Get first value of array and store in new array php - php

I am trying to make card game.
I have 6 variable that are stored in array. Than I use fisherYates method to randomize array, and display four of them.
Problem is, when I randomize it this way only, it will give only random output of those six, with all different types.
So I want that some repeats like, if you draw four cards, you get output of
ex: club, club, diamond,heart, or heart, star,star,heart.. if you get a point..
I thought to do it like this way: put the array in loop of 4 times, and every time it loops, it stores first, or last value in new array, so that way, I can have greater chances of combination of same cards in output array.
But I'm stuck, and I don't know how to do it :/
this is what I've tried so far
$diamond = 'cube.jpg';
$heart = 'heart.jpg';
$spade = 'spade.jpg';
$club = 'tref.jpg';
$star='star.jpg';
$qmark='qmark.jpg';
$time=microtime(35);
$arr=[$diamond,$heart,$spade,$club,$star,$qmark];
function fisherYatesShuffle(&$items, $time)
{
for ($i = count($items) - 1; $i > 0; $i--)
{
$j = #mt_rand(0, $i);
$tmp = $items[$i];
$items[$i] = $items[$j];
$items[$j] = $tmp;
}
return $items;
}
$i=0;
do {
$niz[$i]=fisherYatesShuffle($arr,$time);
reset($niz);
$i++;
} while ($i <= 3);

Got a solution. Was just to simply do foreach of first element of multidimensional array :)
Code goes like this:
$diamond = 'cube.jpg';
$heart = 'heart.jpg';
$spade = 'spade.jpg';
$club = 'tref.jpg';
$star='star.jpg';
$qmark='qmark.jpg';
$time=microtime(35);
$arr=[$diamond,$heart,$spade,$club,$star,$qmark];
$niz=array();
$i=0;
do {
$niz[$i]=fisherYatesShuffle($arr,$time);
//reset($niz);
$i++;
} while ($i <= 3);
foreach ($niz as $key ) {
$randomArr[]=$key[0]; ;
}
function fisherYatesShuffle(&$items, $time)
{
for ($i = count($items) - 1; $i > 0; $i--)
{
$j = #mt_rand(0, $i);
$tmp = $items[$i];
$items[$i] = $items[$j];
$items[$j] = $tmp;
}
return $items;
}
print_r($randomArr);

Related

Problem with php array function displaying only the first item in the array ignoring the rest

I am trying to make a function to display client's items in an array, however only the first item id is shown in the array. What's wrong with my code? I guess I'm doing something wrong with the array.
Example of sItem value: https://pastebin.pl/view/e492ffa1
$items = array();
$client_item = bin2hex($u->sItem);
$x = 0;
for ($i = 0; $i < 78; $i++) {
$item = hexdec(reverse(substr($client_item, $x, 8)));
if ($item != 0) {
$ii = $db->get_object("SELECT * FROM Clients.dbo.ITEM WHERE Num =" . $item);
if (is_object($ii)) {
$items[] = array("ItemID" => $ii->Num, "ItemSlot" => $i);
}
}
$x += 16;
}
The code above will show just the first item in the array. All others are not shown.
var items = [{"ItemID":310511133,"ItemSlot":0}]
I am not sure what I'm doing wrong. If I remove $x += 16; then it will simply add more entries in the array with the first item id. I want more entries but not with the same item id obviously. :)
var items = [{"ItemID":310511133,"ItemSlot":0},{"ItemID":310511133,"ItemSlot":1},{"ItemID":310511133,"ItemSlot":2},{"ItemID":310511133,"ItemSlot":3},{"ItemID":310511133,"ItemSlot":4}....
This is the reverse function:
function reverse($str)
{
$len = strlen($str);
$i = $len - 2;
$ret = NULL;
while (0 <= $i) {
$ret .= substr($str, $i, 2);
$i -= 2;
}
return $ret;
}
Database Query not returning any object SELECT * FROM Clients.dbo.ITEM WHERE Num = $item
can you confirm values exists in database
you can echo $item value and see manually in database are those values exists.

