button has been pressed
if (isset($_POST['submit'])) {
// Check answer
if ($_POST['answer'] == 21) { {
$numcorrect++;
}
if ($_POST['answer1'] == 46) {
$numcorrect++;
}
if ($_POST['answer2'] == 2468) {
$numcorrect++;
}
$average = ($numcorrect/3)*100;
echo "<h1>Your Average is $average %</h1>";
}
}
?>
:)
$average=$numcorrect/count ($numcorrect);
echo "<h1>Your Average is ".$average."%</h1>";
You already calculated the average, so put it in the string with the . string concat operator. Additional hint: Check your code, what happens if I don't know any answer?
Related
I am trying to show people their profiles from my database using PHP.
But every time a button is clicked I want the person_id ($which_person) to go up by 1 so the next person's profile is shown. I don't know how to do that because every time I click a button the page reloads so the variable "which_person" gets reset to 1.
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<link href="assets-putinhouse/css/style1.css" rel="stylesheet" type="text/css">
<link rel="preconnect" href="https://fonts.googleapis.com">
<link rel="preconnect" href="https://fonts.gstatic.com" crossorigin>
<link href="https://fonts.googleapis.com/css2?family=Festive&display=swap" rel="stylesheet">
<title>Put people in a house</title>
</head>
<body>
<?php
include "db/connection.php";
$conn = create_connection();
$which_person = 1; //This resets to "1" every time the page reloads
$getSql = "select * from Person where person_id = 1;";
$data_labels = mysqli_query($conn, $getSql)->fetch_all(MYSQLI_ASSOC);
?>
<div class="pagesize">
<h1>Put people in a house</h1>
<img src="assets-putinhouse/images/create_account.png" alt="profilepic" class="image_person">
<?php
foreach($data_labels as $labels)
{
?>
<li class="labels" data-id="<?php echo $labels['person_id'];?>">
<?php echo $labels["firstname"] ?>
<br>
<br>
<?php echo $labels["secondname"] ?>
<br>
<br>
<?php echo $labels["gender"] ?>
<br>
<br>
<?php echo $labels["descriptie"] ?>
</li>
<?php
}
?>
<br>
<form method="GET">
<input type="submit" class="slytherin_button" value="Slytherin" name="slytherin_button_name">
<br>
<input type="button" class="gryffindor_button" value="Gryffindor" name="gryffindor_button_name">
<br>
<input type="button" class="hufflepuff_button" value="Hufflepuff" name="hufflepuff_button_name">
<br>
<input type="button" class="ravenclaw_button" value="Ravenclaw" name="ravenclaw_button_name">
<br>
<input type="button" class="nextperson_button" value="Go to next person">
<p class="text_firstname">Firstname: </p>
<p class="text_name">Name: </p>
<p class="text_gender">Gender: </p>
<p class="text_info">Info: </p>
<?php
if(isset($_GET['slytherin_button_name'])) {
onFunc($conn, $which_person);
}
if(isset($_GET['gryffindor_button_name'])) {
offFunc();
}
function onFunc($conn, $wich_person){
$sqlUpdate = "UPDATE Person SET slytherin = slytherin + 1 WHERE person_id like '$which_person';"; //this does the value "slytherin" of which_person go up by 1;
mysqli_query($conn, $sqlUpdate);
$wich_person = $wich_person + 1; //which person goes up by 1 so the next person will be shown but gets reset at the start
}
function offFunc(){
echo "Button is clicked";
}
?>
</div>
<script src="assets-putinhouse/js/script.js"></script>
</body>
</html>
ยดยดยด
(Untested) Instead of:
$wich_person = 1;
It seems you could do something like:
if (isset($_GET["id"]) {
$wich_person = (int)$_GET["id"] + 1;
}
else {
$wich_person = 1;
}
and then add the following to your form:
<form action="?<?php echo $wich_person ?>" method="GET">
...
</form>
And also, unless I'm mistaken it seems you've forgot to add </form> to your code.
In any event, this code should add the current ID to your URL every time you press submit, where then it gets increased by 1.
Edit: This is intended as a quick solution based on the code structure you provided, but upon reflection not sure if it's exactly what you're looking for. More robust solutions could be had, such as cookies or sessionStorage.