Combining and Permuting items of two different arrays in PHP

How do I return all possible combinations [12345], [12354] up to [54312], [54321] without having to run 120 for...loop as in the case of combining a 2-item array in the code below?
To return all possible combinations from the given array $word = [1,2],
//break the array into 2 separate arrays
$arr1 = $word[0]; $arr2 = $word[1];
//computer for first array item...each item will have 2 loops
for($i=0; $i<count($arr1); $i++){
for($j=0; $j<count($arr2); $j++){
$ret = $arr1[$i] . $arr2[$j]; array_push($result, $ret);
}
}
//computer for second array item..each item will have 2 loops
for($i=0; $i<count($arr2); $i++){
for($j=0; $j<count($arr1); $j++){
$ret = $arr2[$i] . $arr1[$j]; array_push($result, $ret);
}
}
//display the result
for ($i = 0; $i < count($result); $i++){
echo result([$i];
}
The above code works well.
But for a 5-item array [1,2,3,4,5], it will require about (5 items * 24 loops) = 120 loops.
As seen, you wanted to split 2 strings into chars and obtain all combination by 2 chars: first form blank1 and second from blank2.
Instead of doing the combination manually use a regular for-loop.
$result = array();
for ($i = 0; $i < count($blank1); $i++)
{
for ($j = 0; $j < count($blank2); $j++)
{
//set combination
$aux = $blank1[$i].$blank2[$j];
array_push($result, $aux);
}
}
//result should be populated with combination of 2
//just list it and use as need
for ($i = 0; $i < count($result); $i++)
{
echo $result[$i];
}
//same with stored or checking on db : use loops
For multiple combination, use more nested loops
eg: [blank1][blank2][blank1] - 3 combination
$result = array();
//1
for ($i = 0; $i < count($blank1); $i++)
{
//2
for ($j = 0; $j < count($blank2); $j++)
{
//3
for ($k = 0; $k < count($blank1); $k++)
{
//set combination
$aux = $blank1[$i].$blank2[$j].$blank1[$k];
array_push($result, $aux);
}
}
}
Same as any number you wanted ! It will be a little annoying if have to write many loops but note while can be used with an adequate algorithm. But for the moment just keep as simple as you can and get the desired result.

Calculate from an array the number that is equal or higher and closest to a given number