Im kind of new to programming (taking a course currently) and our task over the weekend is to build a website (really basic) where we have to solve a addition of 2 random numbers. I was able to create those random numbers, but what with is, to create something like a field the user (in this case me) has to fill out and "submit"; and then the website should show my own anwser and the correct one. The issue im facing in addition to that is, that when i create a submit function the website refreshes and those random numbers change each time.
My code looks like this (forgive me for using german terms):
<?php
$zufallszahl = rand(1,100) . "+";
$zufallszahl1= rand(1,100);
$solution= bcadd($zufallszahl,$zufallszahl1);
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta http-equiv="X-UA-Compatible" content="ie=edge">
<title>Homework Taschenrechner</title>
</head>
<body>
<h1>Additionen</h1>
<hr>
<h4>Addiere die folgenden Zahlen:</h4>
<p> <?php echo $zufallszahl; echo $zufallszahl1 ?> <p>
<form method="post">
<input type="number" name="Usereingabe" min="0" placeholder="Deine Antwort">
</form>
</body>
</html>
I would really appreciate a "simple" solution, I googled this issue already for an hour, but most solutions are just too complicated for me right now, and i end up not understanding what the code is about. So just to sum up, I would like to know how to create a submit field that doesnt refresh the website so the random numbers stay and a field that "checks" the answer and says its true/false.
Although, if you were allowed to use JS, it would be a lot simpler. However, since you wanted it in just PHP, the code below should work. Feel free to modify it as per your needs
<?php
if(!isset($_POST['zufallszahl']) && !isset($_POST['zufallszahl1'])) {
$zufallszahl = rand(1,100);
$zufallszahl1= rand(1,100);
// $solution= bcadd($zufallszahl,$zufallszahl1);
} else {
$zufallszahl = $_POST['zufallszahl'];
$zufallszahl1 = $_POST['zufallszahl1'];
$solution = bcadd($zufallszahl,$zufallszahl1);
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta http-equiv="X-UA-Compatible" content="ie=edge">
<title>Homework Taschenrechner</title>
</head>
<body>
<h1>Additionen</h1>
<hr>
<h4>Addiere die folgenden Zahlen:</h4>
<p> <?php echo $zufallszahl . " + "; echo $zufallszahl1 ?> <p>
<form method="post">
<input type="number" name="zufallszahl" value="<?php echo $zufallszahl; ?>" readonly />
<input type="number" name="zufallszahl1" value="<?php echo $zufallszahl1; ?>" readonly />
<input type="number" name="Usereingabe" min="0" placeholder="Deine Antwort" value="<?php echo $_POST['Usereingabe'] ?? ''; ?>">
<button>Check Answer </button>
<?php if(isset($_POST['Usereingabe'])){ ?>
<?php if($_POST['Usereingabe'] == $solution)
echo "Correct Answer";
else {
echo "Wrong Answer. Correct answer is $solution";
} ?>
<?php } ?>
</form>
</body>
</html>
NOTE
If you are using version below PHP 7, just use <?php echo isset($_POST['Usereingabe'])? $_POST['Usereingabe'] : ''; ?> in place of <?php echo $userSolution ?? ''; ?>
So you can keep them in a _SESSION variable and when they submit the answer you can check the _POST variable against the _SESSION one
<?php
if(isset($_POST['Usereingabe']))
{
if($_POST['Usereingabe'] == $_SESSION['sol']){
$check = "correct answer";
}
else
{ $check = "wrong answer"; }
}
else {
$zufallszahl = rand(1,100) . "+";
$zufallszahl1= rand(1,100);
$solution= bcadd($zufallszahl,$zufallszahl1);
$_SESSION['zufallszahl1']=$zufallszahl1;
$_SESSION['zufallszahl']=$zufallszahl;
$_SESSION['sol']=$solution;
}
// do anything else u want
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta http-equiv="X-UA-Compatible" content="ie=edge">
<title>Homework Taschenrechner</title>
</head>
<body>
<h1>Additionen</h1>
<hr>
<h4>Addiere die folgenden Zahlen:</h4>
<?php if(isset($check)) { echo $check; } ?>
<p> <?php echo $_SESSION['zufallszahl']; echo $_SESSION['zufallszahl1']; ?> <p>
<form method="post" action="*your file.php*">
<input type="number" name="Usereingabe" min="0" placeholder="Deine Antwort">
<button type="submit">Submit!</button>
</form>
</body>
</html>
You could use two extra input tags in your form of type="hidden" that contain the random numbers in their value fields, and check if they are empty. If they are, generate new ones, otherwise keep the old ones.
I'm new to PHP so please bear with me.
I'm trying to decide the action based on the given input.
Given below is the code I've written for this simple task
<html>
<head>
<meta charset="UTF-8">
<title>SAMPLE</title>
</head>
<body>
<form method="POST" action="<?php
if(isset($_POST['submit_button']))
{
if($_POST['name_field'] === "USERA")
{
echo "output.php";
}
else
{
echo "wronguser.php";
}
}
?>">
Username : <input type="text" name="name_field" value="<?php
if(!isset($_POST['name_field']) || $_POST['name_field']=== "")
{
echo "Enter Something" ;
}
?>">
<input type="submit" name="submit_button" value="SUBMIT BUTTON !">
</form>
</body>
</html>
Here I want the form to redirect to "output.php" if the user is "USERA" or "wrongouput.php" for any other user name entered. Although it works as expected, I'm redirected to the right page only when I press the submit button the 2nd time.
Why is this ?
Also, reloading the page doesn't seem to bring back the original page with the text field containing the default "Enter Something" text. I have to run it all over again from the IDE.
Why is this ?
You can try a different approach
<?php
if(isset($_POST['submit_button']))
{
if($_POST['name_field'] === "USERA")
{
require_once("output.php");
}
else
{
require_once("wronguser.php");
}
}
else
{
?>
<html>
<head>
<meta charset="UTF-8">
<title>SAMPLE</title>
</head>
<body>
<form method="POST" action="">
Username : <input type="text" name="name_field" value="<?php
if(!isset($_POST['name_field']) || $_POST['name_field']=== "")
{
echo "Enter Something" ;
}
?>">
<input type="submit" name="submit_button" value="SUBMIT BUTTON !">
</form>
</body>
</html>
<?php
}
?>
Take your code out of the action, make the action for the form self so it fires on itself, then put your PHP above all the HTML at the top of the file. That'll stop the double click issue.
<?php
if(isset($_POST['submit_button']))
{
if($_POST['name_field'] === "USERA")
{
echo "output.php";
}
else
{
echo "wronguser.php";
}
}
?>">
Username : <input type="text" name="name_field" value="<?php
if(!isset($_POST['name_field']) || $_POST['name_field']=== "")
{
echo "Enter Something" ;
}
?>
<html>
<head>
<meta charset="UTF-8">
<title>SAMPLE</title>
</head>
<body>
<form method='post' action="<?php $SERVER['PHPSELF']; ?>">
<input type="submit" name="submit_button" value="SUBMIT BUTTON !">
</form>
</body>
</html>
I am having an issue with storing $_SESSION variables, i am a little new at PHP and I like it to the extent of my current knowledge.
first my creds:
Win 7 Pro 64
PHP 5
Remote Server(not sure of its config)
So what I am trying to do is set up a Login Page that contains a hardcoded username and password for testing purposes.
I want to display the username on a successor page to confirm it.