I need to calculate from a given array the number that is equal or higher and closest to a given number in PHP. Example:
Number to fetch:
6.85505196
Array to calculate:
3.11350000
4.38350000
4.04610000
3.99410000
2.86135817
0.50000000
Only correct combination should be:
3.99410000 + 2.86135817 = 6.85545817
Can somebody help me? It's been 3 hours I'm getting mad!
UPDATE: I finally finished my code as following:
$arr = array(3.1135, 4.3835, 4.0461, 3.9941, 2.86135817, 0.5);
$fetch = 6.85505196;
$bestsum = get_fee($arr, $fetch);
print($bestsum);
function get_fee($arr, $fetch) {
$bestsum = 999999999;
$combo = array();
$result = array();
for ($i = 0; $i<count($arr); $i++) {
combinations($arr, $i+1, $combo);
}
foreach ($combo as $idx => $arr) {
$sum = 0;
foreach ($arr as $value) {
$result[$idx] += $value;
}
if ($result[$idx] >= $fetch && $result[$idx] < $bestsum) $bestsum = $result[$idx];
}
return $bestsum;
}
function combinations($arr, $level, &$combo, $curr = array()) {
for($j = 0; $j < count($arr); $j++) {
$new = array_merge($curr, array($arr[$j]));
if($level == 1) {
sort($new);
if (!in_array($new, $combo)) {
$combo[] = $new;
}
} else {
combinations($arr, $level - 1, $combo, $new);
}
}
}
I hope the following example might help you. Please try this
<?php
$array = array(
"3.11350000",
"4.38350000",
"4.04610000",
"3.99410000",
"2.86135817",
"0.50000000"
);
echo "<pre>";
print_r($array);// it will print your array
for($i=0; $i<count($array); $i++)
{
$j=$i+1;
for($j;$j<count($array); $j++)
{
$sum = $array[$i] + $array[$j];
// echo $array[$i]. " + ".$array[$j]." = ".$sum."<br>"; //this will display all the combination of sum
if($sum >= 6.85505196 && ($sum <= round(6.85505196)) )//change the condition according to your requirement
{
echo "The correct combinations are:<br/><br/>";
echo "<b>". $array[$i]. " + ".$array[$j]." = ".$sum."<b>";
echo "<br/>";
}
}
echo "<br/>";
}
?>
We will get the result as below
Array
(
[0] => 3.11350000
[1] => 4.38350000
[2] => 4.04610000
[3] => 3.99410000
[4] => 2.86135817
[5] => 0.50000000
)
The correct combinations are:
4.04610000 + 2.86135817 = 6.90745817
3.99410000 + 2.86135817 = 6.85545817
You should do it in two steps:
a. Work out (or look up) an algorithm to do the job.
b. Implement it.
You don't say what you've managed in the three hours you worked on this, so here's a "brute force" (read: dumb) algorithm that will do the job:
Use a variable that will keep your best sum so far. It can start out as zero:
$bestsum = 0;
Try all single numbers, then all sums of two numbers, then all sums of three numbers, etc.: Every time you find a number that meets your criteria and is better than the current $bestsum, set $bestsum to it. Also set a second variable, $summands, to an array of the numbers you used to get this result. (Otherwise you won't know how you got the solution). Whenever you find an even better solution, update both variables.
When you've tried every number combination, your two variables contain the best solution. Print them out.
That's all. It's guaranteed to work correctly, since it tries all possibilities. There are all sorts of details to fill in, but you can get to work and ask here for help with specific tasks if you get stuck.
Thank you all for your help!
My code is working pretty cool when is needed to fetch one or two numbers (addition) only. But can't figure out how to add more combinations up to the total count of elements in my given array.
I mean if there are, let's say, 8 numbers in my array I want to try all possible combinations (additions to each other) as well.
My actual code is:
$bestsum = 1000000;
for ($i = 0; $i < count($txinfo["vout"]); $i++) {
if ($txinfo["vout"][$i]["value"] >= $spent && $txinfo["vout"][$i]["value"] < $bestsum) {
$bestsum = $txinfo["vout"][$i]["value"];
}
}
for($i = 0; $i < count($txinfo["vout"]); $i++) {
$j = $i + 1;
for($j; $j < count($txinfo["vout"]); $j++) {
$sum = $txinfo["vout"][$i]["value"] + $txinfo["vout"][$j]["value"];
if($sum >= $spent && $sum < $bestsum) {
$bestsum = $sum;
}
}
}
$fee = bcsub($bestsum, $spent, 8);
print("Fee: ".$fee);
New updated code.
<?php
$x = 6.85505196;
$num = array(3.1135, 4.3835, 4.0461, 3.9941, 2.86135817, 0.5);
asort($num); //sort the array
$low = $num[0]; // lowest value in the array
$maxpossible = $x+$low; // this is the maximum possible answer, as we require the number that is equal or higher and closest to a given number
$num = array_values($num);
$iterations = $x/$num[0]; // possible combinations loop, to equate to the sum of the given number using the lowest number
$sum=$num;
$newsum = $sum;
$k=count($num);
for($j=0; $j<=$iterations; $j++){
$l = count($sum);
for($i=0; $i<$l; $i++){
$genSum = $sum[$j]+$sum[$i];
if($genSum <= $maxpossible){
$newsum[$k] = $genSum;
$k++;
}
}
$newsum = array_unique($newsum);
$newsum = array_values($newsum);
$k = count($newsum);
$sum = $newsum;
}
asort($newsum);
$newsum = array_values($newsum);
for($i=0; $i<count($newsum); $i++){
if($x<=$newsum[$i]){
echo "\nMaximum Possible Number = ".$newsum[$i];
break;
}
}
?>

PHP Radix Sort Algorithm - Type conversion ok?

This is a function I wrote for a Radix Sort in PHP.
It works for all cases where the array is populated with numbers greater than 0.
function radix_sort($arr) {
// Find the number of passes needed to complete the sort
$passes = strlen((string)max($arr));
$buckets = [];
// Start the passes
for($i = 1; $i <= $passes; $i++) {
// Create - reinitialize some buckets
for ($b = 0; $b <= 9; $b++) {
$buckets[$b] = [];
}
for ($j = 0; $j < count($arr); $j++) {
// Drop into the proper bucket based on the significant digit
$numStr = (string)$arr[$j];
if (strlen($numStr) < $i) {
$bucketsIndex = 0;
} else {
$bucketsIndex = $numStr[strlen($numStr) - $i];
}
array_push($buckets[$bucketsIndex], $arr[$j]);
}
// Repopulate our array by pulling out of our buckets
$k = 0;
foreach ($buckets as $bucket) {
foreach ($bucket as $value) {
$arr[$k] = $value;
$k++;
}
}
}
return $arr;
}
I feel like there's too much type converting going on. Is it ok to be doing this? If I wanted to pull the Nth digit from a large number, is there a better way in PHP?
You could convert all the value to string before the function, and then revert back to int at the end:
function radix_sort($arr) {
$arr = array_map ('strval', $arr) ;
$passes = strlen(max($arr)) ; // Should still work since all values are numeric
/* Do your stuff... */
return array_map ('intval', $arr) ;
}
Then in your inner loop you could store the length (I don't really know the complexity of strlen in PHP but I assumed it is not O(1)):
for ($j = 0; $j < count($arr); $j++) {
// Drop into the proper bucket based on the significant digit
$numStr = $arr[$j];
$numLen = strlen($numStr) ;
if ($numLen < $i) {
$bucketsIndex = 0;
} else {
$bucketsIndex = $numStr[$numLen - $i];
}
array_push($buckets[$bucketsIndex], $arr[$j]);
}
Or you could even (if you have enough memory) use an array to precompute the length:
$lengths = array_map ('strlen', $arr) ;

Php getting all combinations for a n dimensional array

I have an array of route elements (point1, point2, ...) to provide to a map engine.
I don't know how many points I have. Each point is an array of possible addresses.
I need to perform a check for every combination possible of these points, but only one successful check is required.
My array looks like something akin to:
$point[0] = array($address1, $address2, $adress3);
$point[1] = array($address1, $address2);
$point[2] = array($address1, $address2, $adress3, $adress4);
$point[n] = ...
I want to perform a test for combination: $point[0][0] - $point[1][0] - $point[2][0], $point[0][1] - $point[1][0] - $point[2][0], and so on ! :)
The first successful test (route found) should end the function.
I'm trying to do something with recursion but have spent many hours on this without success.
If I got you right, you want to have a "cartesian product".
This is an example function for it:
It first checks, if there are any subvalues in one of the subarrays and then it creates an array with all possible arraycombinations and returns it.
<?php
function array_cartesian_product($arrays)
{
$result = array();
$arrays = array_values($arrays);
$sizeIn = sizeof($arrays);
$size = $sizeIn > 0 ? 1 : 0;
foreach ($arrays as $array)
$size = $size * sizeof($array);
for ($i = 0; $i < $size; $i ++)
{
$result[$i] = array();
for ($j = 0; $j < $sizeIn; $j ++)
array_push($result[$i], current($arrays[$j]));
for ($j = ($sizeIn -1); $j >= 0; $j --)
{
if (next($arrays[$j]))
break;
elseif (isset ($arrays[$j]))
reset($arrays[$j]);
}
}
return $result;
}
?>

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