Login.php
<?php session_start();?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head >
<title>Login</title>
<link rel="stylesheet" href="style.css" type="text/css" media="screen" />
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<meta http-equiv="content-language" content="en-gb" />
<script type="text/javascript">
// Perform Client side validation of Username and Password
function redirect() {
var username = document.getElementById("username");
var password = (document.getElementById("password"));
if (!username.value == " ") {
if (!password.value == " ") {
if (username.value == "aknight") {
if (password.value == "00226291") {
window.location = "Home.php";
exit();
} else
alert("Username or Password Invalid");
}
} else
alert("Password is required");
} else
alert("Username is required");
}
</script>
</head>
<body>
<div id="header">
<h1>Product Order System</h1>
<br/>
<h2>The most expensive crap youll ever find...</h2>
</div>
<div id="content">
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST'){
$_SESSION['username'] = $_POST['username'];
}else{
?>
<form action="" method="POST">
<fieldset>
<legend>Login Information</legend>
<p>
<label for="Username">Username:</label>
<input type="text" name="username" id="username" />
</p>
<p>
<label for="Password">Password:</label>
<input type="password" name="password" id="password" />
</p>
<p>
<input type="button" name="login" value="Login" onclick="redirect();"/>
<input type="button" name="cancel" value="Cancel" />
</fieldset>
</form>
<?php }
include ('includes/footer.html');
?>
home.php
<?php
session_start();
$page_title = 'Home';
include ('includes/header.php');
if(isset($_SESSION['username'])) { $name = $_SESSION['username'];}else{echo "<p>error</p>";}
echo "<h3>Welcome ".$name."!</h3>" ;
?>
I have tried printing out the $_SESSION values and they are coming up empty.
producing this result
<?php
echo "<pre>".print_r($_SESSION)."</pre>";
?>
Array {
[username] =>
}
Please do not mind the JS, it is preschool client validation just to move forward.
Any help would be greatly appreciated.
Give your login form a name, and then in your JavaScript validation function, instead of window.location, do a document.forms['yourformname'].submit().
I think your Javascript validation is actually what's causing the issue.
You're setting the session variable in Login.php using the POST request, but no POST is actually being sent to Login.php since your Javascript is redirecting to Home.php once the form is considered valid. You need to submit the form at some point in the process, so you actually get some POST values which you'll use to populate your SESSION variables.
If you want to keep your Javascript validation, maybe have a look at submit() : http://www.w3schools.com/jsref/met_form_submit.asp
You'll have to set a correct action property on your form before submitting it.
So heres a fix that seems to be working
<?php session_start();?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head >
<title>Login</title>
<link rel="stylesheet" href="style.css" type="text/css" media="screen" />
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<meta http-equiv="content-language" content="en-gb" />
<script type="text/javascript">
// Perform Client side validation of Username and Password
function redirect() {
var username = document.getElementById("username");
var password = (document.getElementById("password"));
if (!username.value == " ") {
if (!password.value == " ") {
if (username.value == "aknight") {
if (password.value == "00226291") {
document.forms[0].submit();
exit();
} else
alert("Username or Password Invalid");
}
} else
alert("Password is required");
} else
alert("Username is required");
}
</script>
</head>
<body>
<div id="header">
<h1>Product Order System</h1>
<br/>
<h2>The most expensive crap youll ever find...</h2>
</div>
<div id="content">
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST'){
$_SESSION['username'] = $_POST['username'];
header('Location : ../Home.php');
}else{
?>
<form action="Home.php" name="login" method="POST">
<fieldset>
<legend>Login Information</legend>
<p>
<label for="Username">Username:</label>
<input type="text" name="username" id="username" />
</p>
<p>
<label for="Password">Password:</label>
<input type="password" name="password" id="password" />
</p>
<p>
<input type="button" name="login" value="Login" onclick=" redirect();"/>
<input type="button" name="cancel" value="Cancel" />
</fieldset>
</form>
<?php }
include ('includes/footer.html');
?>
Will post again if the nex series of pages has a similiar issue
Thanks
I have the following PHP printExam.php page:
<?php
$logins = array(
'user' => 'pass',
'user1' => 'pass1',
'user2' => 'pass2',
'user3' => 'pass3',
'user4' => 'pass4'
);
// Clean up the input values
foreach($_POST as $key => $value) {
$_POST[$key] = stripslashes($_POST[$key]);
$_POST[$key] = htmlspecialchars(strip_tags($_POST[$key]));
}
/******************************************************************************/
if (isset($_POST['submit'])){
$user = isset($_POST['user']) ? strtolower($_POST['user']) : '';
$pass = isset($_POST['pass']) ? $_POST['pass'] : '';
$report = $_POST['typereport'];
if ((!array_key_exists($user, $logins))||($logins[$user] != $pass)) {
showForm("Wrong Username/Password");
exit();
}
else {
if ($report == "Clinical") {
?>
<html>
<head>
</head>
<body>
CLINICAL PAGE
</body>
</html>
<?php
}
elseif ($report == "Annual Education") {
?>
<html>
<head>
</head>
<body>
ANNUAL EDUCATION PAGE
</body>
</html>
<?php
}
}
} else {
showForm();
exit();
}
function showForm($error=""){
?>
<!DOCTYPE html>
<html><head>
<meta http-equiv="content-type" content="text/html; charset=ISO-8859-1">
<title>Certificate Printing :: Login</title>
<script src="http://code.jquery.com/jquery-1.7.1.min.js" type="text/javascript"></script>
<Script>
$(function() {
$("#user").focus();
});
</Script>
</head>
<body>
<form id="login" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" name="pwd">
<h1>Log In</h1>
<fieldset id="inputs">
<input id="user" name="user" placeholder="Username" autofocus="" required="" type="text">
<input id="pass" name="pass" placeholder="Password" required="" type="password">
</fieldset>
<fieldset id="actions">
<input type="radio" name="typereport" id="cbox" value="Clinical" checked="yes" /> Clinical
<input type="radio" name="typereport" id="cbox" value="Annual Education" /> Annual Education
</fieldset>
<fieldset id="actions">
<input id="submit" name="submit" value="Log in" type="submit">
</fieldset>
<div class="caption"><?php echo $error; ?></div>
</form>
</body>
</html>
<?php
}
?>
For printCert.php and printCertHR.php, the very first line is:
<?php require_once('printExam.php'); ?>
What it is suppose to do is call the printExam.php page each time the user visits either pages. If the username AND password matches and depending on the selection, whether it's clinical or annual education, it should take the user to the correct page. I know the form is working correctly, because if I enter wrong username/password it shows me the error but once correct, it doesnt redirect. Any idea how to resolve it?
Please Note: the username/password is simplified for the example only!
The 'Location' header command in PHP should be followed with an exit;
Otherwise the code below is executed, ie any output is sent to the browser.
See the examples from the PHP header page:
<?php
header("Location: http://www.example.com/"); /* Redirect browser */
/* Make sure that code below does not get executed when we redirect. */
exit;
Location (or any other header) needs to be the first thing echoed by your script. Remove the blank lines in your script.
You have contents being displayed before the header is being called (as for your comment to Rob W). The way to get around it is, put ob_start(); at the top of your php code, and ob_end_flush(); at the end of your code so the header can be called anywhere in between your code.
Is it possible that you might need to use PHP's Output Buffer to fix that? When the script is parsed, having the output of the form in a function might be throwing it off, as the function will be parsed before the rest of the script is run.
Also, you should use strcmp for comparing strings, not the == sign. strcmp vs ==
Try using the output buffer functions and see if that fixes it. it's gonna look something like this:
function showForm($error=""){
ob_start(); ?>
<!DOCTYPE html>
<html><head>
<meta http-equiv="content-type" content="text/html; charset=ISO-8859-1">
<title>Certificate Printing :: Login</title>
<script src="http://code.jquery.com/jquery-1.7.1.min.js" type="text/javascript"></script>
<Script>
$(function() {
$("#user").focus();
});
</Script>
</head>
<body>
<form id="login" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" name="pwd">
<h1>Log In</h1>
<fieldset id="inputs">
<input id="user" name="user" placeholder="Username" autofocus="" required="" type="text">
<input id="pass" name="pass" placeholder="Password" required="" type="password">
</fieldset>
<fieldset id="actions">
<input type="radio" name="typereport" id="cbox" value="Clinical" checked="yes" /> Clinical
<input type="radio" name="typereport" id="cbox" value="Annual Education" /> Annual Education
</fieldset>
<fieldset id="actions">
<input id="submit" name="submit" value="Log in" type="submit">
</fieldset>
<div class="caption"><?php echo $error; ?></div>
</form>
</body>
</html>
<?php
return ob_get_flush();
}
Output Buffers (php.net)
After your elseif ($report == "Annual Education") { block, try print_r($report) - ensure it's what you are expecting...
if ($report == "Clinical") {
header ("Location: printCert.php");
}
elseif ($report == "Annual Education") {
header ("Location: printCertHR.php");
}
print_r($report);
Also, try monitoring FireBug's NET tab (or CHROME's)